Example J2EE_QuickCarRental: not forwarding to a jsp

Question

Hello,
i cannot make a forward to the jsp file; always the path will be "QuickCarRental/servlet/quickCarRentalView.jsp" at the server.
My web.xml-file:
<web-app>
    <display-name>Rent-A-Car</display-name>
    <description>Web resources for Car Rental example</description>
    <servlet>
        <servlet-name>quickCarRentalView.jsp</servlet-name>
        <jsp-file>/quickCarRentalView.jsp</jsp-file>
    </servlet>
    <servlet>
        <servlet-name>QuickReservationServlet</servlet-name>
        <servlet-class>com.sap.examples.quickcarrental.servlet.QuickReservationServlet</servlet-class>
    </servlet>
    <servlet-mapping>
        <servlet-name>quickCarRentalView.jsp</servlet-name>
        <url-pattern>/view</url-pattern>
    </servlet-mapping>
    <servlet-mapping>
        <servlet-name>QuickReservationServlet</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>
    <ejb-local-ref>
        <ejb-ref-name>ejb/QuickOrderProcessorBean</ejb-ref-name>
        <ejb-ref-type>Session</ejb-ref-type>
        <local-home>com.sap.examples.quickcarrental.QuickOrderProcessorLocalHome</local-home>
        <local>com.sap.examples.quickcarrental.QuickOrderProcessorLocal</local>
        <ejb-link>QuickCarRentalEjb.jar#QuickOrderProcessorBean</ejb-link>
    </ejb-local-ref>
</web-app>
code in servlet:
RequestDispatcher dispatcher = request.getRequestDispatcher("/view");
message from server:
Application error occurred during the request procession.
Details: javax.servlet.ServletException: Requested resource ( QuickCarRental/servlet/quickCarRentalView.jsp ) not found.
     at com.sap.examples.quickcarrental.servlet.QuickReservationServlet.doWork(QuickReservationServlet.java:63)
After deployment on server the jsp-file will be in the root-folder.
Thanks,
Frank

Answer 1

try removing the forward slash before your jsp:
<servlet>
<servlet-name>quickCarRentalView.jsp</servlet-name>
<jsp-file>quickCarRentalView.jsp</jsp-file>
</servlet>