FM to find time difference

Hi Experts,
Is there any function module to find time difference between two given time.
Thanks
RR

try using this 1.
SD_CALC_DURATION_FROM_DATETIME

Similar Messages

Function module to find time difference

Can any body help me to find the function module to find the time diff: between two times, time is in 24hrs

Hi again,
1. Difference is always returned in SECONDS.
2. use this code (just copy paste in new program)
REPORT abc.
data : t1 type sy-uzeit.
data : t2 type sy-uzeit.
DATA : DIFF TYPE I.
t1 = '090000'.
t2 = '100000'.
DIFF = T2 - T1.
WRITE :/ DIFF.
regards,
amit m.

Find the Difference in time for creation of two activities for the same SR

Hi
I need to find the difference in time of cretaion of two different activities for an SR. Is there any function which I can use to get the same
For e.g.
SR # |Activity Created Date |Duration
123 12-nov
123 13 nov 1 day
Thanks in advance
Meena

There's a TIMESTAMPDIFF function.
An example from the book Oracle CRM On Demand Reporting has the following example...
TIMESTAMPDIFF( SQL_TSI_MINUTE, Activity."Start Time", Activity."End Time" )
which would return the difference in minutes.
As I type this, I'm thinking you probably know this and your problem is how to get the Activity start time for the next activity into this function. I sorry can't think of any way to do that.

How to find out time difference between 2 consecutive characters coming in

Hi
Data is coming on serial port and m taking this data in a input stream.I need to know the time difdference between consecutive characters.Any ideas?

What do you mean? If you meassure the time between two characters, you want to calculate how accurate it is? First you would need to find out how accurate the System.currentTimeMillis is on the platform you run on. That may be easy
long start = System.currentTimeMillis();
long end;
while ((end = System.currentTimeMills()) == start);
long delta = end - start;But sometimes (on win98) it reports 50, other times 60. So its not quite accurate. But you could redo that test a couple of times and take the avg or the max.
Then if you get a time difference of 0ms between two characters, you know it will be somewhere 0 and 60ms. If you get 60ms between two characters, you know it will be somewhere between 0 and 120 ms. It's +/- delta seconds accurate.
Would this be a way to calculate the percentage accuracy: 100.0-100.0*delta/(time+delta)
Still better to meassure the time over more than just 2 characters unless it is a very slow stream.

I want to find the difference(duration) between logon and logoff time?

i want to find the difference(duration) between logon and logoff time of below table?
can any one tell the query to find using self join?
USR     LOGON_TIME     LOGOFF_TIME
HR     31-AUG-04 03.04.04.000000 AM     -
HR     - 31-AUG-04 03.04.14.000000 AM
Edited by: 794244 on Nov 1, 2010 10:47 PM

No selfjoin, just analytical functions.
CREATE TABLe log_time
(username varchar(20),
LOGON_TIME timestamp,
LOGOFF_TIME timestamp);
insert into log_time (username,LOGON_TIME,LOGOFF_TIME) values ('HR',sysdate,null);
insert into log_time (username,LOGON_TIME,LOGOFF_TIME) values ('HR',null,sysdate+1/38);
insert into log_time (username,LOGON_TIME,LOGOFF_TIME) values ('HR',sysdate+2,null);
insert into log_time (username,LOGON_TIME,LOGOFF_TIME) values ('HR',null,sysdate+2+14/20);
commit;
SELECT username,logon_time,logoff_time, my_logoff_time, my_logoff_time -logon_time,
       time_to_sort
FROM (
        SELECT username,logon_time, logoff_time,
               LEAD(logoff_time,1,logon_time) OVER (PARTITION BY username ORDER BY time_to_sort) my_logoff_time,
               time_to_sort
        FROM (SELECT username,logon_time,logoff_time,NVL(logon_time,logoff_time) time_to_sort
              FROM log_time)
where LOGON_TIME is not null
ORDER BY time_to_sort;
USERNAME     LOGON_TIME     LOGOFF_TIME     MY_LOGOFF_TIME     MY_LOGOFF_TIME-LOGON_TIME     TIME_TO_SORT
HR     02.11.10 11:34:56.000000000          02.11.10 12:12:50.000000000     0 0:37:54.0     02.11.10 11:34:56.000000000
HR     04.11.10 11:34:56.000000000          05.11.10 04:22:56.000000000     0 16:48:0.0     04.11.10 11:34:56.000000000But, if that code which fills that table should better UPDATE than INSERT. You can cover much more issues. (e.g the DB crashes and you get 2 logon but no logoff in a sequence and.....)
-- andy

Extract Time from date and Time and Need XLMOD Funtion to find the Difference between Two Time.

X6 = "1/5/15 5:16 AM" & NOW ....................difference by Only Time
not date
X6 date and Time will be changing, Its not Constant
Dim myDateTime As DateTime = X6
            Dim myDate As String = myDateTime.ToString("dd/MM/yy")
            Dim myTime As String = myDateTime.ToString("hh:mm tt")
            Dim myDateTime1 As DateTime = Now
            Dim myDate1 As String = myDateTime1.ToString("dd/MM/yy")
            Dim myTime1 As String = myDateTime1.ToString("hh:mm tt")
Need to use this function to find the Difference between Two Time. due to 12:00 AM isuue
Function XLMod(a, b)
    ' This replicates the Excel MOD function
    XLMod = a - b * Int(a / b)
End Function
Output Required
dim dd = XLMod(myTime - myTime1)
Problem is myTime & myTime1 is String Need to convert them into Time, Later use XLMOD Funtion.

Induhar,
As an addendum to this, I thought I'd add this in also: If you have two valid DateTime objects you might consider using a class which I put together a few years ago
shown on a page of my website here.
To use it, just instantiate with two DateTime objects (order doesn't matter, it'll figure it out) and you'll then have access to the public properties. For this example, I'm just showing the .ToString method:
Option Strict On
Option Explicit On
Option Infer Off
Public Class Form1
Private Sub Form1_Load(ByVal sender As System.Object, _
ByVal e As System.EventArgs) _
Handles MyBase.Load
Dim date1 As DateTime = Now
Dim date2 As DateTime = #1/1/1970 2:35:00 PM#
Dim howOld As New Age(date1, date2)
MessageBox.Show(howOld.ToString, "Age")
Stop
End Sub
End Class
I hope that helps, if not now then maybe at some point in the future. :)
Still lost in code, just at a little higher level.
Thanx frank, can use this in Future....

Function Module to find the Difference between two times.

Hi All,
Wud you plz let me know the Function Module to find the Difference between two times.
Input Time1( Hours:Minutes) Time2 ( Hours:Minutes)
Need Output in Hours:Minutes only . ( No seconds Needed )
Ex :
Input :
       06:00 to 18:00 Output : 12:00
and 20:00 to 06:00 Output: 10:00 with +ve sign only. No -ve sign.
Thanks,
N.L.Narayana

check this .
data : p_timel like sy-uzeit,
       p_timeh like sy-uzeit,
       diff like sy-uzeit,
       di(8) type c .
       p_timel = '200000'.
       p_timeh = '060000'.
       diff = p_timeh - p_timel.
       concatenate diff+0(2) ':' diff+2(2) into di.
       write:/ di.
also check for this.
       p_timel = '060000'.
       p_timeh = '180000'.
see if this can be implemented in ur code .
or else u can try with Fm L_TO_TIME_DIFF passing startdate enddate starttime endtime with UOM as MIN
hope this helps regards,
vijay

Help I need to subtract times to find the difference between two times?

Hello there, I really need help.
I'm trying to make this attendance tracking system so that when a user enters his or her ID the system wll remember his/her check in time. However I also need to find out either how late the person is or how early to store their over time and late.
So I get the time by using a timestamp, so I'm left with a timestamp that I store into the db. But the problem comes when trying to compute for the late or over time. To do that I have to get the normal login/checkin time from the employee schedules table in the db and either subtract that time from the checkInTime to compute for how late or subtract the checkIn time from it to find early.
The thing is, the schedule is stored in datetime format in the db since the db is sql. Also I have no idea on how to subtract the two dates via java. The month, date and year stored in the sql db are just fillers, all I need computed is the time difference of the hours and minutes between the checkInTime and the schedule.
I've tried to use datediff: SELECT e.employeeNumber, datediff('hh', startTime, checkInTime) as lateTime from employeeschedules e, timandattendance, contractualemployees c where c.scheduleNumber=e.scheduleNumber and t.employeeNumber=c.employeeNumber and t.checkInNumber=1;
But it keeps on giving out various errors: You have an error in your sql syntax check your manual that corresponds to your sql server version. for the right syntax to use near , checkInTime) as lateTime from employeeschedules e, timandattendance, contractualemployees c where c.scheduleNumber=e.scheduleNumber and t.employeeNumber=c.employeeNumber and t.checkInNumber=1;
My sql server is My SQL 5.0.5
Now I'm thinking of useing Gregorian instead, but I don't know how to use Gregorian and dont know the various methods. Can someone tell me what to do, provide some sample codes and references that I can use to accomplish what I need to do?

NewtonsApple_2 wrote:
Now I'm thinking of useing Gregorian instead, but I don't know how to use Gregorian and dont know the various methods. Can someone tell me what to do, provide some sample codes and references that I can use to accomplish what I need to do?it may help...
GregorianCalendar

How to find the difference between 2 time values in Java

hi all,
i have 2 time values
String time1="6:20";
String time2="21:30"
How to find the difference between 2 times in Java?
pls help
thanx in advance....

Calculating Java dates: Take the time to learn how to create and use dates
Working in Java time: Learn the basics of calculating elapsed time in Java
Formatting a Date Using a Custom Format
Parsing a Date Using a Custom Format

How to find the time difference..?

HI
How to find the time difference between two times
for Example
the difference between '24/10/2005 8:25:00 PM' and '25/10/2005 5:20:00 AM'
is 8.55
Kris

This is a procedure taht do the job
CREATE OR REPLACE FUNCTION Diff_Time
     LD$Date_Deb IN DATE DEFAULT SYSDATE
     ,LD$Date_Fin IN DATE DEFAULT SYSDATE
     ,LN$JJ       OUT PLS_INTEGER
     ,LN$HH       OUT PLS_INTEGER
     ,LN$MI       OUT PLS_INTEGER
     ,LN$SS       OUT PLS_INTEGER
) RETURN NUMBER
IS
dif   NUMBER ;
BEGIN
IF LD$Date_Fin < LD$Date_Deb THEN
     RETURN ( -1 ) ;
END IF ;
SELECT LD$Date_Fin - LD$Date_Deb INTO dif FROM dual ;
SELECT TRUNC ( LD$Date_Fin - LD$Date_Deb) INTO LN$JJ FROM dual ;
SELECT TRUNC ( (LD$Date_Fin - LD$Date_Deb) * 24) - ( LN$JJ * 24 ) INTO LN$HH FROM dual ;
SELECT TRUNC ( (LD$Date_Fin - LD$Date_Deb) * 1440) - ( (LN$HH * 60) + ( LN$JJ * 1440) ) INTO LN$MI FROM dual ;
SELECT TRUNC ( (LD$Date_Fin - LD$Date_Deb) * 86400) - ( (LN$MI * 60) + (LN$HH * 3600) + ( LN$JJ * 3600 * 24 ) ) INTO LN$SS FROM dual ;
RETURN( dif ) ;
END ;
/You may have to modify it to fit your own requirement.
Francois

How to find the date and time difference in InfoPath 2013?

Hi All,
My date and time format is like: 2013-12-24T10:47:38 and have three fields Start date, End date and Actual time taken.
If start date and end date filled then actual time taken field should automatically should fill, for example 2 days 12 hours 48 min 3 sec.
How to achieve this?

Hi Sam,
I believe we had discussed the same issue in the below thread. Can you please refer the below one?
http://social.msdn.microsoft.com/Forums/sharepoint/en-US/d93e16ff-c123-4b36-b60b-60ccd34f6ca7/calculate-time-differences-in-infopath?forum=sharepointcustomizationprevious
If it's not helping you please let us know
Sekar - Our life is short, so help others to grow
Whenever you see a reply and if you think is helpful, click "Vote As Helpful"! And whenever
you see a reply being an answer to the question of the thread, click "Mark As Answer

How to calculate the % of time difference between different state

Hi there,
The below query returns the follwoign outptut. I need to calculate the % of time period that a specific state ( state ex: open or closed or all report )exists.
I have to find the time difference between the 2 states . How could I do that ?
The first row shows null for the previous state . How could get actual previous state for the first row?
SELECT si.station_name,
                vppstation.avi_control_state_code.STATE_SHORT_NAME,
                ash.state_id ,
                lag(ash.state_id) over (order by ash.STATE_EFF_DATE desc) previous_state,
                TO_NUMBER(TO_CHAR(ash.state_eff_date, 'SSSSS')) "periods in sec",
                TO_CHAR(ash.state_eff_date, 'dd-mon-yyyy hh24:mi:ss am') "Date"
           from vppstation.avi_state_history ash
left outer join vppstation.avi_control_state_code
             on ash.state_id = vppstation.avi_control_state_code.state_id
LEFT OUTER JOIN vpproadside.stations_installed si
             ON ash.station_id = si.station_id
          where ash.state_eff_date >= to_date('28/02/2010', 'dd/mm/yyyy')
            and ash.state_eff_date <= to_date('03/03/2010', 'dd/mm/yyyy') ;
       group by si.station_name
                     ash.state_id
       order by ash.state_eff_date asc ;
STATION_NAME                   STATE_SHORT_NAME STATE_ID               PREVIOUS_STATE         periods in sec         Date
IRDNCST02                      Open             1                    NULL                  85166                  01-mar-2010 23:39:26 pm
IRDNCST02                      All Report       3                      1                      85159                  01-mar-2010 23:39:19 pm
IRDNCMT01                      Closed           2                      3                      81376                  01-mar-2010 22:36:16 pm
IRDNCST02                      Open             1                      2                      78723                  01-mar-2010 21:52:03 pm
IRDNCST02                      All Report       3                      1                      76023                  01-mar-2010 21:07:03 pm
IRDNCMT01                      Open             1                      3                      55922                  01-mar-2010 15:32:02 pm
IRDNCMT01                      Closed           2                      1                      54931                  01-mar-2010 15:15:31 pm
IRDNCHA01                      Closed           2                      2                      41291                  01-mar-2010 11:28:11 am
IRDNCAS01                      Open             1                      2                      38847                  01-mar-2010 10:47:27 am
IRDNCAS01                      All Report       3                      1                      37947                  01-mar-2010 10:32:27 am
IRDNCST02                      Open             1                      3                      35332                  01-mar-2010 09:48:52 am
IRDNCST02                      All Report       3                      1                      32632                  01-mar-2010 09:03:52 am
IRDNCST02                      Open             1                      3                      31502                  01-mar-2010 08:45:02 am
IRDNCST02                      All Report       3                      1                      28802                  01-mar-2010 08:00:02 am
IRDNCHI01                      Open             1                      3                      25368                  01-mar-2010 07:02:48 am
IRDNCHI02                      Open             1                      1                      23939                  01-mar-2010 06:38:59 am
IRDNCMT01                      Open             1                      1                      20696                  01-mar-2010 05:44:56 am
IRDNCCH02                      Open             1                      1                      13452                  01-mar-2010 03:44:12 am
Edited by: Indhu Ram on Mar 11, 2010 1:34 PM
Edited by: Indhu Ram on Mar 11, 2010 2:20 PM

If you look at the table which is output of the given query , there is column called "STATE_ID" It shows the current state ie open or closed or all report.
The column 'PREVIOUS_STATE' shows the state before the current state. .In the table in 2nd row in previous_state column there is state_id = 1 (open)which is the state before 'all report state'

Calculate time difference in Labview from excel file

I am reading in values from a excel files, the file contains date and time data in one cell, then either an On or Off value in the cell next to it. I would like to find the time difference between the on and the off cycles. The VI I have so far brings in the Excel file but I don't know how to subtract the dates. Any help would be appreciated. I have attached the vi and hopefully I can attach and example excel file.
Attachments:
Hobo Import.vi ‏156 KB

Hi Bryan!
I made a small VI (in LabVIEW 7.1) that converts to strings (of your format) to timestamp datatype and then subtracts them resulting in a difference measured in seconds. There might be a more optimal way to do this in your application, but I thought I'd at least try to contribute. Also, notice that there is a Y3K bug in there :-)
Hope this helps!
Travis H.
National Instruments
Travis H.
LabVIEW R&D
National Instruments
Attachments:
FormattoTimeStamp.vi ‏38 KB

How to write a query to get the time difference of two varchar type time columns

Hi,
I want to get the time difference between the two varchar type columns.please see the attached image for more details:
My requirement is like:
timestarted
timeended
timediff
9:00:00
10:00:00
1:00
9:15
9:30:00
0:15

Storing time alone as VARCHAR2 value is a incorrect design. Always store it as DATE or TIMESTAMP.
If you already have a messed up design and cant change it, then you need to convert your VARCHAR2 time into a DATE or TIMESTAMP and find the difference. I have converted it to TIMESTAMP and obtained the difference as INTERVAL.
SQL> with t
2 as
3 (
4 select '09:00:00' timestarted, '10:00:00' timeended from dual
5 union all
6 select '09:15:00' timestarted, '09:30:00' timeended from dual
7 )
8 select timestarted
9       , timeended
10       , (timeended - timestarted) day to second diff
11    from (
12          select to_timestamp('01011900' || timeended, 'ddmmyyyyhh24:mi:ss') timeended
13               , to_timestamp('01011900' || timestarted, 'ddmmyyyyhh24:mi:ss') timestarted
14            from t
15         );
TIMESTARTED                                        TIMEENDED                                          DIFF
01-JAN-00 09.00.00.000000000 AM                    01-JAN-00 10.00.00.000000000 AM                    +00 01:00:00.000000
01-JAN-00 09.15.00.000000000 AM                    01-JAN-00 09.30.00.000000000 AM                    +00 00:15:00.000000
SQL>

Avg Time Difference of Two timestamps in Oracle SQL

Hello Members,
I am trying to find the average of Time Difference of two timestamp columns by order number. I need to show the average of the time difference in hours:mins format. I have is SQL Server , but unable to get this in Oracle SQL. Could anyone please let me know how I need to find the time difference of two timestamp columns and show them in hh:mm fomat and then take average of these differences and show them in hh:mm format. Below is what I have tried in SQL server.
CREATE TABLE temp
startdate smalldatetime,
enddate smalldatetime
INSERT temp
SELECT '6/22/2013 19:00',
'6/22/2013 19:20'
UNION ALL
SELECT '6/22/2013 19:22',
'6/22/2013 19:44'
UNION ALL
SELECT '6/22/2013 19:45',
'6/22/2013 19:50'
UNION ALL
SELECT '6/22/2013 19:52',
'6/22/2013 20:02'
UNION ALL
SELECT '6/22/2013 20:05',
'6/22/2013 20:10'
UNION ALL
SELECT '6/22/2013 20:15',
'6/22/2013 20:20'
SELECT CAST
CAST
( SUM
DATEDIFF(MINUTE,startdate,enddate)
6*60
As float)
as varchar) + ':' +
cast
cast
cast
SUM
DATEDIFF(MINUTE,startdate,enddate)
6
as int )
% 60 as float )
as varchar ) AS avg_time_diff_in_hh_mm_format
FROM temp
Please let me know if you need additional information.
Thanks in Advance.

Thanks for the reply Frank,
I have tried some similar lines with your suggested approach, please see below:
--DDL
CREATE TABLE XX_ORD_TIMES
(ORDER_NUM NUMBER(15),
         ACTUAL_START_DATE DATETIME,
         ACTUAL_FINISH_DATE DATETIME)
--Sample Data
Insert into XX_ORD_TIMES
   (ORDER_NUM, ACTUAL_START_DATE, ACTUAL_FINISH_DATE)
Values
   ('SFM-07', TO_DATE('06/20/2013 14:22:58', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('06/21/2013 07:58:55', 'MM/DD/YYYY HH24:MI:SS'));
Insert into XX_ORD_TIMES
   (ORDER_NUM, ACTUAL_START_DATE, ACTUAL_FINISH_DATE)
Values
   ('SFM-07', TO_DATE('06/21/2013 09:12:42', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('06/21/2013 09:18:15', 'MM/DD/YYYY HH24:MI:SS'));
Insert into XX_ORD_TIMES
   (ORDER_NUM, ACTUAL_START_DATE, ACTUAL_FINISH_DATE)
Values
   ('SFM-07', TO_DATE('06/20/2013 15:59:07', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('06/20/2013 17:06:17', 'MM/DD/YYYY HH24:MI:SS'));
Insert into XX_ORD_TIMES
   (ORDER_NUM, ACTUAL_START_DATE, ACTUAL_FINISH_DATE)
Values
   ('SVCEXT', TO_DATE('05/16/2013 11:56:05', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('05/24/2013 14:47:54', 'MM/DD/YYYY HH24:MI:SS'));
Insert into XX_ORD_TIMES
   (ORDER_NUM, ACTUAL_START_DATE, ACTUAL_FINISH_DATE)
Values
   ('SVCEXT', TO_DATE('05/07/2013 09:23:37', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('05/07/2013 13:00:14', 'MM/DD/YYYY HH24:MI:SS'));
Insert into XX_ORD_TIMES
   (ORDER_NUM, ACTUAL_START_DATE, ACTUAL_FINISH_DATE)
Values
   ('SVCEXT', TO_DATE('05/09/2013 14:06:08', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('05/22/2013 13:25:03', 'MM/DD/YYYY HH24:MI:SS'));
Insert into XX_ORD_TIMES
   (ORDER_NUM, ACTUAL_START_DATE, ACTUAL_FINISH_DATE)
Values
   ('SVCNEWPLON', TO_DATE('05/21/2013 13:17:45', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('05/24/2013 14:35:04', 'MM/DD/YYYY HH24:MI:SS'));
Insert into XX_ORD_TIMES
   (ORDER_NUM, ACTUAL_START_DATE, ACTUAL_FINISH_DATE)
Values
   ('SVCNEWPLON', TO_DATE('05/24/2013 09:00:04', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('05/29/2013 09:30:32', 'MM/DD/YYYY HH24:MI:SS'));
--Avg time diffs
SELECT ORDER_NUM,
         ACTUAL_START_DATE
         ACTUAL_FINISH_DATE
                TO_NUMBER (
                   SUBSTR (
                      NUMTODSINTERVAL (
                         AVG (
                              CAST (ACTUAL_FINISH_DATE AS DATE)
                            - CAST (ACTUAL_START_DATE AS DATE)),
                         'DAY'),
                      2,
                      9))
              * 24
            + TO_NUMBER (
                 SUBSTR (
                    NUMTODSINTERVAL (
                       AVG (
                            CAST (ACTUAL_FINISH_DATE AS DATE)
                          - CAST (ACTUAL_START_DATE AS DATE)),
                       'DAY'),
                    12,
                    2))
         || ':'
         || CASE
               WHEN LENGTH (
                       TO_NUMBER (
                          SUBSTR (
                             NUMTODSINTERVAL (
                                AVG (
                                     CAST (ACTUAL_FINISH_DATE AS DATE)
                                   - CAST (ACTUAL_START_DATE AS DATE)),
                                'DAY'),
                             15,
                             2))) < 2
               THEN
                     '0'
                  || TO_NUMBER (
                        SUBSTR (
                           NUMTODSINTERVAL (
                              AVG (
                                   CAST (ACTUAL_FINISH_DATE AS DATE)
                                 - CAST (ACTUAL_START_DATE AS DATE)),
                              'DAY'),
                           15,
                           2))
               ELSE
                  TO_CHAR (
                     SUBSTR (
                        NUMTODSINTERVAL (
                           AVG (
                                CAST (ACTUAL_FINISH_DATE AS DATE)
                              - CAST (ACTUAL_START_DATE AS DATE)),
                           'DAY'),
                        15,
                        2))
            END
            AS TIME_DIFF
    FROM XX_ORD_TIMES
   GROUP BY ORDER_NUM,
         ACTUAL_START_DATE
         ACTUAL_FINISH_DATE
         order by 1;
Yes, I am trying to show the time difference of two timestamps ( finish date , start date ) in Hours:Mins and also calculate the average of this Hours : Mins by ORDER_NUM .
Please advise.
Thanks again.

FM to find time difference

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