Find characters in a string....

Hello, I have trouble writing the syntax for checking if some characters are part of a string.
I want this to function:
Return true (or the characters in question), otherwise null or false.
For example: check if '1Y' is part of 'NOKLIB 1Y' (true in this case).
I work with this code:
select substr('2Y','1',INSTR('NOKLIB 2Y'),'1') from dual
[\code]
All help greatly appreciated!
many thanks
Harald

not sure what you want but may be this?
SQL> SELECT CASE
2            WHEN LENGTH (REPLACE (str, '2Y') ) = LENGTH (str) THEN 'FALSE'
3            ELSE 'TRUE'
4          END output
5     FROM (SELECT 'NOKLIB 2Y' str
6             FROM DUAL
7           UNION ALL
8           SELECT 'NOKLIB'
9*            FROM DUAL)
SQL> /
OUTPU
TRUE
FALSEor this?
SQL> SELECT CASE
2           WHEN INSTR (str, '2Y') = 0 THEN 'FALSE'
3           ELSE 'TRUE'
4         END output
5    FROM (SELECT 'NOKLIB 2Y' str
6            FROM DUAL
7          UNION ALL
8          SELECT 'NOKLIB'
9*           FROM DUAL)
SQL> /
OUTPU
TRUE
FALSEFormatted
Message was edited by:
devmiral

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Windows PowerShell is a powerful command tool and we can use it for management and operations. In this article we introduce the detailed steps to use Windows PowerShell to find and replace test string in the
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Figure 1.
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Thank you for the information, but does this thread really need to be stuck to the top of the forum?
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