File Compression Using ByteArrayInput/OutputStream

Question

Hi,
I want to write a File compression program using ByteArrayInput/OutputStream. It should access multiple files and zip the contents of the files and give it in the ByteArrayOutputStream so the user can name that file and store it as zip. How to do this. I have done this with OutputStream. I want the code its very urgent!

Answer 1

u can use this code to compress and zipping the files
import java.util.zip.*;
public class Compress
public static void doit(String filein[], String filepath[], String fileout)
// Common Input streams for all the files that will be zipped
FileInputStream fis = null;
// Output stream for the ZIP file
FileOutputStream fos = null;
try
fos = new FileOutputStream(fileout);
// Initialize Zip output stream
ZipOutputStream zos = new ZipOutputStream(fos);
// Add entries to the ZIP file
ZipEntry ze = null;
// Initialize buffer for the output data
final int BUFSIZ = 4096;
byte inbuf[] = new byte[BUFSIZ];
int n;
for ( int i = 0; i < filein.length; i++)
fis = new FileInputStream(filein);
// Add entries into the ZIP file and give it the display name.
// Upon unzip the same directory structure as given in the filepath will be followed
// The file path is the complete path of the file including the file name.
ze = new ZipEntry(filepath[i]);
zos.putNextEntry(ze);
inbuf = new byte[BUFSIZ];
// write output to the out put stream
while ((n = fis.read(inbuf)) != -1)
zos.write(inbuf, 0, n);
fis.close();
fis = null;
zos.close();
fos = null;
catch (IOException e)
     System.err.println(e);
finally
     try
          if (fis != null)
               fis.close();
     if (fos != null)
     fos.close();
catch (IOException e)
     System.err.println("\nError Occured while Zipping the files: " + e.getMessage());
public static void main(String args[])
// Files to be Zipped
String filein[] = {"file1.txt", "file2.txt", "file3.txt",};
          // Display name that appears in Win ZIP or any other unzip utility
          String filepath[] = {"temp\\file1.txt", "temp\\file2.txt", "temp\\file3.txt",};
// Name of the Zip file
String fileout = "compress.zip";
// Zip it
doit(filein, filepath, fileout);