Finding the missing value
Hi, I have two arrays. First array contain 1,3,5,7, with the Second array contain 1,3,4,5,7,. The difference between the two array is the additional of 4 in the second one.
How do I get the number the does not exist in array one?
Please advise. Thanks in advance
if you have these arrays sorted then it's no problem... you just use binary search like search algoithm.
i assume you have only one element extra in array2, so you could:
int len = array1.length;
if (array1[len/2] != array2[len/2]) {
if (array1[len/2] == array2[len/2 + 1]) {
// now i know that this XTRA value is in the first part
} else {
// here i know that XTRA value is in second half of array2
}this way you don't have to check at the worst case n*(n+1) times...
if your arrays are not sorted, then you may do it easily!
or you could use [iAdvanced Search[/i] (upper right corner of that page;)
Similar Messages
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How to find the maximum value among four fields in a single record
Hi Gems...
I have a record in which there are 4 currency fields.
Now i would like to know the maximum of these 4 fields.
I tried with Max functions in which i put all the 4 values...but it is showing error like ") is missing" though it is there.
Can we insert more than 2 values in Max function?
Or else is there any other option to find the max value among the 4 values which lies in a single record
Thanks
JitenHi Anil,
Say suppose i have a single record in which 4 premiums of a particular bond exists.
for eg:
Prem1 Prem2 Prem3 Prem4
129000.00 388000.00 228000.00 14800.00
Now this is a single record for a particular bond ... now i need to calculate the max value among these 4 premiums.
How would we proceed to achieve this?
Regards
Jiten
Edited by: Jitendra Yuddandi on Feb 3, 2009 1:04 PM -
How to find the RGB Values of a Color for Hyperion
When customizing your Hyperion forms, we come across situations where we need the exact RGB value of a given color. This article explains a simple technique to find the RGB values using MS Paint and the Calculator applications that come as standard applications with your operating system.
Here are the steps to find the exact RGB value of a given color.
1) View your Hyperion form using IE, scroll down until you see the color you want to find the RGB value and press the "Print Screen" button (in your keyboard).
2) Open MS Paint and click Edit -> Paste or simply Ctrl+V. What you saw in the browser will be copied as a new untitled image.
3) Select the Color Picker tool and click on an area that has the color you want to match.
4) Now go to Edit Colors... option and click on the "Define Custom Colors >>" button. The color you picked will be selected on this palette. At the bottom right hand corner you will see the Red, Green and Blue values you need. Note down the R,G,B values (given in decimal).
5) Now we need to find out the hexa-decimal values that correspond to those decimal values. This is where we use the simple Calculator. Open the Calculator application from Program -> Accessories. Switch to the scientific mode by clicking View ->Scientific.
6) By default it will be in the decimal number mode. Enter the R value (238 in this example) and click on the Hex radio button. The corresponding hexa-decimal value (EE in this case) will be shown in the dial.
The selected color in this case has the same value for R, G and B. (In fact, all shades of gray has the same values for R, G and B.) Therefore, the RGB value of the background color that we need is #eeeeee. Repeat step 6 to find out the hex value for the Green and Blue elements, if they are different.
Tip:
If you find it difficult to pick a color, zoom the image by pressing Ctrl+PageDown or using View -> Zoom -> Custom... option.These tips are to find the RGB color of HFM default row where row is text and text lines in data columns are also visible to business users as Yellow as an input cell. By applying the same RGB color you can apply the same color to your data cells or rows. This post shows how to identify color from any web view-able object.
Regards,
Manaf -
How to find the PREVIOUS value of a non-DB item?
I want to do a simple thing but found it impossible.
I want to find the previous value of a non-DB item in a form.
I tried creating a text item and populating it using PRE-TEXT-ITEM but that does not work.
WHEN-VALIDATE-ITEM does not work either because WVI fires only after item value has changed.
Any suggestions will be greatly appreciated.
Edited by: Channa on Apr 2, 2010 4:34 AMChanna wrote:
I want to do a simple thing but found it impossible.
I want to find the previous value of a non-DB item in a form.
I tried creating a text item and populating it using PRE-TEXT-ITEM but that does not work.
WHEN-VALIDATE-ITEM does not work either because WVI fires only after item value has changed.
Any suggestions will be greatly appreciated.
Edited by: Channa on Apr 2, 2010 4:34 AMPlease make it clear what is your requirement then possibly we can provide you a better answer
You can use Global variables for to store old values also on Post-query populate a value in separate field or Parameter -
Finding the missing number from the table
I have vendor table with the following column, refvendor_id, the refvendor_id is a primary key in the table. the customer use the application to enter information to the vendor table using an interface
created in Java. my question is how can I query the refvendor_id numbers that have been skipped by the customer when they enter information to the vendor table.
refvendor_id is a varchar data type.
for example
refvenodr_id
1
2
3
5
6
9
I would like to capture in my sql the refvendor_id that is skipped here.
4,7,8
select refvendor_id
from vendorI suggest to find the number values with a regular expression.
Here is a modified version, that will only use the pure number refvendor_ids
-- Test-Data:
with vendor as
select '1' refvendor_id from dual union all
select '2' refvendor_id from dual union all
select '3' refvendor_id from dual union all
select '5' refvendor_id from dual union all
select '6' refvendor_id from dual union all
select '9' refvendor_id from dual union all
select '10' refvendor_id from dual union all
select '12' refvendor_id from dual union all
select 'A' refvendor_id from dual
-- Query:
select rownum from dual connect by rownum <= (select max(to_number(refvendor_id)) from vendor where regexp_like(refvendor_id,'^[0-9]+$') )
minus
select to_number(refvendor_id) from vendor where regexp_like(refvendor_id,'^[0-9]+$')
order by 1;(I produce output in number-format, because i want numeric ordering in output)
Edited by: hm on 14.12.2010 13:32 :
Of cause you can also use your restrictions, but I can't see if that are really only numbers:
select rownum from dual connect by rownum <= (select max(to_number(refvendor_id)) from vendor where SUBSTR (refvendor_id, 1, 1) IN ('1', '2', '3', '4', '5', '6', '7', '8', '9') AND LENGTH (refvendor_id) < 5 )
minus
select to_number(refvendor_id) from vendor where SUBSTR (refvendor_id, 1, 1) IN ('1', '2', '3', '4', '5', '6', '7', '8', '9') AND LENGTH (refvendor_id) < 5 )
order by 1; -
How do I find the closest value to a constant in an array
I have an array of floating numbers and I want to find a value in that array that is closest to a floating constant. For example if I have the array 5.9, 2.8, 3.7, 5.8, 6.9, and if I have the constant 5.4, how would I find the closest value to 5.4 in the array, which in this case would be 5.8. The only approach I can think of is to subtract each value in the array from 5.8 and find the minimum value of an array which would be created from the differences. Is there a better approach?
Thank you.Just be sure to take the absolute value of the difference and your proposed method is fine.
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How to find the nearlest value in 1-D array ?
Hi.. everybody..
I need to seperate the raw data(1-D) into 2 group of array by the center value and then make the average value in each array. But I also still have the problem about if the center value is not the same of some value in the 1-D array. I cannot use the split function.
"How to find the nearlest value to the center point that I calculated, in the 1-D array ?"
Thanks a lot for anybody helpIn a general sense, since I'm not sure what your data values are or how far away your calculated center is from the true value, I would do it one of two ways:
1) Use a threshold value and scan the array until the threshold is reached (assumes constantly increasing values in the array).
2) Use either a) round to nearest integer b) round to + Infinity (round up) or c) round to - infinity (round down). If you don't have decimal values, you'll have to devide the values by a power of 10.
2006 Ultimate LabVIEW G-eek. -
Finding the min value in a hashtable
Hi,
I'm trying to work out the lowest value contained in a hashTable. So far I've got.
import java.util.Enumeration;
import java.util.Hashtable;
import java.util.Vector;
public class StoreValuesDouble extends Statistic {
* Each object of the class (StoreValuesDouble) will have these attributes.
* When you call the StoreValuesDouble class you can use
* myDoubleValues (a Vector holding Double types),
* Hashtable (a Hashtable using Double types as values and keys) and
* nullValues (an Double currently set to 0.0).
Vector<Double> myDoubleValues; //declare a variable myDoubleValues that is of data type Vector
Hashtable<Double, Double> myValues; //declare a variable myvalues that is a data type Hashtable
Double nullValues = 0.0; //Double attribute to count the number of null values contained in the vector
* pass myDoubleValues to inValues
* @param Vector /<Double/> a vector holding Double values
* @param inValues the values in the vector
* @return
public void DoubleStat(Vector<Double> inValues) {
myDoubleValues = inValues;
* calculate the mean of myDoubleValues
* @return mean of myDoubleValues as a double
public double meanDouble() {
double mean = 0;
Double currentDouble;
double nonNull = 0;
for (double j = 0; j < myDoubleValues.size(); j++)
currentDouble = myDoubleValues.elementAt((int) j);
if (currentDouble != null) {
mean += currentDouble.doubleValue();
nonNull++;
return mean / nonNull;
* calculate the standard devitation of myDoubleValues
* @return standard devitation of myDoubleValues as a double
public double standardDeviationDouble() {
double m = meanDouble();
double t = 0.0;
Double currentDouble;
double n = 0;
for (double j = 0; j < getDoubleValues(); j++) {
currentDouble = myDoubleValues.elementAt((int)j);
if (currentDouble != null) {
n = currentDouble.doubleValue();
t += (n - m) * (n - m);
return Math.sqrt(t / (myDoubleValues.size() - 1.0));// n - 1 as sample varience
* return the number of values of myDoubleValues to help calculate the mean & standard deviation
* @return the size of myDoubleValues as a Double
public double getDoubleValues() {
return myDoubleValues.size();
* compute the number of null values
* @return a double value representing the number of null values
public Double getDoubleNull() {
Double nbNull = 0.0;
// test if myIntValues is null
if (myDoubleValues == null) {
System.out.println("Please enter values that are not null!");
return 0.0;
// if not null, parse all values
// for each value, test if it is null or not
Double currentDouble;
for (double i = 0; i < myDoubleValues.size(); i++) {
currentDouble = myDoubleValues.elementAt((int)i);
if (currentDouble != null) {
/// nothing to do
else {
nbNull++;
return nbNull;
//find the MIN values in the Hashtable to give us the range (with the MAX value)
public Double MinDouble()
Double MinDouble = null;
Double currentValue;
for (double j = 0; j < myDoubleValues.size(); j++)
currentValue = myDoubleValues.elementAt((int) j);
if (currentValue != null){
if (currentValue <= MinDouble) {
MinDouble = currentValue;
return MinDouble;
/*find the MAX value in the Hashtable to give us the range (with the MIN value)
public double MAX()
* Create an instance of StoreValuesDouble to hold vector values and number of times the values
* appear. StoreValuesDouble automatically contains the variables defined above
* (myDoubleValues, myValues and nullValues) we have to initialise myDoubleValues and myValues
* as they have been defined but not initialised. nullValues has been defined (int) and initialised (0).
* @param Vector /<Double/> a vector holding Double values
* @param inValues the values in the vector
* @return
public StoreValuesDouble(Vector<Double> inValues) {
myDoubleValues = inValues; //the attribute myDoubleValues defined in the StoreValuesDouble class
//is the inValues parameter, this allows us to store the Vector in inValues
myValues = new Hashtable<Double, Double>(); // create an instance of/initialise Hashtable
* Now define the methods to make the instance StoreValuesDouble do what we want it to do
* (ie parse all the double values of the myDoubleValues Vector attribute.
public void computeDoubleValues() {
Double currentDouble;//local variable to store the current read Double object
* Use a for loop to read through all the values contained in the vector
for (double i = 0; i < myDoubleValues.size(); i++) {
currentDouble = myDoubleValues.elementAt((int)i);
//currentDouble is now the Double object stored at i
//to check that i is not null we use the if statment
if (currentDouble != null) {
//i is not null so we want to add it to the hashtable. Rather than writing a lot of code
//here to do checking and adding we just call a method that can be written seperately
updateDoubleTable(currentDouble);
else {
//i is null so we just count it by adding it to our nullValues attribute
nullValues++;
* Update the current distribution of Doubles
* @param Double for the value of the key
* @param inDouble for the value entered into the Hashtable (the object)
public void updateDoubleTable(Double inDouble) {
//First test that variable inDouble is not null
if (inDouble != null) {
//update the table myValues this involves two tasks
//1)see if the double object has already been seen
//so we create a local variable to test the Hashtable
boolean alreadyPresent;
alreadyPresent = myValues.containsKey(inDouble);
//here we check whether inDouble is already in myValues
if (alreadyPresent) {
//if it is present we need to increase the counter
Double counter = myValues.get(inDouble);
//local variable counter to get the value associated to the key inDouble
Double newCounter = new Double(counter.intValue() + 1.0);
//update counter values and then ...
myValues.put(inDouble, newCounter);
//put into myValues
//as Hashtable can store only Objects, we cannot use primitive types
// so we use Objects related to primitive types as Integer, Float, Double
// or Boolean (here, we use Double)
} else {
//store the double and set it's counter to 1
myValues.put(inDouble, new Double(1));
} else {
//do nothing
//now we want to display the values
public void displayDoubleTable() {
// to display the distribution, we need to parse all the keys of the
// hashtable and access to the value associated to each key
Enumeration<Double> keys = myValues.keys();
Double currentKey;
Double currentValue;
System.out.println("");
System.out.println("Hashtable Information:");
System.out.println("");
System.out.println(myDoubleValues.size() + " Double objects in initial vector");
System.out.println("");
while (keys.hasMoreElements()) {
currentKey = keys.nextElement();
currentValue = myValues.get(currentKey);
System.out.println("The value " + currentKey.doubleValue()
+ " has been seen " + currentValue.doubleValue()
+ " time(s) in the initial Vector");
System.out.println("");
System.out.println("There were " + nullValues
+ " null Double object(s) in the inital Vector");
}As part of the StoreValuesDouble class. And to display it.
package statistics;
import java.util.Vector;
public class TestStatDouble {
static Vector<Double> doubleVector;
* Create and initialise a vector of values and compute the mean,
* standard deviation, distribution and MIN/MAX values.
public static void main(String[] args) {
// initialise the values in initValues
initValues();
// create an instance of StoreValuesDouble taking double as the parameter
StoreValuesDouble is = new StoreValuesDouble(doubleVector);
//Display the results
displayVectorContent(doubleVector);
System.out.println("");
System.out.println("Number of null values: " + is.getDoubleNull());
System.out.println("Number of non-null values is: " +(is.getDoubleValues() - is.getDoubleNull()));
System.out.println("Number of all values: " + is.getDoubleValues());
System.out.println("The mean is: " + is.meanDouble());
System.out.println("Standard deviation is: " + is.standardDeviationDouble());
System.out.println("The lowest value is " + is.MinDouble());
System.out.println("");
* now I want to display the results from the displayTable method in the StoreValuesDouble
* class so I create an instance of StoreValuesDouble and use the computeDoubleValues and
* displayDoubleTable methods.
StoreValuesDouble storeValues = new StoreValuesDouble(doubleVector);
storeValues.computeDoubleValues();
storeValues.displayDoubleTable();
* create the class method initValues() to add values to the Vector doubleVector
public static void initValues()
doubleVector = new Vector<Double>();
doubleVector.addElement(null);
doubleVector.addElement(new Double(10.9));
doubleVector.addElement(new Double(15.95));
doubleVector.addElement(new Double(17));
doubleVector.addElement(null);
doubleVector.addElement(new Double(1));
doubleVector.addElement(new Double(4));
doubleVector.addElement(new Double(10.499));
doubleVector.addElement(null);
doubleVector.addElement(new Double(10.4999));
doubleVector.addElement(new Double(17));
doubleVector.addElement(new Double(-15));
doubleVector.addElement(null);
doubleVector.addElement(new Double(14));
doubleVector.addElement(new Double(20));
doubleVector.addElement(new Double(-3));
doubleVector.addElement(null);
doubleVector.addElement(new Double(9));
doubleVector.addElement(new Double(1.5));
doubleVector.addElement(null);
doubleVector.addElement(new Double(10.22));
doubleVector.addElement(new Double(15.23));
doubleVector.addElement(new Double(17.91));
doubleVector.addElement(null);
* class method to print values contained in the vector doubleVector to the console.
* @param doubleVector the Vector to be displayed
public static void displayVectorContent(Vector doubleVector)
Double currentDouble;
System.out.println("Double values within the Vector:");
for (int i=0; i<doubleVector.size();i++)
try
currentDouble = (Double) doubleVector.elementAt(i);
if (currentDouble != null)
System.out.print(currentDouble.toString() + " ");
catch(ClassCastException cce)
System.out.print(cce.getMessage() + " ");
cce.printStackTrace();
System.out.println("");
It compiles fine but when I try and run it I get a
Exception in thread "main" java.lang.NullPointerException
at statistics.StoreValuesDouble.MinDouble(StoreValuesDouble.java:139)
at statistics.TestStatDouble.main(TestStatDouble.java:37)
TestStatDouble 37 is
System.out.println("The lowest value is " + is.MinDouble());139 is
if (currentValue <= MinDouble) {I guess the problem's in my if loop but I'm not sure why. Any help would be appreciated.
Message was edited by:
Ali_DCouple of points about your code:
1. Don't declare your instance variables as solid types, declare them using their interfaces (where applicable), so in your case don't specifiy that you are using Vector or Hashtable, use List and Map. This will allow you to easily change your code to use a different collection, if and when appropriate. Also the unnecessary overhead of Vectors synchronisation means that you should use ArrayList instead of vector (that means that you will have to use get(int) instead of elementAt() but that's a very small price to pay.
2. Declare local variables as close to their point of usage as possible. (Unless you need to do this for your course work, in which case you don't have a choice).
3. Use the appropriate data type. For your count of null values you should be using an int or a long (you can't have a fractional count value!) Also, this should have been obvious to you, when you had to cast the value to an int for use with your lists. (Using double as an index is a very bad idea... And before you go posting the question, do a search on why floating point precision may not give you the results you expect)
4. Code defencively... e.g. in your meanDouble() method, you set nonNull to 0, and then you do a division using that value. What do you think is going to happen if your loop doesn't execute once? Division by zero... You should handle these cases, rather than letting them fail ignominiously.
5. If you are doing code like this... if (currentDouble != null) {
// / nothing to do
} else {
nbNull++;
} Why have the empty block? You should just do the inverse.
if (currentDouble == null) {
nbNull++;
} Far simpler, and expresses exactly what you are trying to do, not what you are not trying to do.
6. Enumeration --- What version of java is that course being run in? I can see that you are using autoboxing, so it has to be 1.5 so, WHY is your lecturer encouraging the use of Vectors, Hashtables, and Enumerations!?!?!
Anyway, that should be enough to be going on with. -
The situation:
I want to use basetext font, but some of the glyphs are missing in it, and are highlighted with pink boxes. common font [stix, etc.] have much more glyphs than basetext font. I can apply common font [stix, etc.]manually for each of the missing glyphs or insert two character and use kerning set it up, but it is tedious.
Question:
How find the missing glyph using javascript [like indesign preflight], and replace same glyph available font or insert two character and use kerning set it up?
Any one know how to do this?
Thanks in Advance,
~JackTry Peter kehrl's script
http://www.kahrel.plus.com/indesign/missing_glyphs.jsx -
How to use my findTheHighest method to find the highest value in my two dim
I am going to create a 13row by 10 colume two dimensional array.
how to use my findTheHighest method to find the highest value in my two dimensional array.
.When i compile this program , i got those as following;
"Exception in thread "main" java.lang.ArrayIndexOutOfBoundsExce
at TaxEvolution.findTheHighest(TaxEvolution.java:31)
at TaxEvolutionClient.main(TaxEvolutionClient.java:25)"
public class TaxEvolution{
public double[][] salesTaxRates;
public TaxEvolution()
salesTaxRates = new double[13][10];
fillProvinTaxRates();
private void fillProvinTaxRates()
for ( int row = 0; row < salesTaxRates.length; row++ )
for ( int column = 0; column < salesTaxRates[row].length; column++ )
salesTaxRates[row][column]= (int)(Math.random()*5000) + 1;
public double findTheHighest()
double highest = salesTaxRates[0][0];
for ( int row = 0; row <= salesTaxRates.length; row++ )
for ( int column = 0; column <= salesTaxRates[row].length; column++ )
if ( salesTaxRates[row][column] >= highest )
highest = salesTaxRates[row][column];
return highest;
public double[][] arrayTaxEvolution()
double[][] returnTaxRates = new double[13][10];
for ( int row = 0; row < salesTaxRates.length; row++ )
for ( int column = 0; column < salesTaxRates[row].length; column++ )
returnTaxRates = salesTaxRates;
return returnTaxRates;
public class TaxEvolutionClient{
public static void main( String[] args ){
TaxEvolution protaxRateList = new TaxEvolution();
double[][] taxRateList = protaxRateList.arrayTaxEvolution();
for ( int i = 0; i < taxRateList.length; i++ )
for ( int j = 0; j < taxRateList[0].length; j++ )
System.out.print( taxRateList[i][j] + "\t" );
System.out.print( protaxRateList.findTheHighest + "\t" );
}Multiposted
http://forum.java.sun.com/thread.jspa?threadID=699057&tstart=0 -
Finding the largest values of an array without using if condition
Hi,
I am trying to find the largest values of an array without using any if condition. Can any one tell me the solution for that..
ThanksI am trying to find the largest values of an arrayThe 'S' to values suggests that you want not only the largest one, but multiple ones among the largest ones. The best way, I think, is to sort the array, so that its largest values are grouped topgether. If the type is already Comparable, the following single line does the job:
Collections.sort(myArray);After this, the last values of the array are the largest ones.
Jerome. -
Hi team,
I have the following query where i need to find the max value
[code]
with t as (
select 'L1' R_nm ,'Data' R_Data , 'Obj' R_Obj , 'Wd' r_prec , '2' val from dual
union all
select 'L1' , 'Data', 'Obj' , 'No', '4' from dual
union all
select 'L2' , 'Data', 'Obj' , 'No', '4' from dual )
select t.*, max(val) over(partition by r_nm,r_data,r_obj) rk from t
[/code]
My expected output should be
[code]
r_nm r_data r_obj r_prec val rk
L1 Data Obj Wd 2 1
L1 Data Obj No 4 2
L2 Data Obj Yes 1 1
[/code]
Thank YouHi,
It looks like you're not interested in the MAX at all. It looks like you want to rank the rows, such that the one with the lowest value is assigned the number 1, the row with the 2nd lowest values gets 2, ..., and the row with the N-th lowest value gets N. If doesn't matter if the MAX is 4, or 2, or 420.
Here's one way to do that:
SELECT t.*
, RANK () OVER ( PARTITION BY r_nm, r_obj
ORDER BY val
) AS rk
FROM t
ORDER BY r_nm, r_obj
, val
Depending on how you want to deal with ties, you might want to use ROW_NUMBER or DENSE_RANK instead of RANK. -
How to find the FND_PROFILE.VALUE(ORG_ID) in custom apex schema
Hi,
How to find the FND_PROFILE.VALUE('ORG_ID') from dual in custom schema......
Actually I have integrated Apex 4.2 version with EBS r12
select FND_PROFILE.VALUE('ORG_ID') from dual ; in apps schema I m getting 198 value
but the same query(select apps.FND_PROFILE.VALUE('ORG_ID') from dual ) in custom schema (XXCVBB) returning null value..
Is there any pre steps I have to do...
kindly provide the useful inputs to retrieve the profile value..........
Regards,
PavanHi,
fnd_profile.value('ORG_ID'); will fetch you value only if there is a organization assigned to any application [or only if its a single Org], being it custom application you should have used set policy context or mo_global.init to populate the global temporary table which will hold all the Org's which that specific user has access too.
in your custom code use MO_GLOBAL.SET_POLICY_CONTEXT('S','ORG ID WHICH YOU NEED TO SET');
after setting the policy context, you should be able to see value from fnd_profile.value('ORG_ID');
Hope this Helps!!
MO_GLOBAL.SET_POLICY_CONTEXT
This procedure has two parameters
p_access_mode
Pass a value "S" in case you want your current session to work against Single ORG_ID
Pass a value of "M" in case you want your current session to work against multiple ORG_ID's
p_org_id
Only applicable if p_access_mode is passed value of "S"
MO_GLOBAL.INIT
Purpose of mo_global.init :-
It will check if new Multi Org Security Profile is set, to decide if new Security Profile method will be used.
If the new MO security profile is set, then mo_global.init inserts one record, for each Organization in Org Hierarchy, in table mo_glob_org_access_tmp
Regards,
Yuvaraj -
Finding the smallest value from an array
Hi there :)
I started learning Java a few days ago and have now run into my first problem :p
I am using Netbeans on Mac OS X.
I need to find the smallest value from an array. So far I've had no luck. Any suggestions would be fantastic.
The code so far:
* Math Problems
* Created on May 4, 2007, 10:54 AM
* PROJECT 1: - IN PROGRESS
* Create a program that allows you to create an integer array of 18 elements with the following values
* 3, 2, 4, 5, 6, 4, 5, 7, 3, 2, 3, 4, 7, 1, 2, 0, 0, 0
* - The program computes the sum of elements 0 to 14 and stores it in element 15 // COMPLETED
* - The program computes the average and stores it in element 16 // COMPLETED
* - The program finds the smallest value from the array and stores it in element 17
* PROJECT 2: - TO DO
* Write a program that accepts from the command line and prints them out. Then use a for loop to print
* the next 13 numbers in the sequence where each number is the sum of the previous two. FOR EXAMPLE:
* - input>java prob2 1 3
* - output>1 3 4 7 11 18 29 47 76 123 322 521 843 1364
* PROJECT 3: - TO DO
* Write a program that accepts from the command line two numbers in the range from 1 to 40. It then
* compares these numbers against a single dimension array of five integer elements ranging in value
* from 1 to 40. The program displays the message BINGO if the two inputted values are found in the array
* element. FOR EXAMPLE:
* - input>java prob3 3 29
* - output>Your first number was 3
* - Your second number was 29
* - Its Bingo! // This message if 3 and 29 are found in the array
* - Bokya! // This message if 3 and 29 are not found in the array
* - The array was 7 5 25 5 19 30
* PROJECT 3 EXTENSION: - OPTIONAL
* Generate the array of 5 unique integers using random numbers
package mathproblems;
* @author Mohammad Ali
public class Main {
/** Creates a new instance of Main */
public Main() {
* @param args the command line arguments
public static void main(String[] args) {
int A[]={3,2,4,5,6,4,5,7,3,2,3,4,7,1,2,0,0,0};
int O = A.length - 3;
int B = A[0] + A[1] + A[2] + A[3] + A[4] + A[5] + A[6] + A[7] + A[8] + A[9] + A[10] + A[11] + A[12] + A[13] + A[14];
A[15] = B; // Stores the sum of the integers in A[15]
int C = B / O;
A[16] = C; // Computes and stores the average in A[16]
int D = 101;
if (A[0] < A[1]) { D = A[0]; }
else { D = A[1]; }
if (A[1] < A[2]) { D = A[1]; }
else { D = A[2]; }
System.out.println("There are " + O + " numbers in the Array");
System.out.println("Those numbers add up to " + B + ".");
System.out.println("The average of those numbers is " + C + ".");
System.out.println("The smallest value in the array is " + D + ".");
}The code is incomplete, but it works so far. The problem is I know there must be an easier way. SAVE ME :)OK :)
Just thought I should show you the output as to help anyone else with the same problem:
* Math Problems
* Created on May 4, 2007, 10:54 AM
* PROJECT 1: - IN PROGRESS
* Create a program that allows you to create an integer array of 18 elements with the following values
* 3, 2, 4, 5, 6, 4, 5, 7, 3, 2, 3, 4, 7, 1, 2, 0, 0, 0
* - The program computes the sum of elements 0 to 14 and stores it in element 15 // COMPLETED
* - The program computes the average and stores it in element 16 // COMPLETED
* - The program finds the smallest value from the array and stores it in element 17 // COMPLETED
* PROJECT 2: - TO DO
* Write a program that accepts from the command line and prints them out. Then use a for loop to print
* the next 13 numbers in the sequence where each number is the sum of the previous two. FOR EXAMPLE:
* - input>java prob2 1 3
* - output>1 3 4 7 11 18 29 47 76 123 322 521 843 1364
* PROJECT 3: - TO DO
* Write a program that accepts from the command line two numbers in the range from 1 to 40. It then
* compares these numbers against a single dimension array of five integer elements ranging in value
* from 1 to 40. The program displays the message BINGO if the two inputted values are found in the array
* element. FOR EXAMPLE:
* - input>java prob3 3 29
* - output>Your first number was 3
* - Your second number was 29
* - Its Bingo! // This message if 3 and 29 are found in the array
* - Bokya! // This message if 3 and 29 are not found in the array
* - The array was 7 5 25 5 19 30
* PROJECT 3 EXTENSION: - OPTIONAL
* Generate the array of 5 unique integers using random numbers
package mathproblems;
* @author Mohammad Ali
import java.util.Arrays;
public class Main {
/** Creates a new instance of Main */
public Main() {
* @param args the command line arguments
public static void main(String[] args) {
int A[]={3,2,4,5,6,4,5,7,3,2,3,4,7,1,2,0,0,0};
Arrays.sort(A);
System.out.println("The smallest value in the array is " + A[0] + ".");
int num = A.length;
System.out.println("There are " + num + " values in the Array.");
int sum = 0;
for (int i = 0; i < A.length; i++) {
sum+=A;
System.out.println("Those numbers add up to " + sum + ".");
double d = (double)sum/num;
System.out.println("The average value of those numbers is " + d + ".");
What Iearned:
1) How to create for loops properly
2) How to import java.util.Arrays ( =D )
3) How to get a more accurate average using double instead of int
4) This forum is the best and has very helpful people 24/7 ( =D)
Thanks Again,
Mo. -
Hi guys,
I'm creating a method where it finds the largest value in a list of integers, using a loop. When it finds it, it's stored in the "max" and returns the "max".
Here's the code...
public Integer findMax()
List<Integer> list = Arrays.asList(4,8,2,10,24);
int max = 0;
for(Integer i = 0 ; i < list.size() ; i++) {
if(max == list.get(i))
max = i;
return max;
}It complies, but when i run it, it doesn't actually get the largest value (which should be 24). It's still 0 when i Inspect it.
Does anybody know where i'm going wrong with this?Well i went through the method and it seems to be printing 0 five times...
public Integer findMax()
List<Integer> list = Arrays.asList(4,8,2,10,24);
int max = 0;
for(Integer i = 0 ; i < list.size() ; i++) {
if(max >= list.get(i))
max = list.get(i);
System.out.println(max);
return max;
}After looking looking through the API, i used the length, instead of size, but when i compile the program it says it can't find the method. Do you know what else i have to change or add in the code for it to compile?
DrClap wrote:
if(max == list.get(i)) Can you explain, in words, what this comparison was meant to do?I've edited that, because that's wrong.
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