Query with Outer Join - Infocube X Infoobject

Hi,
I Have an infoobject(0account) and an infocube(Ic_accounts) in a Multicube.
I Have a Query and i need to show in this Query the accounts from infoobject(0account) that are not in infocube(ic_accounts).
How can I do this ?
Thanks

Identify a KF for which there are non-zero values for all accounts in the cube.
Create the query with Account (from MP coming from both IO and cube) and this KF. KF will have 0 values for accounts not existing in the cube. Create a condition to show only the 0 value for the KF. This should show you all the accounts in the IO which are not in the cube.

Similar Messages

  • Tabular form from query with outer join destroys the universe!

    Well, maybe just my app...
    At any rate, what I have is a query that pulls RISKS for a project and does a reasonable outer join which joins the latest value from a RISK_HISTORY table. Values for RISK are updated and the value for RISK_HISTORY is changed and a new entry added to the RISK_HISTORY table.
    At least that's how it's supposed to be.
    I was able to do this with a report-with-a-form region by adding an extra update process to do a new insert into RISK_HISTORY but it seems that the tabular form is a bit more work.
    Here's the query I'm using:
    select * from(
    select
    r.RISK_SEQ RISK_SEQ_DISPLAY,
    r.RISK_PRIORITY,
    r.RISK_INFO,
    r.RISK_MITIGATION,
    r.ONGOING_FLAG,
    r.RISK_DATE,
    r.WEEK_GROUP_SEQ,
    r.CREATED_ON,
    r.CREATED_BY,
    r.LAST_MODIFIED_ON,
    r.LAST_MODIFIED_BY,
    rh.STATUS,
    row_number() over (partition by rh.risk_seq order by rh.last_modified_on desc) rn
    from RISK r, WEEK_GROUP w, RISK_HISTORY rh
    where w.PROJECT_SEQ=43
    and r.week_group_seq= w.week_group_seq
    and w.week_index=0
    and rh.RISK_SEQ = r.RISK_SEQ
    ) where rn = 1
    Clicking "Add Row" gets me this:
    Error in mru internal routine: ORA-20001: no data found in tabular form
    Running debug doesn't seem to expose much for me either. Is there a better tact for me to take here?
    Thanks,
    Jon

    Hi Prazy,
    using nvl also didn't solve my problem.Actually my problem is I am having a table a in which I have a column called satus, status has the values like A or I .I have one lookup called MTH_BUYSINESS_FUNCTION in which for lookup_code A I have menaing as Active and for lookup_code I meaning is Inactive.Now in table a for sttaus I have two values one A and one null Now I want to write sql which displayes the meaning for column staus.Result should be Active and null .If I am uisng 1 query which I gave u I am not able to get the 2nd row in my output.If I use 2nd query then I get duplicate rows.
    Thanks ,
    Amrit

  • Rewrite the query with out joins and group by

    Hi,
    This was an interview question.
    Table Names: bookshelf_checkout
    bookshelf
    And the join condition between these two tables is title
    We need to rewrite below query without using join condition and group by clause ?
    SELECT b.title,max(bc.returned_date - bc.checkout_date) "Most Days Out"
               FROM bookshelf_checkout bc,bookshelf b
               WHERE bc.title(+)=b.title
               GROUP BY b.title;When I was in college, I read that most of the SELECT statements can be replaced by basic SQL operations (SET OPERATORS). Now I am trying to rewrite the query with SET operators but not able to get the exact result.
    Kindly help me on this.
    Thanks,
    Suri

    Something like this?
      1  WITH books AS (
      2  SELECT 'title 1' title FROM dual UNION ALL
      3  SELECT 'title 2' FROM dual UNION ALL
      4  SELECT 'title 3' FROM dual ),
      5  bookshelf AS (
      6  SELECT 'title 1' title, DATE '2012-05-01' checkout_date, DATE '2012-05-15' returned_date FROM dual UNION ALL
      7  SELECT 'title 1' title, DATE '2012-05-16' checkout_date, DATE '2012-05-20' returned_date FROM dual UNION ALL
      8  SELECT 'title 2' title, DATE '2012-04-01' checkout_date, DATE '2012-05-15' returned_date FROM dual )
      9  SELECT bs.title, MAX(bs.returned_date - bs.checkout_date) OVER (PARTITION BY title) FROM bookshelf bs
    10  UNION
    11  (SELECT b.title, NULL FROM books b
    12  MINUS
    13* SELECT bs.title, NULL FROM bookshelf bs)
    SQL> /
    TITLE   MAX(BS.RETURNED_DATE-BS.CHECKOUT_DATE)OVER(PARTITIONBYTITLE)
    title 1                                                           14
    title 2                                                           44
    title 3Lukasz

  • Query with outer join not dispalying the correct results

    Hi All,
    I am having a table which has a column called status it can either be null or has the code which comes from the lookup b.When I use this query
    select b.menaing from a
    where a.status=b'lookup_code(+)
    AND b.lookup_type='MTH_BUSINESS_FUNCTION'
    AND b.LANGUAGE = USERENV('LANG')
    then I don't get the rows from table a, where status is null
    and if I use the condition:
    select b.menaing from a
    where ((a.status IS NULL) OR
    (a.status=b.lookup_code
    AND b.lookup_type='MTH_BUSINESS_FUNCTION'
    AND b.LANGUAGE = USERENV('LANG') ))
    then I get many extra rows.Can soemone please tell me hwo to achieve this(My query should display the menaing if status column is blank then it should dispaly blank otherwise after joining iwth the lookup table it should display meaning)

    Hi Prazy,
    using nvl also didn't solve my problem.Actually my problem is I am having a table a in which I have a column called satus, status has the values like A or I .I have one lookup called MTH_BUYSINESS_FUNCTION in which for lookup_code A I have menaing as Active and for lookup_code I meaning is Inactive.Now in table a for sttaus I have two values one A and one null Now I want to write sql which displayes the meaning for column staus.Result should be Active and null .If I am uisng 1 query which I gave u I am not able to get the 2nd row in my output.If I use 2nd query then I get duplicate rows.
    Thanks ,
    Amrit

  • Use of db link in subquery with outer join

    I have a query where i am using db link to get data from another database.
    I have an outer join where i am using a subquery using the same db link but it fails gives me the error:
    ORA-00991: illegal use of LONG datatype.
    But the same query with inner join is not giving me the error.
    Is this a limitation of Oracle or am I doing something wrong.

    This is an example of what i am running. That last outer join does not work c.acad_plan(+).
    select count(1)
    from ( select a.* from cb001_tbl a where a.strm='1800' ) a ,
    ( select distinct emplid,national_id,strm, acad_plan, acad_career from ps_uhcb_001@SAPRD where institution='00730') b ,
    ( select * from ps_acad_plan_tbl@SAPRD a
    where a.institution='00730'
    and a.eff_status='A'
    and a.effdt=(select max(b.effdt) from ps_acad_plan_tbl@SAPRD b
    where a.institution=b.institution
    and a.acad_plan=b.acad_plan
    and b.effdt<=to_date(20100514,'yyyymmdd'))) c
    where a.stdnt_id=b.national_id (+)
    and a.strm=b.strm (+)
    and b.acad_plan=c.acad_plan (+)

  • Help requried with outer joins

    Hi All,
    I neeed a query help can any one please help me getting this done,
    for the below query
    select trunc(assumed_time_sql) AS date1,sum(rp.rebate_due)as sum1 from mn_date_dim dd ,mn_rebate_payment rp,mn_prc_program prc,mn_structured_doc sd
    where trunc(assumed_time_sql) in (TO_DATE('01-JUL-10','dd-mon-yy'),add_months(TO_DATE('01-JUL-10','dd-mon-yy'),-3),add_months(TO_DATE('01-JUL-10','dd-mon-yy'),-6),add_months(TO_DATE('01-JUL-10','dd-mon-yy'),-9))----input parameter
    AND trunc(dd.assumed_time_sql)=TRUNC(rp.start_date)
    AND prc.prc_program_id=rp.tiered_rebate_id
    AND sd.struct_doc_id=prc.struct_doc_id
    AND sd.struct_doc_id_num='M0000763'----input parameter
    group by trunc(assumed_time_sql);
    I am getting output as
    date1      sum1
    01-JAN-10      10
    01-APR-10     15
    01-JUL-10     20
    But i want my output to be as
    date1      sum1
    01-JAN-10      10
    01-APR-10     15
    01-JUL-10     20
    01-OCT-09 NULL
    I have tried with outer joins but this didn't help me
    Can any one please give me help in getting this done
    Thanks

    Hi,
    As SB pointed out, you'd better provide tables and data in order to be helped more efficiently.
    Anyway, you may want to investigate the use of NVL and/or DECODE so that you can translate NULL into valid values so they are returned to your select statement.
    HTH,
    Thierry
    Handle:  p78   
    Status Level:  Newbie (10) 
    Registered:  Mar 9, 2009 
    Total Posts:  60 
    Total Questions:  35 (30 unresolved)  Be kind to share your helpful / correct threads with other with marking them as ANSWERED
    Edited by: Urgent-IT on Feb 13, 2011 11:00 AM

  • Please suggest a select query / sub query with out using any subprograms or

    source table: Three columns ORIGIN, DESTINATION,MILES
    Origin      Destination Miles
    Sydney      Melbourne      1000
    Perth      Adelaide      3000
    Canberra      Melbounre      700
    Melbourne      Sydney           1000
    Brisbane      Sydney           1000
    Perth      Darwin           4000
    Sydney      Brisbane      1000
    out put :Three columns ORIGIN, DESTINATION,MILES
    Duplicate routes are to be ignored so the output is
    Origin      Destination      Miles
    Sydney      Melbourne      1000
    Perth      Adelaide      3000
    Canberra      Melbounre      700
    Brisbane      Sydney           1000
    Perth      Darwin           4000
    Please suggest a select query / sub query with out using any subprograms or functions/pkgs to get the out put table.

    Hi,
    user9368047 wrote:
    ... Please suggest a select query / sub query with out using any subprograms or functions/pkgs to get the out put table.Why? If the most efficient way to get the results you want involves using a function, why wouldn't you use it?
    Here's one way, without any functions:
    SELECT     a.*
    FROM           source_table  a
    LEFT OUTER JOIN      source_table  b  ON   a.origin          = b.destination
                                          AND  a.destination       = b.origin
                          AND  a.miles          = b.miles
    WHERE   b.origin  > a.origin    -- Not b.origin > b.origin
    OR     b.origin  IS NULL
    ;If you'd care to post CREATE TABLE and INSERT statements for your sample data, then I could test this.
    Edited by: Frank Kulash on Nov 6, 2012 7:39 PM
    Corrected WHERE clause after MLVrown (below)

  • Generate a where clause with outer join criteria condition: (+)=

    Hi,
    In my search page, I use Auto Customization Criteria mode, and I build where clause by using get Criteria():
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    Vector parameters = new Vector(5);
    int clauseCount = 0;
    int bindCount = 1;
    for(int i=0; i < dicSize; i++){
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    Object value = dic[i].get(OAViewObject.CRITERIA_VALUE);
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    String criteriaCondition = (String)dic[i].get(OAViewObject.CRITERIA_CONDITION);
    String criteriaDataType = (String)dic[i].get(OAViewObject.CRITERIA_DATATYPE);
    String viewAttributename = (String)dic[i].get(OAViewObject.CRITERIA_VIEW_ATTRIBUTE_NAME);
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    If I want to generate following where clause:
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    ,emp.name
    ,emp.email
    ,emp.salesrep_number
    ,comp.name
    ,gs.srp_goal_header_id
    ,gs.status_code
    ,gs.start_date
    ,gs.end_date
    from g2c_goal_shr_emp_assignments_v emp
    ,jtf_rs_salesreps rs
    ,xxg2c_srp_goal_headers_all gs
    ,cn_comp_plans_all comp
    where 1 = 1
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    and gs.comp_plan_id = comp.comp_plan_id (+)
    and gs.period_year (+) = :1 -- :1 p_fiscal_year
    How can I generate a where clause with outer join : gs.period_year (+) = :1 ? Will I get '(+)=' from get(OAViewObject.CRITERIA_CONDITION)?
    thanks
    Lei

    If you are using SQL-Plus or Reports you can use lexical parameters like:
    SELECT * FROM emp &condition;
    When you run the query it will ask for value of condition and you can enter what every you want. Here is a really fun query:
    SELECT &columns FROM &tables &condition;
    But if you are using Forms. Then you have to change the condition by SET_BLOCK_PROPERTY.
    Best of luck!

  • How to use common object from two tables with out join.

    HI,
    I have two tables called A & B In A table i have the following objects
    1.weekend
    2.S1(measure)
    3.S2(measure)
    4.S3(measure)
    5.S4(measure)
    And In B table i have followning columns
    1.week end
    2.p1(measure)
    3.p2(measure)
    4.p3(measure)
    5.p4(measure)
    Now in universe i created all the measure objects i.e.s1,s2,s3,s4,p1,p2,p3,p4 A.weekend,B.weekend.
    instead of using week end two times i wnt to use only once because this is common in both table.
    if i use join between these tables i am getting values fine
    But With out join is there any thing to do in universe level to create common objects to use from both the tables..I tried using aggregate awareness but while reporting it is taking as two SQL.which is not synchronized.
    Please help me on this ...

    hi,
    Although  Weekend column is present in both tables, by creating a single Object in Universe, Universe can identify relationship with only table referenced in Object Creation.
    So, there will be no identification of relationship with other table measures.
    Obviously, you need to create 2 Weekend objects in Universe (in two classes).
    Case 1: You need not join these two tables in Universe. When you create 2 Queries in WEBI, automatcially Weekend objects are synchronized (if both are of same datatype)
    Case 2: If you join these two tables in Universe, Obviously,
    your SQL may contain Weekend from Table1, measures from Table 2
    or
    your SQL may contain Weekend from Table2, measures from Table 1
    Finally, You need to create 2 objects in Universe. But your query may contain a single Object based on Case 2.
    Regards,
    Vamsee

  • How to poll a blob using db adapter, with outer joins condition

    Hi All,
    We are trying to poll tables which contain column types as long and blob, we are using relationships in adapter and kept outer joins. by this we got select distinct t1.document .....etc
    distinct keyword cannot be used for blobs.
    is there any way to poll these tables having blob column types with outer joins.
    thanks a lot in advance,
    RR

    Hi,
    Procedure will be an explicit Invoke not Polling. If you can alter you design such that your BPEL process instead of polling gets triggered by some external entity (Java, PL/SQL, Scheduler, another BPEL etc.), you can put the data fetching logic in the procedure and call this procedure from your BPEL process to get the data. And your BPEL process is called periodically at an interval by an external entity.
    Also see if you can restrict the duplicate records at the database level itself. Polling, AFAIK, is limited in terms of customization and wouldn't be easy to customize. However, would like to learn a way if someone has.
    Regards,
    Neeraj Sehgal

  • Absolute dynamic select query with dynamic join and where

    Has anyone ever tried creating an absolutely dynamic SELECT query with dynamic Join and Where conditions.
    I have a requirement of creating such a query in an Utility Class, and i have written the code. But its throwing my sysntax errors.
    Please let me know where am I going wrong OR is it really possible to create such a dynamic Query??
        SELECT (FIELDS) INTO TABLE IT_TABLES
          FROM ( (ME->TABLE1)  inner join ( me->table2 )
          on ( on_condition ) )
          WHERE (me->where_fields).
    Ags.

    It worked for me in a following way:
    select * into corresponding fields of table <result_table>
            from (join_string)
            where (l_where).
    Where the contents of join_string were dynamically build using concatenation. So it will be something like
    concatenate ME->TABLE1 'as a INNER JOIN' me->table2 'as b ON (' into join_string separated by space.
    <...>
    add here matching/reference colums, something like
    concatenate 'a~' me->TABLE1_JOIN_COL into temp1.
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    concatenate join_string temp1 '=' temp2 into join_string separated by space.
    <...>
    concatenate join_string ')' into join_string separated by space.
    And then use similar approach for l_where variable.

  • Group by with outer join

    Group by sum doesn't work with outer join. Can anyone please help me to get it right?
    I've posted some sample data and queries below:
    CREATE TABLE COMPLAINT
      CNO     NUMBER,
      REASON  VARCHAR2(15 BYTE),
      TOTAL   NUMBER
    Insert into COMPLAINT
       (CNO, REASON, TOTAL)
    Values
       (1, 'edge', 250);
    Insert into COMPLAINT
       (CNO, REASON, TOTAL)
    Values
       (2, 'edge', 250);
    Insert into COMPLAINT
       (CNO, REASON, TOTAL)
    Values
       (3, 'brst', 300);
    Insert into COMPLAINT
       (CNO, REASON, TOTAL)
    Values
       (4, 'crea', 400);
    COMMIT;
    CREATE TABLE SCOTT.COMPLAINTROLL
      CNO   NUMBER,
      ROLL  VARCHAR2(15 BYTE)
    SET DEFINE OFF;
    Insert into COMPLAINTROLL
       (CNO, ROLL)
    Values
       (2, 'roll22');
    Insert into COMPLAINTROLL
       (CNO, ROLL)
    Values
       (1, 'roll4');
    Insert into COMPLAINTROLL
       (CNO, ROLL)
    Values
       (1, 'roll3');
    Insert into COMPLAINTROLL
       (CNO, ROLL)
    Values
       (1, 'roll2');
    Insert into COMPLAINTROLL
       (CNO, ROLL)
    Values
       (1, 'roll1');
    COMMIT;
    select * from complaint
    CNO     REASON     TOTAL
    1     edge     250
    2     edge     250
    3     brst     300
    4     crea     400
    select * from complaintroll
    CNO     ROLL
    1     roll1
    1     roll2
    1     roll3
    1     roll4
    2     roll22
    -- total of reason code edge is 500
    select reason,sum(total)
    from complaint c
    group by reason
    REASON     SUM(TOTAL)
    brst     300
    crea     400
    edge     500
    -- total of reason code edge after outer join is 1250
    select reason,sum(total)
    from complaint c,complaintroll cr
    where c.cno=cr.cno(+)
    group by reason
    REASON     SUM(TOTAL)
    brst     300
    crea     400
    edge     1250
    {\code}
    Thanks for reading this post.                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                   

    The problem that you described is simple. The outer join duplicates all the rows from the parent table (complaint). If you want to sum a column from the parent table, then this sum includes all the duplicated rows.
    There are several solutions for this problem.
    A) One had been shown already by Cenutil. Instead of doing an outer join, you can do a subquery in the select clause that delivers the additional information from the detail table.
    SQL> select reason,
       sum(total),
       sum((select count(*) from complaintroll cr where c.cno=cr.cno)) cnt_rolls
    from complaint c
    group by c.reason;
    REASON          SUM(TOTAL)  CNT_ROLLS
    crea                   400          0
    brst                   300          0
    edge                   500          5b) sum in two steps. First sum and count including the join criteria, then use this information to calculate the correct total sum.
    SQL> select reason, sum(stotal), sum(stotal/scount), sum(scount), sum(cnt_rolls)
      2  from (select reason, sum(total) stotal, count(*) scount, count(cr.cno) cnt_rolls
      3         from complaint c
      4         left join complaintroll cr on c.cno=cr.cno
      5         group by reason, c.cno
      6         )
      7   group by reason;
    REASON          SUM(STOTAL) SUM(STOTAL/SCOUNT) SUM(SCOUNT) SUM(CNT_ROLLS)
    crea                    400                400           1              0
    brst                    300                300           1              0
    edge                   1250                500           5              5
    sql> c) another option is to do the left join, but do the aggregation only one time for the parent table. Analytic functions are helpful for that. However since analytic fuinctions can't be used inside an aggregation function, we would again need an inline view.
    SQL> select reason, sum(case when rn = 1 then total end) sum_total, count(*), count(crcno)
      2  from (select row_number() over (partition by c.reason order by c.cno) rn,
      3                   c.*, cr.cno crcno
      4         from complaint c
      5         left join complaintroll cr on c.cno=cr.cno
      6         )
      7  group by reason;
    REASON           SUM_TOTAL   COUNT(*) COUNT(CRCNO)
    brst                   300          1            0
    crea                   400          1            0
    edge                   250          5            5
    SQL> Edited by: Sven W. on Feb 10, 2011 1:00 PM - formatting + column added to 2nd option

  • Update with Outer Join, round 2

    Thanks for those of you who helped me out on the first one (I never thought that you could use a one-row SELECT like that).
    However, here is a new version of my problem:
    I have three tables.
    Table_1 has a column that needs to be updated based on values in Table_2 and Table_3.
    Both Table_1 and Table_2 have values used to determine which Table_3 row to use.
    However, not every Table_1 row has a corresponding Table_3 row, in which case the Table_3 value to use is assumed to be 1.
    The tables and corresponding columns are:
    TABLE_1
    value_1 - the value to be updated
    key_2 - a pointer to TABLE_2
    key_3a - a pointer to TABLE_3, or a dummy value if there is no corresponding TABLE_3 record
    TABLE_2
    key_2 - the primary key
    key_3b - a secondary pointer to TABLE_3
    value_2 - a value to be used in calculating TABLE_1.value_1
    TABLE_3
    key_3a - the first part of the unique key
    ley_3b - the second part of the unique key
    value_3 - a value to be used in calculating TABLE_1.value_1
    If there is a row in table_3 that matches the table_1.key_3a and table_2.key_3b values (where table_2.key_2 = table_1.key_2):
    set table_1.value_1 = table_2.value_2 * table_3.value_3
    If there is no such row in table_3:
    set table_1.value_1 = table_2.value_2
    I want to do something like this:
    UPDATE table_1 t1
    SET value_1 =
    SELECT t2.value_2 * NVL(t3.value_3, 1)
    FROM table_2 t2
    LEFT JOIN table_3 t3
    ON (t3.key_3b = t2.key_3b and t3.key_3a = t1.key_3a)
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    I can do it with a clone of table_1 using ROWIDs:
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    FROM table_1 t1a
    JOIN table_2 t2
    ON t2.key_2 = t1a.key_2
    LEFT JOIN table_3 t3
    ON (t3.key_3b = t2.key_3b and t3.key_3a = t1a.key_3a)
    WHERE t1a.row_id = t1.row_id
    However, is there an easier way to do this using ANSI joins (i.e. without (+) syntax)?
    I have this feeling I am missing something reasonably obvious here.

    ddelgran wrote:
    Thanks for those of you who helped me out on the first one (I never thought that you could use a one-row SELECT like that).
    I want to do something like this:
    UPDATE table_1 t1
    SET value_1 =
    SELECT t2.value_2 * NVL(t3.value_3, 1)
    FROM table_2 t2
    LEFT JOIN table_3 t3
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    Oracle related stuff blog:
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    SQLTools++ for Oracle (Open source Oracle GUI for Windows):
    http://www.sqltools-plusplus.org:7676/
    http://sourceforge.net/projects/sqlt-pp/

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