Getting File Name (Sender File Adapter )

Question

Hi EveryBody,
I need to capture only the the FileName in to the outbound xml that is present in the filepath of XI server.
I checked:
Adapter Specific Message Attributes:
Checked box on --> 1)Set Adapter Specific Message Attributes
                             2) File Name
And my dt IS OF TYPE :
<?xml version="1.0" encoding="UTF-8"?>
<MT_DMS_FINAL>
   <Header>
      <FileName/>
   </Header>
</MT_DMS_FINAL>
Now i put the File into the path , i donot need any content of file in XML , only needed the file name.
i tried above config and it says mapping error, but i test it"s running good with the test tab.
i guess file picked up by Sender file Adapter is not matching witj the outbound interface ?? is it so ?
advice. i see in the sxmb_moni that only the content not in xml structure is displayed.
srini

Answer 1

Refer to the blog that i asked you to go thru. It has no input fields. It accesses the file name through the Dynamic Configuration. Provides the same as output. Its just a java function without any input parameter. Create an UDF and deleted all the arguments(even "a").
Code:-
DynamicConfiguration conf = (DynamicConfiguration) container.getTransformationParameters().get(StreamTransformationConstants.DYNAMIC_CONFIGURATION);
DynamicConfigurationKey key = DynamicConfigurationKey.create("http://sap.com/xi/XI/System/File","FileName");
String ourSourceFileName = conf.get(key);
return  ourSourceFileName; 
Oops sorry, i guess i forgot to provide the blog link. Anyway its here:
/people/michal.krawczyk2/blog/2005/11/10/xi-the-same-filename-from-a-sender-to-a-receiver-file-adapter--sp14
Regadrs,
Sanjeev.
Edited by: Sanjeev Shekhar Singh on May 30, 2008 2:12 PM