File2IDoc - new IDoc when client-number in sub-segment of MT is different

Question

Hi, we have an Message-Type and IDoc with four different Segments. Each of it contains a client-number.
First segment: Header
Second-fouth: Childs
When i read File via FTP in XI it could happen that the Header-Segment is not depending on the child. That is when the client-number in the text-file is different. When this happens, XI should create a new IDoc where no Header-Segment will occur.
How should i manage this in mapping? i have to read the payload and must compare the client-number of each child in the txt-file.
Could you give me some help?!
This is the source-structure:
<?xml version="1.0" encoding="UTF-8"?>
<MT_BESTFILE>
   <BestfileRecordSet>
      <BestFileHeader>
         <BDKDNR/> (=client-number)
      </BestFileHeader>
      <BestFilePos>
         <BDKDNR/>(=client-number)
      </BestFilePos>
      <BestFilePos1>
         <BDKDNR/>(=client-number)
      </BestFilePos1>
      <BestFilePos2>
         <BDKDNR/>(=client-number)
      </BestFilePos2>
   </BestfileRecordSet>
</MT_BESTFILE>

Answer 1

Hi Carsten,
Below UDF will solve your problem,
Here it will take input as BDKDNR from Header, Pos, Pos1 and Pos2, and output should be mapped to IDOC Header so that it will create a new idoc when ever there is a change in child segment.
as per your query it is clear that BDKDNR from header will match with child segments but some times it will differ at that point we should create a new IDOC.
in the UDF header BDKDNR will be compared to the child BDKDNR's if it is not matching with  the header then it will create a new idoc.
Please let me know it the problem still exits.
public void test(String[] header,String[] pos,String[] pos1,String[] pos2,ResultList result,Container container){
int i,j,count=0;
for(i=0;i<header.length;i++)
  result.addValue(header<i>);  
  for(j=0;j<pos.length;j++)
    for(i=0;i<header.length;i++)
     if(!(pos[j].equals(header<i>)))
     count++;
   if(count>0)
   result.addValue(pos[j]);
   count=0;  
  for(j=0;j<pos1.length;j++)
   for(i=0;i<header.length;i++)
    if(!(pos1[j].equals(header<i>)))
     count++;
if(count>0)
   result.addValue(pos1[j]);
   count=0;  
  for(j=0;j<pos2.length;j++)
   for(i=0;i<header.length;i++)
  if(!(pos2[j].equals(header<i>)))
     count++;
if(count>0)
   result.addValue(pos2[j]);
   count=0;  
Regards,
Karan