Difference between 8 and 9?

Can someone tell me the biggest differences between imovie 8 and imovie 9? My computer has 8 on it, but I am teaching a class on imovie to teachers with 9. Thanks! Kelly
The class is tomorrow!

That's a rather difficult question to answer since different improvements will have different importance to different people. And whilst I don't wish to appear rude, I don't think it would be appropriate to try to teach without knowing the differences personally.
For me the biggest difference was precision editing.

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    Mrsthebraggster wrote:
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  • Difference between ';' and '/' in the SQL scripts

    Hi All,
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    SYSDATE
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    968217 wrote:
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  • Difference between ' and " in tags

    I see some people posting code with tag library tags using ' (single quote) around attributes sometimes. Is there a functional difference between the 2 styles like in Perl, or is it like Javascript where it doesn't matter, or is this just typing mistakes?

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  • [Solved] Shell: Is there a difference between / and // in directories?

    Hello:
    I'm making this tiny program in Shell:
    # Function.
    # NAME: chk_df
    # Synopsis:
    # Check if a local directory (dirName) exist and has a file (fileName).
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    # 99 : dirName does not exists
    # 0 : dirName exists and has fileName
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    # Parameters:
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    # Out values: returnCode <int>
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    chk_df(){
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    # In this case, two, dirName, fileNAme.
    if [[ ${#@} != 2 ]]; then
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    We get: /foo/lola.txt
    II) If we do: chk_df /foo/ lola.txt
    We get: /foo//lola.txt [Notice the //]
    In both cases the code seems to work. Why?
    Could I leave it like that or it will bring problems? Is there a difference? UNIX assume it to the right way?
    EXTRA QUESTION: why I can not do the returns with negative numbers? This is:   return -1
    Thank you.
    Last edited by gromlok (2011-11-07 15:48:44)

    If this script is bash only, you could use bash parameter expansion to get rid of any number of //:
    $ DIR="/long//numerous//doubleslashed/path/to/"
    $ FILE="file"
    $ MYPATH="$DIR/$FILE"
    $ cd $MYPATH
    bash: cd: /long//numerous//doubleslashed/path/to//file: No such file or directory
    $ cd ${MYPATH//\/\//\/}
    bash: cd: /long/numerous/doubleslashed/path/to/file: No such file or directory
    See http://mywiki.wooledge.org/BashGuide/Pa … _Expansion if you want a better explanation.
    Edit: changed variable name from PATH to MYPATH.  Boy was I surprised by bash: pacman: command not found
    Last edited by alphaniner (2011-11-07 17:26:02)

  • What is difference between == and equals ??? i wanna know in detain example

    Hi
    1) String s1 = new String("abs");
              String s2 = s1;
              System.out.println(s1==s2);
              System.out.println(s1.equals(s2));
    Output:
    true
    true
    2)
    String s1 = new String("abs");
              String s2 = s1;
              s2 = "abs";
              System.out.println(s1==s2);
              System.out.println(s1.equals(s2));
    output:
    false
    true
    i m not getting that here s1 is object and its assigned to s2 object so both are point to same memory location...but while assinging s2 = "abs" which is same as s1 then its behave like different object y?

    but while assinging s2 = "abs" which is same as s1 then its behave like different object"abs" is "the same as" s1 in the sense that it represents the same characters in the same order. But it is also different from s1 in that it refers to a different object. It's the same distinction as you get comparing two $20 notes: they are equal but, since there are two of them they cannot be identical.
    With Java reference variables this equal/indentical distinction is represented by equals()/==.
    In general each class defines its own equals(). (Much as there will be a legal definition what what counts as being equal to $20.) This realationship is generally what you mean and hence the rule "when comparing objects use equals()".

  • Differences between == and .equals

    I'm rather new to Java programming and have learned that == can only be used to compare primitive types in Java (for example when comparing to int) and when comparing objects, one should use the .equals-method (that should be overloaded from the one in Object). This is because == compare the object's reference adress (is this correct?) For example:
    Vector v1 = new Vector();
    Vector v2 = new Vector();
    v1.add("hello");
    v2.add("hello");
    System.out.println(v1 == v2);This program should print false, since v1 and v2 are different objects.
    System.out.println(v1 == v1);should print true.
    OK, so far so good. However, an experiment I've made clearly shows that there's an exception to this rule. When comparing objects of type String, you don't need to use .equals, == works perfectly. My question is why?

    When comparing objects of type String, you
    don't need to use .equals, == works perfectly. My
    question is why?It doesn't work perfectly at all.
    String literals
    Don't confuse String's equals() method with the equality operator '=='. The == operator checks that two references refer to the same object. If you want to compare the contents of Strings (whether two strings contain the same character sequence), use equals(), e.g. if (str1.equals(str2))...
    Example:String s1 = "foo";
    String s2 = new String("foo");
    System.out.println("s1 == s2: " + (s1 == s2)); // false
    System.out.println("s1.equals(s2): " + (s1.equals(s2))); // trueFor more information, check out Comparison operators: equals() versus ==

  • What's the difference between | and ||

    I have three strings and if even one of them is null (s1 == null), I need to do something. So I have this:
    if( s1 == null | s2 == null | s3 == null)
       //action code
    }Yet the action code is occuring even if none of the strings are null.

    Try to run this code:
    public static void main(String[] args) {
      String s = null;
      if (s == null || s.equals("blah"))
        System.out.println("without exception");
    }And now try this:
    public static void main(String[] args) {
      String s = null;
      if (s == null | s.equals("blah"))
        System.out.println("with exception");
    }Try to understand why these two cases are different, and what�s going on.

  • Differences between & and &&

    Check out my code.. as far as I can see & and && results the same.. From my understanding with && - if the first condition is true.. the statement next would be executed regardless of the second condition (false)..
    class help
         public static void main (String args[])
              boolean t = true;
              boolean f = false;
              if (t & f)
                   System.out.println("t & f"); //doesn't execute
              if (t && f)
                   System.out.println ("t && f"); //doesn't execute
              if (t & t)
                   System.out.println ("t & t"); //executes
              if (t && t)
                   System.out.println ("t && t");  //executes                              
              if (f & t)
                   System.out.println ("f & t"); //doesn't execute
              if (f && t)
                   System.out.println ("f && t"); //doesn't execute
    }Thanks!
    Message was edited by:
    duked

    && and || are short-circuit. If the left-hand side is enough to determine the value of the whole expression, then the right-hand side will not be evaluated.
    & and | always evaluate both sides.
    public class AndOr {
      public static void main(String[] args) throws Exception {
        if (t("t && f") && f("t && f")) {}
        System.out.println();
        if (t("t & f") & f("t & f")) {}
        System.out.println();
        if (f( "f && t") && t("f && t")) {}
        System.out.println();
        if (f( "f & t") & t("f & t")) {}
        System.out.println();
        if (t("t || f") || f("t || f")) {}
        System.out.println();
        if (t("t | f") | f("t | f")) {}
        System.out.println();
        if (f( "f || t") || t("f || t")) {}
        System.out.println();
        if (f( "f | t") | t("f | t")) {}
        System.out.println();
      static boolean t(String str) {
        System.out.println(str + " true");
        return true;
      static boolean f(String str) {
        System.out.println(str + " false");
        return false;
    }

  • Difference between == and .equals

    How do they differ in functionality?
    Thanks in advance

    hi javanovice33,
    simply put:
    == tests if two object references point to the same and only one object
    and
    .equals() tests if two object references contain identical contents
    Illustration A:
    String hello1 = "Hello";
    String hello2 = "Hello";
    is hello1==hello2?
    answer: TRUE
    reason: both object references point to the same and only one
    object "Hello". Note that literal String "Hello" is immutable and
    can no longer be changed. JVM memory heap will try to look
    first for the existence of the same value if another object reference
    is initialized to the same literal String "Hello". Therefore, in this case,
    the declaration and initialization above can be rewritten as hello2=hello1.
    is hello1.equals(hello2)?
    answer: TRUE
    reason: both object references contain identical contents "Hello"
    Illustration B:
    String hellow1 = new String("Hello");
    String hellow2 = new String("Hello");
    is hellow1==hellow2?
    answer: FALSE
    reason: each object reference points to distinct object in memory
    thus, they are not equal
    Is hellow1.equals(hellow2)?
    answer: TRUE
    reason: both object references contain identical contents "Hello"
    Regards,

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