Exists and not exists

hi my requirement is
id column exists in all tables means
view v , tables A,B,C
i want to copmare like..
the id's which are available in V and not available in the three tables A,B,C
is this correct one or any simplify
select id from v
where not exists(select id from a where a.id=v.id)
and not exists(select id from b where b.id=v.id)
and not exists(select id from c where c.id=v.id)
thanks

bpat wrote:
You are welcome.
Just one small comment on the solution, since we do not require any sort of sorting, I would prefer to use UNION ALL.Bpat:
I would probably test it both ways. Because of the minus, there is going to be two sort uniques in there somewhere. Each half of the minus has to be sorted and distincted before the minus can be done.
I used your sample to generate real tables, just to eliminate the effects of the hierarchical query, and it looks to me like, at least for a small sample set, union or union all are exactly the same, right down to the plan_id.
SQL> SELECT id
2 FROM t_data1 t1
3 minus
4 (select id from t_data2
5   union
6   select id from t_data3
7   union
8   select id from t_data4);
Execution Plan
Plan hash value: 2968485990
| Id | Operation            | Name    | Rows | Bytes | Cost (%CPU)| Time     |
|   0 | SELECT STATEMENT     |         |    20 |   650 |    12 (84)| 00:00:01 |
|   1 | MINUS               |         |       |       |            |          |
|   2 |   SORT UNIQUE        |         |    20 |   260 |     3 (34)| 00:00:01 |
|   3 |    TABLE ACCESS FULL | T_DATA1 |    20 |   260 |     2   (0)| 00:00:01 |
|   4 |   SORT UNIQUE        |         |    20 |   650 |    12 (84)| 00:00:01 |
|   5 |    UNION-ALL         |         |       |       |            |          |
|   6 |     TABLE ACCESS FULL| T_DATA2 |     5 |    65 |     2   (0)| 00:00:01 |
|   7 |     TABLE ACCESS FULL| T_DATA3 |    10 |   130 |     2   (0)| 00:00:01 |
|   8 |     TABLE ACCESS FULL| T_DATA4 |    15 |   195 |     2   (0)| 00:00:01 |
Note
   - dynamic sampling used for this statement
Statistics
          0 recursive calls
          0 db block gets
         12 consistent gets
          0 physical reads
          0 redo size
        588 bytes sent via SQL*Net to client
        488 bytes received via SQL*Net from client
          2 SQL*Net roundtrips to/from client
          2 sorts (memory)
          0 sorts (disk)
          5 rows processed
SQL> SELECT id
2 FROM t_data1 t1
3 minus
4 (select id from t_data2
5   union all
6   select id from t_data3
7   union all
8   select id from t_data4);
Execution Plan
Plan hash value: 2968485990
| Id | Operation            | Name    | Rows | Bytes | Cost (%CPU)| Time     |
|   0 | SELECT STATEMENT     |         |    20 |   650 |    12 (84)| 00:00:01 |
|   1 | MINUS               |         |       |       |            |          |
|   2 |   SORT UNIQUE        |         |    20 |   260 |     3 (34)| 00:00:01 |
|   3 |    TABLE ACCESS FULL | T_DATA1 |    20 |   260 |     2   (0)| 00:00:01 |
|   4 |   SORT UNIQUE        |         |    20 |   650 |    12 (84)| 00:00:01 |
|   5 |    UNION-ALL         |         |       |       |            |          |
|   6 |     TABLE ACCESS FULL| T_DATA2 |     5 |    65 |     2   (0)| 00:00:01 |
|   7 |     TABLE ACCESS FULL| T_DATA3 |    10 |   130 |     2   (0)| 00:00:01 |
|   8 |     TABLE ACCESS FULL| T_DATA4 |    15 |   195 |     2   (0)| 00:00:01 |
Note
   - dynamic sampling used for this statement
Statistics
          0 recursive calls
          0 db block gets
         12 consistent gets
          0 physical reads
          0 redo size
        588 bytes sent via SQL*Net to client
        488 bytes received via SQL*Net from client
          2 SQL*Net roundtrips to/from client
          2 sorts (memory)
          5 rows processedEven a simple two table minus gets 2 sorts.
SQL> SELECT id
2 FROM t_data1 t1
3 minus
4 select id from t_data2;
15 rows selected.
Execution Plan
Plan hash value: 1776821228
| Id | Operation           | Name    | Rows | Bytes | Cost (%CPU)| Time     |
|   0 | SELECT STATEMENT    |         |    20 |   325 |     6 (67)| 00:00:01 |
|   1 | MINUS              |         |       |       |            |          |
|   2 |   SORT UNIQUE       |         |    20 |   260 |     3 (34)| 00:00:01 |
|   3 |    TABLE ACCESS FULL| T_DATA1 |    20 |   260 |     2   (0)| 00:00:01 |
|   4 |   SORT UNIQUE       |         |     5 |    65 |     3 (34)| 00:00:01 |
|   5 |    TABLE ACCESS FULL| T_DATA2 |     5 |    65 |     2   (0)| 00:00:01 |
Note
   - dynamic sampling used for this statement
Statistics
          0 recursive calls
          0 db block gets
          6 consistent gets
          0 physical reads
          0 redo size
        668 bytes sent via SQL*Net to client
        488 bytes received via SQL*Net from client
          2 SQL*Net roundtrips to/from client
          2 sorts (memory)
          0 sorts (disk)
         15 rows processedJohn

Similar Messages

Exist and not Exist

Hello,
I am doing following validation, when user does not have admin privileges, it should display error page - "User does not have admin privileges".
SELECT 1 FROM apex_workspace_apex_users WHERE
user_name =:P6_USERNAME
AND is_admin = 'Yes'
if
I am confused over the use of "Exist" and "Not Exist" in the condition. Can you please help me out with this.

I am confused over the use of "Exist" and "Not Exist" in the condition. Can you please help me out with this.The validation is successful if the query meets the condition:
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- "Not Exists": succeeds if the query returns no rows
So for:
SELECT 1 FROM apex_workspace_apex_users WHERE
user_name =:P6_USERNAME
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(Please update your forum profile with a better handle than "user9065603")

Decode for EXISTS and NOT EXISTS conditions

Hello all,
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DECODE will not replace part of the query. Functions don't work that way.
(It won't work if you put EXISTS and NOT EXISTS in quotes, either.)
What you want is something like
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SELECT 1
FROM dual
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details and options to be found here: https://boc.sdn.sap.com/node/20046

Not in and Not Exists

Hi everyone,
I need some explanation on why the index is not being used in one of my queries.
Here are the queries:
SELECT COUNT (1)
FROM (SELECT hdr.ALLOC_HDR_SEQ_NBR hdrnbr
FROM sm_vda_allocation_header hdr
INNER JOIN
sm_vda_type vdatype
ON hdr.vda_typ_cd = vdatype.vda_typ_cd
WHERE
vdatype.SAP_POST_TYP_CD = 'JE'
AND vdatype.vda_alloc_flg = 'Y'
AND hdr.vda_liab_flg IS NULL
AND hdr.sap_extrct_dt IS NULL
AND hdr.ALLOC_HDR_SEQ_NBR NOT IN
(SELECT alloc_hdr_seq_nbr
FROM sm_vda_allocation_detail));
return 0 rows.
explain plan::
Plan
SELECT STATEMENT CHOOSECost: 671 Bytes: 26 Cardinality: 1
     8 SORT AGGREGATE Bytes: 26 Cardinality: 1
          7 HASH JOIN Cost: 671 Bytes: 293,254 Cardinality: 11,279
               1 TABLE ACCESS FULL SM_APPL.SM_VDA_TYPE Cost: 5 Bytes: 56 Cardinality: 7
               6 MERGE JOIN ANTI Cost: 665 Bytes: 281,106 Cardinality: 15,617
                    3 TABLE ACCESS BY INDEX ROWID SM_APPL.SM_VDA_ALLOCATION_HEADER Cost: 496 Bytes: 241,860 Cardinality: 20,155
                         2 INDEX FULL SCAN UNIQUE SM_APPL.SM_VDA_ALLOCATION_HEADER_PK Cost: 438 Cardinality: 20,450
                    5 SORT UNIQUE Cost: 169 Bytes: 417,480 Cardinality: 69,580
                         4 INDEX FAST FULL SCAN NON-UNIQUE SM_APPL.SM_VDA_ALLOCATION_DETAIL_FK_I Cost: 86 Bytes: 417,480 Cardinality: 69,580
2nd query::
SELECT COUNT (1)
FROM (SELECT hdr.ALLOC_HDR_SEQ_NBR hdrnbr
FROM sm_vda_allocation_header hdr
INNER JOIN
sm_vda_type vdatype
ON hdr.vda_typ_cd = vdatype.vda_typ_cd
WHERE
vdatype.SAP_POST_TYP_CD = 'JE'
AND vdatype.vda_alloc_flg = 'Y'
AND hdr.vda_liab_flg IS NULL
AND hdr.sap_extrct_dt IS NULL
AND NOT exists
(SELECT 1
FROM sm_vda_allocation_detail b where
hdr.ALLOC_HDR_SEQ_NBR = b.ALLOC_HDR_SEQ_NBR));
explain plan:::
Plan
SELECT STATEMENT CHOOSECost: 831 Bytes: 20 Cardinality: 1
     6 SORT AGGREGATE Bytes: 20 Cardinality: 1
          5 FILTER
               3 HASH JOIN Cost: 828 Bytes: 14,560 Cardinality: 728
                    1 TABLE ACCESS FULL SM_APPL.SM_VDA_TYPE Cost: 5 Bytes: 56 Cardinality: 7
                    2 TABLE ACCESS FULL SM_APPL.SM_VDA_ALLOCATION_HEADER Cost: 822 Bytes: 12,096 Cardinality: 1,008
               4 INDEX RANGE SCAN NON-UNIQUE SM_APPL.SM_VDA_ALLOCATION_DETAIL_FK_I Cost: 3 Bytes: 90 Cardinality: 15
In the 2nd query with NOT EXISTS, I see FULL table scan for SM_APPL.SM_VDA_ALLOCATION_HEADER
In the first query, the index is used in the same place:
2 INDEX FULL SCAN UNIQUE SM_APPL.SM_VDA_ALLOCATION_HEADER_PK Cost: 438 Cardinality: 20,450
ALLOC_HDR_SEQ_NBR is a primary key column.
Actually NOT IN and NOT EXISTS both used index for the second inner table (SM_APPL.SM_VDA_ALLOCATION_DETAIL).
But NOT exists is not using the index for the first table but not in is using.
how come.

872605 wrote:
Hi everyone,
I need some explanation on why the index is not being used in one of my queries.
Here are the queries:
SELECT COUNT (1)
FROM (SELECT hdr.ALLOC_HDR_SEQ_NBR hdrnbr
FROM sm_vda_allocation_header hdr
INNER JOIN
sm_vda_type vdatype
ON hdr.vda_typ_cd = vdatype.vda_typ_cd
WHERE
vdatype.SAP_POST_TYP_CD = 'JE'
AND vdatype.vda_alloc_flg = 'Y'
AND hdr.vda_liab_flg IS NULL
AND hdr.sap_extrct_dt IS NULL
AND hdr.ALLOC_HDR_SEQ_NBR NOT IN
(SELECT alloc_hdr_seq_nbr
FROM sm_vda_allocation_detail));
return 0 rows.
explain plan::
Plan
SELECT STATEMENT CHOOSECost: 671 Bytes: 26 Cardinality: 1
     8 SORT AGGREGATE Bytes: 26 Cardinality: 1
          7 HASH JOIN Cost: 671 Bytes: 293,254 Cardinality: 11,279
               1 TABLE ACCESS FULL SM_APPL.SM_VDA_TYPE Cost: 5 Bytes: 56 Cardinality: 7
               6 MERGE JOIN ANTI Cost: 665 Bytes: 281,106 Cardinality: 15,617
                    3 TABLE ACCESS BY INDEX ROWID SM_APPL.SM_VDA_ALLOCATION_HEADER Cost: 496 Bytes: 241,860 Cardinality: 20,155
                         2 INDEX FULL SCAN UNIQUE SM_APPL.SM_VDA_ALLOCATION_HEADER_PK Cost: 438 Cardinality: 20,450
                    5 SORT UNIQUE Cost: 169 Bytes: 417,480 Cardinality: 69,580
                         4 INDEX FAST FULL SCAN NON-UNIQUE SM_APPL.SM_VDA_ALLOCATION_DETAIL_FK_I Cost: 86 Bytes: 417,480 Cardinality: 69,580
2nd query::
SELECT COUNT (1)
FROM (SELECT hdr.ALLOC_HDR_SEQ_NBR hdrnbr
FROM sm_vda_allocation_header hdr
INNER JOIN
sm_vda_type vdatype
ON hdr.vda_typ_cd = vdatype.vda_typ_cd
WHERE
vdatype.SAP_POST_TYP_CD = 'JE'
AND vdatype.vda_alloc_flg = 'Y'
AND hdr.vda_liab_flg IS NULL
AND hdr.sap_extrct_dt IS NULL
AND NOT exists
(SELECT 1
FROM sm_vda_allocation_detail b where
hdr.ALLOC_HDR_SEQ_NBR = b.ALLOC_HDR_SEQ_NBR));
explain plan:::
Plan
SELECT STATEMENT CHOOSECost: 831 Bytes: 20 Cardinality: 1
     6 SORT AGGREGATE Bytes: 20 Cardinality: 1
          5 FILTER
               3 HASH JOIN Cost: 828 Bytes: 14,560 Cardinality: 728
                    1 TABLE ACCESS FULL SM_APPL.SM_VDA_TYPE Cost: 5 Bytes: 56 Cardinality: 7
                    2 TABLE ACCESS FULL SM_APPL.SM_VDA_ALLOCATION_HEADER Cost: 822 Bytes: 12,096 Cardinality: 1,008
               4 INDEX RANGE SCAN NON-UNIQUE SM_APPL.SM_VDA_ALLOCATION_DETAIL_FK_I Cost: 3 Bytes: 90 Cardinality: 15
In the 2nd query with NOT EXISTS, I see FULL table scan for SM_APPL.SM_VDA_ALLOCATION_HEADER
In the first query, the index is used in the same place:
2 INDEX FULL SCAN UNIQUE SM_APPL.SM_VDA_ALLOCATION_HEADER_PK Cost: 438 Cardinality: 20,450
ALLOC_HDR_SEQ_NBR is a primary key column.
Actually NOT IN and NOT EXISTS both used index for the second inner table (SM_APPL.SM_VDA_ALLOCATION_DETAIL).
But NOT exists is not using the index for the first table but not in is using.
how come.WHY MY INDEX IS NOT BEING USED
http://communities.bmc.com/communities/docs/DOC-10031
http://searchoracle.techtarget.com/tip/Why-isn-t-my-index-getting-used
http://www.orafaq.com/tuningguide/not%20using%20index.html

Exist and no exists

Hello,
i need help with this query.
how can i re-write without using the not exists.
here is my query:
insert into rel (id)
select id from test a where bo ='QW' and not exists (select 1 from testing where id = a.id);
Thanks.

789287 wrote:
i would like to see if i can use not in or some other way to produce the same results.Its always good to have multiple ways of doing things in case one doesn't work for some reason!
NOT/EXISTS is probably your best bet for performance if the subquery is properly indexed, but other options include IN and INTERSECT/MINUS (depending on circumstances), something like (untested)
insert into rel (id)
select id from test a
where bo ='QW'
and id not IN (
select id from testing where id = a.id
insert into rel (id)
select id from test a
MINUS
select id from testingINTERSECT can be used to simulate EXISTS/IN but only when one value is selected. Similarlary MINUS can be used to simulate NOT EXISTS/IN.
Any such workarounds must be carefully tested to ensure that the correct results are returned. I would probably stick with IN/EXISTS for simplicity unless one of the other methods worked better for performance or other reasons.

How to remove devices shown in RME and not existing in DCR?

I have problem with some devices (in fact IP addresses) that was discovered and used by RME in the past but are not reachable anymore. They spoil statistics in RME (collection of inventory and configuration) however they do not exist in DCR. Do you have any ideas how to get rid of them?
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Tune the query with join and not exists

This is on 10g R2.
I have a query similar to :
Select A.*, C.*
From A inner join B on A.id = B.id
Left join C on A.kid = C.kid
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(select * from D where A.fid = D.fid and A.stat = 2);
I want avoiding to use the NOT EXISTS in the last part of the query
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from baandb.ttfacr200201 a
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call     count       cpu    elapsed       disk      query    current        rows
Parse        1      0.00       0.00          0          0          0           0
Execute      1      0.01       0.01          0          0          0           0
Fetch        5      1.06      52.11      29925      45943          0          54
total        7      1.07      52.12      29925      45943          0          54
Misses in library cache during parse: 1
Misses in library cache during execute: 1
Optimizer mode: ALL_ROWS
Parsing user id: 31
Rows     Row Source Operation
     54 HASH JOIN RIGHT ANTI (cr=45943 pr=29925 pw=0 time=2317005 us)
   9957   INDEX FAST FULL SCAN TCISLI205201$IDX1 (cr=39 pr=0 pw=0 time=54 us)(object id 16639)
10067   NESTED LOOPS OUTER (cr=45904 pr=29925 pw=0 time=68531937 us)
10067    HASH JOIN (cr=35837 pr=29925 pw=0 time=68471521 us)
10420     TABLE ACCESS FULL TTFACR200201 (cr=2424 pr=0 pw=0 time=20894 us)
33156     TABLE ACCESS FULL TTFGLD106201 (cr=33413 pr=29925 pw=0 time=117767552 us)
     51    INDEX UNIQUE SCAN TTFGLD910201$IDX1 (cr=10067 pr=0 pw=0 time=53177 us)(object id 20402)
OVERALL TOTALS FOR ALL NON-RECURSIVE STATEMENTS
call     count       cpu    elapsed       disk      query    current        rows
Parse        2      0.00       0.00          0          0          0           0
Execute      3      0.02       0.02          0          0          0           0
Fetch        6      1.06      52.11      29925      45943          0          55
total       11      1.08      52.14      29925      45943          0          55

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OK, i create a directory i have read/write permissions on the directory, but still even if the file exists its bringing back the result as if it doesnt i need help with this...
set serveroutput on
DECLARE
fexists    BOOLEAN;
flen NUMBER;
bsize NUMBER;
BEGIN
sys.utl_file.fgetattr('TMP_LOCATION', 'test.txt', fexists, flen, bsize);
IF fexists THEN
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ELSE
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REWARDS: Please remember to mark helpful or correct posts on the forum, not just for my answers but for everyone! :)

How to use EXISTS or NOT EXISTS in analysis

Hi all,
I'm using OBIEE 11g. My question is how to use the functionality of SQL - EXISTS/ NOT EXISTS? I have a model where i have 2 fact tables . When i select from the first fact in some circumstances i want to anti-join the other fact table. Let us consider that the two fact tables are big enough /around 300mln of records/. Any ideas?
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Stop asking these stupid vague questions and do some of your own research.
Start here:
http://www.regular-expressions.info/
http://java.sun.com/j2se/1.5.0/docs/api/java/util/regex/Pattern.html

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What is the difference when you use these statements when evaluating whether one tables differences to another. I thought they were supposed to act the same.

The MINUS query returns all rows in the first query that are not returned in the second query.
Each SQL statement within the MINUS query must have the same number of fields in the result sets with similar data types.
The EXISTS condition is considered "to be met" if the subquery returns at least one row.
The EXISTS condition can also be combined with the NOT operator

How to display id exist or not exist ?

For example
I have a students table with the fields student_id,student_name,student_email. I need to write a function and passing a student id and to show the output as
Student_id Exist
Student_id doesn't exist
Please help me

Hi,
You can do something like this:
CREATE OR REPLACE FUNCTION student_exist
( in_student_id IN student.student_id%TYPE
RETURN VARCHAR2
AS
    return_val     VARCHAR2 (20);
BEGIN
    SELECT MIN ('Exist')
    INTO    return_val
    FROM    students
    WHERE   studeent_id     = in_student_id;
    RETURN NVL ( return_val
                  , 'Doesn''t exist'
END student_exist;
SHOW ERRORSA function like this might be convenient, but it will be slow to use in SQL statements. Outer-joining the student table, or using scalar sub-queries, would be faster.
I hope this answers your question.
If not, post a little sample data (CREATE TABLE and INSERT statements, relevant columns only) for all the tables involved, and the results you want from that data.
Explain, using specific examples, how you get those results from that data.
Always say what version of Oracle you're using (e.g. 11.2.0.2.0).
See the forum FAQ {message:id=9360002}

How check on the WS - exist or not exist InventoryJob ?

From The C1 create XP_Inventory politic and apply it to the WS.
Use time shedule:
Tusday between 13:00...16:00 , System, below normal prior.
at the 12:45 WS was rebooted (reboot | log in to the NW| reboot again | log
in to the NW)
But i do not see any info about WS in the Tree. See only WS object without
Minimal Information of the Workstation.
What and where i can check on the WS for check :
1 - get WS this Job for inventory ?
2 - run WS this Job or no ?
3 - debug file for Inventory on the WS ?
Serg

Wed, 06 Dec 2006 09:09:12 +0000, Marcus Breiden
> On Tue, 05 Dec 2006 15:20:51 GMT, Serg wrote:
>
>> Tusday between 13:00...16:00 , System, below normal prior.
>
> did you select random spread for this time too?
>
> if yes, the inventory will start sometime between 13:00 and 16:00..
>
> so let's say you start working on 8:00, the wks picks 14:35 to run
> inventory and you shut down at 14:20... no inventory done...
>
> you start the machine again at 14:25, the wks picks 13:05, already in the
> past.... no inventory done..
For test i shedule at this morning (wedn. between 11:10..16:30) and as i
see - not inventory..
How check on the WS - ws get this job or no ?
Serg

NOT EXISTS - not working

Dear all,
I have 3 tables say A1000, B1000, C1000
create table A1000(a number);
create table B1000(a number);
create table C1000(a number);
With below values:
insert into A1000 values(1)
insert into B1000 values(1)
insert into C1000 values(2)
My Query:
SELECT a.a FROM a1000 a, b1000 b
WHERE a.a=b.a
AND NOT EXISTS (SELECT a FROM C1000)
Since both the tables a1000 & b1000 has matching records, I am expceting one row from A1000. But the query is not returning any row.
Even though table C1000 has one record with value as 2, it should not affect the result set right?
Regards
Natarajan M

it should not affect the result set right?Right, when you tell Oracle the right thing:
SQL> select a.a
2 from   a1000 a
3 ,      b1000 b
4 where a.a = b.a
5 and not exists ( select null   --< don't select anything here
6                   from   c1000 c
7                   where c.a = a.a
8                 );
         A
         1
1 row selected.The fact that you selected 'a' (without any alias) makes me think you treat EXISTS a bit like IN, but they differ.
See:
http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:442029737684
http://asktom.oracle.com/pls/asktom/f?p=100:11:3637710709480187::::P11_QUESTION_ID:953229842074
for (much) more information

How to use the not exists query

Hello,
Using obiee 11g,
i would like to know how to deal with not exists query in the obiee11g,
the query is like this
select count(a.col1),a.col2 from table1 a ,table2 b where a.col1=b.col1
and not exists
(select d.col1 from table3 d, table4 e
where d.col1=e.col1 and d.col1=a.col1)
group by a.col2
there are 4 tables.
table1,table2,table3,tabel4
this is what i need in a report,these tables are used in othere places also,
would prefer if its possible to do in for a report i.e.e analysis itself.
If not possible then may be in rpd since if i change in rpd it may reflect every place
and not in for a report itself.
thanks

Implement this in report itself can be a tricky and tedious job..But better to have it in RPD - Physical - Select Table type
USE NOT IN in place of NOT Exist..You can simply use SELECT statement in SELECT TABLE TYPE
Hope it clear

Exists and not exists

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