Does key comparison work for character arrays?

Question

I am using the berkeley db(C) to store a 2-column table with key as a character array(not strings). Even though I can see that a record is present when i display all records, I cant get that record using the get function with the correct key. Is there a problem with key comparison? How does berkeley db check two keys for equality? Is there a way around this?
thanks in advance.

Answer 1

Hi,
Your code posting was messed up due to the indexed addressing (the i in square brackets) which is in fact the italic start tag. You can put some spaces inside the square brackets, and make sure to enclose your source code between pre tags ([ pre ] <code goes here> [ / pre ], remove the spaces).
So, I assume you are trying to store a line of the bi-dimensional char array.
     key.data = a + i;          
     key.size = sizeof(a[ i ]);
// char *aa = "0a0s0d0f0g0h0j0k0l0q0w0e0r0t0y0f";(I've changed the name of this pointer to distinguish it from the array)
aa points to a sequence of chars (a string in fact) that should be the same as the ones in the line of the bi-dimensional char array, line that was stored as key in the database, right?
key.data = aa;
key.size = sizeof(aa);Now, here is the problem. aa is a pointer to char, thus sizeof(aa) is 2B or 4B (depending on the pointer type, near or far) on a 32-bit machine. So, you're performing the search looking only for the match of the first 2 or 4 chars. Change that line to key.size = strlen(aa); or key.size = sizeof(*(a + i)); (the same as key.size = sizeof(a[ i ]);, a being the char array).
Regards,
Andrei