Different results from different machines

I have one program to output jpg photo
to control quality:
ImageWriteParam param = writer.getDefaultWriteParam();
param.setCompressionMode(ImageWriteParam.MODE_EXPLICIT);
param.setCompressionQuality(0.8f);
param.setCompressionType("JPEG");
writer.write(null, new IIOImage(bimage, null, null), param);
I got satisfied photo on my computer
when I run the same program on another machine I got bad quality jpg photo
both machines is windows system
that second machine max color=256, is that cause poor quality of jpg images?

that second machine max color=256Are you sure the bad quality doesn't come from just the display? JPEG images typically have thousands of colours so they are bound to look crappy on a 256 colour display.

Similar Messages

Does the bad formance results from Virtual Machine?

My Oracle 10g testing database is runing on a Virtual Mchine and its performance is not good. Does the bad formance results from Virtual Machine?
Though the resources are enough, I still think the virtual machine can damage the performance. Does any one has the same experience?
Thank you

Answered the same just a while ago...
Can Virtual Machin system make negative impact to the database performance?

Data not populated when run from a different machine

I have a stored procedure which populates a table
The stored procedure when it is run on my machine using SQL Plus populates data correctly in a table.
I select using SQL PLUS and it shows that the data is there
But when I run the SAME procedure ( SAME schema, SAME parameters, same everything ) from a
different machine using SQL PLUS , it shows that "PL/SQL procedure completed successfully", BUT does not populate
the table.
SAme thing is happening for all other procedures too.
Why is this happening
Please help
Ashwin

I checked using this
SELECT * FROM V$PARAMETER WHERE LOWER(NAME) ='nls_language'
AND I get same results on both machines
NUM NAME TYPE
VALUE
ISDEFAULT ISSES ISSYS_MOD ISMODIFIED ISADJ DESCRIPTION
UPDATE_COMMENT
96 nls_language 2
AMERICAN
TRUE TRUE FALSE FALSE FALSE NLS language name
Thanks
Ashwin N.

Generally when creating a Word file from either a Mac or Win7 pc and opening it on two different machines (either one first) it always prompts that the file is open and will be opened as read only. However opening a CSS file does not prompt that it is alr

Generally when creating a Word file from either a Mac or Win7 pc and opening it on two different machines (either one first) it always prompts that the file is open and will be opened as read only.
However opening a CSS file does not prompt that it is already open on or from any machine which is causing code edits to be lost.
What we found from out testing:
- The file can be saved from one user to the server and WILL NOT PROMPT on other machines until the saving machine has the Dreamweaver program closed completely
- The file can be closed and Dreamweaver minimised to the launch bar but it still will not register on other machines that it has been changed.
- Also, until the Dreamweaver program is closed on the machines, it will continue to open it's saved version of the file.
Example Scenario:
- User 1 opens test.css (which is 2000 lines) and adds some code to the end of the file to bring it up to 2500 lines
- Meanwhile User 2 opens test.css as well (opens as 2000 lines as User 1’s edits have not yet been saved) and adds in code to bring it to 2300 lines
- User 1 saves his file and closes it - but Dreamweaver is still open.
- User 2 also saves his file and leaves Dreamweaver open.
- The server will report the size and last edit of the file the same as User 2 as he was the last person to save it (and if you open from the Win7 Machine it will show as User 2’s 2300 line version)
- If User 1 then open's the file again (from either the 'recent' in Dreamweaver OR clicking on the file directly in Finder...which version opens.... The version that User 1 saved! Not the true version on the server, but the version that User 1 edited and saved with 2500 lines in it.
- Same for User 2, he will open 'his' version with 2300 lines in.
Other information:
- Files are opened directly from the server
- Sometimes the users will save incrementally and re-open
- Most of the time users will save incrementally and keep the files open
- The users will never not save incrementally and just save when closing the file once finished
- The users are usually working on the files all day
- It is always the bottom lines of code that are lost. It could be a case of the two versions being mixed up and cutting off the newly added lines based on the line count (possibly).
It is as if Dreamweaver is holding a cache of the version locally and then only properly looking back to the server when it has been completely closed. It is very difficult to see how the server is causing such an impact on these files, there are very few logs which are giving any indication to the root cause of the problems.
Anyone know if this is a known issue?
Is there a way that there can be a featured implemented on the server that doesn't allow another user to open a file if it is already open on another machine?
Thanks

Your server file handling has nothing, and really nothing to do with Adobe software. If files don't get locked for (over-)writing and/or lose connection to the program opening them, then your server is misconfigured. It's as plain and simple and that. Anything from "known file types"/ file associations not being set correctly, MIME types being botched, crooked user privileges and file permissions, missing Mac server extensions, delayed file writing on the server, generic network timeout issues and what have you. Either way, you have written a longwinded post with no real value since you haven't bothered to provide any proper technical info, most notably about the alleged server. Either way, the only way you can "fix" it is by straightening out your server and network configuration, not some magic switch in Adobe's software.
Mylenium

How can i look up a EJB residing in different machine from client side?

hai ,
How can i look up a EJB residing in different machine from client side?
this is my code...........i don't know what should i use as Initial Context Factory...................i am using a sun appserver 8............
package com.parx.lms.lmsdelegate;
import com.parx.lms.exception.LMSException;
import javax.naming.Context;
import javax .ejb.CreateException;
import javax.naming.InitialContext;
import javax.naming.NamingException;
import javax.rmi.PortableRemoteObject;
import java.rmi.RemoteException;
import com.parx.lms.controller.*;
import com.parx.lms.vo.UserVo;
import com.parx.lms.exception.BusinessException;
import java.util.Hashtable;
import java.lang.*;
public class LmsDelegate{
private final static String JNDI_NAME="LmsBean";
private static String url="http://localhost:4848";
public static Lms lms = null;
public void getController() throws CreateException,
NamingException,RemoteException{
if(lms == null){
Hashtable h=new Hashtable();
h.put(Context.INITIAL_CONTEXT_FACTORY," ********what should i use here???????*************************");
h.put(Context.PROVIDER_URL,url);
System.out.println("Before Loading Context in Delegate");
Context ctx=new InitialContext(h);
System.out.println("Loaded Context in Delegate");
Object obj=ctx.lookup(JNDI_NAME);
System.out.println("Loaded Object in Delegate");
System.out.println("Before Loading Home in Delegate");
LmsHome home = (LmsHome )PortableRemoteObject.narrow(obj,com.parx.lms.controller.LmsHome.class);
System.out.println("Loaded Home in Delegate");
lms = home.create();
System.out.println("Loaded remote in Delegate");
public void addUserDelegate(UserVo vo) throws BusinessException{
try{
getController();
System.out.println("Before calling the addUser of Session");
lms.addUser(vo);
}catch(CreateException e){
System.out.println("Create Exception in Delegate due to--->"+e);
e.printStackTrace();
throw new BusinessException(e);
}catch(NamingException e){
System.out.println("Naming Exception in Delegate due to--->"+e);
e.printStackTrace();
throw new BusinessException(e);
catch(RemoteException e){
System.out.println("Remote Exception in Delegate due to--->"+e);
e.printStackTrace();
throw new BusinessException(e);
}catch(LMSException e){
System.out.println("duplicate user name--->"+e);
e.printStackTrace();
throw new BusinessException(e);
pls help me..........

h.put(Context.INITIAL_CONTEXT_FACTORY," ********what should i use here???????*************************")
Each app server provides their own jndi factory class. For ex for weblogic it is weblogic.jndi.WLInitialContextFactory. SInce you are using sun app server, check if there are any examples to find out or the docs.
private static String url="http://localhost:4848
Since the client is in a different machine the localhost is not going to work here. provide the url or the machine name of the system in which ur sunapp server is running. In addition u will need to have the stubs of the remote interfaces in ur client machine.

So I have just had my potentially duff hard drive replaced and uploaded my data from time machine to discover that pages is now speaking to me in a different language. The keyboard has been selected as UK during setup. How do I get back to qwerty?

So I have just had my potentially duff 1Tb hard drive replaced by apple and uploaded my data from time machine only to discover that pages is now speaking to me in a different language. The keyboard has been selected as UK during setup. Any idea how I can get back to qwerty?

roxandiv wrote:
pages is now speaking to me in a different language.
What exactly are you referring to? Are the menus or templates for Pages in a different language? Does something strange appear on the screen when you type?
Could you perhaps use the Camera icon here to post a screenshot of what you are seeing?
To make sure you have the right keyboard, go to system preferences/language & text/input sources and make sure that only the box for US or British is checked (and that the box for French or German or anything else is not checked).

How to backup from Time Machine of a different computer

I want to restore my emails from time machine from a different computer?

Look at the Pondini web site and it should be able to address all of your Time Machine questions.
http://pondini.org/OSX/Setup.html
Ciao.

My hard drive crashed and I am using a different machine. How do I retrieve my personalized Pages 5.2 templates from my backup drive? I have searched at length and can't seem to find them.

My hard drive crashed and I am using a different machine. How do I retrieve my personalized Pages 5.2 templates from my backup drive? I have searched at length and can't seem to find them.

login_directory = /Users/yourname
If the Library folder is not shown in your login directory, then open a Finder window, and press command+J. This will open a Finder View Options panel. On it, there is a selectable entry to Show Library Folder. Once this is selected, the Library folder will appear. Now, follow the instructions in my May 6 post. You will have to right-click on com.apple.iWork.Pages and choose Show Package Contents, before continuing.
Correction: login_directory/Library/Containers/com.apple.iWork.Pages/Data/Library/Applicatio n Support/User Templates/
The host software persists in changing the correct Application Support text above to Applicatio n Support, which does not exist.

JDBC connection to two different machines from the same program

I want to use JDBC to connect to two different databases that are on two different MySQL installations on two different machines.
One of the installations is MySQL 4.1.12 and the other is 4.1.14-nt
For some reason, all my statements seem to be going only to one machine, even though I am very clearly set it up to go to two different machines.
Does anyone know whether connecting to two different installations from one program presents any unusual problems?
Thanks.

Unless there is some horrible defect in the MySQL JDBC driver (which I doubt!), there should be no problem and like the other poster says, please post snippits of your code so we can see what your doing...

Why do I get two different results from the same coefficients?

I am getting two different results from the Polynomial Evaluation function.
For the first one, I am getting the coefficients from a Polynomial Fit function. I feed the coefficients from the Fit function into the Poly Eval function and get the correct result of 12.8582 when I evaluate 49940.
For the second one, I create constant array of the SAME values that were returned from the Polynomial Fit function (i typed them in). However, I am getting an incorrect result of -120.7913 when I feed the constant array into the Poly Eval function when I evauate 49940.
How can this happen when I am using the same array values?
Attached is an image of what I am explaining.
Solved!
Go to Solution.
Attachments:
polynomial_evaluation.jpg ‏213 KB

Hi Altran,
are you sure about using the "same" coefficients?
Did you compare them? Did you (atleast) set the display properties to 17 significant digits?
Please attach a VI instead of a picture...
Best regards,
GerdW
CLAD, using 2009SP1 + LV2011SP1 + LV2014SP1 on WinXP+Win7+cRIO
Kudos are welcome

RMI client running from different machine giving error

HI all
I am trying to run the sample application getStart hello world.
I am able to run the java applet from the same machine ....
but i am get error when i am trying run client applet from the different machine .
(HelloApplet exception: access denied (java.net.SocketPermission)
client applet on machine1 and server and registory on machine2 in same lan .
i copied the Helloapplet.class and Helloclient.html to machine1.
appletviewer Helloclient.html
but the java version is different in both machines.......
can any one give some idea ....
the errror i am geting is :
HelloApplet exception: access denied (java.net.SocketPermission Neind-ws-003 res
olve)
java.security.AccessControlException: access denied (java.net.SocketPermission N
eind-ws-003 resolve)
at java.security.AccessControlContext.checkPermission(AccessControlConte
xt.java:272)
at java.security.AccessController.checkPermission(AccessController.java:
399)
at java.lang.SecurityManager.checkPermission(SecurityManager.java:545)
at java.lang.SecurityManager.checkConnect(SecurityManager.java:1042)
at java.net.InetAddress.getAllByName0(InetAddress.java:559)
at java.net.InetAddress.getAllByName0(InetAddress.java:540)
at java.net.InetAddress.getByName(InetAddress.java:449)
at java.net.Socket.<init>(Socket.java:100)
at sun.rmi.transport.proxy.RMIDirectSocketFactory.createSocket(RMIDirect
SocketFactory.java:25)
at sun.rmi.transport.proxy.RMIMasterSocketFactory.createSocket(RMIMaster
SocketFactory.java:120)
at sun.rmi.transport.tcp.TCPEndpoint.newSocket(TCPEndpoint.java:499)
at sun.rmi.transport.tcp.TCPChannel.createConnection(TCPChannel.java:190
at sun.rmi.transport.tcp.TCPChannel.newConnection(TCPChannel.java:174)
at sun.rmi.server.UnicastRef.newCall(UnicastRef.java:318)
at sun.rmi.registry.RegistryImpl_Stub.lookup(Unknown Source)
at java.rmi.Naming.lookup(Naming.java:84)
at examples.hello.HelloApplet.init(HelloApplet.java:23)
at sun.applet.AppletPanel.run(AppletPanel.java:344)
at java.lang.Thread.run(Thread.java:484)
The helloapplet.java code is :
package examples.hello;
import java.applet.Applet;
import java.awt.Graphics;
import java.rmi.Naming;
import java.rmi.RemoteException;
public class HelloApplet extends Applet {
String message = "blank";
// "obj" is the identifier that we'll use to refer
// to the remote object that implements the "Hello"
// interface
Hello obj = null;
public void init() {
     try {
          System.out.println("Path looking: " +getCodeBase().getHost());
     //obj = (Hello)Naming.lookup("//" +
          //     getCodeBase().getHost() + "/HelloServer");
               obj = (Hello)Naming.lookup("//Neind-ws-003/HelloServer");
     message = obj.sayHello();
     } catch (Exception e) {
     System.out.println("HelloApplet exception: " +
                    e.getMessage());
     e.printStackTrace();
public void paint(Graphics g) {
     g.drawString(message, 25, 50);
The helloclient.html code:
<HTML>
<title>Hello World</title>
<center> <h1>Hello World</h1> </center>
The message from the HelloServer is:
<p>
<applet
          code="examples.hello.HelloApplet"
width=500 height=120>
</applet>
</HTML>

Your problem is at the following line.
obj = (Hello)Naming.lookup("//Neind-ws-003/HelloServer");
The line you had commented beforehand is
//obj = (Hello)Naming.lookup("//" +
// getCodeBase().getHost() + "/HelloServer");
This worked because the applet was being retreived from the same server where the RMI server exists.
Remember, applets can only connect themselfs to the same host they are stored in and retreived from. This is because of VM, the sandbox does not allow you to connect to other machines other than the server where it resides on. If you use a applet viewer it might work if you loosen the security features. On a browser i do not belive it can be done. Maybe if you modify your security options for the VM you are able to achieve something, but personally i'm going for the "It cannot be done " answer because of what I said before.
Hope this helps
If any trouble then reply and I'll answer later.
Rui P.

Strange query plans, and so different results from a view.

In my database (11g), I have a currency exchange rate table, which contains all currencies and their exchange rate to USD. I need to have a number of different exchange rates - To GBP, EUR, etc...
To accomplish this I have created a view, which has one union statement of all the USD exchange rates, with the same data joined back on itself to give the exchange rates based on their exchange rate to USD - ie: SELECT b1.Date, b1.Currency AS FromCurrency, b2.Currency as ToCurrency, b1.Rate/b2.Rate as Exchange Rate FROM Rates b1, Rates b2 on b1.Date = b2.Date
This view works fine when I query it, and returns the data as I expect.
I have a second view that is joined to this view to give a return of the amount in each currency for reporting. This view seems to work correctly when I narrow down the search requirements and have a small set of data.
The issue I am having is when I query the second view and get it to return all the data. Instead of receiving 4 rows per transaction (I am only interested in 4 exchange rates for display) I typically receive up to 2 rows. The first record is for the conversion to USD, the second record is for the conversion to the supplied currency. The issue is that this exchange rate actually includes the aggregate for all 3 other requested currencies (not the USD).
So instead of getting something like:
Amt RC BC (Amt = Amount, RC = Reporting Currency. BC = Base Currency)
60 GBP GBP
80 EUR GBP
100 USD GBP
1000 ZAR GBP
60 GBP USD
80 EUR USD
100 USD USD
1000 ZAR USD
I get the following set of results:
1140 GBP GBP
100 USD GBP
100 USD USD
Has anyone come accross something similar or have any ideas on how I can resolve this?
Thanks
PS: I can get both sets of results from the same view depending on the filter criteria. Also if I convert the exchange rates into a table, it then returns the correct results as expected.

943081 wrote:
The idea is to seek help in solving the problem. I was hoping that perhaps someone had experienced the same thing - different results for "effectively" the same query:Well, that's the issue... without additional info, it's not clear what issue you were seeing.
SELECT * FROM view WHERE Date = '01 January, 2012'
verse
SELECT * FROM view WHERE Date > '31 December, 2011' ORDER BY DateNow it's a bit clearer. That second query is not "effectively" the same as the first query. If the date column is in DATE format, then you ought to have a to_date() around the date string to explicitly convert it into a date so you can do date-to-date comparisons correctly. Also, DATE datatype stores times as well as dates, so asking for data matching midnight of a specific date is different than asking for data greater than midnight of the previous day.
If the date string is a string, then ... well, the string "31 December 2011" is greater than the string "31 August 2013", despite it being an earlier date. This is why making sure you're using the right datatype for the job is important - a date is different to a string that just happens to contain a date.
DateID
I have no objection to using a Date but always struggle to understand what someone means when they tell me "06/07/2012" - granted if the day is above 12 or the same day and month I don't have a problem - but it still leaves 121 days a year that are confusing. sure, but just because you find outputting the display (or rather, someone else's output) confusing doesn't mean you still shouldn't use the correct datatype. Store things as a date, and you can then output it in whatever format you like. Try doing that with a string or a number.
Don't say it doesn't happen as I got a birthday card from a company in May this year when I have specifically entered my date of birth as being the 5 of a month (name drop down box on their website)!Just because someone else doesn't understand how to work with dates correctly doesn't mean you can't! It's not exactly rocket science, after all!*{;-)

Possible solution to avoid deadlock when two inserts happen on same table from two different machines.

Possible solution to avoid deadlock when two inserts happen on same table from two different machines.
Below are the details from deadlock trace.
Deadlock encountered .... Printing deadlock information
Wait-for graph
NULL
Node:1
KEY: 8:72057594811318272 (ffffffffffff) CleanCnt:3 Mode:RangeS-S Flags: 0x1
Grant List 2:
Owner:0x00000013F494A980 Mode: RangeS-S Flg:0x40 Ref:0 Life:02000000 SPID:376 ECID:0 XactLockInfo: 0x000000055014F400
SPID: 376 ECID: 0 Statement Type: INSERT Line #: 70
Input Buf: RPC Event: Proc [Database Id = 8 Object Id = 89923542]
Requested by:
ResType:LockOwner Stype:'OR'Xdes:0x0000002AA53383B0 Mode: RangeI-N SPID:238 BatchID:0 ECID:0 TaskProxy:(0x00000027669B4538) Value:0x10d8d500 Cost:(0/38828)
NULL
Node:2
KEY: 8:72057594811318272 (ffffffffffff) CleanCnt:3 Mode:RangeS-S Flags: 0x1
Grant List 2:
Owner:0x0000000B3486A780 Mode: RangeS-S Flg:0x40 Ref:0 Life:02000000 SPID:238 ECID:0 XactLockInfo: 0x0000002AA53383F0
SPID: 238 ECID: 0 Statement Type: INSERT Line #: 70
Input Buf: RPC Event: Proc [Database Id = 8 Object Id = 89923542]
Requested by:
ResType:LockOwner Stype:'OR'Xdes:0x000000055014F3C0 Mode: RangeI-N SPID:376 BatchID:0 ECID:0 TaskProxy:(0x000000080426E538) Value:0x30614e80 Cost:(0/41748)
NULL
Victim Resource Owner:
ResType:LockOwner Stype:'OR'Xdes:0x0000002AA53383B0 Mode: RangeI-N SPID:238 BatchID:0 ECID:0 TaskProxy:(0x00000027669B4538) Value:0x10d8d500 Cost:(0/38828)
deadlock-list
deadlock victim=process5daddc8
process-list
process id=process5daddc8 taskpriority=0 logused=38828 waitresource=KEY: 8:72057594811318272 (ffffffffffff) waittime=2444 ownerId=2994026815 transactionname=user_transaction lasttranstarted=2014-07-25T12:46:57.347 XDES=0x2aa53383b0 lockMode=RangeI-N schedulerid=43 kpid=14156 status=suspended spid=238 sbid=0 ecid=0 priority=0 trancount=2 lastbatchstarted=2014-07-25T12:46:57.463 lastbatchcompleted=2014-07-25T12:46:57.463 clientapp=pa hostname=pa02 hostpid=1596 loginname=myuser isolationlevel=serializable (4) xactid=2994026815 currentdb=8 lockTimeout=4294967295 clientoption1=671088672 clientoption2=128056
executionStack
frame procname=mydb.dbo.SaveBill line=70 stmtstart=6148 stmtend=8060 sqlhandle=0x03000800d61f5c056bd3860170a300000100000000000000
INSERT INTO [dbo].[Prod1] .....
inputbuf
Proc [Database Id = 8 Object Id = 89923542]
process id=process5d84988 taskpriority=0 logused=41748 waitresource=KEY: 8:72057594811318272 (ffffffffffff) waittime=2444 ownerId=2994024748 transactionname=user_transaction lasttranstarted=2014-07-25T12:46:57.320 XDES=0x55014f3c0 lockMode=RangeI-N schedulerid=39 kpid=14292 status=suspended spid=376 sbid=0 ecid=0 priority=0 trancount=2 lastbatchstarted=2014-07-25T12:46:57.440 lastbatchcompleted=2014-07-25T12:46:57.440 clientapp=pa hostname=pa01 hostpid=1548 loginname=myuser isolationlevel=serializable (4) xactid=2994024748 currentdb=8 lockTimeout=4294967295 clientoption1=671088672 clientoption2=128056
executionStack
frame procname=pa.dbo.SaveBill line=70 stmtstart=6148 stmtend=8060 sqlhandle=0x03000800d61f5c056bd3860170a300000100000000000000
INSERT INTO [dbo].[Prod1]....
inputbuf
Proc [Database Id = 8 Object Id = 89923542]
resource-list
keylock hobtid=72057594811318272 dbid=8 objectname=pa.dbo.prod1 indexname=PK_a id=lock1608ee1380 mode=RangeS-S associatedObjectId=72057594811318272
owner-list
owner id=process5d84988 mode=RangeS-S
waiter-list
waiter id=process5daddc8 mode=RangeI-N requestType=convert
keylock hobtid=72057594811318272 dbid=8 objectname=pa.dbo.prod1 indexname=PK_a id=lock1608ee1380 mode=RangeS-S associatedObjectId=72057594811318272
owner-list
owner id=process5daddc8 mode=RangeS-S
waiter-list
waiter id=process5d84988 mode=RangeI-N requestType=convert

Don't know. Perhaps these can help. I scanned the second link but didn't see much about Ending Deadlocks. I'd say the Fourth link probably has better information than the first three links. But maybe read them all just in case the Fourth is missing something
one of the first three have.
Deadlocking
Detecting and Ending Deadlocks
Minimizing Deadlocks
Handling Deadlocks in SQL Server
Google search for "SQL Deadlock"
La vida loca

Different Results From V$Rman_Backup_job_details and V$Rman_Status

Does anyone know why I would get different results from V$Rman_Backup_job_details and V$Rman_Status on the same instance?
Image of Quries: www.hydell.com/OracleBackupDifferences.png
Dates Returned For Latest Backup
V$Rman_Status = 10/13/2011
V$Rman_Backup_job_details = 7/24/2011
Which view is the best to use for monitoring backups?
Thanks in advance for the help.
Rob

oracle.dba.89 wrote:
Please show the script and that might help look into this. Also the timezone of the OS shows EST. And cron shows the scheduled time at 12hrs. It should run at 12:00 EST hours and not GMT.
Also please post output for below queries. Are backups run from the same node? (If RAC)
select value from dba_scheduler_global_attribute where attribute_name = 'DEFAULT_TIMEZONE';
Hi,
This is the backup script
#Set Variables
ORACLE_HOME=/projects1/oramroprod/oracle/product/10.2.0/db_4
ORACLE_SID=MROPROD
PATH=$PATH:$ORACLE_HOME/bin
btype="FULL"
RMAN_BACKUP_LOC=/data1/RMAN/MROPROD
export ORACLE_HOME
export ORACLE_SID
export PATH
export btype
tag="$ORACLE_SID"_"$btype"
#Print commands and their arguments as they are executed
set -x
SDATE=`date +%m%d%y`
STIME=`date +%H%M%S`
DD=`date +%d%m%y`
#Create daily backup directories
mkdir -p $RMAN_BACKUP_LOC/datafiles_backup/bkp_${DD}
mkdir -p $RMAN_BACKUP_LOC/controlfile_backup/bkp_${DD}
mkdir -p $RMAN_BACKUP_LOC/arch_backup/bkp_${DD}
mkdir $RMAN_BACKUP_LOC/logs
#Take backup
rman target / nocatalog log=$RMAN_BACKUP_LOC/logs/rman_${btype}_backup_${SDATE}_${STIME}.log << EOF1
change archivelog all crosscheck;
run {
CONFIGURE RETENTION POLICY TO REDUNDANCY 1;
CONFIGURE DEVICE TYPE DISK PARALLELISM 2 BACKUP TYPE TO BACKUPSET;
backup as compressed backupset incremental level 0 database tag '$tag' format '$RMAN_BACKUP_LOC/datafiles_backup/bkp_${DD}/%d_%s_%p';
backup as compressed backupset archivelog all not backed up 1 times FORMAT '$RMAN_BACKUP_LOC/arch_backup/bkp_${DD}/ARCH_%d_%s_%p';
CONFIGURE CONTROLFILE AUTOBACKUP FORMAT FOR DEVICE TYPE DISK TO '$RMAN_BACKUP_LOC/controlfile_backup/bkp_${DD}/%F';
delete noprompt obsolete;
delete noprompt archivelog all completed before 'sysdate-2';
EXIT;
EOF1
This is not RAC.
SQL> select value from dba_scheduler_global_attribute where attribute_name = 'DEFAULT_TIMEZONE';
VALUE
GMT

Different results from all_objects

Can someone please explain me,
How it is possible to get different results from "all_objects", once I query it from "SQL Worksheet" and next time when I execute the procedure with the same query ?
The procedure is created by schema user (owner) and it's executed by it.
Same as the query.
I am querying for objects which belongs to other owners.
Is there a way how to trace which privileges are used for querying the "all_objects" ?
Any hint will be very welcomed ?

You are correct, sorry.
Oracle 11g EE 11.2.0.1.0 - 64bit Production on Windows 2K8
I already lost my whole day, probably I will lost the weekend, too.
Here is the sample code:
CREATE OR REPLACE PROCEDURE PROCEDURE1 AS
BEGIN
FOR c IN (SELECT object_name from all_objects d
WHERE d.owner IN ('DWH_CM')
LOOP
dbms_output.put_line(c.object_name);
end loop;
END PROCEDURE1;
Test
exec procedure1;
-- does not write anything in output and it is enabled
select object_name
from all_objects O
WHERE o.owner IN ('DWH_CM');
-- returns 99 rows
Edited by: user9377205 on Aug 6, 2010 9:06 AM

I have two (paid) copies of lightroom 5 from your photography promotion installed (on two different machines). I would like to deactivate one copy on one desktop so I can install a copy on my laptop. How do I go about this?

I have two (paid) copies of lightroom 5 from your photography promotion installed (on two different machines). I would like to deactivate one copy on one desktop so I can install a copy on my laptop. How do I go about this?

While the standalone version of LR has no deactivation, the Photography Program which is LR + PS-CC bundled and licensed through the Cloud will have a 2-activation limit per Adobe ID, and you cannot decouple the LR from the PS-CC in the Photographers Bundle.
You can license the cloud on up to two computers per AdobeID by signing into the cloud. When you try to sign in on a third computer you have the option to deactivate the other two copies, which you can do, and then never sign into the cloud on the one computer you don’t want activated and you’ll be fine.

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