File Date needs to be insterted into Table

Question

We process/insert two CSV files from the file system into the DB that is executed from a CRON job(I think).
The CRON job calls SQLPLUS and calls the stored procedures to load the files. The SPs are using UTIL_FILE to open and read the file.
This works well but now I need to get the date the file was created and insert that as well.
Anyone know how I can get file date?

Answer 1

Hi,
Some simple method for fetching the creation date of your file from OS and insert it into oracle DB is :-
Method 1:
1. in your cron tab fist write a shell script ( is you know the name of your file ) like this
ls -l my_file.csv | cut -b52-63 > my_file.date
this will write the creation date of CSV file in to a text file.
2. Since you know the name of your file ( just file extention is changed ) You can read this file from you stored procedure thru UTL file package. Read the Date from that file an insert into your Db.
i.e. your unix shell script will contain a command that i have mentioned in step one, and the call of that procedure.
Method 2:
Another way is
create a shell script ( say a.sh ) like this
1) echo 'insert into x (x) values (' > a.sql
echo "'" >> a.sql
ls -l my_file.csv | cut -b52-63 >> a.sql
echo "'" >>a.sql
echo ');' >> a.sql
echo 'commit;' >>a.sql
sqlplus -s user/pwd@dbnm @a.sql
2) $ chmod 777 a.sh
3) $ sh a.sh
4) $ more a.sql
insert into x (x) values (
Jul 5 2002
commit;
--- this means just run step 1 and two, add entry in crontab for step 3.
this will work.
( i have written insert statement , like wise u can write your update statement )
Hope this will help you
Regards
Ripudaman