Count Of each char in a String(Column)

Hi,
I have on column which stores any string.
I need count of each alphabet, repeated how many times.
For Ex:
If a column has value "ORACLE TECHNOLOGY",
O is repeated 2 times, R occurs 1 time, E is repeated 2 time etc.,
Please send the SQL Query for the above problem!!!
Thanks,
regards,
Suman Naidu.S

Or..
http://forums.oracle.com/forums/thread.jspa?messageID=
1410941?Nice one Janeesh. I had to laugh though at the number of reponses who were giving PL/SQL answers whilst the OP kept on saying "No, I want a Query" meaning he wanted it just as SQL. Only one person gave a valid answer.
;)

Similar Messages

How do I count the unique value pairs in two columns of a table?

I have a table (Table 2) that is populated with data from an imported .csv file. On table 1 I need to count the unique value pairs in two columns of Table 2.
Here's what I have:
Date                                        Person
7/10/2011                         A
7/12/2011                         W
7/12/2011                         X
7/12/2011                         X
7/12/2011                         X
7/12/2011                         Z
7/14/2011                         Z
7/15/2011                 X
7/16/2011                         Z
I'm focusing on person "X" and can easily count how many days that person shows up but what I want is to see on how many unique days that person shows up.
Here's the result I'm looking for (Person "X" shows up on 2 different days - 3 times on 7/12/2011 and once on 7/15/2011):
X                    2
I can't seem to find a function that allows me to do that. I also am not allowed to modify Table 2 so that leaves me to come up with a solution on Table 1.
Any ideas would be greatly appreciated.

Hi John,
Not being allowed to modify Table 2 is a minor inconvenience. Just copy (using a formula) the necessary two columns onto Table 1.
Yellow columns may be hidden. The procedure progresses from left to right. All formulas are entered into row 2 then filled down that column to the end of the table. The table must be as long as the list in column A of Table 2.
A2: =Table 2::A
Fill right to column B.
Fill both columns down as far as needed.
I've used actual Date and Time values in column A, formatted to show only the Date part, but the technique will work with text in these cells, provided all cells representing the same 'date' have exactly the same content.
C2: =A&B
This concatenates the contents of each row of columns A and B into a single text string.
D2: =COUNTIF($C$2:C2,C)
This counts the number of occurrences of the Date&Name string on the current row from the first regular cell in column C (C2) to the current cell.
E2: =IF(COUNTIF($B$2:B2,B)=1,MAX($E$1:E1)+1,"")
This constructs the index of first occurrences of each name, in the order they first occur. The index is used by LOOKUP in column F.
F2: =IF(ROW()-1>MAX(E),"",LOOKUP(ROW()-1,$E,$B))
This uses the index value created in E as a search-for value to extract a single copy of the names in column B. The result is a list of all distinct names in the list. Note that spelling differences will be counted as distinct names.The IF statement stops the listing when the last distinct name is extracted.
G2: =IF(LEN(F)>0,COUNTIFS($B,"="&F,$D,"=1"),"")
This counts the number of 'first occurrences of distinct Date & Name strings for each name on the list (ie. the number of distinct dates on which each name appears in the original list).
All of the functions used are described, with at least one example for each, in the iWork formulas and Functions User Guide. You can download the guide, and the Numbers '09 User Guide, via the Help menu in numbers.
Regards,
Barry

Get the Count for each row

I'm trying to get the count for each row to total count for each month
Something like this
Hardware | Jan
Monitors | 5
Processors | 137
Printers | 57
etc........
How can I write a query for this. I can get the Hardware column but don't know how to get the next column.

If you can provide more data like sample input DML statements it would have been wonderful..
Assuming is , you need a pivot. Here is an article on basic Pivot..
http://sqlsaga.com/sql-server/how-to-use-pivot-to-transform-rows-into-columns-in-sql-server/
something like this may be..
DECLARE @Input TABLE
Hardware VARCHAR(20),
[Date] VARCHAR(20)
INSERT INTO @Input VALUES('Monitor', '01/01/2014'), ('CPU', '01/01/2014'), ('Monitor', '01/03/2014')
, ('ABC', '01/01/2014'),('Monitor', '02/01/2014')
;WITH CTE AS
SELECT Hardware, LEFT(DATENAME(M, [Date]),3) AS [MonthName] FROM @Input
SELECT *
FROM
SELECT Hardware, [MonthName], COUNT(Hardware) AS Count FROM CTE GROUP BY Hardware, [MonthName]) a
PIVOT (MAX([Count]) FOR [MonthName] IN ([Jan], [Feb])) pvt
Please mark as answer, if this has helped you solve the issue.
Good Luck :) .. visit www.sqlsaga.com for more t-sql code snippets and BI related how to articles.

Method to count number of characters in a string?

hi.
i'm trying to write some script that will count the number of characters in a string passed into a constructor and then compare it against another value to check whether the string passed in is valid.
something like this
public class Stringcheck
public static int maxStringLength;
public static double minSize;
public static boolean testStringLength(String x)
// Insert method for counting number of chars in String x and name as 'int numberOfChars
if(number of Chars <= maxStringLength )
return true;
else
return false;
can someone help me with writing this script.
Thanks
Richard.

ummm, you dont need anything fancy. try:
String test = "this is the test string";
int length = test.length();

Deleting the last char of a string

How can I Delete the last char of a string???
example:
asd@fdg@vvdfgfd@gdgdfgfd@gdfgdf@
I want delete the last @!
Tks in advance!

hi,
try this:
lv_count = strlen(string).
lv_count_last = lv-count - 1.
replace string+lv_count_last(lv_count) in string by ' '.
This should work.
thnx,
ags.
Edited by: Agasti Kale on Jun 4, 2008 9:03 PM

Count() for each group, but only groups having 1+ element like... AND all elements like...

There are tables(and columns) like:
'Clients'(clientID)
'Houses' (houseID)
'Visits' (clientID, houseID, visit_date)
'Contracts'(contractID, houseID, clientID, rentDate_from, rentDate_end)
I have problem with writing MS SQL query of this kind:
how many visits to houses did each client, before renting one of them?
Its easy to count total number of Visits for each client, listing all visits + group by clientID and selecting count(*) for each group.
Lets say this is select_1, and select_2 is listing all Contracts for all clients.
Select_1 is not answer, because count must be performed only on groups, which:
-have at least 1 row "like" row in select_2 (it means that at least one of visited houses was rented, because it can happen that client visited few houses, but rented other, not visited house). my idea for this is comparing select_1 and select_2 with:
"where s1.clientID=s2.clientID and s1.houseID=s2.houseID"
-each group must have all rows(visits) with date of same day or earlier than contract date
maybe: "datediff(day, s1.visit_date, s2.rentDate_from) >= 0"

In future, please provide proper DML, DDL and example data, like I have for you below.
DECLARE @clients TABLE (clientID INT, name VARCHAR(20))
INSERT INTO @clients (clientID, name)
VALUES (1, 'Jonathan'),(2, 'Christopher'),(3, 'James'),(4, 'Jean-Luc'),(5, 'William')
DECLARE @houses TABLE (houseID INT, address VARCHAR(20))
INSERT INTO @houses (houseID, address)
VALUES (1, 'NX01'),(2, 'NCC 1701'),(3, 'NCC 1071A'),(4, 'NCC 1701D'),(5, 'NCC 1701E')
DECLARE @visits TABLE (clientID INT, houseID INT, visitDateTime DATETIME)
INSERT INTO @visits (clientID, houseID, visitDateTime)
VALUES (1,1,'2001-01-01 12:13:14'),
(2,2,'2001-01-02 12:13:14'),
(3,2,'2001-01-01 12:13:14'),(3,3,'2001-01-01 12:13:14'),
(4,4,'2001-01-01 12:13:14'),(4,5,'2001-01-01 12:13:14'),
(5,4,'2001-01-01 12:13:14'),(5,5,'2001-01-01 12:13:14')
DECLARE @contracts TABLE (contractID INT IDENTITY, houseID INT, clientID INT, rentStartDate date, rentEndDate date)
INSERT INTO @contracts (houseID, clientID, rentStartDate, rentEndDate)
VALUES (1,1,'2001-01-02',NULL),(2,2,'2001-01-02',NULL),(3,3,'2001-01-02',NULL),(4,4,'2001-01-02',NULL),(5,5,'2001-01-02',NULL)
SELECT contractID, c.houseID, c.clientID, rentStartDate, rentEndDate, cl.clientID, name, h.houseID, address, COUNT(v.clientID) AS visits
FROM @contracts c
LEFT OUTER JOIN @clients cl
ON c.clientID = cl.clientID
LEFT OUTER JOIN @houses h
ON c.houseID = h.houseID
LEFT OUTER JOIN @visits v
ON c.clientID = v.clientID
AND c.rentStartDate >= v.visitDateTime
GROUP BY contractID, c.houseID, c.clientID, rentStartDate, rentEndDate, cl.clientID, name, h.houseID, address

Compare individual char of 2 string

Hi
I need to compare the each individual char of 2 string.
String a = "Ae12";
String b = "aE12";
// I tried the followings:
// a
String c = a.substring(0,0);
String d = a.substring(1,1);
String e = a.substring(2,2);
String f = a.substring(3,3);
// b
String c1 = b.substring(0,0);
String d1 = b.substring(1,1);
String e1 = b.substring(2,2);
String f1 = b.substring(3,3);
if(c.equalsIgnoreCase(c1)&&d.equalsIgnoreCase(d1)&&e.equalsIgnoreCase(e1)&&f.equalsIgnoreCase(f1)) // Cannot be compared
// and I tried the followings:
// a
char c = a.charAt(0);
char d = a.charAt(1);
char e = a.charAt(2);
char f = a.charAt(3);
// b
char c1 = b.charAt(0);
char d1 = b.charAt(1);
char e1 = b.charAt(2);
char f1 = b.charAt(3);
if(c==c1&&d==d1&&e==e1&&f==f1) // cannot be compared.
Both cases cannot be compared. How can I fix it?
Because I want to compare those 2 strings without case sensitive and numbers.
Thanks

techissue2008 wrote:
String a = "Ae12";
String b = "aE12";
Then, are "Ae12" and "aE12" the same when ignore case?
If so, the Strings are actually the same.No, the Strings are not the same, if by same, you mean the "same" Object, or the "same" value when case is not ignored, but they are the "same" value when case is ignored.
This prints true (try it yourself), as it should
public class Test {
public static void main (String[] args) {
System.out.println("aE12".equalsIgnoreCase("Ae12"));
}They are still two distinct instances with two distinct values however, so where, exactly, is your problem?

Convert string Column into set or Rows.

Hi,
I have a difficult time converting a string column in the source table to be spitted and insert them as individual rows in target table. The source sting is separated by "-" character. And the source sting can have any number of "-" which may result in any number of out put rows.
e.g. "- IL - NY - NJ - KY - TX" "RAY" should look like
RAY IL
RAY NY
RAY NJ
RAY KY
RAY TX
in the target table.
Thanks,
Ashvin.
Edited by: user591315 on Mar 13, 2009 8:03 AM

This is working.
All you need to do in owb is pull the table function operator , config it take a ref-cursor and also give the attribute names that are declared in the type record to each of the out put variables in the table function operator.(in this case-8 variables).
Thanks,
Ashvin.
CREATE OR REPLACE
type RDW.STAFF_MEMBER_BREAKDOWN_RECORD is object
( survey_i_id number,
survey_id number,
client number,
company number,
csg number,
contact number,
pred_mode_type number,
pred_mode_string varchar2(2000));
CREATE OR REPLACE
type RDW.STAFF_MEMBER_BREAKDOWN_TABLE
is table of staff_member_breakdown_record;
CREATE OR REPLACE package RDW.refcur_pkg
as
type staff_teams_cur_type is ref cursor;
end refcur_pkg;
CREATE OR REPLACE function RDW.parse_teams
(staff_teams_cur refcur_pkg.staff_teams_cur_type)
return staff_member_breakdown_table
pipelined
is
v_survey_i_id NUMBER;
v_survey_id NUMBER;
v_client NUMBER;
v_company NUMBER;
v_csg NUMBER;
v_contact NUMBER;
v_pred_mode_type NUMBER;
v_team_members_r VARCHAR2(2000);
v_team_members VARCHAR2(2000);
cnt NUMBER;
exit_flag NUMBER;
begin
loop
fetch staff_teams_cur into v_survey_i_id,v_survey_id ,v_client,v_company,v_csg,v_contact,v_pred_mode_type,v_team_members;
exit when staff_teams_cur%notfound;
exit_flag := 0;
v_team_members_r := ltrim(v_team_members,'#') ;
loop
cnt := instr( v_team_members_r, '#' );
if ( cnt > 0 )
then
v_team_members := substr(v_team_members_r,1,instr(v_team_members_r,'#')-1);
v_team_members_r := substr(v_team_members_r,instr(v_team_members_r,'#')+1);
else
v_team_members := v_team_members_r;
exit_flag := 1;
end if;
pipe row (staff_member_breakdown_record(
to_number(v_survey_i_id),v_survey_id ,v_client,v_company,v_csg,v_contact,v_pred_mode_type, v_team_members));
exit when exit_flag = 1;
end loop;
end loop;
end parse_teams;
/

GETTING COUNTS FOR EACH SSN

I am doing a report in ORACLE REPORT WRITER. How can I get counts for each SSN. I want to check the last 7 SSNS
and if the competence codes are different get a count for them. If the fitness codes are different get a count for them. This is for each SSN. Sometimes SSNS may have different competence codes but the fitness codes are the same. I still need counts for the competence codes. Other times the SSNS have different fitness codes but the competence codes are the same and I need counts for the fitness codes. Other times the fitness codes are different and the competence codes are different and I need counts for the fitness codes and counts for the competence codes. Here is a sample of what the report should look like:
SSN TOTAL TOTAL
Competence Fitness
000000111 13 6
000000222 6 0
000000333 0 7
I have everything wrapped up under one count. I don't know to change the query to display 2 separate counts.
I have used Summary Columns but that does not work.
I could use 2 separate querys and get counts for competence and fitness respectively but the SSNS would be out of order. The SSNS must be in order.
Here is the query.
SELECT DISTINCT T2.IND_SSN, COUNT(*)cnt1
FROM (SELECT distinct(t.ind_ssn), t.ind_competence_rtg_old, t.ind_competence_rtg_new, ROW_NUMBER()
OVER (PARTITION BY t.ind_ssn ORDER BY t.IND_SSN ASC, t.ind_er_per_end_dt DESC) rn
FROM NCOER_JRNL T) t2
WHERE t2.rn <= 7
and (t2.ind_competence_rtg_old <> t2.ind_competence_rtg_new)
GROUP BY T2.IND_SSN
UNION
SELECT DISTINCT T2.IND_SSN, COUNT(*)cnt2
FROM (SELECT distinct(t.ind_ssn), t.ind_FIT_rtg_old, t.ind_FIT_rtg_new, ROW_NUMBER()
OVER (PARTITION BY t.ind_ssn ORDER BY t.IND_SSN ASC, t.ind_er_per_end_dt DESC) rn
FROM NCOER_JRNL T) t2
WHERE t2.rn <= 7
and (t2.ind_FIT_rtg_old <> t2.ind_FIT_rtg_new)
GROUP BY T2.IND_SSN
ORDER BY 1

Thanks for you reply Ricardo. It does work (but only if select 1 ticket).
My bad I only posted one Ticket Number. Actually there are lots of them ( as below). Your code take all the tickets as one tickets.
TicketNumber
OwningTeam
Status
Date
Team Number
123
TEAM 1
Pick Up
11/12/2014
1
123
TEAM 1
Complete
11/12/2014
1
123
TEAM 2
Pick Up
11/12/2014
2
123
TEAM 2
Complete
11/12/2014
2
123
TEAM 2
Resolve
11/17/2014
2
123
TEAM 2
Complete
11/24/2014
2
123
TEAM 2
Pick Up
12/8/2014
2
123
TEAM 2
Complete
12/9/2014
2
123
TEAM 2
Provide Info
12/17/2014
2
123
TEAM 1
Pick Up
1/8/2015
3
123
TEAM 1
Resoved
1/8/2015
3
456
TEAM 1
Pick Up
11/12/2014
1
456
TEAM 1
Complete
11/12/2014
1
456
TEAM 2
Complete
11/24/2014
2
456
TEAM 2
Pick Up
12/8/2014
2
456
TEAM 2
Complete
12/9/2014
2
456
TEAM 3
Pick Up
12/17/2014
3
456
TEAM 3
Working
12/18/2014
3
456
TEAM 1
Pick Up
1/8/2015
4
456
TEAM 1
Resoved
1/8/2015
4
789
TEAM 1
Pick Up
11/12/2014
1
789
TEAM 1
Complete
11/12/2014
1
789
TEAM 2
Complete
11/24/2014
2
789
TEAM 2
Pick Up
12/8/2014
2
789
TEAM 2
Complete
12/9/2014
2
789
TEAM 1
Complete
12/12/2014
3
Any work around is really appreciated.
Thanks,
Rajneet

How to delete the last char in a String?

i want to delete the last char in a String, but i don't want to convert the String to a StringBuffer or an array, who knows how to do?

Try it in this way
String MyString = "ABCDEF";
MyString = MyString.substring(0,MyString.length()-1);

How to get each character in a string

as in 'C' we use arrays to get each character of a string stored in array.how can we get each character of a string stored in a variable.

Hi,
For that you need to do offset.
for example one variable called VAR contains string 'HUMERAH'.
if you want each character of that string then you need to decalre as many variable as the number of string.
like
data : var1(1),
var2(1),
var(3),
var(4).
var1 = var+(1).
var2 = var+1(1).
var3 = var+2(1).
var4 = var+3(1).
now var1,var2,var3,var4. contains the single characters.
Regards,
Guru
mark helpful answers

I also have a .csv file with the name of a jpeg in one column and a text description of each jpeg in a second column. Is there a way to automatically insert one jpeg (photo) and its corresponding text, each pair on one page, into a Indesign document?

I also have a .csv file with the name of a jpeg in one column and a text description of each jpeg in a second column. Is there a way to automatically insert one jpeg (photo) and its corresponding text, each pair on one page, into a Indesign document?

I would also recommend to write the description into the meta data. This would allow to place a text frame above the image and it is possible to add meta information and file name automatically together with the image, when you place it or even in a prepared template.
Meta data information can be written easily in Bridge in the Meta File Workspace.

Count the no. of rows in a column

I want to count the no. of rows in APR_QTY column that are not equal to zero.
SELECT DISTINCT
SUPP_NAME,
ITEM_NAME,
(CASE WHEN BH_CAL_PERIOD=4 THEN TO_NUMBER(BI_QTY || '.' || BI_QTY_LS) ELSE 0 END)APR_QTY,
(CASE WHEN BH_CAL_PERIOD=4 THEN BI_RATE ELSE 0 END)APR_RATE,
(CASE WHEN BH_CAL_PERIOD=5 THEN TO_NUMBER(BI_QTY || '.' || BI_QTY_LS) ELSE 0 END)MAY_QTY,
(CASE WHEN BH_CAL_PERIOD=5 THEN BI_RATE ELSE 0 END)MAY_RATE,
(CASE WHEN BH_CAL_PERIOD=6 THEN TO_NUMBER(BI_QTY || '.' || BI_QTY_LS) ELSE 0 END)JUNE_QTY,
(CASE WHEN BH_CAL_PERIOD=6 THEN BI_RATE ELSE 0 END)JUNE_RATE,
(CASE WHEN BH_CAL_PERIOD=7 THEN TO_NUMBER(BI_QTY || '.' || BI_QTY_LS) ELSE 0 END)JUL_QTY,
(CASE WHEN BH_CAL_PERIOD=7 THEN BI_RATE ELSE 0 END)JUL_RATE
FROM
OM_SUPPLIER,
OM_ITEM,
OT_BILL_HEAD,
OT_BILL_ITEM,
OT_BILL_ITEM_TED
WHERE BI_BH_SYS_ID = BH_SYS_ID
AND SUPP_CODE = BH_SUPP_CODE
AND ITEM_CODE = BI_ITEM_CODE
AND BH_SYS_ID = ITED_H_SYS_ID
AND BI_SYS_ID = ITED_I_SYS_ID
AND BH_TXN_CODE='SBRLRAW'
GROUP BY BH_CAL_PERIOD,BH_TXN_CODE,SUPP_NAME,ITEM_NAME,BI_RATE,BI_QTY,BI_QTY_LS
ORDER BY ITEM_NAME
Message was edited by:
yogeshyl

Select sum(decode(apr_qty,0,0,1)) as cnt_apr_qty
from ...

How do I program a NI 6602 card to send trigger pulses, one at each output port, triggered by an input trigger signal, using only one counter for each output port?

Hello,
I have managed to program a NI 6602 card in LabView to send pulses on three different output ports, one pulse on each output port (with individually chosen delays) for each input trigger pulse coming on a separate input port. It is the DAQmx Create Channel (CO-Pulse Generation-Time)-VI that I have used for this, see attached code. However, this VI controls both pulse delay and pulse width, and therefore uses two counters for each output port (although you only specify one counter in the VI input signals), as I understand.
In my application though, I only need to have the delay chosen, the pulse width can be arbitrarily short, and thus I should only need one counter for each output port. How do I accomplish to program this in LabView?
Best regards,
Claes
Attachments:
Configure Side Camera Flash 1 Triggering.vi ‏47 KB

Well you're welcome to do that--it will work just fine as long as you are configuring a start trigger.
<rant>
However, personally I really don't like putting multiple counter outputs in the same task. I have seen so many people assume that the counter outputs would be synchronized due to having them in the same task when this is not the case (you need to configure a start trigger in order to synchronize the counter outputs even if they are in the same task). This is the only case I can think of where multiple channels in a DAQmx task are not automatically synchronized.
As an example:
Running this on my PCIe X Series gives a measured 2 edge separation of 1 ms + {7.78 us - 10.11 us}. This would likely be much worse on a bus with more latency (e.g. USB).
The resulting output is close enough to what you might expect that it might go unnoticed, but really these counter outputs are not synchronized and it would be easy to glance at the code and not even think twice about it. For the small amount of extra work on my end to create a separate task for each counter, it really clears up some ambiguity about what the counters are actually doing. For me it's worth it.
So again, for your case there really isn't a problem with having the counters in the same task since you are using an external start trigger anyway. I have just gotten in the habit of avoiding doing this.
</rant>
Best Regards,
John Passiak

Regarding count for each type Trace entry

Hi Friends,
I am using ALV grid Display to display the Result.
my requirement is to display report with sorting & Count for each entry on a particular field.
Can anybody give me the idea or smalll code on this Plz...
Thanks in advance.
Regards,
Ravish

Hi,
For sorting you can use standard ALV sorting functionality. (Pass the parameter it_sort by filling the sort field name and sort order like up or down(Either one).
For count you need to keep explicit logic.
Sample code.
SORT i_final BY field1. "Your count field criteria.
LOOP AT i_final INTO wa_final.
ADD 1 TO l_count.
AT END OF field1.
MOVE l_count TO wa_final-count.
MODIFY i_final FROM wa_final WHERE field1 = wa_final-field1 TRANSPORTING count.
CLEAR l_count.
ENDON.
ENDLOOP.
Make sure that your count based field is the first field in itab. For displaying the output you can adjust the fieldcat.
Thanks,
Vinod.

Count Of each char in a String(Column)

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