Formules de calcul de la précision absolue des cartes NI

Bonjour,
je poste sur ce forum car j'aimerai évaluer la précision de mesure de mes cartes NI. Pour cela je me suis renseigné avec la documentation en ligne de NI, qui dit que la précision absolue égale:
±((Input Voltage * % of reading) + (Range*% Offset of the Range) + System Noise + Temperature Drift)
http://digital.ni.com/public.nsf/allkb/8BA2242D4BCC41B286256D1D00815B90
et que la dérive liée à la température égale:
±(Input Voltage * % of Reading/° C + Offset/° C) * Temperature Difference.
Et il est précisé que si la température ambiante se situe dans la gamme [15°c-35°c], il ne faut pas tenir compte de cette dérive de la température.
Ma question est: cette gamme de température est-elle la même pour toutes les cartes d'acquisition NI, ou seulement pour un type d'instrument particulier?
Question subsidiaire:
On voit que la température moyenne de cette gamme est 25°c, on pourrait donc se dire que c'est la température de calibration de l'appareil. Or lorsque l'on regarde les procédures de calibration de NI, la température de calibration doit être de 23°c +/-5°c (exemple p.6 :http://www.ni.com/pdf/manuals/375971b.pdf). La gamme, où la dérive de température ne doit pas être prise en compte, ne devrait-elle pas donc être [13°c-33°c]?
Cordialement,

Merci pour votre réponse.
Le problème est que cette gamme de température n'est pas toujours précisée...
Alors j'avais été voir l'Accuracy Calculator mais il n'y a pas mon matériel NI dans la liste (NI9208, NI6009 entre autres).
J'en profite aussi pour ajouter une question dans le même style: Concernant la NI6009 , la précision absolue est donnée à 25°c en mode RSE à 14.7mV, suivie d'une surchauffe maximale qui entraine une dérive max de 138mV (http://www.ni.com/pdf/manuals/371303m_0114.pdf page 22); Mais la valeur température égale à la surchauffe max n'est pas précisée.
Donc si je fais une mesure à 35°c, qu'elle est la dérive liée à ma température?
Est ce: 138mV/(Température max de fonctionnement - 25°c) => 138/(55-25) =4.6 mV/°c ?
Et donc pour une mesure dans une ambiance de 35°c, Précision =14.7+10x4.6 = 60.7 mV
Ou pas du tout?

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