Generic arguments in a Method on an interface.

Question

Hi all,
I'm having trouble with the following code:
Basically this is what i want:
the Classes:
public class SuperClass
public class ClassA extends SuperClass
public class ClassB extends SuperClass
public class ClassC extends SuperClass
The interface
public interface interfaceX
   public methodX(SuperClass A);
Implementation of the interface
public class classX implements interfaceX
     public methodX(ClassA A)
}My problem is on the declaration of the interface interfaceX in the class classX.
How can i do such thing?
I'm trying to avoid the "correct" declaration. this is:
public methodX(SuperClass A)
        { ... }because I have a couple of class that extends that interface with deferents arguments, all of them extending from the SuperClass.
I know i could use the instanceof keywork, but i'm trying to avoid the extra checking...
Thanks in advance for any help!!
Edited by: ValdemarP on Mar 29, 2010 1:55 AM

Answer 1

i know I'm changing the contract, but only the arguments. if you notice, the new arguments is child of class SuperClass... How can I do this? Declare an method in an interface that accepts an arguments of some class and implement that interface, with argument that are children of the arguments declared in the interface... hope i was more clear this time... :(
Example. I can do this on an interface:
public void MethodListGeneric(List<? extends SuperClass> xpto )and during the implementation of the interface, I can declare the method using any arguments for the generic list, that extends SuperClass.
Example:
public class xpto extends InterfaceX
    public void MethodListGeneric(List<ClassA> xpto )
     // in here I've use ClassA insted of SuperClass
}Edited by: ValdemarP on Mar 29, 2010 3:15 AM
Edited by: ValdemarP on Mar 29, 2010 3:15 AM