Easy math problem...I suppose....

I am trying to make these calculations in a Java program, but they will not simply work.
I want to power a variable r(the radius of a sphere) with 2 and then 3.
v(volume), a(area) and r(radius) are all Integer.
What am I doing wrong?
v = (4*(Math.PI)*rE3)/3;
a = 4*Math.PI*rE2;
Many thanks
/Martin

rE2 - looks like you're assuming that means 'raise r to the 2nd power'. It doesn't (it just looks for a variable named 'rE2').
Use Math.pow(r, 2)

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Someone told me of an application for the iPhone that is an alarm clock in which you can use a mode that, when the alarm sounds, you need to solve a math problem or other visual test in order to cease the alarm. That way the user is more awake by the time the alarm is stopped. Sounds annoying, yes, but would be just what I need.
Anyone know which alarm app this is? Or if it even exists?

There's another app that got a lot of press recently called *Proactive Sleep*.
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Getting the top left corner of a grid cell (math problem)

I'm making a map editor for a tile based game. The editor makes a grid:
private function drawGrid():void {
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How can I do that? I came up with an idea but it didn't work because I have a math problem. Let's pretend that the user mouse is at position mouseX = 456:
I could remove the hundreds and use the quotient 56 and check if it is above 50. If it is above 50 I would place it at x = 500 if not I would place it at x = 450. How can I remove the hundreds? Do you have a better idea?
Message was edited by: wilsonsilva7 because unconsciously I pressed ctrl+s (to save) and the message was posted

Thanks. I asked a friend and he told me about the %but I still had a problem. Your expression solved my problem
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That way every tile is centered every 50 pixels

Strange math-problem with LabVIEW 7.1

Hello!
I am using LabVIEW 7.1 and I came to this strange math-problem. Could it be that it is a problem of LabVIEW 7.1?
Ok try this with LabVIEW 7.1:
open a new VI
place a subtract-VI (pallet numerical) on the block diagram and try to subtract 0.2 from 1.6
place a less-VI (pallet compare) on the block diagram and wire a numerical constant 1.4 to input x
wire the result of the subtraction to input y of the comparison
place an LED to the output of the comparison
and start this.
What does it say?
The LED should turn on and this means here that 1.4 would be less than 1.4 .
But I would have expected that 1.4 is not less than 1.4 .
This works also if you add or subtract upto 0.2 to/from the values 1.4 and 1.6 (or equivalent with 0.2) .
If you change the inputs of the comparison then the result is as expected and 1.4 is reported not to be less than 1.4 .
If you compare two constants with the same value 1.4 you will not get the same strange result.
Does anybody have an explanation for this?
Espelkamper

Hello,
For floating point math: Rounding to multiples of 0.1 is problematic as
those numbers are infinite fractions in base2 representation...
So maybe you should change your numbers to integers using fixed point math. If all your input values are in the range of 1.4 to 1.8 you can multiply by 10000 and round to next integer. Then do your comparison on that integer (there's also an 'InRange' function in the comparison palette).
Best regards,
GerdW
CLAD, using 2009SP1 + LV2011SP1 + LV2014SP1 on WinXP+Win7+cRIO
Kudos are welcome

Re: Help needed for easy Math & Java problems

The logic in pseudo code :
IF length <= 1
Price = Base price;//Base price = 8 in your case;
ELSE IF length <= 10
Price = Base price + (Extra Meter Price * (length - 1));
ELSE IF length <= 20
Price = (Base price + (Extra Meter Price * (length - 1))) * Discount1
ELSE
Price = (Base price + (Extra Meter Price * (length - 1))) * Discount2
RETURN Price.
Code it in Java then.
Do not use magic numbers.

The logic in pseudo code :
IF length <= 1
Price = Base price;//Base price = 8 in your case;
ELSE IF length <= 10
Price = Base price + (Extra Meter Price * (length - 1));
ELSE IF length <= 20
Price = (Base price + (Extra Meter Price * (length - 1))) * Discount1
ELSE
Price = (Base price + (Extra Meter Price * (length - 1))) * Discount2
RETURN Price.
Code it in Java then.
Do not use magic numbers.

Maths Problem in Action Script 2.0

Hi surfers,
We have a problem in Action Script 2.0 to solve the maths equation given below:
write a code in Action Script 2.0 to solve these two equation.
Aim: To know the value of "a" in both different equations.
1. 2a + 5 = 3a + 1
2. 4a + 3 = 11
Thanks in Advance.
Pls give me ASAP, i'm struggle here.

Hello, you are at the wrong forum. for AS 2.o questions, hop on there: http://forums.adobe.com/community/flash/flash_actionscript
BTY, people answer when they can, not when you want...

Easy Transfer problems

new Computer                       C:drive with win 7 is 40gb,
E:drive is 1tb
old computer                         C:drive with win 7 is
500gb, D:drive is 80gb
I want to transfer the contents of my old computer (400gb) to the E:drive on the new computer but when using the easy transfer cable it will only transfer to the smaller C:drive HDD at 40gb
on the new computer and wants me to discard files
Have any solution to my problem?
Do I rename the  C
Regards
Bill Anderson

Hi Bill,
First of all, I must to tell you, rename the C:\ cannot change its drive letter, just change its label. And I don't recommend you change the system drive letter, it would affect the system normal usage.
Next let's go back to your problem.
When you transfer files, the information on each drive on your old computer will be transferred to the respective drives on your new computer. Unless Windows Easy Transfer detects that the drive names on your old and new computers don't match. For example,
if you choose to transfer files and settings from the C: and D: drives on your old computer, but your new computer only has a C: drive, then you will be asked to select which drive on your new computer you want to transfer information to.
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Transferring files and settings: frequently asked questions
http://windows.microsoft.com/en-in/windows/transferring-files-settings-faq#1TC=windows-7
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TechNet Community Support

Logic for this math problem

Before I get stinker replies for cross posting , let me tell that , i have been recommended to post this in this forum.
My problem is such:
I need to find a logic to implement the following :
In the floating point number , say , 1.0.. the Integral part will remain constant(1) but the decimal part has to get incremented by 1
1.1 +0.1
1.2+0.1
1.3+0.1
1.4+0.1
1.5 +0.1
1.6+0.1
1.7+0.1
1.8+0.1
1.9+0.1
1.10+0.1
1.2... But what I need here is 1.11 ,1.12
I need my programming logic to detect there needs to be a change in the increment value from 0.1 to 0.01 when I reach 1.1
and from 0.01 to 0.001 when i reach 1.111..so on,
please suggest..

you can't do it with a double,
since double d = 1.10d; will be treated as 1.1d
what you can do is treat the double as a String
public void test(){
String s1 = "1.9";
String s2 = "1.10";
String s3 = "1";
String s4 = "1.1";
System.out.println(increment(s1));
System.out.println(increment(s2));
System.out.println(increment(s3));
System.out.println(increment(s4));
public String increment(String d){
int pos = d.indexOf(".");
if (pos != -1){
if (d.charAt(d.length()-1) == 0)
return d.substring(0, d.length()-2) +
ength()-2) + "1";
String temp = d.substring(pos+1);
int num = Integer.parseInt(temp);
num++;
return d.substring(0, pos+1) + num;
else
return d + ".1";
}gives
1.10
1.11
1.1
1.2
I leave it to you to understand the logic...it's to
get you started..it does not check for all conditions
of the inputI think it is a Math with algorithm problem. Your solution is good, but you are using String functions so much. There is other solution, handling with numbers only.

Easy DMS - problem with object linking (unicode client)

Hi Gurus,
I have a problem concerning linking a materialmaster to a DIR in a uniciode environment. I tested following scenarios:
1) Easy DMS 6.00 SP10 non unicode + non unicode Backend --> no problem
2) Easy DMS 6.00 SP10 non unicode + unicode Backend        --> no problem
3) Easy DMS 6.00 SP10 unicode        + non unicode Backend --> no problem
4) Easy DMS 6.00 SP10 unicode        + unicode Backend         --> problem
Following Problem appears in scenario 4:
Our Material Number Format is ______-____-___ (6 digits - 4 digits - 3 digits), "Lexicographical" is disabled, "Leading Zeros" is enabled.
When I type in material number "111111-2222-333" and press "check all objects and read description" Easy DMS reads the description for
111111-2222-333 but after that easy dms changes 111111-2222-333 to 000001-1111-122 and when I try to save the DIR it tells me that
000001-1111-122 is not a valid material master.
As I mentioned this only appears with the unicode client + unicode backend. Any Ideas?

Hi David,
please tell us which version of EasyDMS you use currently. If you do not use EasyDMS 6.00 SP10 I would kindly ask you to see SAP note 1105699 and download this SP from the Service Marketplace.
Further please check if you have maintained the object link customizing correclty in your backend system. Therefore please see the information in the SDN WIKI area for DMS under https://www.sdn.sap.com/irj/sdn/wiki?path=/display/plm/ca-dms-Object+link
Best regards,
Christoph
P.S.: Please reward points for useful information.

EASY DMS Problem 6.0 SP11 Patch01 (Unicode), display classification data

hallo
i have installed Easy DMS 6.0 SP11. In the search result, no classification data are shown. The problem doesn't exist in 6.0 SP03. Any idea?
Regards
Hans
Edited by: Hans Koeniger on Feb 2, 2009 8:58 AM

Problem seems to be solved, perhaps by transports in the backend.

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I need to be able to write the exponent wherever I write something when within Firefox.

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Math Problem

I need some help! I admit, I'm not a java guru...far from it, just a college student with a book that doesn't have many examples for what I'm looking for. Any help will be greatly appreciated!!!
My problem: My java program is to find a root using the Newton-Rapson method. The input is a function, i.e. f(x) = x^2 + x + 2. The program is to prompt the user for the beginning numbers, i.e. 225 and -43, and then find the answer to the nearest hundredth.
I can do this on paper - no problem, my problem is I don't know enough about Java to program it to do the math.
Unfortunately, if there are any predefined classes or methods that will do this problem for me, I'm NOT allowed to use them. Every step has to be hard coded. :(
I'm not sure how to get Java to recognize the + sign or
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Any help offered would be greatly appreciated, and I'm sure would in-turn help me the the bisection algorithm and all the future algorithm's I have to put into a program.
Thanks for your time.

[mode=Pedantic] Its Newton-Raphson [mode]
Anyway use this as a starting point, its from a guy by the name of Neil Broadbent (see: http://www.neiljohan.com/java/ for lots of java samples)
This will calculate the square root of a number using Newton-Raphson factoring, you can use this as a starting point.
//Program to calculate the square root of a number using the Newton-Raphson.
//It stops when the difference between consecutive approximations is less than 0.00005
//by Neil Broadbent
import java.io.IOException;
import NeilClass.*;
public class NewtonRaphsonClass
     private static boolean debugging = true;
     /** @param tFactorial the value from which to find the square root
      * precondition tFactorial>0
      * @return x1 so that x1>0 */
    public static double iSquareRoot (double tFactorial) throws IOException
            double x1=0;
            double x0=tFactorial/2;
            double a=tFactorial;
            boolean finished=false;
     /* check pre-condition */
     if (debugging && (tFactorial<=0)){
          System.out.println("Pre-condition violoated");
          finished=true;
            while (finished==false)
                x1=(x0+(a/x0))/2;
                if (x1>x0){
                    if ((x1-x0)<0.00005){
                        finished=true;
                else if (x0>x1){
                    if ((x0-x1)<0.00005){
                        finished=true;
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          /* check post-condition */
          if (debugging && (x1<=0)){
               System.out.println("Post-condition violoated");
            return x1;
}

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Probably a simple answer: easy div problem

Hello,
I have a very easy problem but can't find the answer. 3 divs: 1 "wrapper" and 2 inside it (one left column, one right). I want to get the CSS settings so that the left and right column are both the same length. Right now they are on auto length and the left column is longer. I tried to "fill out" the wrapper with the right column by setting the right column to 100% length, but now I realize the "wrapper" div is being shrink-wrapped around the shorter right column and is not stretching it. I just want both columns to be as long as the (longer) left column.
Thanks!

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Tables are the intuitive way to solve this if you are not concerned with separating content and organization, which good modern designers are usually concerned with:
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<tr>
<td>first column</td>
<td>second column</td>
</tr>
</table>
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Creating a form with a field that contains a simple math problem.

I am creating a form in Acrobat 9 Standard that contains a field that requires a simple math function (divide).
if (QuantityRow1 > 0)
ExtensionRow1 / QuantityRow1
Take the value input in ExtensionRow1 and divide it by the value in QuantityRow1. I have included an IF statement to prevent an error that occur if QuantityRow1 were equal to zero.
After inputting the data into the two fields I tab past the field where I expect to see my result and the field remains blank. I don't receive any error messages.
Any ideas? Thanks - jb

This is a duplicate of your question on Acrobatusers.com (
http://answers.acrobatusers.com/Need-simple-math-operation-function-Acrobat-9-Standard-cre ating-form-q142800.aspx
Did the information provided there not help you with your problem?
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PDF Acrobatics Without a Net
PDF Software Development, Training and More...
[email protected]
http://www.khkonsulting.com

Easy math problem...I suppose....

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