Flex 4.5 Mobile Login Form needs 2 clicks???

Hi,
I have been working on developing an application for the android market thta firstly requires the users to login to a account. I have put the code together below, along with a data link to a database in order to check the credentials. However the application does not switch to the second view on the first click of the "Login" button however it seems to take 2 or more clicks sometimes. I presume as it is fetching data from a database that it takes time to be verifies, could someeone tell me how to solve this and maybe implement a BusyIndicator along with it?
<![CDATA[
               protected function login_btn_clickHandler(event:MouseEvent):void
                    var match:Boolean;
                    getEmployeesByNameResult.token = employeeService.getEmployeesByName(usr_nme_txtbox.text, pass_txtbox.text);
                    if (getEmployeesByNameResult.lastResult != null)
                         navigator.pushView(HomeView, getEmployeesByNameResult.lastResult.id);
          ]]>
<s:Button id="login_btn" width="100%" label="Login"
                                click="login_btn_clickHandler(event)"/>
Thanks

hi
try putting the pushView code inside the result handler for employeeService - currently you are checking login details immediately but as you say, you need to wait for the server response (which will trigger the result handler)
the easiest way to handle busy indicator is probably to use states - ie: a 'login' state that shows the login controls and a "busy" state that displays "connecting" or some other indicator for the user. then switch states at the appropriate time

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Flash Builder 4.5 Mobile Login Form needs 2 clicks???

Hi,
I have been working on developing an application for the android market thta firstly requires the users to login to a account. I have put the code together below, along with a data link to a database in order to check the credentials. However the application does not switch to the second view on the first click of the "Login" button however it seems to take 2 or more clicks sometimes. I presume as it is fetching data from a database that it takes time to be verifies, could someeone tell me how to solve this and maybe implement a BusyIndicator along with it?
<![CDATA[
               protected function login_btn_clickHandler(event:MouseEvent):void
                    var match:Boolean;
                    getEmployeesByNameResult.token = employeeService.getEmployeesByName(usr_nme_txtbox.text, pass_txtbox.text);
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                         navigator.pushView(HomeView, getEmployeesByNameResult.lastResult.id);
          ]]>
<s:Button id="login_btn" width="100%" label="Login"
                                click="login_btn_clickHandler(event)"/>
Thanks

(While original poster might have found the solution or given up, I guess it's a good idea to leave the question answered)
The service is asynchronous. You cannot check right after calling, instead you need to use a handler for reading the result.

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I have created a workset in portal which provides links for various BI reports. In the properties of each page for report I set the property to lunch it in headerless window.
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Need some help in the login form ???!?!?!?!!

can any one help me with correcting the code or can any one give me another code for using it in the login form.
this is my problem:-
i had make a login form using in oracle 9i form builder >>>in this form i have three text boxes one for intering user name and the second one for entering the password and the third text box is not visible and it is used for counting the tries.
In addition i have a three buttons , one is for login and the two others are not visible and they are a show main menu button and a exit button. For login button i had put a WHEN-BUTTON-PRESSED trigger in the login button and it must check if the user name and the password match what it is on the login table so it allow the user to see the show main menu button otherwise if the user name or the password are wrong and has been putted wrong for 3 times of trying then it will show the exit button.
and this is a picture of the login form in the design view.
http://www.al7loh.com/uploader/uploads/login.JPG
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declare
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dummy1 tbl_login.USER_NAME%type;
     dummy2 tbl_login.PASS%type;
begin
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     if sql%found
          then
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                                                                           else
                                                                           message ('Invalid password....try again');
                                                                           :LOGIN.TRIES := :LOGIN.TRIES+1;
                                                                           :LOGIN.USER_NAME := null;
                                                                           :LOGIN.PASS := null;
                                                                                end if;
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can any one help me correcting the code of the WHEN-BUTTON-PRESSED trigger on the login form or can any one give me another code for using it in the login form.
i hope to get some help from the experts>>> ??!?!?!?!?!

Something like this
declare
alertNum number;
dummy1 tbl_login.USER_NAME%type;
dummy2 tbl_login.PASS%type;
begin
Begin
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    into   dummy1, dummy2
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Exception
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end;
end;Francois

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Edited by: etech on May 24, 2010 4:39 PM

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</cond>
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at Error$/throwError()
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http://www.ibm.com/developerworks/java/library/j-dao/
http://www.javaworld.com/javaworld/jw-03-2002/jw-0301-dao.html
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http://www.fluffycat.com/java-design-patterns/
http://java.sun.com/blueprints/corej2eepatterns/Patterns/index.html
http://www.cmcrossroads.com/bradapp/javapats.html
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RaHuL

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