Creating a View at Database level to be used in an another application

Posted - 01/20/2012 : 11:43:27
I have a table Named Customer_Distribution in which we store all the recepient information based on a request submitted by the customer.
Maximum number of recepients for a request is 3.So if a customer submits a request with 3 recepients the Customer_Distribution table will have 3 records inserted for the request as below
ReqNo recepientdesc recepientname recepientemail
1 R Abc [email protected]
1 U xyz [email protected]
1 S sap [email protected]
I'm trying to create a view and need help to create the view such that the entire Request Information is in a single row rather than multiple rows as we are trying to use this view in another application where it will be easy to retreive if the entire information is in a single row
The View should have the data in the below format
ReqNo desc1 name1 email1 desc2 name2 email2 desc3 name2 email2
1 R Abc [email protected] U Xyz [email protected] S sap [email protected]
Thanks

user12946819 wrote:
Hi
Would you be able to elaborate more on your response as i am new to oracle and have hard time using your response
Thanks
ME_XE?with
2     data as
3 (
4     select 1 as ReqNo, 'R' as recepientdesc, 'Abc' as recepientname, '[email protected]' as recepientemail      from dual union all
5     select 1 , 'U', 'xyz', '[email protected]'         from dual union all
6     select 1 , 'S', 'sap', '[email protected]'       from dual union all
7     select 2 , 'Q', 'me',   '[email protected]'        from dual
8 )
9 select
10     ReqNo,
11     max( decode( rn, 1, recepientdesc))     as desc1,
12     max( decode( rn, 2, recepientdesc))     as desc2,
13     max( decode( rn, 3, recepientdesc))     as desc3,
14     max( decode( rn, 1, recepientname))     as name1,
15     max( decode( rn, 2, recepientname))     as name2,
16     max( decode( rn, 3, recepientname))     as name3,
17     max( decode( rn, 1, recepientemail))    as email1,
18     max( decode( rn, 2, recepientemail))    as email2,
19     max( decode( rn, 3, recepientemail))    as email3
20 from
21 (
22     select
23             ReqNo, recepientdesc, recepientname, recepientemail,
24             row_number() over (partition by ReqNo order by recepientdesc asc) as rn
25     from data
26 )
27 group by ReqNo;
             REQNO DES DES DES NAME1     NAME2     NAME3     EMAIL1                                        EMAIL2                                        EMAIL3
                 1 R   S   U   Abc       sap       xyz       [email protected]                                 [email protected]                               [email protected]
                 2 Q           me                            [email protected]
2 rows selected.
Elapsed: 00:00:00.01
ME_XE?In the future, posting sample data in a format that someone can easily use (like i did above) will get you answers a lot quicker. I'm in a decently good mood this morning so i did it myself. 7 times out of 10 i'll skip over questions that don't make it easy for me to help. Just an FYI to help you in future posting.

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glink indicates a databse link between Haggis and Gus
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Thank you for the reply will follow up the code format
Create views in your HAGGIS schema database which will join all of the exam grades together. You should have one view which will produce the following relation :
examGrade(upn, subject, examlevel, sn, grade,academicYear)
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select count(upn)
from comqdhb.student@glink I get 9000
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select distinct s.upn as upn
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, g.grade as grades
, '9364097'
, to_number(g.academicyear) as academicyear
from comqdhb.student s
, comqdhb.grade g
where s.upn=g.upn
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, g.grade
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, sc.sn
from comqdhb.subject@glink sb
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932002 some results.
2:
Another problem i am having which i am trying to solve and written up my ideas but haven't been getting the expected results.Hope you can help.Thank you.
Information:
=======
All children take exams at the age of 16 called a General Certificate of SecondaryEducation (GCSE).
They have to study and take exams in Mathematics, English and Science, and can take other subjects such as History, French, Art etc. Most students will study between 5 and 10 different subjects before taking their GCSEs.
For each exam, a student is awarded a grade from A*, A, B,C,D,E,F,G,U,X An A* grade is the best grade achievable and an X is the worst grade.
In order to analyze how students have performed, each grade is mapped to a numeric value as follows:
Grade Numerical score
A* 8
A 7
B 6
C 5
D 4
E 3
F 2
G 1
U 0
X 0
Now why i need this avgGCSE is because i have to create a view containing avgGCSE of the students it is used in the next question where a condition is avgGCSE is between 6.5 and 7
In order to calculate the avgGCSE the idea is to calculate the grades of the students and map the grades to their corresponding scores/values
add them all up and div by the total no of grades to get the avg.
desc comqdhb.STUDENT@glink;
STUDENT
=======
UPN
FNAME
CNAME
DOB
GENDER
PREVIOUSSCHOOL
XGCSE
SCHOOL
ACYR
STUDENTINGROUP
=============
UPN
GID
STARTDATE
ENDDATE
GRADE
GRADEVALUES
===========
GRADE
LEVEL
VALUE
I have a opinion that xgcse in STUDENT table refers to the avgGCSE which i want to calculate as when i asked my professor as to what xgcse he said that he forgot to take it out of the table and it is not necessary while creating avggcse.
select *
from comqdhb.student@glink
where xgcse<6.5; Displaying a result
returns:
UPN FAMILYNAME COMMONNAME DATEOFBIR GENDER PREVIOUSSCHOOL XGCSE SCHOOL ACYR
===========================================================================
1011 KIMBERLY ABBOT 07-JUL-79 f none 3.93500948 2 2
select *
from comqdhb.student@glink
where xgcse between 6.5 and 7 and upn = 1386; Displaying a result
returns:
UPN FAMILYNAME COMMONNAME DATEOFBIR GENDER PREVIOUSSCHOOL XGCSE SCHOOL ACYR
===========================================================================
1386 STEPHANIE AANNESSON 15-JAN-79 f none 6.88873 2 2 so if xgcse is the avgGCSE then upn 1011 has avggcse<6.5 and 1386 has avggcse >6.5
my idea was backward strategy like so now if we find out upn 1368 has suppose xgcse(avggcse)>6.5 how to extract the avggcse for the particular upn We need to map grades from GRADEVALUES to grade in STUDENTINGROUP and map upn from studentingroup to upn in student to output the values for the corresponding grades from GRADEVALUES
select grade
from comqdhb.studentingroup@glink
where upn = 1011;
Result:
GRADE
=====
D
F
B
E
C
E
E
B
8 rows selected. Mapping each grade to the corresponding value and calculating we get
32/8=4 total(values to corresponding grades)/no of grades.
But the xgcse for upn 1011 is 3.935 and i am getting 4!! maybe xgcse isn't avggrade but ? is the procedure by me correct for calculating avggcse
select grade
from comqdhb.studentingroup@glink
where upn = 1386;
Result:
GRADE
======
A*
A*
A*
A*
B
A*
A*
A
B
B
B
11 rows selected. grade to the corresponding value and calculating we get
79/11=7.12 total(values to corresponding grades)/no of grades.
But the xgcse for upn 1011 is 6.88... and i am getting 7.12!!
But another problem
when i say
select g.value,g.grade
from comqdhb.gradevalues@glink g
, comqdhb.studentingroup@glink sg
where g.grade=sg.grade
and sg.upn=1011;
result:
======
VALUE GRADE
===========
100 B
100 B
 80 C
 60 D
 40 E
 40 E
 40 E
 20 F
 6 B
 6 B
 5 C
VALUE GRADE
=============
 4 D
 3 E
 3 E
 3 E
 2 F
16 rows selected.
select distinct g.value,g.grade
from comqdhb.gradevalues@glink g
, comqdhb.studentingroup@glink sg
where g.grade=sg.grade
and sg.upn=1011;
result:
======
VALUE GRADE
============
 2 F
 100 B
 6 B
 3 E
 60 D
 5 C
 4 D
 80 C
 40 E
 20 F
10 rows selected. I am getting only 8 for the query
select grade
from comqdhb.studentingroup@glink
where upn = 1386; here its becomming 10 and also its displaying values as 100 and ...
select distinct *
from comqdhb.gradevalues@glink;
GRADEVALUES
===========
LEVEL GRADE VALUE
================================
a A 120
a B 100
a C 80
a D 60
a E 40
a F 20
a U 0
a X 0
g A 7
g A* 8
g B 6
LEVEL GRADE VALUE
================================
g C 5
g D 4
g E 3
g F 2
g G 1
g U 0
g X 0
18 rows selected. I was hoping if i could map the grades and get the values and calculate avggrade by total(values)/count(values)that would be it but here there are values like 100...
select sum(g.value)/count(g.grade) as avggrade
from comqdhb.gradevalues@glink g
, comqdhb.studentingroup@glink sg
where g.grade=sg.grade
and sg.upn=1386;
avggrade
========
37.4375 the avggrade cant be this big and when i map each grade i obtained for 1368 like a to 7+b to 6 so on i get avggrade 7.12
kindly help.
Edited by: Trooper on Dec 15, 2008 4:49 AM

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Creating a View at Database level to be used in an another application

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