Getting the nodes of an xsd

Question

I have a schema, which has both complex type and simple type elements. I want to parse the schema and get the root element, complex type and simple type element names.
Though i have seen some similar queries in the forum but none of them provide a complete solution.
I have tried using XMLSchema and getXMLSchemaNodeTable() but this gives only the root nodes.
My schema looks like this:
<?xml version="1.0" encoding="UTF-8"?>
<schema xmlns="http://www.w3.org/2001/XMLSchema"
     targetNamespace="http://www.abc.com/schema/teamDesc"
     attributeFormDefault="unqualified">
<element name="team">
<complexType>
<sequence>
<element name="teamLongDesc" maxOccurs="unbounded">
<complexType>
<sequence>
<element name="TeamId" type="integer" default="0" />
<element name="TeamCode" type="string" />
<element name="TeamDesc" type="string" />
</sequence>
<attribute name="isMaster" use="required" />
<attribute name="primaryKey" use="required" />
</complexType>
</element>
</sequence>
</complexType>
</element>
</schema>

Answer 1

Thanks for the reply..when i use schema.getXMLSchemaNodeTable(), the Hashtable contains only the following items, this is as per the schema i have given above
(java.util.Hashtable<K,V>) {http://www.ifs.com/schema/teamDesc=oracle.xml.parser.schema.XMLSchemaNode@124e935, http://www.w3.org/2001/XMLSchema=oracle.xml.parser.schema.XMLSchemaNode@4ac866}