GetURL needs to incorporate username and password!!!!

Question

Hi,
I need a Java program to go to a URL and then save the web page in a text file. I have successfully done this by finding the GetURL method (see bottom of page). But I need to do it for a URL where a standard username and password prompt appears. I know I need to use the following piece of code somewhere in the GetURL program to bypass this authorisation:
HTTPConnection con = new HTTPConnection(this);
con.addBasicAuthorization("protected-space", "goofy", "woof");
The problem is that I am a complete Java novice and am desperately trying to finish a project, therefore I just don�t have the time to learn the language.
Can someone PLEASEEEEEEE tell me how I can incorporate the above code into the following GetURL program (which I know works for URL�s without the authorisation needed):
[by the way, the URL is in the program below and the username = Bazza99  and the password = upge5w7u]
import java.io.*;
import java.net.*;
* This simple program uses the URL class and its openStream() method to
* download the contents of a URL and copy them to a file or to the console.
public class GetURL {
public static void main(String[] args) {
InputStream in = null;
OutputStream out = null;
try {
// Check the arguments
if ((args.length != 1) && (args.length != 2))
throw new IllegalArgumentException("Wrong number of arguments");
// Set up the streams
URL url = new URL("http://www.advfn.com/cmn/fun/advfnFun.php?epic=BAA"); // Create the URL
in = url.openStream(); // Open a stream to it
if (args.length == 2) // Get an appropriate output stream
out = new FileOutputStream("badata.txt");
else out = System.out;
// Now copy bytes from the URL to the output stream
byte[] buffer = new byte[4096];
int bytes_read;
while((bytes_read = in.read(buffer)) != -1)
out.write(buffer, 0, bytes_read);
// On exceptions, print error message and usage message.
catch (Exception e) {
System.err.println(e);
System.err.println("Usage: java GetURL <URL> [<filename>]");
finally {  // Always close the streams, no matter what.
try { in.close();  out.close(); } catch (Exception e) {}

Answer 1

Hi,
I wasn't sure how to incorporate your code into the GetURL program (afriad I am a java novice). I tried to run the code at the bottom of the page but it came back with the following error:
java.io.FileNotFoundException: http://www.advfn.com/cmn/fun/advfnFun.php?epic=BAA
Usage: java GetURL <URL> [<filename>]
code run:
import java.io.*;
import java.net.*;
* This simple program uses the URL class and its openStream() method to
* download the contents of a URL and copy them to a file or to the console.
public class GetURL {
public static void main(String[] args) {
InputStream in = null;
OutputStream out = null;
try {
// Check the arguments
if ((args.length != 1) && (args.length != 2))
throw new IllegalArgumentException("Wrong number of arguments");
// Set up the streams
URL url = new
URL("http://www.advfn.com/cmn/fun/advfnFun.php?epic=BAA"); // Create the URL
URLConnection conn = url.openConnection();
conn.setRequestProperty("Authorization", "Basic " + new
sun.misc.BASE64Encoder().encode("(Bazza99):(upge5w7u)".getBytes()));
in = conn.getInputStream();
if (args.length == 2) // Get an appropriate output stream
out = new FileOutputStream("baadata.txt");
else out = System.out;
// Now copy bytes from the URL to the output stream
byte[] buffer = new byte[4096];
int bytes_read;
while((bytes_read = in.read(buffer)) != -1)
out.write(buffer, 0, bytes_read);
// On exceptions, print error message and usage message.
catch (Exception e) {
System.err.println(e);
System.err.println("Usage: java GetURL <URL> [<filename>]");
finally {  // Always close the streams, no matter what.
try { in.close();  out.close(); } catch (Exception e) {}