From varchar to date format mm/dd/yyyy

Hi everyone,
I am pretty sure this question has been asked before, but I've been going through the blog for quite a while and can't seem to find anything!
Here is my problem. I am trying to compare a field in my database with a certain date, but the field is a varchar in the format mddyyyy, without comas or bars or anything, and I need to campare it with a date of the format mm/dd/yyy.
In Excel I used a quite complicated formula:
Right('0000000000' & [Maturity_Date],8) AS [New Mat #],
CDate(Left([New Mat #],2) & "/" & Mid([New Mat #],3,2) & "/" & Right([New Mat #],4)) AS [Mat Date],
But, to start with, Oracle doesn't seem to have the "right" operator.
Anyone could give me an idea.
Thanks for your time!! :)

Hi,
849073 wrote:
Hi!
Thank you very much, for your fast answer and your ideas!
Let me do this right then :) I'm using Oracle 9.2.0.8. Then you can't use REGEXP_REPLACE. Regular expressions were introduced in Oracle 10.
I didn't write the query beacuse it is mainly a bunch of joins I have already tested and they are right. I got the problem when inserting the date.
So, one of the problems is that the varchar might have only 1 digit for the month, so it would be like mddyyyy.
LPAD ( string_a
     , 8
     , '0'
     )will return a copy of string_a, with an extra '0' added at the beginning if it's only 7 characters long. That is
LPAD ('3312011', 8, '0')returns '03312011', which you can then use in any of the expressions I gave earlier, or in TO_DATE.
If string_a is already 8 characters long, e.g. '12312010', then the LPAD expression above returns it unchanged.
This is why the TODATE function will give back an error.
Then, as you correctly stated, I need to convert the string into a DATE type, since I need to check dates before a certain other or not. I am not sure if I made myself clear :SSorry, no. That's why you need to post some sample data, and the results you want from that data. In this case, the sample data would be just 2 columns (the string and the DATE), perhaps 6 rows and the results would be the rows where the one that is supposed to be earlier really is.

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I have a query
select UPPER(t.val_10) "TYPE", count(val_3) "Number of Transfers"
from table1 t
where t.is_active = 1
and t.val_4 = 'INBOUND'
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8/29/2008 6:31:10 PM
Does anyone have an answer?
Thanks in advance
Edited by: user2360027 on 26-Mar-2009 03:50

first off, you've got to_date(to_date(...)) - NEVER do this - you're forcing an implicit to_char which can cause all sorts of problems!
What is the data type of your column val_5? If it's DATE then your query is simply:
select UPPER(t.val_10) "TYPE",
       count(val_3) "Number of Transfers"
from   table1 t
where t.is_active = 1
and    t.val_4 = 'INBOUND'
and    val_5 between to_date('01/08/2008','DD/MM/YYYY') and add_months(to_date('01/08/2008','DD/MM/YYYY') ,1)
group by UPPER(t.val_10)
order by UPPER(t.val_10)If it's a varchar2 (why, oh why, oh why, ...?!), then your query should be:
select UPPER(t.val_10) "TYPE",
       count(val_3) "Number of Transfers"
from   table1 t
where t.is_active = 1
and    t.val_4 = 'INBOUND'
and    to_date(val_5, 'mm/dd/yyyy hh:mi:ss AM') between to_date('01/08/2008','DD/MM/YYYY') and add_months(to_date('01/08/2008','DD/MM/YYYY') ,1)
group by UPPER(t.val_10)
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Remember also that your nls_date_format defines the default format that you'll see a date, which is what is used in the implicit conversion that oracle does when you select a date:
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Session altered.
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SYSDATE
26/03/2009 11:01:53
1 row selected.
SQL> alter session set nls_date_format='mm/dd/yy hh12:mi:ss AM';
Session altered.
SQL> select sysdate from dual;
SYSDATE
03/26/09 11:02:24 AM
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Message was edited by:
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