Example VIs produce random numbers

Hi,
I am using the 7831R FPGA board. I trying to run one of the
example VIs to see if my system is functioning properly. The Vi is the
AI-single. It is supposed to monitor one analog input. When I open
Labview, I choose the PCI-7831 device as the target. When I run the VI,
it asks me to compile it, and it takes a minute and compiles. Then I
switch the targets on the device emulator to Labview for Windows as
this creates the host VI, is this right? When I run the VI, I get
something like a rondom number generator, with values up to tens of
thousands. I set the min and maximum values to -4 and 4 , and then the
values stay under 120-ish, but still do not make sense. Did I install
my hardware/software right? Because when I was installing it there was
an error with NI-watchdod 2.1 installation. Is this important? Thanks
much, my head hurts.
Gregg

Hi Gregg,
The 7831R doesn't use watchdog timers, so the NI-Watchdog install problem shouldn't affect your application. A re-install of the drivers might take care of it though.
As for your example, you did all the correct steps leading up to running the example. After "AI-Single.vi" compiles and downloads to the FPGA, just keep it targetted to the PCI-7831R in order to run it, instead of targetting back to LabVIEW for Windows. This is actually taking real-world values, so if nothing is connected to your device the signal will be floating. (Note: this does not make use of a Host VI)
If you want to use a Host VI architecture, you are correct in that you will have to then change the target back to LabVIEW for Windows. To better understand this type of application, take a look at the shipping examples "Synchronization - Polling (FPGA)" and "Synchronization - Polling (Host)". You'll notice that all the Host VI does is call an Open VI Reference (which opens and runs the pre-compiled FPGA application, "Synchronization - Polling (FPGA)" ), and then uses Read/Write Controls to pass data back and forth from the Host to the FPGA.
Let me know if you have anymore questions.
Jeff M.
Applications Engineering
National Instruments

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Generate the random numbers

How Do I Generate Random Numbers in iWorks
Excel has the "F9" key to generate random numbers numbers don't
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Type the word "PB" into cell A6.
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Enter the function "=RANDBETWEEN(1,39)" into cell B6.
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firstly your not asking about generating random numbers, your asking how do you make a workbook recalculate new random numbers. From M$'s website:
F9
Calculates all worksheets in all open workbooks
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Message was edited by: jaxjason

Random numbers generator

i would my program to generate an int random number between 0 and "int max", how to do that?
thanks for help
Nite

True. :-) But I meant that java.security.SecureRandom
is a better source for randomnessLike I said, it all depends on the OP requirements. You can't use better in this case, IMHO.
If the OP needs this for cryptographic purpose, then yes, SecureRandom is better. But if the OP needs it for his/her dice-game, then Random will suffice.
(SecureRandom is RNG, Random is PRNG).If you mean that SecureRandom is a true random generator and Random is a pseudo random generator, you are gravely mistaken. SecureRandom is a pseudo random generator as well!
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How to generate unique random numbers

Hi All,
I am wondering whether there is already a random library or built-in function available in Java to produce some random numbers between certain ranges that are not repetitive. Let's look at a common examples as follows:
Random diceRoller = new Random();
for (int i = 0; i < 10; i++) {
int roll = diceRoller.nextInt(6) + 1;
System.out.println(roll);
}My understanding from this approach is that it allows the same number to be repeated over and over again. However, I would like to find out how to continue generating random numbers from remaining ones that haven't been generated earlier.
Using the above example to illustrate my intention:
1st random number generated - possibility of 1 - 6 showed up. Say 5 is picked.
2nd random number generated - possibility of 1, 2, 3, 4, 6 only. Say 2 is picked.
3rd random number generated - possibility of 1, 3, 4, 6 available. Say 1 is picked.
4th random number generated - possibility of 3, 4, 6 left. Say 6 is picked.
5th random number generated - possibility of 3, 4 remains. Say 4 is picked.
Any assistance would be much appreciated.
Many thanks,
Jack

htran_888 wrote:
Hi All,
I am wondering whether there is already a random library or built-in function available in Java to produce some random numbers between certain ranges that are not repetitive. Let's look at a common examples as follows:
Random diceRoller = new Random();
for (int i = 0; i < 10; i++) {
int roll = diceRoller.nextInt(6) + 1;
System.out.println(roll);
}My understanding from this approach is that it allows the same number to be repeated over and over again. However, I would like to find out how to continue generating random numbers from remaining ones that haven't been generated earlier.
Using the above example to illustrate my intention:
1st random number generated - possibility of 1 - 6 showed up. Say 5 is picked.
2nd random number generated - possibility of 1, 2, 3, 4, 6 only. Say 2 is picked.
3rd random number generated - possibility of 1, 3, 4, 6 available. Say 1 is picked.
4th random number generated - possibility of 3, 4, 6 left. Say 6 is picked.
5th random number generated - possibility of 3, 4 remains. Say 4 is picked.
Any assistance would be much appreciated.If it is your school assignment then you have the answer above (List & the lists length).
(You might want to look at Collections)

How do I generate an array of random numbers that relate to an output wave that falls within a certain frequency range?

I have been creating random numbers that I'm using within a system, the system is working fine, but now I have realised that the random numbers must be outputted to speakers in such a way as to filter out all but a low frequency range.
I was thinking about generating a dither signal with a bandpass filter, but could not get it to give me out a full array of 250 values which I could then manipulate.
The sampling frequency of the output is 200Hz and the 250 data points must fall within the 0-100Hz range.
Another course of action I am considering is to use an FFT and an inverse FFT to get the data that I'm looking for, but I'm fair
ly inexperienced with using labVIEW and can't quite get it to work.
Thanks for the help,
Hank.

As you may already know, in the Functions palette/Analysis VIs/Filters VIs are VIs for filtering. There are also some examples for using these filters under Examples/Analysis/fltrxmpl. You may find some of these are related to your situation, especially for filtering out the higher values.
An option is to simply output the random values to a Comparison/"less than or equal" function, where only values <= to 100 would be sent to an array which is in a For loop. Use the iteration counter of the For loop to count up to 250, at which time you would pass the whole array to your next node. This would let you have 250 values between 0 and 100 for your final array.
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How to generate random numbers that doesnt contain characters?

How do we generate random numbers in ESB ROuting Service/ XSL transformation that does not contain characters. I have been using "orcl:generate-guid()" , but it contains some characters, so, I substring it to get only numbers. I dont want to take this risk and in future, my substring itself may contain characters.
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Thanks,

If the goal is to have a pseudo random number then consider using the translate function to replace the occurances of the A - E characters with another digit. For example:
translate(orcl:generate-guid(),'0123456789ABCDEF','0123456789123456')
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I would perform a large sample test to see just how unique the values end up being.
As for why hex is used, well GUID's are most commonly written in text as a sequence of hexadecimal digits such as: 3F2504E0-4F89-11D3-9A0C-0305E82C3301. i.e. 128 bits represented in 32 characters formatted into 5 sections.
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I am trying to generate an array of 30 random numbers. after every 5 readings a new vi should open and tell the user that 5 readings has been completed. and again carry on with the generation of array.

since i do not have a transducer now, i am currently generating an array of 30 random numbers. after every 5 readings a warning should be given to the user that 5 readngs are complete. this cycle should repeat. the array size is 30.
please help me out, waiting for reply asap.
once i have the transducer, i will be taking 30 analog samples and then after every 5 smaples that wraning will be displaye din a new VI
Solved!
Go to Solution.

Use a while loop with a time delay representing your sampling period.
Use the count terminal to check if equals 4, so 4th iteration=5th sample.
Use a case structure. The true case will only be executed on the 4th iteration.
In the true case place a subVI with your desired message in the front panel. Go to the VI properties window and set "open front panel when called".
The closing condition of the warnign is not giving in your description.
Consider that rather than usign a subvi for this, you could use the "One/Two/Three button dialog" or "display message" vis at the "dialog and user interface" pallete.
Please give it a try and send your own VI. Do not expect us to provide a working solution.
Regards,

How can you generate Multiple random numbers from 1 to 49?

I am very new at programming with the iPhone SDK and I need some help with a project I am working on. What I want to do is set up a window with 6 labels and 1 button. When the user clicks the button, the program will populate 6 randomized numbers each ranging from 1 to 49, and then place each of 6 numbers in a label. But each time the program ends and starts again the numbers cannot be the same, and also when the user clicks the button, no label can have the same number twice, so for example. If label 1 had the number 10, the other 5 labels cannot have that number until the button is clicked again. I know how to set up the interface, I just need the code. I would so greatly appreciate someone's help in this matter. I have been trying to do this for days and I cannot figure it out. Possibly someone who knows tons about Objective C programming can help me!
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One simple way to get the random indices needed is to extract six random bytes from Randomization Services using SecRandomCopyBytes, then loop over them, using the modulo operator (%) to select an index within the size of the array.
And no, I'm not going to write your code for you. If I was going to do that, I could package and sell the app myself.

Problem with Purchase Order creation with Random numbers .

Hi Experts
Currently i am facing an issue with Bapi BAPI_PO_CREATE1 to create Purchase order with random numbers for example items 1, 3,5.
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Hi Neha,
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Review the SAP note 365604 and 493900 for more
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Random numbers without duplicates

Hello,
I'm having trouble locating an explained example for selecting a set of random numbers without duplicates. Specifically, I'm working on this example from Ivor Horton's Beginning Java, chapter 3.
3. A lottery program requires that you select six different numbers from the integers 1-49. Write a program to do this for you and generate five sets of entries.
This is not homework, I'm just trying to teach myself Java to eventually work my way up to servlets and JSPs.
This is what I have so far. I tried to use array sorting but it didn't work (the first three numbers in my entries was always 0), so I commented out that part. I've included sample output after the code. I don't necessarily need the exact code although that would be nice; I just need at least an explanation of how to go about making sure that if a number has been picked for an entry, not to pick it again.
Thanks for any help,
javahombre
package model;
import java.util.Random;
import java.lang.Math.*;
import java.util.Arrays;
public class Lottery {
public static void main(String[] args) {
// Lottery example.
// We need the following data:
// - An integer to store the lottery number range (in this case 59).
// - A mechanism to choose a number randomly from the range.
// - An array to store the entries (6 different numbers per entry).
// - A loop to generate 5 sets of entries.
int numberRange = 59;
int currentPick = 0;
int[] entry = new int[6]; // For storing entries.
//int slot = -1; // For searching entry array.
Random rn = new Random();
for (int n = 0; n < 5; n++)
// Generate entry.
for (int i = 0; i < 6; i++)
currentPick = 1 + Math.abs(rn.nextInt()) % numberRange;
//Arrays.sort(entry);
//slot = Arrays.binarySearch(entry, currentPick);
//System.out.println("i: " + i + "\t| slot: " + slot + "\t| pick: " + currentPick + "\t| compare: " + (slot < 0));
// Add the current pick if it is not already in the entry.
//if (slot < 0)
entry[i] = currentPick;
System.out.println("pick entered: " + currentPick);
// Output entry.
System.out.print("Entry " + (n + 1) + ": ");
for (int j = 0; j < 6; j++)
System.out.print(entry[j] + "\t");
System.out.println("");
// Set the array contents back to 0 for next entry.
Arrays.fill(entry,0);
Sample output (notice duplicates, as in Entry 3):
pick entered: 11
pick entered: 29
pick entered: 33
pick entered: 8
pick entered: 14
pick entered: 54
Entry 1: 11     29     33     8     14     54
pick entered: 51
pick entered: 46
pick entered: 25
pick entered: 30
pick entered: 44
pick entered: 22
Entry 2: 51     46     25     30     44     22
pick entered: 49
pick entered: 39
pick entered: 9
pick entered: 6
pick entered: 46
pick entered: 46
Entry 3: 49     39     9     6     46     46
pick entered: 23
pick entered: 26
pick entered: 2
pick entered: 21
pick entered: 51
pick entered: 32
Entry 4: 23     26     2     21     51     32
pick entered: 27
pick entered: 48
pick entered: 19
pick entered: 10
pick entered: 8
pick entered: 18
Entry 5: 27     48     19     10     8     18

NOTE: the array reference to [ i ] seems to be misinterpreted as italics by the posting form. I've reposted the message here, hopefully it will show the code properly.
Thanks again,
javahombre
Hello,
I'm having trouble locating an explained example for
selecting a set of random numbers without duplicates.
Specifically, I'm working on this example from Ivor
Horton's Beginning Java, chapter 3.
3. A lottery program requires that you select six
different numbers from the integers 1-49. Write a
program to do this for you and generate five sets of
entries.
This is not homework, I'm just trying to teach myself
Java to eventually work my way up to servlets and
JSPs.
This is what I have so far. I tried to use array
sorting but it didn't work (the first three numbers in
my entries was always 0), so I commented out that
part. I've included sample output after the code. I
don't necessarily need the exact code although that
would be nice; I just need at least an explanation of
how to go about making sure that if a number has been
picked for an entry, not to pick it again.
Thanks for any help,
javahombre
package model;
import java.util.Random;
import java.lang.Math.*;
import java.util.Arrays;
public class Lottery {
public static void main(String[] args) {
// Lottery example.
// We need the following data:
// - An integer to store the lottery number range (in
this case 59).
// - A mechanism to choose a number randomly from the
range.
// - An array to store the entries (6 different
numbers per entry).
// - A loop to generate 5 sets of entries.
int numberRange = 59;
int currentPick = 0;
int[] entry = new int[6]; // For storing entries.
//int slot = -1; // For searching entry
array.
Random rn = new Random();
for (int n = 0; n < 5; n++)
// Generate entry.
for (int i = 0; i < 6; i++)
currentPick = 1 + Math.abs(rn.nextInt()) %
numberRange;
//Arrays.sort(entry);
//slot = Arrays.binarySearch(entry, currentPick);
//System.out.println("i: " + i + "\t| slot: " + slot +
"\t| pick: " + currentPick + "\t| compare: " + (slot <
0));
// Add the current pick if it is not already in the
entry.
//if (slot < 0)
entry[ i ] = currentPick;
System.out.println("pick entered: " + currentPick);
// Output entry.
System.out.print("Entry " + (n + 1) + ": ");
for (int j = 0; j < 6; j++)
System.out.print(entry[j] + "\t");
System.out.println("");
// Set the array contents back to 0 for next entry.
Arrays.fill(entry,0);
Sample output (notice duplicates, as in Entry 3):
pick entered: 11
pick entered: 29
pick entered: 33
pick entered: 8
pick entered: 14
pick entered: 54
Entry 1: 11     29     33     8     14     54
pick entered: 51
pick entered: 46
pick entered: 25
pick entered: 30
pick entered: 44
pick entered: 22
Entry 2: 51     46     25     30     44     22
pick entered: 49
pick entered: 39
pick entered: 9
pick entered: 6
pick entered: 46
pick entered: 46
Entry 3: 49     39     9     6     46     46
pick entered: 23
pick entered: 26
pick entered: 2
pick entered: 21
pick entered: 51
pick entered: 32
Entry 4: 23     26     2     21     51     32
pick entered: 27
pick entered: 48
pick entered: 19
pick entered: 10
pick entered: 8
pick entered: 18
Entry 5: 27     48     19     10     8     18

Random Numbers with Objective-C

Hey Guys,
I'm creating a blackjack program and I need to randomize 52 numbers, ensuring not to repeat any number.
I know I can use the following to generate a number between 1-52, but I need the to eliminate the possibility of the same card being drawn twice:
cardNumber = arc4random() % 52 + 1;
Any idea on how I would do this? Code example would be helpful!
Thanks,
Justin

Hi Justin -
Justin Carman wrote:
I'm creating a blackjack program and I need to randomize 52 numbers, ensuring not to repeat any number.
I would initialize an array (the deck) with the card values, then use your random number as the index into the array. Each time a card is chosen just remove its value from the deck and decrement the modulus of the random numbers. NSMutableArray makes a nice deck for this purpose since its count is automatically decremented each time a value is removed. E.g.:
// AppController.m
#import "AppController.h"
#define N_DECK 52
@implementation AppController
@synthesize cardArray; // @property (nonatomic, retain) NSMutableArray *cardArray;
- (void)applicationDidFinishLaunching:(NSNotification *)aNotification {
self.cardArray = [NSMutableArray arrayWithCapacity:N_DECK];
- (IBAction)newDeck:(id)sender {
[cardArray removeAllObjects];
for (int i = 0; i < N_DECK; i++) {
[cardArray addObject:[NSNumber numberWithInt:i+1]];
// NSLog(@"newDeck: cardArray=%@", cardArray);
- (IBAction)getCard:(id)sender {
// check the array
int count = [cardArray count];
assert(count <= N_DECK);
if (count < 1) {
NSLog(@"getCard: Empty deck");
return;
NSLog(@"getCard: count=%d", count);
// select a card from the array
int index = arc4random() % count;
NSNumber *selected = [cardArray objectAtIndex:index];
NSLog(@"getCard: index=%d selected=%@", index, selected);
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int card = [selected intValue];
NSLog(@"getCard: card=%d", card);
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[cardArray removeObjectAtIndex:index];
// note selected NSNumber object has been released
// NSLog(@"getCard: cardArray=%@", cardArray);
@end
For extra credit you might want to wrap the above in a custom Deck class.
Hope that helps!
- Ray

Array of unique random numbers - help?

basically, i'm trying to create a BINGO card.
i stared learning Java a week ago and am finding it easy to learn and use....at least so far.
my instructor gave me the assignment to created a BINGO card. so i used the system.out.format command to make 5 tab fields, 8 spaces each ("%8s %8s %8s %8s %8s", "B", "I", "N", "G", "O"). although the assignment only wanted me to think numbers out of thin air, just to use as examples, i went above and beyond with the idea to make a BINGO card generator that could actually function.
then i started the random number sequences, using the Math.random() command. all told, there are 24 of these in the program, one for each number on a bingo card. the field in the middle is the FREE space, so it has no Math.random command.
in BINGO, each letter (one of my five tab fields) can have a number in ranges of 15. B is 1 to 15, I is 16 to 30, etc. it looks similar to this:
B I N G O
9 19 39 57 66
3 28 32 51 74
3 29 FREE 46 70
14 28 43 55 67
9 24 35 59 62
as you can tell, i'm having trouble with actually making unique random numbers so that none repeat.
is there a command or string or something to help me accomplish this?

The best way I've come up with is to use an object to store the numbers that implements Collection--like ArrayList...
Then you load it with the range of numbers that you want and call, shuffle() on the object, that will randomize your range of numbers and then you can choose the quantity you want from the storage object. So let's say you need 25 number in the range of 1 to 100:
Add the numbers (you have to use classes so I would do Integers) 1 to 100;
call shuffle()
pull back the first 25 numbers
This will guarantee that each number is distinct and in a random order.
If you need multiple sheets populated, you can just call shuffle() between population of each sheet.
package Junk;
import java.util.ArrayList;
import java.util.Collections;
class Junk{
private ArrayList<Integer> l;
Junk(){
    l = new ArrayList<Integer>();
public void loadList(int s, int e){
    for(int i=s; i<=e; i++){
      l.add(new Integer(i));
public void randomizeList(){
    Collections.shuffle(l);
public void printList5(){
    for(int i=0; i<5; i++){
      System.out.println(l.get(i));
public static void main(String[] args){
    Junk j = new Junk();
    j.loadList(10,99);
    j.randomizeList();
    j.printList5();
    System.out.println();
    j.randomizeList();
    j.printList5();
}

How do I generate random numbers from a list of numbers without repeating any number

I am trying to generate a list of random numbers without any repeating numbers. For example say the list is from 1 to 15, how do I randomly generate a list of numbers using each number only once?

pb,
You can build a randomizer by making a 2-column table with 15 rows. In Column A, Fill with the numbers 1 to 15. In column B Fill with RAND(). Then sort on Column B. There will now be a randomized list of the numbers from 1 to 15 in Column A. You can copy this random list and use it in your application.
Jerry

Random Numbers Question

I'm working from a chapter in Gary Rosenzweig's
ActionScript 3.0 Game Programming University. In this
example 36 random cards are created and placed on the stage. I
understand most of the code except for this line:
thisCard.cardFace = cardList[r]; The line above the one I
just mentioned assigns a random value to r and I don't understand
how the computer knows it's not assigning a value to cardFace that
already exists? Since this function is iterating several times
wouldn't it be possible for one of the random numbers to be
repeated?
Joe

yes, one card is deleted. that card is thisCard.cardFace.
it's just like dealing cards. when you deal an ace of clubs
to someone, that card is removed from the deck. any card dealt
after that is randomly selected from the remaining cards.
the code above is more akin to organizing a deck of cards
with the ace of clubs on top, king of clubs beneath, queen of
clubs,...,2clubs,ace of diamonds,...,2diamonds,...,2spades. then
pick a random number between 1 and 52, select that card number and
remove it from the deck. now pic a random number between 1 and 51
and remove that from the dect. etc.

FPGA 20 random numbers

Hello,
I have NI PXIe-7966R FPGA module and i want to generate 20 random numbers with specified distribution. Now i have random number generator with uniform distribuiton and i have quantile function for my distribution in the form of 1000 point array. It takes a lot of logical blocks of FPGA if Im trying to solve this problem with 20 lookup tables or 20 memory blocks with my quantile function. Can you help me to advice?

Theres an example on NI.com that uses the method outlined in this paper from xilinx.

Example VIs produce random numbers

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