Dates Between Query :( with out TO_DATE.
Greetings,
I have a query whete in the where clause I compare a column b/w two dates. The Query looks like this,
trunc(LAST_UPDATE_DATE) BETWEEN '22-FEB-03' AND '21-MAR-03'.
This query doesn't fetch any records. Whereas when I use the query with a TO_DATE function it works fine. The query looks like,
TRUNC(LAST_UPDATE_DATE) BETWEEN TO_DATE('22-FEB-03','DD-MON-YY') AND TO_DATE('21-MAR-03','DD-MON-YY')
Ideally I can't impose this becasue the query is a generarted query by one of the reporting tools.
Kindly Help. I really appreciated your help in this regard.
Thanks,
Badhri ...
Your NLS_DATE_FORMAT is set to something other than 'DD-MON-YY'. This can be changed at a session level by executing a query
ALTER SESSION SET NLS_DATE_FORMAT = 'DD-MON-YY'
You could also change this at an instance level, but that would likely have side-effects on other queries. One of the reasons that not having to_date can be a royal pain.
Justin
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user9368047 wrote:
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Well, maybe just my app...
At any rate, what I have is a query that pulls RISKS for a project and does a reasonable outer join which joins the latest value from a RISK_HISTORY table. Values for RISK are updated and the value for RISK_HISTORY is changed and a new entry added to the RISK_HISTORY table.
At least that's how it's supposed to be.
I was able to do this with a report-with-a-form region by adding an extra update process to do a new insert into RISK_HISTORY but it seems that the tabular form is a bit more work.
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select * from(
select
r.RISK_SEQ RISK_SEQ_DISPLAY,
r.RISK_PRIORITY,
r.RISK_INFO,
r.RISK_MITIGATION,
r.ONGOING_FLAG,
r.RISK_DATE,
r.WEEK_GROUP_SEQ,
r.CREATED_ON,
r.CREATED_BY,
r.LAST_MODIFIED_ON,
r.LAST_MODIFIED_BY,
rh.STATUS,
row_number() over (partition by rh.risk_seq order by rh.last_modified_on desc) rn
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where w.PROJECT_SEQ=43
and r.week_group_seq= w.week_group_seq
and w.week_index=0
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Oracle query with out using self join
hi friends,
i have one table for exeample PERSTATUS
pk/fK STUDENT NUMBER SUBJECT MARKS STATUS
1 ACCOUNTS 15 RED
1 MATHS 35 YELLOW
1 SCINECE 45 GREEN
2 ACCOUNTS 55 BROWN
2 MATHS 35 YELLOW
2 SCINECE 45 GREEN
3 ACCOUNTS 15 RED
3 MATHS 35 YELLOW
3 SCINECE 45 GREEN
i want students how status is both red and yellow so i am using self join
i want students status is both red and yellow so i am using self join
SELECT PS.STUDENTNUMBER,PS.STATUS,PS.STATUS1 FROM PERSTATUS PS ,PERSTATUS PS1
WHERE PS.STUDENTNUMBER-PS1.STUDENTNUMER
PS.STATUS='RED' AND PS1.STAUTS='YELLOW'
i want students status is both RD and YELLOW AND GREEN so i am using self join( two self joinS}
SELECT PS.STUDENTNUMBER,PS.STATUS,PS.STATUS,PS2.STATUS FROM PERSTATUS PS ,PERSTATUS PS1,PERSTATUS PS2
WHERE PS.STUDENTNUMBER-PS1.STUDENTNUMER AND PS.STUDENTNUMBER-PS2.STUDENTNUMBER
PS.STATUS='RED' AND PS1.STAUTS='YELLOW' AND PS2.STAUTUS='GREEN'
if i require MORE STATUS then more self joins required, is there any alternative to achive this
and if results comes in multiple rows are accepted (since with the above query result will come in single row)
i tried to use group by (studentnumber,status) with status='red' and status='yellow'
but it is not possible could you povidet he solutionHi,
Whenever you have a problem, please post CREATE TABLE and INSERT statements for your sample data, and the exact results you want from that data. Explain how you get those results from that data.
See the forum FAQ {message:id=9360002}
Here's an example of how to post the sample data:
CREATE TABLE perstatus
( studentnumber NUMBER
, subject VARCHAR2 (10)
, marks NUMBER
, status VARCHAR2 (10)
INSERT INTO perstatus (studentnumber, subject, marks, status)
VALUES (1, 'ACCOUNTS', 15, 'RED');
INSERT INTO perstatus (studentnumber, subject , marks, status)
VALUES (1, 'MATHS', 35, 'YELLOW');
INSERT INTO perstatus (studentnumber, subject, marks, status)
VALUES (1, 'SCINECE', 45, 'GREEN');
INSERT INTO perstatus (studentnumber, subject, marks, status)
VALUES (2, 'ACCOUNTS', 55, 'BROWN');
INSERT INTO perstatus (studentnumber, subject , marks, status)
VALUES (2, 'MATHS', 35, 'YELLOW');
INSERT INTO perstatus (studentnumber, subject, marks, status)
VALUES (2, 'SCINECE', 45, 'GREEN');
INSERT INTO perstatus (studentnumber, subject, marks, status)
VALUES (3, 'ACCOUNTS', 15, 'RED');
INSERT INTO perstatus (studentnumber, subject , marks, status)
VALUES (3, 'MATHS', 35, 'YELLOW');
INSERT INTO perstatus (studentnumber, subject, marks, status)
VALUES (3, 'SCINECE', 45, 'GREEN');You were on the right track, thinking about GROUP BY. You're interested in something about the whole group of rows that has the same studentnumber. Looking at any individual row won't tell you if that row is part of the group you're interested in or not.
If you want to see information about the group as a whole, you can do the whole job with GROUP BY. In this case, studnetnumber is the only thing that an entire group has in common. If you wanted to see the studentnumbers that had both RED and YELLOW, that is:
STUDENTNUMBER
1
3here's one way you could do it:
SELECT studentnumber
FROM perstatus
WHERE status IN ('RED', 'YELLOW')
GROUP BY studentnumber
HAVING COUNT (DISTINCT status) = 2 -- That is, both RED and YELLOW
ORDER BY studentnumber
;But say you wanted to see details about individuals in the group; for example, say we want to see all the columns for students that have all 3 of RED, YELLOW and GREEN, like this:
STUDENTNUMBER SUBJECT MARKS STATUS
1 SCINECE 45 GREEN
1 ACCOUNTS 15 RED
1 MATHS 35 YELLOW
3 SCINECE 45 GREEN
3 ACCOUNTS 15 RED
3 MATHS 35 YELLOWWe used the aggregate COUNT function earlier, but aggregate functions require collapsing the results down to one row per group.
However, most of the aggregate functions, like COUNT, have analytic counterparts, that can give the same results without collapsing the result set. Here's one way to get the results above, using the analytic COUNT function:
WITH got_cnt AS
SELECT studentnumber, subject, marks, status
, COUNT ( DISTINCT CASE
WHEN status IN ('RED', 'YELLOW', 'GREEN')
THEN status
END
) OVER (PARTITION BY studentnumber) AS cnt
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FROM got_cnt
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ORDER BY studentnumber
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Hierarchical query with out using Connect by prior
Hi Guys,
I am supporting a product which is enterprise based and only allowd to write queries which are ANSII standard.
I have an requirement like If I provide the child I need to know all the parents till highest level.
My table structure is like below
Table_name : Org_unit
Columns are
Org_unit_id name desc parent_org_unit_id
I wil pass the org_unit id and want to list all the parents of the chile org_unit_id and it has to be accomplished without using connec by prior.
Please suggest me some ideas and aprroches
I am using Orcle 11g versionHi,
960593 wrote:
Hi Guys,
I am supporting a product which is enterprise based and only allowd to write queries which are ANSII standard.
I have an requirement like If I provide the child I need to know all the parents till highest level.
My table structure is like below
Table_name : Org_unit
Columns are
Org_unit_id name desc parent_org_unit_id
I wil pass the org_unit id and want to list all the parents of the chile org_unit_id and it has to be accomplished without using connec by prior.
Please suggest me some ideas and aprroches
I am using Orcle 11g version
The data model you posted (org_unit_id as primary key, parent_org_unit_id as foreign key to the same table for the parent, when there is a parent) is called the Adjacency Model because it keeps track of which nodes are adjacent (or next to) each other.
I'm familiar with 2 other ways to model hierarchies: the Nested Sets Model, and what I call the Lineage Model. I'll show how to find a given node's ancestors (in hierarchical order) in each model. Neither the Nested Sets nor the Lineage Model requires CONNECT BY or recursive WITH clauses to work.
The following table contains all the columns necessary for using each of these 3 models:
EMPNO MGR ENAME LINEAGE NS_LOW NS_HIGH
7839 KING /7839/ 1 28
7698 7839 BLAKE /7839/7698/ 2 13
7499 7698 ALLEN /7839/7698/7499/ 3 4
7900 7698 JAMES /7839/7698/7900/ 5 6
7654 7698 MARTIN /7839/7698/7654/ 7 8
7844 7698 TURNER /7839/7698/7844/ 9 10
7521 7698 WARD /7839/7698/7521/ 11 12
7782 7839 CLARK /7839/7782/ 14 17
7934 7782 MILLER /7839/7782/7934/ 15 16
7566 7839 JONES /7839/7566/ 18 27
7902 7566 FORD /7839/7566/7902/ 19 22
7369 7902 SMITH /7839/7566/7902/7369/ 20 21
7788 7566 SCOTT /7839/7566/7788/ 23 26
7876 7788 ADAMS /7839/7566/7788/7876/ 24 25
The Lineage Model keeps track of all of a given nodes ancestors, so if all you need to find are the primary keys of a given node, it's really trivial: it's all in the lineage column. If you want to find more information about those ancestors, then you can do a self-join, like this:
SELECT a.empno, a.ename, a.lineage
FROM emp a
JOIN emp d ON d.lineage LIKE '%/' || a.empno || '/%'
WHERE d.ename IN ('ADAMS')
ORDER BY d.ename
, a.lineage
Output:
EMPNO ENAME LINEAGE
7839 KING /7839/
7566 JONES /7839/7566/
7788 SCOTT /7839/7566/7788/
7876 ADAMS /7839/7566/7788/7876/
The Nested Sets model is harder to understand.
Imagine everyone in the hierarchy standing on a wide staircase, as if for a group picture; everyone on the same level standing on the same step. Everyone is holding up an umbrella that is wide enough to cover himself and all the people who are under him in the hierarchy. The people with no underlings have small umbrellas, denoted like this "<-SMITH->", and peole that manage others have bigger umbrellas, like this: <-------- JONES -------->. So the group picture might look like this:
<-------------------------------------------- KING --------------------------------------------->
<---------------------- BLAKE ---------------------> <-- CLARK --> <-------- JONES -------->
<-ALLEN-> <-JAMES-> <-MARTIN-> <-TURNER-> <-WARD-> <-MILLER-> <-- FORD--> <--SCOTT-->
<-SMITH-> <-ADAMS->
Each parent's umbrella covers all of his descendants (children, grandchildren, etc.), and nobody else.
Now draw vertical lines trom the edges of each umbrella downwards, and number those lines from left to right:
<-------------------------------------------- KING ------------------------------------------------>
| |
| <---------------------- BLAKE ---------------------> <-- CLARK -> <-------- JONES ----------> |
| | | | | | | |
| |<-ALLEN-> <-JAMES-> <-MARTIN-> <-TURNER-> <-WARD->| |<-MILLER->| |<-- FORD--> <--SCOTT---> | |
| || | | | | | | | | || || || || | | | | |
| || | | | | | | | | || || || ||<-SMITH->| |<-ADAMS-> | | |
| || | | | | | | | | || || || ||| || || | | | |
1 1 11 11 11 112 22 22 2 2 2 2
1 23 4 5 6 7 8 9 0 1 23 45 67 890 12 34 5 6 7 8
The numbers corresponding to the left arnd right edges of each umbrella are what I called ns_low and ns_high in the table. Each employyes ns_low and ns_high numbers will be inside the range of each of his ancestors ns_low and ns_high.
To find the ancestors of a given node in the nested set model you can do this:
SELECT a.empno, a.ename, a.ns_low, a.ns_high
FROM emp a
JOIN emp d ON d.ns_low BETWEEN a.ns_low
AND a.ns_high
WHERE d.ename IN ('ADAMS')
ORDER BY d.ename
, a.ns_low
Both the Lineage and Nested Sets models are good for tree structures only, whereas the Adjacency Model can handle other kinds of graphs, including graphs with loops.
Both the Lineage and Nested Sets models can be very difficult to maintain if the hierarchy is re-organized.
I'd like to repeat some of the warnings that others have made. You could write separate code for each system (Oracle, SQL Server, ...) that you want to run in, and the code for each system will be more or less different. You're looking for some code that will get the same results in all systems. That code will be more complicated that the most complicated of the single-system versions, and it will be sloweer than the slwoest of the single-system versions. You're giving up a lot of functionality, and probably also ease of maintenance, by writing code that has to work on multiple systems without changes.
Here's how I created the emp table shown above from scott.emp:
CREATE TABLE emp
AS
WITH connect_by_results AS
SELECT empno, mgr, ename
, LEVEL AS lvl
, ROWNUM AS r_num
, SYS_CONNECT_BY_PATH (empno, '/') || '/' AS lineage
FROM scott.emp
START WITH mgr IS NULL
CONNECT BY mgr = PRIOR empno
ORDER SIBLINGS BY ename
SELECT empno, mgr, ename, lineage
, (2 * r_num) - lvl AS ns_low
, (2 * r_num) + ( 2 * (
SELECT COUNT (*)
FROM connect_by_results
WHERE lineage LIKE '%/' || cbr.empno || '/%'
- (lvl + 1) AS ns_high
FROM connect_by_results cbr
This relies on the fact that the hierarchy in scott.emp has only one root (that is, a node with no parent). Computing the Nested Sets numbers is a little more complicated if you can have multiple roots. -
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I currently have 4 Cell Phones on my Personal Verizon Account and have been with Verizon for longer than I can remember. None of my lines are under any type of Time restrictive agreement (i.e. One or Two Year). The company I work for uses Verizon as well and said they will pay for on of my lines, if I transfer it to their Business Account. I was told by a Verizon Representative that because all of my contracts/agreements are more than 13 months old that when the day comes to transfer my phone number back to my Personal Verizon Account I "Will Not" be forced into a new 1 or 2 year agreement. (i.e. Existing Personal VZ Number, with no pending agreements, transferred to a Business Account and when transferred back I will not be forced into a New early termination agreement...) Is this correct?
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Usually a company will issue a line of service and device if they require you to have one for work use.
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When I was in charge of adding users to our account we opened the line and number and had total control of the billing and use of the line.
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Dear Guru,
I have a single web template, that contains 2 query data providers (e.g. Query A, Query B), and all users access to this web template for both queries.
Now, there are some users that have authority to Query A only.
When they access to this web template, the system automatically say the users do not have authority for Query B in the variable entry screen, and show the variable selection for query A only.
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Hi,
I am trying to transfer data from Oracle 10g (character set :UTF08) to Oracle 8i ( character set: US7ASCII). I have tried the transfer using the DBLinks and found that there is no way the data could be transferred from 10g to Oracle 8i.
The last option available is to use staging database for transfer. The staging database would be Oracle 10g only but the character set would be US7ASCII. I am expecting that since the character set is US7ASCII, this would be able to get compatible with Oracle 8i (US7ASCII). Secondly, Transfer from 10g to staging 10g should also work, since staging 10g would support UTF08 character set.
Kindly tell me if this option would work or if there is any other way around.
Thanks
Nitin
Message was edited by:
Nits
Message was edited by:
Nits
Message was edited by:
NitsYou possibly have a fundamental problem,which is more important than any technical issues. If your UTF8 (Unicode) database stores non-english characters you will lose these characters when transferring.
Werner
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