Error while calling a function.

Question

Hi,
below is my callable statement through which am calling a function which returns the service years of a person with personid as parameter.
But dont know why am getting an error which is returning the serviceyrs as 0.
when i try to debug, the problem is in this statement
System.out.println("the output1 is "+cs.getInt(1));
is there any problem with my code.
please look the code below
thanks
kumar
OADBTransaction txn=getOADBTransaction();
OracleCallableStatement cs = (OracleCallableStatement) txn.createCallableStatement("begin :1:=LMIG_UTILITY_PKG.GET_TOTAL_SERVICE(p_person_id => :2); end;",1);
try
cs.registerOutParameter(1,Types.INTEGER);
cs.setInt(2,Integer.parseInt(pid));
System.out.println("person id is "+pid);
System.out.println("the output1 is "+cs.getInt(1));
cs.execute();
serviceyrs= cs.getInt(1);
cs.close();
catch(SQLException sqle)
System.out.println("ERROR"+sqle.toString());
System.out.println("Service years are "+serviceyrs);

Answer 1

Hi, Guess u are missing the connection to the JDBC call.
Try the following...it worked for me..
Connection conn = this.getOADBTransaction().getJdbcConnection();
OracleCallableStatement ocs = null;
String param = null;
try {       
     String stmt = "BEGIN :1 := <PkgName>.<FunctionName>(:2); end;";
     ocs = (OracleCallableStatement)conn.prepareCall(stmt);
     ocs.registerOutParameter(1, OracleTypes.CHAR);
     ocs.setString(2, <param>);
     ocs.execute();
     param = ocs.getString(1);
} catch(SQLException se)
{       throw OAException.wrapperException(se);    
finally
     try {               
          ocs.close();
          return(param);
     } catch(Exception e)
          throw OAException.wrapperException(e);
}