Do I need to synchronize vector to do this?

Question

I need to add some code to an existing legacy java class. In this class,
it already has had a Vector call v.
What I need to do is remove the last element from the vector and do
something. I think I can add the following code to do this:
<pre>
v.remove(v.size()-1).
</pre>
However, in multi-thread environment, this could cause problems. Say, the vector
has size 2. The first thread comes in and get v.size() =2, and then the second
thread comes in and get vi.size()=2. Then both of them is try to remove the
second element.
I think I can add a synchronized(v) around the code, but this is really performamce-expensive. considering vector is already synchronized. Does anyone have a better idea about how to handle this?
thanks,
JT

Answer 1

Can you refactor so that you always remove thefirst
element? zero is always the first elementregardless
of what the other thread is doing.
Not true, if a thread thinks that a Vector's size is
greater then zero (thus it can remove an element), and
then is interrupted, another thread comes in, removes
the last element, element zero, then the first thread
is resumed, then the first thread will fail with an
exception.
You are, of course, correct.
I had assumed that was the only thread removing things and there is another thread adding