Extracting zip files

I am attempting to install the latest iomega software for my external NAS drive which needs to be extracted by my mac. My mac does not do this automatically, so how do I do this please?

The Unarchiver, which is free, can be downloaded from App store.

Similar Messages

Error while extracting zip file

I am using the following code to extract zip files from jar file
source = "zip/test.zip"
destination = "c:\\"
public void unzip(String source,String destination){
          try{
               ZipInputStream in = new ZipInputStream( this.getClass().getResourceAsStream(source));
               FileOutputStream fos = null;
               ZipEntry ze = null;
               File ff = null;
               while ( (ze=in.getNextEntry() ) != null ){
                    System.out.println( "name=" + ze.getName() );
                    ff = new File( destination + ze.getName() );
                    if ( ze.isDirectory() ){
                         System.out.println("making "+ze.getName()+" dir ("+ ff.mkdirs() +")");
                    else{
                         fos = new FileOutputStream( ff );
                         byte[] buf = new byte[1024];
                         int len;
                         while ((len = in.read(buf)) > 0){
                              fos.write(buf, 0, len);
                         fos.close();
                         System.out.println("wrote file "+ff.getPath()+" success=" + ff.exists() );
               in.close();
          }catch(Exception e){
               e.printStackTrace();
     }     But i found error in extracting zip file
java.io.FileNotFoundException: C:\eclipse\.eclipseproduct (The system cannot find the path specified)
I need some quick response on it.

Nothing to do with the resource path....thats fine. Use the code below.....most likely this will fix it.......
Added a check for directories that start with a ".". The File utility probably thinks its a file, also added a try....check it does make the "." directories.........dont forget the dukes.
    ZipInputStream zis = null;
    FileOutputStream fos = null;
    try
      zis = new ZipInputStream( new FileInputStream( "C:\\your_path\\your_zipfile_or_jar.zip" ) );
      ZipEntry ze = null;
      File ff = null;
      while ( ( ze = zis.getNextEntry() ) != null )
        System.out.println( "name=" + ze.getName() );
        ff = new File( "C:\\your_path\\" + ze.getName() );
        if ( ze.isDirectory() || ze.getName().startsWith("."))
          try{ System.out.println( "making " + ze.getName() + " dir (" + ff.mkdirs() + ")" ); }catch(Exception e2){}
        else
          fos = new FileOutputStream( ff );
          byte[] buf = new byte[1024];
          int len;
          while ( ( len = zis.read( buf ) ) > 0 )
            fos.write( buf, 0, len );
          fos.close();
          System.out.println( "wrote file " + ff.getPath() + " success=" + ff.exists() );
      zis.close();
    catch( Exception ex )
      ex.printStackTrace();
    finally
      try { zis.close(); }catch(Exception ex){}
      try { fos.close(); }catch(Exception ex){}
    }

Problems creating/extracting ZIP files, anyone?

Greetings,
I am having some odd bugs with OSX in creating and extracting ZIP files. I’m curious if anyone else has run across this or if anyone has any remedies to suggest.
The issue is that when I extract a ZIP archive, the extracted files have their creation dates and modification dates changed from the original versions. For example, I have a directory created in 2010 and all the files were created and last modified in 2010. However, when I ZIP the directory and re-extract it, many of the file dates change. Some files have the creation dates changed so to match the last modified date. In other cases, both the creation date and modification date are changed to something later than both, perhaps the date the directory was ZIPed or the date the directory was extracted. And some files don’t seem to have the dates changed.
I have tried various options, such as terminal, and third party programs (BetterZip, Keka, Stuffit, & Archiver to name a few) and they all seem to have some variation of this behavior. I have tried creating the Zip with one program and extracting with the other, and still this behavior persists. Different files seem to be affected with each combination of creating and extracting programs.
Another odd behavior was that I tried password protecting some directories with financial data, and OSX could create the ZIP file with the password, but OSX could not unzip the file with the password it created for some files. In every case, third party program could unzip the files with the password created in the terminal command. This seem to happen inconsistently.
I have tried creating a dummy account and tested it in that account, with similar results.
I’ve read the man page for the command line version of ZIP to see if there is some -option to preserve dates, but found nothing. The typical command looks like this:
> zip -er filename.zip sourceDir
> unzip filename.zip
File types include directories, PDFs, Text docs, Quicken files. Ive tested other directories too with other file types. It doesn’t seem to affect every file, but seems unpredictable. Luckily, I still have the original uncompressed version of most directories. But I really want to archive some directories and unarchive them when needed. The dates matter to me because they are mostly financial files and I use the dates to know what versions were used for taxes and other things. Also, if dates change, then backup programs start replacing the good backups with files with the corrupted dates.
I’d appreciate any suggestions or feedback. I there some bug in the ZIP protocol? Is there some bug in OSX file system that is corrupting the dates with the archive and unarchive process?
Thank you for any suggestions-
OSX 10.9.5,
MBPro 2012

OK, sorry did not read it correctly. Read the first sentance and quit.
No, Bridge is just a browser. You can extract more than one file at a time in Win. Explorer. You have to do them individually, but can run multiple extractions at the same time.
There are other zip/unzip programs out there. I know the the CS6 beta a number of users could not open it with WinZip and used alternate product just fine.

Stage Area Size is 38 gb after extracting zip file of oracle R12.1.1

Dear All,
I need verification from you that after extracting zip file I have total size 38 gb after extracting zip file of oracle R12.1.1 for solaris 5.1 sparc 64 bit.
I have downloaded 42 files.
B53824-01 Part 1 of 4      29M
     B53824-01 Part 2 of 4      97M
     B53824-01 Part 3 of 4      393M
     B53824-01 Part 4 of 4      81M
     V15635-01 Part 1 of 3      1.2G
     V15635-01 Part 2 of 3      1.2G
     V15635-01 Part 3 of 3      1.1G
     V15636-01      976M
     V15637-01 Part 1 of 3      1.7G
     V15637-01 Part 2 of 3      1.7G
     V15637-01 Part 3 of 3      576M
     V15638-01 Part 1 of 3      1.6G
     V15638-01 Part 2 of 3      1.7G
     V15638-01 Part 3 of 3      557M
     V15639-01 Part 1 of 3      1.6G
     V15639-01 Part 2 of 3      1.6G
     V15639-01 Part 3 of 3      463M
     V15640-01 Part 1 of 3      1.5G
     V15640-01 Part 2 of 3      1.6G
     V15640-01 Part 3 of 3      514M
     V15641-01 Part 1 of 3      1.2G
     V15641-01 Part 2 of 3      1.6G
     V15641-01 Part 3 of 3      756M
     V15642-01      1.0G
     V15643-01 Part 1 of 7      567M
     V15643-01 Part 2 of 7      560M
     V15643-01 Part 3 of 7      593M
     V15643-01 Part 4 of 7      612M
     V15643-01 Part 5 of 7      582M
     V15643-01 Part 6 of 7      480M
     V15643-01 Part 7 of 7      551M
     V15644-01 Part 1 of 2      1.5G
     V15644-01 Part 2 of 2      1.6G
     V15645-01      1.7G
     V15646-01 Part 1 of 3      1.5G
     V15646-01 Part 2 of 3      1.2G
     V15646-01 Part 3 of 3      1.1G
     V15647-01 Part 1 of 3      1.7G
     V15647-01 Part 2 of 3      1.2G
     V15647-01 Part 3 of 3      626M
     V15648-01 Part 1 of 2      1.2G
     V15648-01 Part 2 of 2      836M
Does these have all basice needs.
There is also some files which I did not download may be for soa ,warehouse and library like.
Please verify that am I going on right?
Thanks

I need verification from you that after extracting zip file I have total size 38 gb after extracting zip file of oracle R12.1.1 for solaris 5.1 sparc 64 bit.
I have downloaded 42 files.
Does these have all basice needs.You need the following files:
From: Oracle E-Business Suite Release 12.1.1 Rapid Install Start Here (Part 1 of 4), Part Number: B53824-01 Part 1 of 4
To: Oracle E-Business Suite Release 12.1.1 for Sun Solaris SPARC (64-bit) Rapid Install APPL_TOP - Disk 3 (Part 2 of 2), Part Number: V15648-01 Part 2 of 2
There is also some files which I did not download may be for soa ,warehouse and library like.
Please verify that am I going on right?You do not need to download those files.
Thanks,
Hussein

Create Zip File In Windows and Extract Zip File In Linux

I had created a zip file (together with directory) under Windows as follow (Code are picked from [http://www.exampledepot.com/egs/java.util.zip/CreateZip.html|http://www.exampledepot.com/egs/java.util.zip/CreateZip.html] ) :
package sandbox;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
* @author yan-cheng.cheok
public class Main {
     * @param args the command line arguments
    public static void main(String[] args) {
        // These are the files to include in the ZIP file
        String[] filenames = new String[]{"MyDirectory" + File.separator + "MyFile.txt"};
        // Create a buffer for reading the files
        byte[] buf = new byte[1024];
        try {
            // Create the ZIP file
            String outFilename = "outfile.zip";
            ZipOutputStream out = new ZipOutputStream(new FileOutputStream(outFilename));
            // Compress the files
            for (int i=0; i<filenames.length; i++) {
                FileInputStream in = new FileInputStream(filenames);
// Add ZIP entry to output stream.
out.putNextEntry(new ZipEntry(filenames[i]));
// Transfer bytes from the file to the ZIP file
int len;
while ((len = in.read(buf)) > 0) {
out.write(buf, 0, len);
// Complete the entry
out.closeEntry();
in.close();
// Complete the ZIP file
out.close();
} catch (IOException e) {
e.printStackTrace();
The newly created zip file can be extracted without problem under Windows, by using [http://www.exampledepot.com/egs/java.util.zip/GetZip.html|http://www.exampledepot.com/egs/java.util.zip/GetZip.html]
However, I realize if I extract the newly created zip file under Linux, using modified version of [http://www.exampledepot.com/egs/java.util.zip/GetZip.html|http://www.exampledepot.com/egs/java.util.zip/GetZip.html] . The original version doesn't check for directory using zipEntry.isDirectory()).public static boolean extractZipFile(File zipFilePath, boolean overwrite) {
InputStream inputStream = null;
ZipInputStream zipInputStream = null;
boolean status = true;
try {
inputStream = new FileInputStream(zipFilePath);
zipInputStream = new ZipInputStream(inputStream);
final byte[] data = new byte[1024];
while (true) {
ZipEntry zipEntry = null;
FileOutputStream outputStream = null;
try {
zipEntry = zipInputStream.getNextEntry();
if (zipEntry == null) break;
final String destination = Utils.getUserDataDirectory() + zipEntry.getName();
if (overwrite == false) {
if (Utils.isFileOrDirectoryExist(destination)) continue;
if (zipEntry.isDirectory())
Utils.createCompleteDirectoryHierarchyIfDoesNotExist(destination);
else
final File file = new File(destination);
// Ensure directory is there before we write the file.
Utils.createCompleteDirectoryHierarchyIfDoesNotExist(file.getParentFile());
int size = zipInputStream.read(data);
if (size > 0) {
outputStream = new FileOutputStream(destination);
do {
outputStream.write(data, 0, size);
size = zipInputStream.read(data);
} while(size >= 0);
catch (IOException exp) {
log.error(null, exp);
status = false;
break;
finally {
if (outputStream != null) {
try {
outputStream.close();
catch (IOException exp) {
log.error(null, exp);
break;
if (zipInputStream != null) {
try {
zipInputStream.closeEntry();
catch (IOException exp) {
log.error(null, exp);
break;
} // while(true)
catch (IOException exp) {
log.error(null, exp);
status = false;
finally {
if (zipInputStream != null) {
try {
zipInputStream.close();
} catch (IOException ex) {
log.error(null, ex);
if (inputStream != null) {
try {
inputStream.close();
} catch (IOException ex) {
log.error(null, ex);
return status;
*"MyDirectory\MyFile.txt" instead of MyFile.txt being placed under folder MyDirectory.*
I try to solve the problem by changing the zip file creation code to
+String[] filenames = new String[]{"MyDirectory" + "/" + "MyFile.txt"};+
But, is this an eligible solution, by hard-coded the seperator? Will it work under Mac OS? (I do not have a Mac to try out)
p/s To be honest, I do a cross post at [http://stackoverflow.com/questions/2549766/create-zip-file-in-windows-and-extract-zip-file-in-linux|http://stackoverflow.com/questions/2549766/create-zip-file-in-windows-and-extract-zip-file-in-linux] Just want to get more opinion on this.
Edited by: yccheok on Apr 26, 2010 11:41 AM

Your solution lies in the File.separator constant; this constant will contain the path separator that is used by the operating system. No need to hardcode one, Java already has it.
edit: when it comes to paths by the way, I have the bad habit of always using the front slash ( / ). This will also work under Windows and has the added benefit of not needing to be escaped.

Partially extracted .zip file taking up valuable disc space

Hello people.
I recently tried extracting a ~500mb .zip file using the standard Bomarchiver, and unfortunately for me the extracted file was turning out to be much bigger than I anticipated. As a result I started running out of disc space as the file was being extracted, and cancelling the action did not appear to work so I killed the process.
Alas I have not regained the disc space I lost initially, and it seems to still be occupied by a partially extracted file somewhere on the drive. The original .zip was on the desktop, yet there is no sign of a .part file anywhere.
Is there a specific location that partial extracts are stored? How can I regain the lost disc space?
I am running 10.4.11 on an old Wallstreet G3 Powerbook, and its limitation of an 8gb boot partition is causing me headaches!

Hello, see if you can't Trash a couple of Big 4 MB sized files, your in dangerous Territory, with the OS near or at self destruction, & Empty the Trash.
If not at least try a Safe Boot , (holding Shift key down at bootup), that should at least clear up some caches.
If you can get a little breathing room...
How much free space is on the HD, where has all the space gone?
OmniDiskSweeper is likely the easiest/best, and is now free...
http://www.omnigroup.com/applications/omnidisksweeper/download/
You could get & boot from a Firewire Drive, if it has FW, & not have the 8 GB limit.

Cannot extract Zip file with Winzip after zipping with java.util.zip

Hi all,
I write a class for zip and unzip the text files together which can be zip and unzip successfully with Java platform. However, I cannot extract the zip file with Winzip or even WinRAR after zipping with Java platform.
Please help to comment, thanks~
Below is the code:
=====================================================================
package myapp.util;
import java.io.* ;
import java.util.TreeMap ;
import java.util.zip.* ;
import myapp.exception.UserException ;
public class CompressionUtil {
public CompressionUtil() {
    super() ;
public void createZip(String zipName, String fileName)
      throws ZipException, FileNotFoundException, IOException, UserException {
    FileOutputStream fos = null ;
    BufferedOutputStream bos = null ;
    ZipOutputStream zos = null ;
    File file = null ;
    try {
      file = new File(zipName) ; //new zip file
      if (file.isDirectory()) //check if it is a directory
     throw new UserException("Invalid zip file ["+zipName+"]") ;
      if (file.exists() && !file.canWrite()) //check if it is readonly
     throw new UserException("Zip file is ReadOnly ["+zipName+"]") ;
      if (file.exists()) //overwrite the existing file
     file.delete();
      file.createNewFile();
      //instantiate the ZipOutputStream
      fos = new FileOutputStream(file) ;
      bos = new BufferedOutputStream(fos) ;
      zos = new ZipOutputStream(bos) ;
      this.writeZipFileEntry(zos, fileName); //call to write the file into the zip
      zos.finish() ;
    catch (ZipException ze) {
      throw ze ;
    catch (FileNotFoundException fnfe) {
      throw fnfe ;
    catch (IOException ioe) {
      throw ioe ;
    catch (UserException ue) {
      throw ue ;
    finally {
      //close all the stream and file
      if (fos != null)
     fos.close() ;
      if (bos != null)
     bos.close();
      if (zos != null)
     zos.close();
      if (file != null)
     file = null ;
    }//end of try-catch-finally
private void writeZipFileEntry(ZipOutputStream zos, String fileName)
      throws ZipException, FileNotFoundException, IOException, UserException {
    BufferedInputStream bis = null ;
    File file = null ;
    ZipEntry zentry = null ;
    byte[] bArray = null ;
    try {
      file = new File(fileName) ; //instantiate the file
      if (!file.exists()) //check if the file is not exist
     throw new UserException("No such file ["+fileName+"]") ;
      if (file.isDirectory()) //check if the file is a directory
     throw new UserException("Invalid file ["+fileName+"]") ;
      //instantiate the BufferedInputStream
      bis = new BufferedInputStream(new FileInputStream(file)) ;
      //Get the content of the file and put into the byte[]
      int size = (int) file.length();
      if (size == -1)
     throw new UserException("Cannot determine the file size [" +fileName + "]");
      bArray = new byte[(int) size];
      int rb = 0;
      int chunk = 0;
      while (((int) size - rb) > 0) {
     chunk = bis.read(bArray, rb, (int) size - rb);
     if (chunk == -1)
       break;
     rb += chunk;
      }//end of while (((int)size - rb) > 0)
      //instantiate the CRC32
      CRC32 crc = new CRC32() ;
      crc.update(bArray, 0, size);
      //instantiate the ZipEntry
      zentry = new ZipEntry(fileName) ;
      zentry.setMethod(ZipEntry.STORED) ;
      zentry.setSize(size);
      zentry.setCrc(crc.getValue());
      //write all the info to the ZipOutputStream
      zos.putNextEntry(zentry);
      zos.write(bArray, 0, size);
      zos.closeEntry();
    catch (ZipException ze) {
      throw ze ;
    catch (FileNotFoundException fnfe) {
      throw fnfe ;
    catch (IOException ioe) {
      throw ioe ;
    catch (UserException ue) {
      throw ue ;
    finally {
      //close all the stream and file
      if (bis != null)
     bis.close();
      if (file != null)
     file = null ;
    }//end of try-catch-finally
}

Tried~
The problem is still here~ >___<
Anyway, thanks for information sharing~
The message is:
Cannot open file: it does not appear to be a valid archive.
If you downloaded this file, try downloading the file again.
The problem may be here:
if (fos != null)
fos.close() ;
if (bos != null)
bos.close();
if (zos != null)
zos.close();
if (file != null)
file = null ;
The fos is closed before bos so the last buffer is not
saved.
zos.close() is enough.

Extracting Zip files using PowerShell 3.0 on Windows 2008

I’m using a script to extract data to multiple servers, I’ve tested it many times, however an issue has come up that has me stumped. When extracting the zip file, it wants to create a top level folder the same name as the zip file instead of just extracting
the contents. Here is a sample of my script. What I need it to do is just extract the contents to the location I specify, but not create a folder with the same name as the zip file itself. Hopefully that makes sense.
( now the code I used is from a sample I found online, it’s been edited to fit my needs.
$Date
= Get-Date
#ERROR REPORTING ALL
Set-StrictMode
-Version latest
#STATIC VARIABLES
$search
= ""
$destSRC
= "D:\Destination\DestinationUpdate"
$zips
= "D:\Source\ZipSource"
#log start of script
Write-EventLog
-LogName OpsCenter
-Source ZIP
-EntryType Information
-EventId 3001
-Message "Start Extraction of Update files to
$destSRC @
$Date"
#FUNCTION GetZipFileItems
Function
GetZipFileItems
Param([string]$zip)
$split =
$split.Split(".")
$destSRC
= $destSRC
+ "\"
+ $split[0]
If (!(Test-Path
$destSRC))
Write-Host "Created folder :
$destSRC"
$strDest
= New-Item $destSRC
-Type Directory
$shell   =
New-Object -Com
Shell.Application
$zipItem
= $shell.NameSpace($zip)
$items   =
$zipItem.Items()
GetZipFileItemsRecursive
$items
#FUNCTION GetZipFileItemsRecursive
Function
GetZipFileItemsRecursive
Param([object]$items)
ForEach($item
In $items)
If ($item.GetFolder
-ne $Null)
GetZipFileItemsRecursive
$item.GetFolder.items()
$strItem
= [string]$item.Name
If ($strItem
-Like "*$search*")
If ((Test-Path ($destSRC
+ "\"
+ $strItem))
-eq $False)
Write-Host "Copied file :
$strItem from zip-file :
$zipFile to destination folder"
$shell.NameSpace($destSRC).CopyHere($item)
Else
Write-Host "File :
$strItem already exists in destination folder"
#FUNCTION GetZipFiles
Function
GetZipFiles
$zipFiles
= Get-ChildItem -Path
$zips -Recurse
-Filter "*.zip"
| % {
$_.DirectoryName
+ "\$_" }
ForEach ($zipFile
In $zipFiles)
$split =
$zipFile.Split("\")[-1]
Write-Host "Found zip-file :
$split"
GetZipFileItems
$zipFile
#RUN SCRIPT
GetZipFiles
#log end of script
Start-Sleep
-Seconds 2
$Date
= Get-Date
Write-EventLog
-LogName OpsCenter
-Source ZIP
-EntryType Information
-EventId 3001
-Message "Extracted all ZIP Update files to
$destSRC @
$Date"
Paul Arbogast

@jrv
I hate to hijack an old thread.
I have been playing with this for the past hour.
I have use this fine in an interactive console or the ISE.
But as soon as I place this into a script, and then run the script " .\script.ps1 "; nothing happens.
I obviously have some disconnect going on that I am not finding.
Brian Ehlert
http://ITProctology.blogspot.com
Learn. Apply. Repeat.
Disclaimer: Attempting change is of your own free will.

Is There A Command To Find & Extract ".zip" Files

Is There A Terminal Command I Can Use To Find and "Extract"...All zip Files From one External HD and To Unzip Them To Another External Drive
I Would Like For Terminal To Find all the zip files on my old external Hard Drive inside of my karaoke folder
and extract them to my new (1TB) Drive
Macbook Pro 2013
256 SSD / 8GB Ram

iamdeejaybonez,
yes, you could try something like
mkdir /Volumes/target_external_disk/target_folder
find /Volumes/source_external_disk/karaoke_folder -name '*.zip' -print | xargs unzip -d /Volumes/target_external_disk/target_folder {} \;
(Provide suitable values for target_external_disk, target_folder, source_external_disk, and karaoke_folder.)
Note that this would extract all of the ZIP archives in the source external disk’s karaoke folder into the same target folder on the target external disk.

W10TP - Trying to extract zipped files for VPN setup - Security Warning

I am trying to extract .msi & exe files from a zipped file but receive "Windows found that this file is potentially harmful." To help protect your computer windows has blocked access to this file." I cannot see an option where i can
override this restriction. Please advise.

Hi Broccoli! Are you using FQDN or IP address? What firmware is loaded on your WRVS4400N? I had this problem before with WRVS4400N, I can’t establish VPN connection with other router when I’m using FQDN, according to Linksys tech support, if I’m using FQDN with WRVS4400N, then I also have to use the same model on the other side. I encountered this using 1.00.14 firmware. Have you tried the latest firmware (1.00.15)?

Extracting Zipped file

Hi All,
I have a requirement to extract the zipped file( not a zipped folder) inside a folder in the Application server for uploading records in to the database table. I need to unzip the file and after that I need to read the records from that extracted file. The main file and the zipped file both are having same name.
Help me to achieve this. Good pointers will be rewarded.
Reg,
Prabakaran.S

Hi Syfullah,
Any idea about using ABAP instead of EP and webservices...?
Reg,
Prabakaran.S

Looking for a zip application that will open rather than extract zip files

In OS X, the built-in operation for zip files is that when you double-click on one, os x extracts the whole thing to a new folder. I am looking for an application that will open zip files without extracting them - what winzip does in Windows. Are there any apps that will do this in os x?
Message was edited by: Jon R

Try Zipeg - VersionTracker or MacUpdate.

Pdf take minutes to open inside of an extracted zip file

I received a zip file in an email. I extracted it and there were 3 pdfs inside. I cliked on one and the hour glass would just appear and at the top of the pdf it would say "not responding". It finally will open but it takes minutes. Same issue for the other 2.
What is preventing this from opening? I have checked Control Panel and deleted all other pdf applications. Ran Registry Cleaner and cleared Temporary internet and Windows Files from my Norton Security Suite
I do not have any problem opening individual pdfs that I receive or create from insurance company pdf creators inside of their software.
I am running Adobe Reader 10.1.1 on Windows Vista. I have a friend who also seems to have the same problem who is also running Windows Vista.
I have a new laptop running Windows 7 64 bit but there is no issue opening the pdf in that same zip file received.
Thank you.

Hi Michael.
I went back to the zip folder, right cliked on it and cliked on extract all. Then tried opening each one and it just hangs. It still hasn't opened and it is now at least 5 minutes.

Cant extract .zip files?

Today i went to download some fonts for photoshop. Ive done it before and it worked but all of a sudden when i download the .zip file, the icon for it is now the photoshop icon and when i double click on the file it attempts to open in photoshop but fails saying that the type of file cant be opened there. This is probably a bit confusing but if any one knows how to help, then please do. Thank you!

I'm not sure whether you are running Windows or MacOS, but I'll go with Windows.
Right-click on the zip icon
Choose Open with > Choose Default program
Select your zip extractor program and make sure "alway open with this program" is checked.
Click OK and your zipfile should open properly.
Make note of this tip,you can use it to set the default program for any file type.
Gene

I need program to extract the zip file

Please help me to chose the better program extract zip file from web page or email.
Thanks

http://osxdaily.com/2013/05/13/open-zip-files-iphone-ipad/
 Cheers, Tom

Extracting zip files

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