Formatting a string with Display String

I have a field in my database that is a string with numbers in it and I need it formatted like so: "xx-xx-xx-xxx" nine characters long.
For example: 92438014
I need it to look like: 09-24-38-014
and
141234892
14-12-34-892 etc..
can anyone help me with some code that will do this for me? I'm not the best at crystal custom formatting.
thank you
Edited by: MarcieHennessy on Oct 14, 2009 10:47 PM

Raghavendra.G
I was on this site searching for an answer to my problem, and you provided the solution for me with your response to the above. However, my problem was a bit different. I needed a way to format a 9-digit number string into a standard Social Security number format. I used your formula from above, and WOW - it worked! If I could award you double Forum Points, I would. But, since I can't do that, I will just say thanks, and ask God to bless you profusely.
Kathryn J. Ryan.

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Replacing a special character in a string with another string

Hi
I need to replace a special character in a string with another string.
Say there is a string - "abc's def's are alphabets"
and i need to replace all the ' (apostrophe) with &apos& ..which should look like as below
"abc&apos&s def&apos&s are alphabets" .
Kindly let me know how this requirement can be met.
Regards
Sukumari

REPLACE
Syntax Forms
Pattern-based replacement
1. REPLACE [{FIRST OCCURRENCE}|{ALL OCCURRENCES} OF]
pattern
          IN [section_of] dobj WITH new
          [IN {BYTE|CHARACTER} MODE]
          [{RESPECTING|IGNORING} CASE]
          [REPLACEMENT COUNT rcnt]
          { {[REPLACEMENT OFFSET roff]
             [REPLACEMENT LENGTH rlen]}
          | [RESULTS result_tab|result_wa] }.
Position-based replacement
2. REPLACE SECTION [OFFSET off] [LENGTH len] OF dobj WITH new
                  [IN {BYTE|CHARACTER} MODE].
Effect
This statement replaces characters or bytes of the variable dobj by characters or bytes of the data object new. Here, position-based and pattern-based replacement are possible.
When the replacement is executed, an interim result without a length limit is implicitly generated and the interim result is transferred to the data object dobj. If the length of the interim result is longer than the length of dobj, the data is cut off on the right in the case of data objects of fixed length. If the length of the interim result is shorter than the length of dobj, data objects of fixed length are filled to the right with blanks or hexadecimal zeroes. Data objects of variable length are adjusted. If data is cut off to the right when the interim result is assigned, sy-subrc is set to 2.
In the case of character string processing, the closing spaces are taken into account for data objects dobj of fixed length; they are not taken into account in the case of new.
System fields
sy-subrc Meaning
0 The specified section or subsequence was replaced by the content of new and the result is available in full in dobj.
2 The specified section or subsequence was replaced in dobj by the contents of new and the result of the replacement was cut off to the right.
4 The subsequence in sub_string was not found in dobj in the pattern-based search.
8 The data objects sub_string and new contain double-byte characters that cannot be interpreted.
Note
These forms of the statement REPLACE replace the following obsolete form:
REPLACE sub_string WITH
Syntax
REPLACE sub_string WITH new INTO dobj
        [IN {BYTE|CHARACTER} MODE]
        [LENGTH len].
Extras:
1. ... IN {BYTE|CHARACTER} MODE
2. ... LENGTH len
Effect
This statement searches through a byte string or character string dobj for the subsequence specified in sub_string and replaces the first byte or character string in dobj that matches sub_string with the contents of the data object new.
The memory areas of sub_string and new must not overlap, otherwise the result is undefined. If sub_string is an empty string, the point before the first character or byte of the search area is found and the content of new is inserted before the first character.
During character string processing, the closing blank is considered for data objects dobj, sub_string and new of type c, d, n or t.
System Fields
sy-subrc Meaning
0 The subsequence in sub_string was replaced in the target field dobj with the content of new.
4 The subsequence in sub_string could not be replaced in the target field dobj with the contents of new.
Note
This variant of the statement REPLACE will be replaced, beginning with Release 6.10, with a new variant.
Addition 1
... IN {BYTE|CHARACTER} MODE
Effect
The optional addition IN {BYTE|CHARACTER} MODE determines whether byte or character string processing will be executed. If the addition is not specified, character string processing is executed. Depending on the processing type, the data objects sub_string, new, and dobj must be byte or character type.
Addition 2
... LENGTH len
Effect
If the addition LENGTH is not specified, all the data objects involved are evaluated in their entire length. If the addition LENGTH is specified, only the first len bytes or characters of sub_string are used for the search. For len, a data object of the type i is expected.
If the length of the interim result is longer than the length of dobj, data objects of fixed length will be cut off to the right. If the length of the interim result is shorter than the length of dobj, data objects of fixed length are filled to the right with blanks or with hexadecimal 0. Data objects of variable length are adapted.
Example
After the replacements, text1 contains the complete content "I should know that you know", while text2 has the cut-off content "I should know that".
DATA:   text1      TYPE string       VALUE 'I know you know',
        text2(18) TYPE c LENGTH 18 VALUE 'I know you know',
        sub_string TYPE string       VALUE 'know',
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REPLACE sub_string WITH new INTO text1.
REPLACE sub_string WITH new INTO text2.

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I have to replace a string with another string. Say
for example in a html file it got a line like,
<a href="##"></a>
now i want to replace this ## with the full derived
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How can I substitute a string with another string in a file

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Attachments:
C-V measurement by SR830.vi ‏107 KB
sr830readout1.vi ‏31 KB
sr830 initialize.vi ‏15 KB

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hex to ascii.vi ‏8 KB

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Failure to read multiline string with Read Key.vi

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Attachments:
Save_2D_array_in_config_file.vi ‏29 KB
Read_2D_array_from_config_file.vi ‏31 KB

Hi Michael,
MichaelS wrote in news:506500000008000000F7980000-
[email protected]:
> I converted 2D array into a spreadsheet string and attempetd to write
> it as a key value into a configuration file. This worked just fine.
> However, when I attempted to read this multiline string using Read
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" after your
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Reading a String with dynamic format.

Hello,
I'm learning Java and I'm relatively new to the scene. I decided to make a small free utility with the hope that it will help somebody. The utility is a Game Server (Call of Duty 4) connector that will help Administrators to connect to the server and execute commands without the need of running the game.
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}I've been messing a lot with the code. +_What I want to do is to read this string that the server is sending,split it, and then place it in a 2D Array that I will attach on a table._+ So far I've made the StringTokenizer method to be able to , kind of, sort that String and put it in an array. However I usually get outofbounds errors because not always the lines have the same length. This is an example of the format that the server sends after executing the "status" command:map: mp_crossfire
num score ping guid name lastmsg address qport rate
2 1 84 b5e9d93e88670c6f811a033a7f925117 Davis^7 0 84.185.183.210:-1482 21249 25000
4 15 100 e0d7c91fa7ba9549444ccab3a0e3de62 =HPX= Anogianos^7 0 91.140.25.93:28960 -10752 25000
5 5 68 5d68298d9e16d7491d5700e6e236214f AsChIkUtAbU^7 50 84.60.215.190:17502 26401 25000
6 115 44 cc503f50d990e27eeb990826c2cf1193 Donnergroll^7 50 91.64.153.240:28960 10086 25000
7 141 79 cbd095d37abdc728671e2923296aa9cf souL^7 50 87.78.179.242:-10509 8432 25000
8 116 83 4d0d1a067179516e209ef89cb0a79755 suodeth^7 0 84.250.214.156:27185 -29970 25000
9 11 117 fc3c6777b3d9bf99df1e55b321b75e9e shpalman^7 50 62.101.126.209:-17420 -25455 25000
10 5 82 fb2f20a9f46a212b896baf9ab4ea3eb0 =HPX=Gringo^7 50 213.5.170.94:-619 20175 25000
11 95 68 d3d542b17ab56d9fbf107da39f245269 aga^7 50 78.2.42.253:28960 22173 25000
12 10 100 8e6d08aec08591fb319081d0b40dedd2 madmax^7 0 79.166.47.145:2960 -7933 25000
13 110 77 4fc4d0e24faa634dbce5c4bb4131bc4a Thunderstorm^7 50 87.78.113.218:28960 4512 25000
14 55 67 f789227fcb95853b857115e68741df8d Robbino^7 0 89.217.12.113:28960 -192 25000
15 118 85 b7be8ce58324d0f25c45f5cb372b30a1 Paranoid^7 50 78.1.26.32:28960 27294 25000
16 11 90 38b59f3bbd3aa0ce3c95fccb26858931 $Hockz^7 50 87.181.101.96:-2984 24219 25000
19 16 45 720f2abf81189890851d3e41fcbe4e21 ERASER^7 50 83.236.63.150:-32135 24704 25000
20 145 37 a78f43bc3d3705743a190de45d37fc6a KintaKunte^7 50 88.68.237.239:28960 23539 25000
21 60 49 a96d6a55049d11c5d7cd1c35c4d497c3 #sD|-HaZarD-^7 50 87.78.179.242:-10509 8432 25000
8 116 83 4d0d1a067179516e209ef89cb0a79755 suodeth^7 0 84.250.214.156:27185 -29970 25000
9 11 117 fc3c6777b3d9bf99df1e55b321b75e9e shpalman^7 50 62.101.126.209:-17420 -25455 25000
10 5 82 fb2f20a9f46a212b896baf9ab4ea3eb0 =HPX=Gringo^7 50 213.5.170.94:-619 20175 25000
11 95 68 d3d542b17ab56d9fbf107da39f245269 aga^7 50 78.2.42.253:28960 22173 25000
12 10 100 8e6d08aec08591fb319081d0b40dedd2 madmax^7 0 79.166.47.145:2 0 91.3.110.248:-1185 6274 25000
23 116 109 bfffdf9ff93425d284796532ef214bd0 ze_meedles^7 50 85.243.221.116:28960 24936 25000
95853b857115e68741df8d Robbino^7 0 89.217.12.113:28960 -192 25000
15 118 85 b7be8ce58324d0f25c45f5cb372b30a1 Paranoid^7 50 78.1.26.32:28960 27294 25000
16 11 90 38b59f3bbd3aa0ce3c95fccb26858931 $Hockz^7 50 87.181.101.96:-2984 24219 25000
19 16 45 720f2abf81189890851d3e41fcbe4e21 ERASER^7 50 83.236.63.150:-32135 24704 25000
20 145 37 a78f43bc3d3705743a190de45d37fc6a KintaKunte^7 50 88.68.237.239:28960 23539 25000
21 60 49 a96d6a55049d11c5d7cd1c35c4d497c3 #sD|-HaZarD-^7 50 87.78.179.242:-10509 8432 25000
8 116 83 4d0d1a067179516e209ef89cb0a79755 suodeth^7 0 84.250.214.156:27185 -29970 25000
9 11 117 fc3c6777b3d9bf99df1e55b321b75e9e shpalman^7 50 62.101.126.209:-17420 -25455 25000
10 5 82 fb2f20a9f46a212b896baf9ab4ea3eb0 =HPX=Gringo^7 50 213.5.170.94:-619 20175 25000
11 95 68 d3d542b17ab56d9fbf107da39f245269 aga^7 50 78.2.42.253:28960 22173 25000
12 10 100 8e6d08aec08591fb319081d0b40dedd2 madmax^7 0 79.166.47.145:2As you can see the problem is that the server sends some information twice *but* it splits them with a blank line. In addition some nicknames contain spaces something that makes me wonder how I can set the nicknames to belong to the same position of the array. Something that i know is that all nicknames end with "^7" which is the in-game colour definition. Any help would be much appreciated. Thanks in advance.
Edited by: m33ts4k0z on Dec 21, 2007 11:36 AM
Edited by: m33ts4k0z on Dec 21, 2007 11:43 AM

m33ts4k0z wrote:
Hello DeltaGeek and thanks for your answer.
I have 2 questions for you since you mentioned what the real problem is. The first question is how can I join 2 cells that will contain the 2 parts of the nickname in case of a space? Can I just check if the cell number x,y contains "^7" and then just copy that cell the x,y-1? Ive tried that but then I also have to move the rest of the columns to y-1 as well. Any idea how to do that?
I was assuming you'd be processing the split string anyways, and not just tossing it into your 2-d structure. If you want to use .split(), yes. you would need to merge those cells into the original name. System.arrayCopy() would likely be useful for doing most of the heavy lifting.
Another option you have is to tokenize the string using Scanner. That would let you pull each column out of the string individually. You'll need to populate the array manually (instead of just using what .split() gives you), but allows you to change the token delimiter between pulls.
As for the junk lines, I can just check if they don't much the tokens number and then just not add them to the array I suppose, am I right or....?That's certainly one option. I don't know what's being given back to you, it may be important.

Formatting a string with time stamp and double precision numbers

%s\t%f\r%f
This is a format string that I have in old code that I've decided to change. Problem is I cannot make sense of the string codes in my own old code! Let me explain what I want, and hopefully someone can explain how to do it.
I am using the format into string subvi to merge a time stamp (formatted as %m%d%Y%H%M%S%5u) and two different double precision numbers. This string is then wired into the Write Characters to File subvi so that I can record data as a .txt file, and open it in either Matlab or Excel. There is a minor problem with the string format above because in excel the first time stamp entry is blank, and the first loop only gives the two double precision numbers withouth the time stamp - the time stamp appears in the next loop (probably a looping issue and not due to the string format, but if you see differently please let me know). Now what I want to do is 1. potentially fix that problem and 2. add some more doubles.
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2. How do I add another one - three floating point numbers (double precision)? Are the \'s marking different numbers in this string constant? Or is it the %? I can't find any information about the \'s, but I see that % begins the format specifier.
Ideally, I want these data in the following columns: Date, Time(absolute), FP, FP, FP, carriage return for the next loop (FP is floating point double precision number).
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Here there is no need of string concordinate function (in your code), the same result you can find if you connect the output of the format string to shift register, and shift register in data to initialize string connector in format into string function.
<<KUDOS ARE WELCOME>>
ELECTRO SAM
For God so loved the world that he gave his one and only Son, that whoever believes in him shall not perish but have eternal life.
- John 3:16

How to display string with XML content in 4.6?

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4.6 has not method parse_string.
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a®

Formatting a timestamp into string with $ specifier

Formatting a timestamp into string with $ specifier does not work; the formatted string is empty and no error is reported:
I have forced the width to 10 to show that the format is at least partially scanned but when it is omitted the timestamp field is empty.
I couldn't find this problem reported/addressed so here it is (LabVIEW 8.6)
LabVIEW, C'est LabVIEW

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There are only two ways to tell somebody thanks: Kudos and Marked Solutions
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Formatting a string with Display String

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