I need program to extract the zip file
Please help me to chose the better program extract zip file from web page or email.
Thanks
http://osxdaily.com/2013/05/13/open-zip-files-iphone-ipad/
Cheers, Tom
Similar Messages
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FSCM MP9 - unable to extract the zip file EODS_QUERY_FIX
Hi,
I am applying FSCM 9.1 Maintenance Pack 9 on Finance application.
During on estep I need to apply the project, which can be found on EODS_QUERY_FIX.ZIP
"Please locate EODS_QUERY_FIX.zip in upd878541\upd878541_install and manually apply the project to your Database."
I am unable to extract the zip file.
It's high appreciated if some one can help me in extracting or identifying the project.
Thank You!
Best Regards
SoundappanHi,
I had the same exact issue yesterday. From my install workstation I was unable to open the zip file but from another PC I could open it with no errors, so I've copied the archive I could open from my PC to my install workstation and still I could not open it.. very strange.
The difference between my PC and the install workstation was that on my PC I'm using 7zip and on the install workstation I'm using WinZip.
So I've extracted the zip file with 7zip on my PC then, still on my PC I've recreated a new zip file, transferred this to the install workstation and finally I could open it!
Hope this helps -
Hi,
I want to upload and extract the zip files. However I am able
to upload the zip file but not able to unzip it after uploading. Is
it possible in coldfusion mx 7. I know its possible in coldfusion
8, but I need solution in version 7. Please let me know if there is
any free components or third-party API's.
Thanks!as you know cf mx 7 does not have a built-in zip
functionality.
you will have to install a zip application (i.e. 7zip, which
is free) on
your server and use cfexecute to run it and unzip your file.
if you are on a shared hosting you are pretty much out of
luck - look if
your server has a pre-installed php or other script to manage
zip
archives...
Azadi Saryev
Sabai-dee.com
http://www.sabai-dee.com/ -
How to FTP file and extract the zip file automatically?
Hi,
My app needs to FTP another site and also automatically unzip the transferred file over the internet by user clicking on one button. Any experts? thanks.How do you open a can of beans before you take it out of the pantry?
However I suppose your question only sounded stupid like that, you didn't really mean it that way. One problem is that you didn't mention which way the transfer was going. I assume you are asking about getting a file and unzipping it? Many of the FTP clients described in the article that jmennen referred to allow you to get an InputStream that allows you to read bytes from the server. You would take this InputStream and wrap it in a ZipInputStream. That way you could unzip the file as you transfer it from the server, rather than having to use a temporary file between the two steps.
But if you really meant that you wanted the unzipping to take place on the server before you did the download, no, you can't do that. -
Today I tried to unzip my own zip.file but encountered some problem which never happened before, everytime it says "There is already a folder with same name as the file name you specified. Specify a different name" But i coundn't find a single place to change the file name! I am so confused right now! BTW, I zipped the project from a Mac and now I am trying to unzip it on Windows.
Thanks!zxcvbnm wrote:
I am sorry, but this is an emergency and I have open it within two hours! Please help!I don't care.
Again is this a java question?
Despite the fact that I don't care that it is an emergency I might actually provide an answer if you actually answered my question.
Conversely since you didn't, you now run the risk of me not answering it because, which is why I asked the question in the first place, you didn't provide enough information to provide a correct answer. Answering my question would help to do that. -
Problem in unzipping the zip files
Hi,
I have created a program to unzip the zip files. But when i try to zip it is creating the zipped files outside the folder where it is to be zipped.
what is wrong with my code.
if the zip file is migration.zip
if the path inside the zip file shows
and the path inside says this
/codebase/scripts/
it would create migration folder and create codebase folder outside the migration folder
what is wrong with my code
//Unzip the zip files to the folder with their name
import java.io.BufferedReader;
import java.io.File;
import java.io.FileOutputStream;
import java.io.FilenameFilter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Enumeration;
import java.util.zip.ZipEntry;
import java.util.zip.ZipFile;
// Getting the path to find the type of files
public class zipper implements FilenameFilter{
String ext;
public zipper(String ext)
this.ext="." + ext;
public boolean accept(File dir,String name)
return name.endsWith(ext);
public static void main(String args[]) throws IOException
try
String dir = "D:/a/";
File f2 = new File(dir);
FilenameFilter fn= new zipper("zip");
String ss[]=f2.list(fn);
for ( int j = 0; j < ss.length; j++)
System.out.println(" Extracting ...." + ss[j]) ;
String zipFile = dir + ss[j];
ZipFile zf = new ZipFile(zipFile);
Enumeration entries = zf.entries();
String directoryName = zf.getName();
directoryName = directoryName.substring(0, (directoryName.indexOf(":" + File.separator) + 2));
String folderName = zf.getName();
folderName = folderName.substring(0, folderName.lastIndexOf("."));
File file1 = new File(folderName);
//File file1 = new File(entries.getName());
file1.mkdir();
while (entries.hasMoreElements())
ZipEntry ze = (ZipEntry) entries.nextElement();
String path = directoryName + ze.getName() ;
String path1 = folderName + ze.getName();
//System.out.println(" : " + path);
if (ze.getName().endsWith("/"))
File file = new File(path);
file.mkdir();
continue;
//break;
BufferedReader bReader = new BufferedReader(new InputStreamReader(zf.getInputStream(ze)));
StringBuffer fileBuffer = new StringBuffer(" ");
String line ;
while ((line = bReader.readLine()) != null)
fileBuffer.append(line);
fileBuffer.append("\r\n");
//line = line + "\r\n";
//byte[] b = new byte[line.length()];
//b =line.getBytes();
//out.write();
String fileData = fileBuffer.toString();
File f1 = new File(path);
f1.createNewFile();
//FileOutputStream out = new FileOutputStream(folderName + "/" + ze.getName());
FileOutputStream out = new FileOutputStream(path);
long size = ze.getSize();
byte[] data1 = new byte[fileData.length()];
for (int i = 0; i < fileData.length(); i++)
data1[i] = (byte) fileData.charAt(i);
out.write(data1);
out.close();
bReader.close();
} catch (Exception e)
e.printStackTrace();
Thanks in Advance
AvinashString path = directoryName + ze.getName();
String path1 = folderName + File.separator+ ze.getName();
File f1 = new File(path); // pass path1 instead of path
f1.createNewFile();
FileOutputStream out = new FileOutputStream(path); // pass path1 instead of path -
Problem in Unzipping the zip file
Hi
I have created a program to unzip the zip files in the folder named after the zip file
it is working well well when u try to zip zip files put in a directory
i.e u create a folder name contents and put files into that and then zip it
but when u directly create a zip file , without putting in a folder
it creates the folder and zip the files outside the folder
Another problem is that with the path
for e.g. suppose the zip file name is contents and path should show
contents/filename.txt but there are some other files whose path shows
res/file.txt. In this case it creates a folder of res and put it outside the
folder with the name of zip file
I have pasted my code :
//Unzip the zip files to the folder with their name
import java.io.BufferedReader;
import java.io.File;
import java.io.FileOutputStream;
import java.io.FilenameFilter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Enumeration;
import java.util.zip.ZipEntry;
import java.util.zip.ZipFile;
// Getting the path to find the type of files
public class zipper implements FilenameFilter{
String ext;
public zipper(String ext)
this.ext="." + ext;
public boolean accept(File dir,String name)
return name.endsWith(ext);
public static void main(String args[]) throws IOException
try
String dir = "D:/";
File f2 = new File(dir);
FilenameFilter fn= new zipper("zip");
String ss[]=f2.list(fn);
for ( int j = 0; j < ss.length; j++)
System.out.println(" Extracting ...." + ss[j]) ;
String zipFile = dir + ss[j];
ZipFile zf = new ZipFile(zipFile);
Enumeration entries = zf.entries();
String directoryName = zf.getName();
directoryName = directoryName.substring(0, (directoryName.indexOf(":" + File.separator) + 2));
String folderName = zf.getName();
folderName = folderName.substring(0, folderName.lastIndexOf("."));
File file1 = new File(folderName);
//File file1 = new File(entries.getName());
file1.mkdir();
while (entries.hasMoreElements())
ZipEntry ze = (ZipEntry) entries.nextElement();
String path = directoryName + ze.getName() ;
String path1 = folderName + ze.getName();
//System.out.println(" : " + path);
if (ze.getName().endsWith("/"))
File file = new File(path);
file.mkdir();
continue;
//break;
BufferedReader bReader = new BufferedReader(new InputStreamReader(zf.getInputStream(ze)));
StringBuffer fileBuffer = new StringBuffer(" ");
String line ;
while ((line = bReader.readLine()) != null)
fileBuffer.append(line);
fileBuffer.append("\r\n");
//line = line + "\r\n";
//byte[] b = new byte[line.length()];
//b =line.getBytes();
//out.write();
String fileData = fileBuffer.toString();
File f1 = new File(path);
f1.createNewFile();
//FileOutputStream out = new FileOutputStream(folderName + "/" + ze.getName());
FileOutputStream out = new FileOutputStream(path);
long size = ze.getSize();
byte[] data1 = new byte[fileData.length()];
for (int i = 0; i < fileData.length(); i++)
data1[i] = (byte) fileData.charAt(i);
out.write(data1);
out.close();
bReader.close();
} catch (Exception e)
e.printStackTrace();
Thanks in Advance
AvinashString path = directoryName + ze.getName();
String path1 = folderName + File.separator+ ze.getName();
File f1 = new File(path); // pass path1 instead of path
f1.createNewFile();
FileOutputStream out = new FileOutputStream(path); // pass path1 instead of path -
How to create a self-extracting downloaded Zip file ...
I have a question about Mac file compression for an eBook PDF. I know how to compress the file with Mac OS X 10.8.5. I right-click the PDF I want to compress and select "Compress <file name>" from the Contextual Menu. The file is compressed as a ZIP file. The file I'm compressing will be distributed from a web server to Mac users.
SITUATION: I want the Mac user to be able to download the ZIP file to their Mac. Once the ZIP file is downloaded to their Mac, I want the ZIP file to automatically open to place the eBook PDF on their desktop - so please indulge me here. I know that a Mac user only needs to double-click the ZIP file to extract the eBook PDF, BUT, IF POSSIBLE, I want this to happen automatically after the ZIP file is downloaded.
QUESTION: Is there any way to automatially extract the eBook PDF from the ZIP file once the Mac user downloads the ZIP file to their destop? If so, how do I do this? If not, is there anyother way to do this that does not required any additional software like StuffIt Expander to decompress the file? As an aside, If I compress the eBook PDF using Mac OS X 10.8.5, is this compressed ZIP file compatible with older versions of Mac OS, i.e., can they double-click the compressed ZIP file to open it?
Thank you in advance for your comments and help . . .
Jim Minor
Email: [email protected]In OSX, zip extraction depends on the browser and browser settings. For example, Safari will open files automatically depending on this setting in Sarari Preferences: So the short answer I think is no. Your zip recipients are going to have to click on the zips to open them if their browser is not set to open them automatically.
I'm no zip expert but I would think a zip is a zip and should be compatible with older versions of OSX. That is, 10.4 or later, which didn't include Stuffit any more. Earlier versions would need Stuffit or something similar. -
Need to send the zip file to mail as an attachment
i want to pick the zip file which consists some 2,3 files inside it. and send as it is to mail as an attachment.what i did is
i have taken one zip file,,, "testing.zip" inside it i have "test1.txt" & "test2.csv"
i created sender CC ,,in that i used module payloadzipbean and unzipped and called the file adapter.. created reciever CC as mail ..used same payload module now here i zipped all the payloads.
Result..i see the attachment coming as "test1.txt.zip" ..here i can see inside this zipfile my original file names as "test1.txt"&"test2.csv" as i enabled ASMA in both CC.
issues:i am unable to get the original file name like "testing.zip" ,,
can anyone help me in this.
Regards,
LoordhHi all,
as i posted last time my requirement ,i am going with java mapping for my scenario. i am using this code .
http://wiki.sdn.sap.com/wiki/display/XI/Dynamicfilenameforpass-through+scenario
this is working perfect for zip file (file to file) scenario. but my scenario is file to mail ..as i need to send this to mail package there it is throwing error.i am getting "zip file name as attachment properly but when i try to open it is giving error in zip file." this is what i modied code ..i am able to see my messge in sender CC and reciever CC..any java experts please help on this.
try {
// create XML structure of mail package
String output = "<?xml version=\"1.0\" encoding=\"UTF-8\"?>"
+ "<ns:Mail xmlns:ns=\"http://sap.com/xi/XI/Mail/30\">"
+ "<Subject>" + mailSubject + "</Subject>"
+ "<From>" + mailSender + "</From>"
+ "<To>" + mailReceiver + "</To>"
+ "<Content_Type>multipart/mixed; boundary=\"" + boundary + "\"</Content_Type>"
+ "<Content>";
out.write(output.getBytes());
// create the declaration of the MIME parts
//First part
output = "--" + boundary + CRLF
+ "Content-Type: text/plain; charset=UTF-8" + CRLF
//+ "Content-Transfer-Encoding: 8bit" + CRLF
+ "Content-Disposition: inline" + CRLF + CRLF
+ mailContent + CRLF
//Second part
+ "--" + boundary + CRLF
+ "Content-Type: Application/zip; name=" + attachmentName + CRLF
//+ "Content-Transfer-Encoding: base64" + CRLF
+ "Content-Disposition: attachment; filename=" + attachmentName + CRLF + CRLF;
out.write(output.getBytes());
//Source is taken as attachment
copySource(in, out);
out.write("</Content></ns:Mail>".getBytes());
} catch (IOException e) {
throw new StreamTransformationException(e.getMessage());
protected static void copySource(InputStream in, OutputStream out)
throws IOException {
byte[] bbuf = new bytehttp://in.available();
int bblen = in.read(bbuf);
if (!(bblen < 0)) {
//String sbuf = new String(bbuf);
//String encoded = Base64.encode(sbuf);
// replace all control characters with escape sequences
//sbuf = sbuf.replaceAll("&", "&");
//sbuf = sbuf.replaceAll("\"", """);
//sbuf = sbuf.replaceAll("'", "'");
//sbuf = sbuf.replaceAll("<"<");
//sbuf = sbuf.replaceAll(">", ">");
out.write(bbuf);}} -
How to prevent unauthorized extraction of the zip files I created.
Hi all,
Can anyone help me in knowing abt this.
Is there any way to prevent unauthorized extraction of the zip files I create using Java.
Plz help friends.
Thanks in Advance.
-JamesSince you already found out that Java's zipping methods don't implement password protection, all you could possibly do is encrypting the contents.
-
I have a program that includes a set of around 50 photos. I have zipped those files and included them in my build. Now I'd like to extract those photos to a folder during the installation process. I've reviewed the application builder, but can find no reference to extracting a zip file.
What am I overlooking? I'd appreciate any help. Thanks.You can create another executable that can decompress the file. Then, in Application builder, in the "Installer Settings" tab, there is a button that reads "Advanced...". A dialog will open with an option called "Run executable after installation". You can call your decompression executable from there.
Another option is to check OpenG Builder, which is also an application to deploy LabVIEW software. The zip functions are included, and because is open source, you can modify it so the installer shows the behavior you want.
Regards;
Enrique
www.vartortech.com -
Creation of Password for the Zip file which are sent thru email
Dear Experts,
how to create a password for the zip file which is sent via email through a abap program.
OR
how to create a password in abap for a zip file.
Thanks...
Vishal
Edited by: vishal_reddy786 on Jun 22, 2010 7:31 AMUNSOLVED
-
To upload the ZIP file and get the filenames available in ZIP file in ABAP
Hi Experts,
For my requirement, file from legacy comes as ZIP file with number of files in that.
Please provide one code sample to upload the ZIP file from local workstation and get the filenames available in ZIP file to check few filename validation checks for the available files in report program.
Thanks in Advance,
Regards,
Basani1. Copy the ZIP file into App server
2. Call function
call function 'RFC_REMOTE_PIPE'
destination 'SERVER_EXEC'
exporting
command = command " Unzip command gunzip /path & file
read = 'X'
tables
pipedata = std_lines
then you can read the files and can validate the file names
a® -
Unable to see XML data in the zip file
Hi folks,
Willing to think about a way to automate the setup migration, I'm looking at the iSetup functionnalities in 11i.
Technically speaking, we upgraded iSetup to 11i.AZ.H.delta.2.
I did a simple extract of an FNDLOAD API (flex values) , everything works fine. At the end I got a zip file which contains several files including the ldt file containing my data.
Having done this, I wanted to test an XML API (chart of accounts, GL currencies), both completed without errors but when looking at the zip file, no xml file containing my data exists !
I'm quite sure that it exists because I can report on those data.
is this a bug ?
Thanks for your answer.
Franck JamesFranck:
This could be an issue with the zip tool you are using. You can ignore this as long as you can load and report on the given extract.
Thanks,
Lokesh -
DVD: can I extract the movie files?
DVD: can I extract the movie files?
I created a DVD (burned on DVD media). I did not archive the project since the files are too large. Can I extract the movie files from the DVD? I want to make a edit to the DVD.
I know if I have the movies (clips) in iMovie I can do it but how do I do it from a completed DVD that I created and dont have the assets?
I really don't want to pay for software that I will use once. Low or No cost alternative that won't sacrifice file quality? Thanks! Steve
Message was edited by: Steve WoronAs far as set up goes, others on this forum feel free to add. I rarely use either of the above (although I have access to them on separate power macs).
Reason: Apple's DVDSP works natively with Mpeg-2. I personally have no need for anything else since these features are already included in apple's pro apps.
Q: Doesnt DVDxdv watermark the demo version?
A: Yes. It does, until you pay for it in full.
========================================
Q:what is QT playback component??
A:The QuickTime MPEG-2 Playback Component provides QuickTime users with the ability to import and play back MPEG-2 content, including both multiplexed (a.k.a. muxed, where the audio and video tracks are interleaved into one track) and nonmultiplexed (a.k.a. elementary) streams.
You can read the description here:
http://www.apple.com/quicktime/extending/components.html
Disclaimer: Apple does not necessarily endorse any suggestions, solutions, or third-party software / products that may be mentioned in this topic. Apple encourages you to first seek a solution at Apple Support. The following links are provided as is, with no guarantee of the effectiveness or reliability of the information. Apple does not guarantee that these links will be maintained or functional at any given time. Use the information above at your own discretion.
Message was edited by: SDMacuser
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