GET FULL URL without the file

Hi,
I need to get the
http://www.mysite.com/images/
without coding it in so I can use it on multiple sites without
re-coding. Basically it is an email systems where I want to include
an email header and footer. In order for this to work the images
need to have full paths to the images on the server. I have tried
<cfset mypath = "
http://#cgi.server_name##cgi.script_name#
">
This returns
http://localhost/clients/broker2/layout/siteadmin/email/email_news.cfm
wich is good except the file name at the end.
So I guess my question is - How do you take off the filename?
I want this to work on different pages without re-coding.
How do I take out just the filename ( anything after the last

That works,
But while I was waiting for an answer I came up with
<cfset myPath = replace(GetDirectoryFromPath("
http://"&cgi.server_name&
cgi.path_info),"\","")>
Both seem to work

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I using a JFileChooser to select and read a file. Now I want to get the filename without the file extension
JFileChooser j = new JFileChooser;
String file = j.getSelectedFile.getName();
At the moment I get this result "file.dat". I need only the filename.....
Thank you
Thomas

It's quite that.
Here is the code to do that (and the method to get only the extension):
     public String getFileName(String text) {
          int ind = text.lastIndexOf(".");
          if(0<ind && ind<(text.length()-1)) {
               return text.substring(0, ind);
          return(null);
     public String getFileExtension(String text) {
          int ind = text.lastIndexOf(".");
          if(0<ind && ind<(text.length()-1)) {
               return text.substring(ind+1).toLowerCase();
          return(null);
     }(I used 0<ind instead of ind>0 because with the code formatting there is a bug with > )
I hope this helps,
Denis

URLs without the file extension showing

This is just one of those odd things I've never had to do, so have never thought about it - but I've been asked to upload a powerpoint presentation, with a URL of just www.mydomainname.com/powerpointname
If anyone could let me know how this is done, that would be much appreciated.
Thanks.

Try this: name your powerpoint file index.html and put it into a folder (in your site) named powerpointname.
Ideally, that will default to showing the file without the filename technically showing.
Here is a link that discusses powerpoint presentations as webpages: http://presentationsoft.about.com/od/nextstepsinpowerpoint/ss/save_as_webpage.htm
Beth

Get only the filename not the full path of the file.

hi to all..
how can i get only the filename of the file not the full path and to be placed on a textinput.?
example:
when i'browse the file and select sample.txt
"C:\Users\user\Desktop\folders\sample.txt" this will be inputted on the textinput.
however, what i want to have is when i'browse and select a file..
textinput should only contain "sample".
does anyone knows how to do it?

Hi cyrus@adobe,
How are you getting the full path of the file when you browse, I dont think for security reasons the Flash Player will aloow to do so. You can only get the file name not the full path of the file when you browse.
Are you using Flex4..?? I am not sure whether this is possible in Flex4..However if you are getting full path and if you wanted to show only the filename then you can just use theString class split function to acehive this..
var fullPath:String = "C:\Users\user\Desktop\folders\sample.txt";
var splitPath:Array = fullPath.split("\");
textInput.text = splitPath[splitPath.length-1];
Thanks,
Bhasker

In IE, while saving a file it is taking the full path with the file name

Hi,I am using Tomcat5.5. In one page of my website, there is code responsible for saving an image from the server to the client machine. whenever i am doing this Mozila the file is getting saved with desired name. But in IE it takes full path of the file in the server directory along with its name while being saved in the client machine.Below is the code responsible for this. Plz Help.
DiskFileUpload fu = new DiskFileUpload();
        List fileItems = fu.parseRequest(request);
        Iterator itr = fileItems.iterator();
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                        java.util.Random rd = new java.util.Random();
                        int random = rd.nextInt(100000);
                        String img_code = random + "";
                              if(fi.getContentType().equals("image/jpeg") || fi.getContentType().equals("image/pjpeg") || fi.getContentType().equals("image/gif") || fi.getContentType().equals("image/png") || fi.getContentType().equals("image/x-png") || fi.getContentType().equals("image/bmp") || fi.getContentType().equals("image/wmp") || fi.getContentType().equals("application/octet-stream") || fi.getContentType().equals("audio/wav") || fi.getContentType().equals("audio/x-wav") || fi.getContentType().equals("audio/AMR") || fi.getContentType().equals("audio/amr") || fi.getContentType().equals("audio/mpeg") || fi.getContentType().equals("audio/mp4a-latm") || fi.getContentType().equals("audio/x-realaudio") || fi.getContentType().equals("audio/x-pn-realaudio") || fi.getContentType().equals("audio/x-pn-realaudio-plugin") || fi.getContentType().equals("audio/midi") || fi.getContentType().equals("audio/mid") || fi.getContentType().equals("audio/x-midi") || fi.getContentType().equals("audio/x-mid") || fi.getContentType().equals("audio/x-tone-seq") || fi.getContentType().equals("audio/imelody")
                                   || fi.getContentType().equals("video/mp4v-es") || fi.getContentType().equals("video/mp4") || fi.getContentType().equals("video/3gp") || fi.getContentType().equals("video/3gpp") || fi.getContentType().equals("video/mpeg") || fi.getContentType().equals("video-h263-2000"))
                               System.out.println("Content from FileItem : "+fi.getContentType());
                          File tempfile = new File(fi.getName());
                                String imageFile=tempfile.getName();
                                out.println("imageFile:" +imageFile);
                               imageFile= imageFile.replace(':','_');
                               imageFile=imageFile.replace('\\','_');
                               imageFile= imageFile.replace('/','_');
                               imageFile= imageFile.replace(' ','_');
                               System.out.println(imageFile);
                              out.println("imageFile:"+imageFile);
                               int extIndex=0;
                               String ext="";
                              extIndex = imageFile.lastIndexOf(".");
                              ext = imageFile.substring(extIndex+1);
                                               if( ext.toLowerCase().equals("jpg") || ext.toLowerCase().equals("jpeg") || ext.toLowerCase().equals("jpe") || ext.toLowerCase().equals("bmp") || ext.toLowerCase().equals("gif")|| ext.toLowerCase().equals("png") || ext.toLowerCase().equals("wbmp")
                                                  || ext.toLowerCase().equals("amr") || ext.toLowerCase().equals("mp3") || ext.toLowerCase().equals("mp2") || ext.toLowerCase().equals("mpga") || ext.toLowerCase().equals("wav") || ext.toLowerCase().equals("midi") || ext.toLowerCase().equals("mid") || ext.toLowerCase().equals("kar") || ext.toLowerCase().equals("ra") || ext.toLowerCase().equals("ram") || ext.toLowerCase().equals("rm") || ext.toLowerCase().equals("au")
                                                  || ext.toLowerCase().equals("3gpp") || ext.toLowerCase().equals("3gp") || ext.toLowerCase().equals("mpeg") || ext.toLowerCase().equals("mpe") || ext.toLowerCase().equals("mpg") || ext.toLowerCase().equals("mp4") || ext.toLowerCase().equals("movie") || ext.toLowerCase().equals("avi") || ext.toLowerCase().equals("qt") || ext.toLowerCase().equals("mov") || ext.toLowerCase().equals("viv") || ext.toLowerCase().equals("vivo"))
                          File fNew = new File(application.getRealPath("/userImages/"),img_code+"_"+imageFile);
//                         ImagePath = imagepath+img_code+"_"+tempfile.getName();
                         ImagePath = imagepath+img_code+"_"+imageFile;
                               System.out.println("Image PAth : "+ImagePath);
//                          ImagePath = fNew.getAbsolutePath();
                          //out.println(fNew.toString());
                          ImageName = fNew.getName();
                                System.out.println("Image Name : "+ImageName);
                                out.println("ImageName:" +ImageName);
                          fi.write(fNew);
                                else
                                       System.out.println("Invalid File Type : "+ext);
                                       Error = "1: Invalid File Type/Extension : "+ext;
                        else
                            Error = "2: File uploaded is not valid.";
                   System.out.println("Content from FileItem : "+fi.getContentType());
                            System.out.println("invalid Content Type");
                     else
                            Error = "";
                else
                   Error = "3: File uploaded is not valid. Make sure that the image size does not exceed 300KB";
                   System.out.println("File uploaded is not valid.");
          else
               session.setAttribute(fi.getFieldName(),fi.getString());
session.setAttribute("ImagePath",ImagePath);
session.setAttribute("ImageName",ImageName);
session.setAttribute("barcodepath",barcodepath);
//Added by Mutharasu on 30/08/2005
session.setAttribute("tagpath",tagpath);
Title = (String) session.getAttribute("txtTitle");
if(Title.length()==0)
Error = " Please Enter KoolTag Title : ";
Key = (String) session.getAttribute("txtKey");
URL = (String) session.getAttribute("txtURL");
System.out.println("Key: "+ Key +", URL:"+URL);
System.out.println("trace 5");
if (ImagePath.trim().length()==0 && ImageName.trim().length()==0) {
   if (Key==null && URL==null)
      throw new Exception("4: "+Error);
}

Hi Vigneshwara,
Please reopen a new thread in
ASP.NET Getting Started forum because I can't move it there.
Best regards,
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HT3345 How do I open a password protected excel file created on a PC? I get a message that the "file is encrypted and can't be opened"

How do I open a password protected excel file created on a PC in numbers 09, on a MacBook Air? I get a message that the "file is encrypted and can't be opened"

This is actually not true; I support users who are doing this w/ Excel 2011 (v14.2.2+) for Mac and Windows users w/ Excel 2003 & 2007. Win users are from finance dept, and who have pasword-protected various budget files. The Mac users are (surprise) "creative" users, who enter pw to unlock and edit these budget files.
These files are shared from a Mac server (running 10.6.8 server), and I do have an erratic problem where all users have read-only access to these pw-protected Excel files. The manual work-around has been to copy the troublesome file(s) and confirm users have full access again. I also do a shuffling of filenames, so that the new, working file has original file name.
FYI: the Mac server POSIX and ACL permissions are correct, and don't appear to be source of the problem.
It's easy an SMB file-locking issue or concurrent users trying to edit these files. I keep reminding them that Excel is not a database!

How to get full url using UCM RIDC api

Hi,
I am using RIDC api to get the full url of the document (including protocol, host, port info). I tried using DOC_INFO
and GET_SEARCH_RESULTS api. The GET_SEARCH_RESULTS api returns the path but no protocol, host, port info.
DOC_INFO does not contain any uri. Is there a way to get full url? I only have access to the idc socket connection
configuration to connect to the server.
E.g. I know the idc connection url is idc://hostname:4444
The user supplies document name as "myDoc.txt" and dId = 2000.
I used GET_SEARCH_RESULTS for myDoc.txt and DOC_INFO for dId=2000.
I need to return absolute url to the user that user can copy paste in the browser and download the doc.
Thanks,
--dhiraj

You can ge the docUrl using doc info services DOC_INFO or DOC_INFO_BY_NAME.
dataBinder.putLocal("IdcService", "DOC_INFO");
dataBinder.putLocal("dID", docId);
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I can not download any files using Safari ? when I choose to download application file the URL include the file name and stop responding. Any help??

I can not download any files using Safari ? when I choose to download application file the URL include the file name and stop responding. Any help??

Please read this whole message before doing anything.
This procedure is a test, not a solution. Don’t be disappointed when you find that nothing has changed after you complete it.
Step 1
The purpose of this step is to determine whether the problem is localized to your user account.
Enable guest logins* and log in as Guest. For instructions, launch the System Preferences application, select Help from the menu bar, and enter “Set up a guest account” (without the quotes) in the search box.
While logged in as Guest, you won’t have access to any of your personal files or settings. Applications will behave as if you were running them for the first time. Don’t be alarmed by this; it’s normal. If you need any passwords or other personal data in order to complete the test, memorize, print, or write them down before you begin.
Test while logged in as Guest. Same problem(s)?
After testing, log out of the guest account and, in your own account, disable it if you wish. Any files you created in the guest account will be deleted automatically when you log out of it.
*Note: If you’ve activated “Find My Mac” or FileVault in Mac OS X 10.7 or later, then you can’t enable the Guest account. The Guest login created by “Find My Mac” is not the same. Create a new account in which to test, and delete it, including its home folder, after testing.
Step 2
The purpose of this step is to determine whether the problem is caused by third-party system modifications that load automatically at startup or login.
Disconnect all wired peripherals except those needed for the test, and remove all aftermarket expansion cards. Boot in safe mode* and log in to the account with the problem. The instructions provided by Apple are as follows:
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API call to get FULL URL

I can't seem to find an API call to simply return the full url of the current page.
I just want to do the simplest (at least I think it should be simple) thing: Call a stored procedure (from a portlet) passing the current full url to the procedure. Nothing fancy.
Is there such a thing? Hopefully, I have just overlooked it...
TIA

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In a portal component's Additional PL/SQL Code section, use p_page_url. Example:
BEGIN
htp.p(p_page_url);
END;In a custom PL/SQL portlet, use p_portlet_record.page_url. Example:
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How to get full URL in java?

Hi,
I am working in a spring & hibernate project. For the AJAX request to bookmark, I used RSH (Really Simple Framework) framework. So, my URL changes for the AJAX request as
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Thank you

The hash part is entirely client side. You cannot get it on the server side. You need to pass it as request parameter or as part of real URL.

How do I attach a file to a Mail doc without the file being opened in the Mail document?

How do I attach a file to a Mail doc without the file being opened in the Mail document?

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(What the recipient of your message sees is dictated by that person's email application. If you want to make sure the person gets an attachement which is not previewed, you can zip it (control-click, "Compress...") and then attach the zipped file(s). Or you can try something like Attachment Tamer.)

I own a website and my customers download zipped files. Until yesterday everything worked great. All of the sudden they are getting a message that the file is invalid or corrupt. This does not happen in Chrome.

I own a website selling digital files. My customers receive an email after they place their order with a download link. Up until yesterday (for the past 3 years to be exact) everything worked smoothly. I have not changed one thing on my site or cpanel. Now customers get an error that the file is invalid or corrupt when they try and download with firefox. The links work fine with chrome. Please tell me there is a solution. This is causing major trouble!!!

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*http://www.mozilla.org/security/announce/2011/mfsa2011-39.html
*[https://bugzilla.mozilla.org/show_bug.cgi?id=681140 bug 681140] - Corrupted Content error due to multiple Content-Disposition header field instances
A good place to ask advice about web development is at the mozillaZine Web Development/Standards Evangelism forum.<br />
The helpers at that forum are more knowledgeable about web development issues.<br />
You need to register at the mozillaZine forum site in order to post at that forum.<br />
See http://forums.mozillazine.org/viewforum.php?f=25

How can I insert a number of photos in a numbers doc without the file becoming too large?

How can I insert a number of photos into a numbers doc without the file becoming too large?

Use smaller photos.
Seriously, reduce the file size of the photos in Preview, PhotoShop, iPhoto or other application before inserting tehem into the Numbers document.
Regards,
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A check with Numbers '09 shows it capable of opening .xlsx files when right-clicked (and Numbers chose as the application to open, when double-clicked (if Numbers has been set as the default application to open this type of file, or when dragged to the Numbers icon in the dock.
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Regards,
Barry

TS3694 my iphone crashed during update now i have to restore but dont have my latest photos backed up ? i have a picture of itunes with the usb on my screen and cant go any further? is there a way to get it back without the update?

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worth looking at for the future to understand backing up etc

GET FULL URL without the file

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