Generate uuid(UUID)

Question

Hi guys!
Grettings all.I see j2se has UUID class from where i have generated uuid like the following way
UUID.randomUUID().toString()
which actually produce this: f5b97880-dd6a-43fd-b9ee-053b337aeea9 and which is a 32 bit character separated by "- " character.
I want to generate this kind of UUID in j2me side, I see theres javax.bluetooth.UUID class.but i cant play with it for due to lacks of document.I saw ppl tried to use code like
String uuidString = "102030405060708090A0B0C0D0E0F010";
          UUID uuid = new UUID(uuidString, false);
by calling toString of UUID class it actually returns what i have provided.
Would you please tell me how can generate uuid as like standard jvm (j2se) does.
Your advice and help would be great.

Answer 1

There is a wikipedia article:
http://en.wikipedia.org/wiki/Universally_unique_identifier#Version_4_.28random.2 9
Assuming you want to make "Version 4" UUID:
You can make a table with columns for:
- Version which is always "4"
- Y which may be the digit 8, 9, A, or B
- 30 columns which contain a random value from the set 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F (hexidecimal digits)
the formula for C2=NUMTOBASE(RANDBETWEEN(8, 11), 16)
Fill this straight down
D2 =NUMTOBASE(RANDBETWEEN(0,15), 16)
fill to the right, then fill cell D2 - AG1 down
B2 should be 4
fill down (copy , then select range B3 to the end, then paste)
B2=D2&E2&F2&G2&H2&I2&J2&K2&"-"&L2&M2&N2&O2&"-"&B2&P2&Q2&R2&"-"&C2&S2&T2&U2&"-"&V 2&W2&X2&Y2&Z2&AA2&AB2&AC2&AD2&AE2&AF2&AG2
fill down