Date difference in one column

Hi all,
I need the column DATEDIFFERENCE as per below
Kindly help me out .
How to perform on the same column .
Regards, Subathra

create table test (id varchar(10), createddate datetime, assigneddate datetime, resolveddate datetime)
insert into test values ('SD1023','4/2/2014 10:02:00','4/2/2014 10:06:00','6/2/2014 20:06:03')
insert into test values ('SD1023','4/2/2014 10:02:00','4/2/2014 10:20:01','6/2/2014 20:06:03')
insert into test values ('SD1023','4/2/2014 10:02:00','4/2/2014 12:02:00','6/2/2014 20:06:03')
insert into test values ('SD1023','4/2/2014 10:02:00','6/2/2014 20:06:03','6/2/2014 22:10:03')
insert into test values ('SD10123','6/2/2014 20:06:03','6/2/2014 20:06:03','6/2/2014 23:06:06')
insert into test values ('SD10123','6/2/2014 20:06:03','6/2/2014 21:06:04','6/2/2014 23:06:06')
insert into test values ('SD10123','6/2/2014 20:06:03','6/2/2014 22:06:05','6/2/2014 23:06:06')
insert into test values ('SD10123','6/2/2014 20:06:03','6/2/2014 23:06:06','6/2/2014 23:06:06')
;with mycte as (select *,row_number() Over(Partition by id Order by AssignedDate) rn1
,row_number() Over(Partition by id Order by AssignedDate DESC) rn2
from test)
,mycte1 as (
Select m0.id,m0.createddate,m0.assigneddate,m0.resolveddate,
CASE WHEN m0.rn1=1 Then m0.createddate Else m1.assigneddate End as dt1,
CASE WHEN m0.rn2=1 Then m0.resolveddate Else m0.assigneddate end as dt2
from mycte m0 left join mycte m1 on m0.id=m1.id and m0.rn1=m1.rn1+1)
select id,createddate,assigneddate,resolveddate
,datediff(second,dt1,dt2) as [Date Difference in seconds] from mycte1
order by dt1
drop table test

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Dear All,
I have the table data like this.
type quantity revenue_mny count country
a 10           10          2 India
a 20          12          3 India
b 30          15          1 India
a 35          20          2 US
b 20          10          1 US
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I woulkd like to split the date based on type column.
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Like this?
with t as
select 'a' type, 10 quantity, 10 revenue_mny, 2 cnt, 'India' country from dual union all
select 'a', 20, 12, 3, 'India' from dual union all
select 'b', 30, 15, 1, 'India' from dual union all
select 'a', 35, 20, 2, 'US' from dual union all
select 'b', 20, 10, 1, 'US' from dual union all
select 'b', 60, 15, 1, 'US' from dual
select country,
sum(case when type='a' then revenue_mny else 0 end ) revenue_mny_a,
sum(case when type='a' then quantity else 0 end) quantity_a,
sum(case when type='a' then cnt else 0 end) cnt_a,
sum(case when type='b' then revenue_mny else 0 end ) revenue_mny_b,
sum(case when type='b' then quantity else 0 end) quantity_b ,
sum(case when type='b' then cnt else 0 end) cnt_b
from t
group by country;result:
COUNTRY REVENUE_MNY_A QUANTITY_A CNT_A REVENUE_MNY_B QUANTITY_B CNT_B
India    22            30         5     15            30         1
US       20            35         2     25            80         2Or you can do it with a decode instead of case. The result will be the same:
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sum(decode(type,'b',quantity,0)) quantity_b,
sum(decode(type,'b',cnt,0)) cnt_b
from t
group by country;(I changed tablename from TEST to T and columnname from COUNT to CNT, because you should not use reserved words as tablename or columnname.)
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select to_char(CREATEDON,'DD-MM-YYYY HH24:MM:SS'),LABSTATUS,REMARKS from history_paperlesstran
where hnum='797551D' order by to_char(CREATEDON,'DD-MM-YYYY HH24:MM:SS');
Rownum TO_CHAR(CREATEDON,' LABSTATUS REMARKS
1 20-10-2010 08:10:08 1 Barcode number generated and printed
2 20-10-2010 08:10:08 1 Barcode number generated and printed
3 20-10-2010 08:10:08 1 Barcode number generated and printed
4 20-10-2010 08:10:08 1 Barcode number generated and printed
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10 20-10-2010 09:10:58 3 Recieved in department
11 20-10-2010 09:10:58 3 Recieved in department
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14 20-10-2010 11:10:34 1 Barcode number generated and printed
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16 20-10-2010 12:10:08 3 Recieved in department
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Dear Friends, Now i want to get the date difference on labstatus based,i.e rownum1 - rownum7, rownum2 - rownum8, and rownum17 - rownum18
Thing is Barcode number generated and printed - Recieved in department for each & every samples.
Advance thanks for your solution...
Edited by: bharathit on Oct 21, 2010 2:18 AM

You mean something like this?
SQL> ed
Wrote file afiedt.buf
1 with t as (select 1 as rn, to_date('20-10-2010 08:10:08', 'DD-MM-YYYY HH24:MI:SS') as dt, 1 as labstatus, 'Barcode number generated and printed' as comments from dual union all
2             select 2, to_date('20-10-2010 08:10:08','DD-MM-YYYY HH24:MI:SS'), 1, 'Barcode number generated and printed' from dual union all
3             select 3, to_date('20-10-2010 08:10:08','DD-MM-YYYY HH24:MI:SS'), 1, 'Barcode number generated and printed' from dual union all
4             select 4, to_date('20-10-2010 08:10:08','DD-MM-YYYY HH24:MI:SS'), 1, 'Barcode number generated and printed' from dual union all
5             select 5, to_date('20-10-2010 08:10:08','DD-MM-YYYY HH24:MI:SS'), 1, 'Barcode number generated and printed' from dual union all
6             select 6, to_date('20-10-2010 08:10:08','DD-MM-YYYY HH24:MI:SS'), 1, 'Barcode number generated and printed' from dual union all
7             select 7, to_date('20-10-2010 09:10:55','DD-MM-YYYY HH24:MI:SS'), 3, 'Recieved in department' from dual union all
8             select 8, to_date('20-10-2010 09:10:58','DD-MM-YYYY HH24:MI:SS'), 3, 'Recieved in department' from dual union all
9             select 9, to_date('20-10-2010 09:10:58','DD-MM-YYYY HH24:MI:SS'), 3, 'Recieved in department' from dual union all
10             select 10, to_date('20-10-2010 09:10:58','DD-MM-YYYY HH24:MI:SS'), 3, 'Recieved in department' from dual union all
11             select 11, to_date('20-10-2010 09:10:58','DD-MM-YYYY HH24:MI:SS'), 3, 'Recieved in department' from dual union all
12             select 12, to_date('20-10-2010 10:10:38','DD-MM-YYYY HH24:MI:SS'), 3, 'Recieved in department' from dual union all
13             select 13, to_date('20-10-2010 11:10:34','DD-MM-YYYY HH24:MI:SS'), 1, 'Barcode number generated and printed' from dual union all
14             select 14, to_date('20-10-2010 11:10:34','DD-MM-YYYY HH24:MI:SS'), 1, 'Barcode number generated and printed' from dual union all
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16             select 16, to_date('20-10-2010 12:10:08','DD-MM-YYYY HH24:MI:SS'), 3, 'Recieved in department' from dual union all
17             select 17, to_date('20-10-2010 14:10:03','DD-MM-YYYY HH24:MI:SS'), 1, 'Barcode number generated and printed' from dual union all
18             select 18, to_date('20-10-2010 14:10:44','DD-MM-YYYY HH24:MI:SS'), 3, 'Recieved in department' from dual)
19 --
20 -- END OF TEST DATA
21 --
22     ,x as (select rn, dt, labstatus, comments, row_number() over (partition by labstatus order by rn) as labrn from t)
23 --
24 select y.rn as rn1, y.dt as dt1, z.rn as rn2, z.dt as dt2, round((z.dt - y.dt)*24*60) as mins_diff
25 from x y join x z on (y.labrn = z.labrn)
26 where y.labstatus = 1
27* and   z.labstatus = 3
SQL> /
       RN1 DT1                        RN2 DT2                  MINS_DIFF
         1 20/10/2010 08:10:08          7 20/10/2010 09:10:55         61
         2 20/10/2010 08:10:08          8 20/10/2010 09:10:58         61
         3 20/10/2010 08:10:08          9 20/10/2010 09:10:58         61
         4 20/10/2010 08:10:08         10 20/10/2010 09:10:58         61
         5 20/10/2010 08:10:08         11 20/10/2010 09:10:58         61
         6 20/10/2010 08:10:08         12 20/10/2010 10:10:38        121
        13 20/10/2010 11:10:34         15 20/10/2010 11:10:35          0
        14 20/10/2010 11:10:34         16 20/10/2010 12:10:08         60
        17 20/10/2010 14:10:03         18 20/10/2010 14:10:44          1
9 rows selected.
SQL>

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Hello PL/SQL Gurus/experts,
I am using Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - 64bit Production version
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DROP TABLE T2;
create table T2(Manager,Employee) as select
'Nikki','Ram' from dual union all select
'Nina', 'Rita' from DUAL union all select
'Mike', 'Radha' from dual union all select
'Michael', 'Ratnam' from DUAL union all select
'Hendi', 'Ratna' from dual union all select
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'Maria', 'Rolly' from dual union all select
'Kistrien', 'Rachna' from dual union all select
'Andrew', 'Ritvik' from dual union all select
'Emma', 'Ramesh' from dual union all select
'Andy', 'Ranpal' from dual union all select
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Mike           Radha
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Michael      Ratnam
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Hendi           Ratna
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Robert          Raman
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Maria          Rolly
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Kistrien     Rachna
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Andrew          Ritvik
          Satvik
Emma          Ramesh
          Somesh
          Piyush
Andy          Ranpal
          Sonpal
          Pavan
Brandy          Raunak
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In SQL, something like this...
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Wrote file afiedt.buf
1 select case when row_number() over (partition by emp.manager order by employee) = 1 then
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Brandy   Paramjeet
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Emma     Piyush
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Wrote file afiedt.buf
1 select case when row_number() over (partition by emp.manager order by employee nulls first) = 1 then
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SQL> /
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Andrew
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         Satvik
Andy
         Pavan
         Ranpal
         Sonpal
Brandy
         Paramjeet
         Raunak
         Samar
Emma
         Piyush
         Ramesh
         Somesh
Hendi
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         Satna
Kistrien
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Maria
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Michael
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         Satnam
Mike
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Nikki
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Nina
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         Sita
Robert
         Raman
         Samar
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Microsoft SQL Server 2008
Microsoft SQL Server 2008 R2
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Please click to vote if the post helps you. This can be beneficial to other community members reading the thread.

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a1 TYPE string,
a2 TYPE string,
a3 TYPE string,
p1 TYPE string,
p2 TYPE string,
p3 TYPE string,
END OF ty_str.
DATA: lt_str TYPE TABLE OF ty_str,
      ls_str TYPE ty_str,
      lv_block TYPE string,
      lv_flag TYPE boolean.
LOOP AT lt_data INTO lv_data.
CASE lv_data.
    WHEN '[Version]' OR '[StdSatz]' OR '[Arbeitstag]' OR '[Pecunia]'
         OR '[Mita]' OR '[Kunde]' OR '[Auftrag]' OR '[Position]'.
      lv_block = lv_data.
      lv_flag = abap_false.
    WHEN OTHERS.
      lv_flag = abap_true.
ENDCASE.
CHECK lv_flag EQ abap_true.
CASE lv_block.
    WHEN '[Auftrag]'.
      SPLIT lv_data AT ';' INTO ls_str-a1 ls_str-a2 ls_str-a3.
    WHEN '[Position]'.
      SPLIT lv_data AT ';' INTO ls_str-p1 ls_str-p2 ls_str-p3.
      APPEND ls_str TO lt_str.
ENDCASE.
ENDLOOP.

Query to get the data of all the columns in a table except any one column

Can anyone please tell how to write a query to get the data of all the columns in a table except one particular column..
For Example:
Let us consider the EMP table.,
From this table except the column comm all the remaining columns of the table should be listed
For this we can write a query like this..
Select empno, ename, job, mgr, sal, hiredate, deptno from emp;
Just to avoid only one column, I mentioned all the remaining ( 7 ) columns of the table in the query..
As the EMP table consists only 8 columns, it doesn't seem much difficult to mention all the columns in the query,
but if a table have 100 columns in the table, then do we have to mention all the columns in the query..?
Is there any other way of writing the query to get the required result..?
Thanks..

Your best best it to just list all the columns. Any other method will just cause more headaches and complicated code.
If you really need to list all the columns for a table because you don't want to type them, just use something like...
SQL> ed
Wrote file afiedt.buf
1 select trim(',' from sys_connect_by_path(column_name,',')) as columns
2 from (select column_name, row_number() over (order by column_id) as column_id
3        from user_tab_cols
4        where column_name not in ('COMM')
5        and   table_name = 'EMP'
6       )
7 where connect_by_isleaf = 1
8 connect by column_id = prior column_id + 1
9* start with column_id = 1
SQL> /
COLUMNS
EMPNO,ENAME,JOB,MGR,HIREDATE,SAL,DEPTNO
SQL>

When I save a PDF as an Excel File, all of the data in the PDF is put into one column (AdobeXI)

Hi, thanks for taking the time...
I'm running a machine with Windows 7, Office 2010, and Acrobat XI. When I save a specific PDF as an Excel workbook, all of the data in the original PDF is sorted correctly in four columns. When the same task is performed on this file on another user's machine, all of the data is sorted into one column. The user has the same versions of Windows, Office, and Acrobat. I've attempted the "Repair installation" option but the problem persists. Any suggestions? Thanks again for helping,
-E

Thanks for the quick reply. I figured out how to get the desired results by using tagging. For anyone who may reference this post in the future, I went to "Customize" in the top right corner of Adobe, then selected "Create new tool set...", looked under "accessiblity and found the "tag" option. Hit ok, tag is added to the toolbar. Then I highlighted the dataset in the PDF that was relevant to the output format, then clicked "tag", saved as spreadsheet. Sorry I can't provide more details on how tagging works or if there's a more elegant solution available, but I'm sure one's out there.

Date difference in one column

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