Counting letters in a word

Question

I am using lingo to count and display letters in a word but my script is stuck on a point. Can any help to solve this?
property 
SpriteNum
global 
gCurrentCounter, CurrentWord, lettersofCurrentWord, sSoundName
On 
MouseDown me
 if  gCurrentCounter < 10 then
p = "00" & gCurrentCounter
else if  gCurrentCounter < 100 then
p = "0" & gCurrentCounter
elsep = gCurrentCounterend ifj = 1
letter_no = spritenum
letter_name = member("PE_" & string(j)).text
letter_uppercase = "A"
 -- puppetSound 1, "A sound"
CurrentWord = member("word - " & p)i =
1
If  sprite (letter_no).within(sprite(spritenum)) Thenif 
charToNum(member(CurrentWord).paragraph[1].char[1]) <= 90 then
member ("pe_space_" & string(i)).text = letter_uppercase
elsemember ("pe_space_" & string(i)).text = letter_name
end if   
end if set the  loc of sprite letter_no to point(300,330) 
-- i = 2
put  i 
-- repeat while i <= CurrentWord.char.count
 if  charToNum(member(CurrentWord).paragraph[1].char[i]) >= 200 then
member ("pe_space_" & string(i)).text = member(CurrentWord).paragraph[1].char[i]
sprite  (letter_no).within(sprite (10 + i))
elsemember ("pe_space_" & string(i)).text = letter_name 
end if 
i = i + 1
 -- end repeat
 end  mousedown me
　 end

Answer 1

**** Hello Sean see responses to questions in RED
So what sort of sprite/member holds the completed word?
Sean -  A complete set of sprite equal the number of letters in
the word named pe_space_
Presumably the code you posted is attached to individual letters of the
alphabet?
Sean - You assumed right
I have re-posted your code with questions and comments interspersed -
perhaps you could addess some of these:
global gCurrentCounter, CurrentWord, lettersofCurrentWord, sSoundName
property SpriteNum
on mouseDown me
if gCurrentCounter < 10 then
p = "00" & gCurrentCounter
else if gCurrentCounter < 100 then
p = "0" & gCurrentCounter
else
p = gCurrentCounter
end if
j = 1
letter_no = spritenum
-- I don't understand: since you declared j = 1
-- your local var 'letter_name' will always be member("PE_1").text
letter_name = member("PE_" & string(j)).text
-- again, you have hard-coded something with no apparent reason
letter_uppercase = "A" ***  Sean - In case the first letter is uppercase
-- puppetSound 1, "A sound"
CurrentWord = member("word - " & p)
i = 1
if sprite (letter_no).within(sprite(spritenum)) then
if charToNum(member(CurrentWord).paragraph[1].char[1]) <= 90 then
member("pe_space_" & string(i)).text = letter_uppercase
else
member("pe_space_" & string(i)).text = letter_name
end if
end if
sprite(letter_no).loc = point(300,330)
-- i = 2
-- i will always equal 1 because that's how you declared it above, and it
isn't changed
Yes Sean, this is the reason for my been stuck on the first sprite
or letter of my word. I was hoping to achive repeat effect by clicking on the mouse
or keydown to get word spelt.
But on mouseDown me or keyDown does not work with my code
put i - This tell me that I am stuck on i = 1
-- can you explain what this block of code is doing?
-- I have no idea what the various members
-- member("pe_space_" & string(i))
-- are or how they're used
Sean the pe_space_  are the fields where my letter PE_ get attached to,
so when I release my letters on grab and move they are within these
sprites/fields
So, Sean can still help?
repeat while i <= CurrentWord.char.count
if charToNum(member(CurrentWord).paragraph[1].char[i]) >= 200 then
member("pe_space_" & string(i)).text =
member(CurrentWord).paragraph[1].char[i]
-- 'within' is an operator that returns TRUE/FALSE
-- so it isn't clear what you're trying to do here
sprite(letter_no).within(sprite (10 + i))
else
member("pe_space_" & string(i)).text = letter_name
end if
i = i + 1
end repeat
end mouseDown
Message was edited by: efeelo