Group by having count error
I have this code with an error:
SELECT (CASE id_type
WHEN 4 THEN companyid
ELSE nric
END) AS customerid
FROM customer
GROUP BY customerid HAVING COUNT (*customerid*) = 1
The error is at the bold word with the error: Invalid identifier. How should I rewrite my sql statement?
SELECT CUSTOMERID FROM
SELECT (CASE id_type
WHEN 4 THEN companyid
ELSE nric
END) AS customerid
FROM customer
GROUP BY customerid HAVING COUNT (customerid) = 1
Similar Messages
-
Hi...
I'm back again and I'm ever hopeful that I will get some needed help.
I'm trying to use the groupby and having Count(*) on a table, but I think
I have my group by wrong...I keep getting the wrong output.
Here's my code:
Select Course_ID,Count(*),Department_ID,Class_ID,Class_Room
from Class
Group By Course_ID,Department_ID,Class_ID,Class_Room
Having Count(*) >=1
and this is the output:
COURS COUNT(*) DEPARTMENT_ID CLASS_ID CLASS_ROOM
50 1 MATH 103600 140
101 1 BIO 109100 180
101 1 ENGL 108300 150
115 1 HIST 108400 200
183 1 PSYCH 103400 150
183 1 PSYCH 108600 240
184 1 HIST 104500 200
198 1 PHILO 104200 150
199 1 ENG 110300 255
199 1 ECON 120200 235
Now, what should be happeing is that Count should give me 2*101,2*183,2*199 but I keep
getting 1 of each...
Any ideas about where I'm going Wrong?Drake,
In short, you are grouping on too many things. You need to group on only course_id when looking for duplicates, and then join the duplicate courses back to the course table to get the rest of the data:
select c.course_id, c.department_id,
c.class_id, c.class_room
from class c,
(select course_id, count(*) howmany
from class
group by course_id
having count(*) > 1) dups
where c.course_id = dups.course_id;
Hi...
I'm back again and I'm ever hopeful that I will get some needed help.
I'm trying to use the groupby and having Count(*) on a table, but I think
I have my group by wrong...I keep getting the wrong output.
Here's my code:
Select Course_ID,Count(*),Department_ID,Class_ID,Class_Room
from Class
Group By Course_ID,Department_ID,Class_ID,Class_Room
Having Count(*) >=1
and this is the output:
COURS COUNT(*) DEPARTMENT_ID CLASS_ID CLASS_ROOM
50 1 MATH 103600 140
101 1 BIO 109100 180
101 1 ENGL 108300 150
115 1 HIST 108400 200
183 1 PSYCH 103400 150
183 1 PSYCH 108600 240
184 1 HIST 104500 200
198 1 PHILO 104200 150
199 1 ENG 110300 255
199 1 ECON 120200 235
Now, what should be happeing is that Count should give me 2*101,2*183,2*199 but I keep
getting 1 of each...
Any ideas about where I'm going Wrong? -
Count(field) group by having changed to an analytic function
Goal: Be able to show columns with data not in the group by clause.
I couldn't find this on the 'net either by looking here or by googling for it (unless I'm looking for the wrong thing). I'm doing a regular:
select fielda, count(fielda)
from some_table
group by fielda1
having count(field1) > 1;
to find out where I have duplicates in a table (fielda). I get fielda and the count of those records back (ie X, 2). However, I want to add several more fields that may or may not be different for each of those records.
For example:
1 record has fielda = X, field2 = Test, field3 = Oracle, field4 = Unix
1 record has fielda = X, field2 = Testa, field3 = Sybase, field4 = Windows.
I want to be able to have the following output:
X, 2 (count of records with fieldA = X), Test, Oracle, Unix
X, 2 (count of records with fieldA = X), Testa, Sybase, Windows
I'm not sure if this is one of those where I have to do a subquery on or not. Any ideas?
Thanks as always!
VicSorry, I misread your statement - it is poorly formatted. Besides incorrect use of aliases you are referencing columns that are not in inline view, therefore you must include it there:
select nsn,
item_type_name,
item_type_id,
date_time_added,
function_name
from (
select it.nsn,
it.item_type_name,
it.item_type_id,
it.date_time_added,
fn.function_name,
count(*) over (partition by it.nsn) cnt,
it.item_type_cat_id,
ic.item_category_id,
ic.function_id ic_function_id,
fn.function_id fn_function_id
from item_types it,
item_categories ic, functions fn
where it.nsn is not null
and it.item_type_cat_id = ic.item_category_id
and ic.function_id = fn.function_id
where cnt > 1
and nsn is not null
and item_type_cat_id = item_category_id
and ic_function_id = fn_function_id
order by nsn;SY. -
A method of grouping a total count of errors by date
Dear SQL Gurus,
Can anyone guide me (with the script below) as to how I'm can group a total count of error by DISTINCT(CREATION_DATE)?
11g Enterprise Edition Release 11.2.0.2.0
SCRIPT:
select
CREATION_DATE, request_id, rpad (regexp_substr(summary,'[^\.|^:]+'), 60, '_') as "iCash Dep Error Summary",count(*)
from BKS_OM.bks_icash_dep_errors
group by CREATION_DATE, request_id, regexp_substr(summary,'[^\.|^:]+');
RESULTS:
CREATION_DATE REQUEST_ID iCash Dep Error Summary COUNT(*)
02-JUL-12 415967 Validation Failure__________________________________________ 1
02-JUL-12 415967 Validation Failure__________________________________________ 1
02-JUL-12 415967 Validation Failure__________________________________________ 1
02-JUL-12 415967 Validation Failure__________________________________________ 1
02-JUL-12 415967 Validation Failure__________________________________________ 2
06-JUL-12 417699 Validation Failure__________________________________________ 1
06-JUL-12 417699 Validation Failure__________________________________________ 1
06-JUL-12 417773 Validation Failure__________________________________________ 16
02-JUL-12 415967 Validation Failure__________________________________________ 1
06-JUL-12 417773 Validation Failure__________________________________________ 1
Regards,
DIBS812
Edited by: DIBS812 on Aug 3, 2012 10:51 AMThat did the trick John. Thank you for providing me the solution.
Thanks everyone for your response!
select trunc(creation_date), request_id,
rpad(regexp_substr(summary,'[^\.|^:]+'), 60, '_') as "iCash Dep Error Summary",
count(*)
from bks_om.bks_icash_dep_errors
group by trunc(creation_date), request_id, regexp_substr(summary,'[^\.|^:]+');
TRUNC(CREATION_DATE) REQUEST_ID iCash Dep Error Summary COUNT(*)
19-JUL-12 422601 Validation Failure__________________________________________ 326
19-JUL-12 423343 Validation Failure__________________________________________ 383
20-JUL-12 423650 Validation Failure__________________________________________ 439
02-JUL-12 415967 Validation Failure__________________________________________ 53
16-JUL-12 421687 Validation Failure__________________________________________ 277
06-JUL-12 417699 Validation Failure__________________________________________ 21
10-JUL-12 419189 Validation Failure__________________________________________ 124
06-JUL-12 417773 Validation Failure__________________________________________ 124
18-JUL-12 422529 Validation Failure__________________________________________ 269
19-JUL-12 422894 Validation Failure__________________________________________ 326
19-JUL-12 422901 Validation Failure__________________________________________ 326
18-JUL-12 422357 Validation Failure__________________________________________ 277
19-JUL-12 422865 Validation Failure__________________________________________ 326 -
HAVING clause error in JPA 2 examples
In Chapter 8: Query Language of the Pro JPA 2 Mastering the Java Persistence API book, the jpqlExamples WAR has this query:
SELECT e, COUNT(p)
FROM Employee e JOIN e.projects p
GROUP BY e
HAVING COUNT(p) >= 2
When executed, the following error occurs:
java.lang.IllegalArgumentException: An exception occurred while creating a query in EntityManager:
Exception Description: Error compiling the query [SELECT e, COUNT(p) FROM Employee e JOIN e.projects p GROUP BY e HAVING COUNT(p) >= 2], line 1, column 80: invalid HAVING expression [COUNT(p) >= 2] for query with grouping [GROUP BY e]. The HAVING clause must specify search conditions over the grouping items or aggregate functions that apply to grouping items.
I bring this us because I have an application which is getting the same error and need a fix. If the query is indeed legal in JPA 2, then why the error? If if it is my setup however, then I would like suggestions on fixing it. I am using GlassFish v3 (build 74.2), updated regularly with the Update Tool.The bug has been reopened. Now it says:
Reopening because there is some debate about whether this should be supported
by the spec. Some people read the spec to say the above query is allowed - I
am not convinced, but discussion can be appended to this bug if necessary.
This is Bug 308482, and I assume at least a few might want to take a look.
https://bugs.eclipse.org/bugs/show_bug.cgi?id=308482 -
Can I write merge SQL statement having count(*)?
Hi this is a followup question of my previous post. I tried to use a merge SQL statement to solve my problem but now I bump into another problem.
Now I have a table where the field I need to update is a partial PK
when using a merge SQL statement, I have to put a where clause that check if count(*) = 1 because of the PK constraint
Where can I put the count(*) = 1 clause?
Here are the details:
I have two tables TA and TB, where TA contains the fields ID, FULLNAME, TYPE and TB contains the fields ID, FIRSTNAME
I want to update the firstnames in TB to be the firstnames from TA where TB.ID = TA.ID and TA.TYPE = 'ABC'
{ID, FIRSTNAME} are PKs but for the same ID, there can be more than 1 firstname.
e.g.
TA
ID | FULLNAME | TYPE
1 Caroline T ABC
2 Mary C DEF
3 Peter J ABC
TB
ID | FIRSTNAME
1 Caroline
1 Carol
1 C,
3 Peter
I need to update TB with the new firstnames from TA where type is 'ABC' but only for those fields that have count(TB.ID) = 1
when I try to run this SQL statement
merge into TB B using TA A
on (A.ID = B.ID and A.TYPE = 'ABC')
when matched then update set B.FIRSTNAME = substr(A.FULLNAME, 1, instr(A.FULLNAME, ',') - 1)
I got this error SQL Error: ORA-00001: unique constraint (TEST.PK_TB) violated
which I believe is because I updated those fields say ID = 1, all with 'Caroline'
that means I will have to add a clause having count(TB.ID) = 1
How would you do it?
Server is Oracle 11g
Thank you!Hi,
One way is to join ta and tb in the USING clause, and eliminate the duplicates there.
MERGE INTO tb dst
USING (
SELECT ta.id
, REGEXP_SUBSTR ( MIN (ta.fullname)
, '^[^,]*'
) AS firstname
FROM ta
JOIN tb ON ta.id = tb.id
WHERE ta.type = 'ABC'
GROUP BY ta.id
HAVING COUNT (*) = 1
) src
ON (scr.id = dst.id)
WHEN MATCHED THEN UPDATE
SET dst.firstname = src.firstname
;If you'd care to post CREATE TABLE and INSERT statements for your sample data, then I could test this.
I used REGEXP_SUBST instead of SUBSTR and INSTR to find the firstname, because I find it a little cleaner, and becuase it returns something even when there is no ',' in fullname, which I'm guessing is what you really want. (None of the fullnames in your sample data have ','s.) You could use SUBSTR and INSTR instead. -
I'm not very tech savvy but am trying my best to use Disc Utility to copy my hard drive to a brand new external drive and am having the error "Unable to create...(Cannot allocate memory)".
Last night no problems, woke this morning and it was freezing so I forced a restart and got the grey screen with the folder and question mark. Ran off to best buy to get an external drive... Please help! Thank you!I have done both. When I hold down the "C" key it pauses for a few seconds while the cd spins and then the flashing folder icon appears.
Could be you have the wrong cd/dvd. The mac will only boot a supported cd/dvd for your machine. The flashing question mark indicdates your machine could not find a valid os.
When I hold down the "option" key for the startup manager the cursor comes up and moves but the actually manager doesn't come up no matter how long I leave the laptop on.
Not sure. Could be your machine does not support the startup manager. You would think the machine would ignore the key.
Where did you get the dvd? What is the number on the DVD?
What machine do you have anyway?
This site provides more information, but lacks security.
"A serial number is a unique, identifying number or group of numbers and letters assigned to an individual piece of hardware or software. It's used for various things depending on the product / brand but what is your Mac's serial number for and more importantly... what is it hiding and what can it do for you ?"
http://www.appleserialnumberinfo.com/Desktop/index.php
or
This site provides more information, but lacks security too.
"A serial number is a unique, identifying number or group of numbers and letters assigned to an individual piece of hardware or software. It's used for various things depending on the product / brand but what is your Mac's serial number for and more importantly... what is it hiding and what can it do for you ?"
http://www.appleserialnumberinfo.com/Desktop/index.php
http://www.chipmunk.nl/klantenservice/applemodel.html
( hint by K Shaffer ) -
Select query having count function is returning null
Hi Everyone,
Please see the query and help me to get this solved.
DB version
Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - 64bi
PL/SQL Release 10.2.0.1.0 - Production
"CORE 10.2.0.1.0 Production"
TNS for Linux: Version 10.2.0.1.0 - Production
NLSRTL Version 10.2.0.1.0 - ProductionQUERY
SELECT COUNT(*) as V_COUNT
FROM LAB_ORDER_TMPLT_TEST
WHERE TEST_ID IN
(SELECT WEST_TEST_ID
FROM TEST_CODE_CONVERSION TCC
WHERE TCC.EAST_TEST_ID = 2769)
GROUP BY LAB_ORDER_TMPLT_ID
HAVING COUNT(*) > 1;
It's returning null. Is there any way I can get the value as zero instead of null? Please help.Regards,
BS2012.Hi,
BS2012 wrote:
Hi Everyone,
Please see the query and help me to get this solved.
DB version
Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - 64bi
PL/SQL Release 10.2.0.1.0 - Production
"CORE 10.2.0.1.0 Production"
TNS for Linux: Version 10.2.0.1.0 - Production
NLSRTL Version 10.2.0.1.0 - ProductionQUERY
SELECT COUNT(*) as V_COUNT
FROM LAB_ORDER_TMPLT_TEST
WHERE TEST_ID IN
(SELECT WEST_TEST_ID
FROM TEST_CODE_CONVERSION TCC
WHERE TCC.EAST_TEST_ID = 2769)
GROUP BY LAB_ORDER_TMPLT_ID
HAVING COUNT(*) > 1;
It's returning null.
Really? COUNT never returns NULL; it always returns 0 or a positive integer.
Do you mean the query results in "no rows selected"?
Is there any way I can get the value as zero instead of null? Please help.Do you want a query that will produce the same output as the query above, but will produce a single row containing 0 when the query above does not produce anything? That sounds like a job for an outer join:
WITH original_query AS
SELECT COUNT(*) AS v_count
FROM lab_order_tmplt_test
WHERE test_id IN
( SELECT west_test_id
FROM test_code_conversion tcc
WHERE tcc.east_test_id = 2769
GROUP BY lab_order_tmplt_id
SELECT NVL (o.v_count, 0) AS v_count
FROM dual
LEFT OUTER JOIN original_query o ON o.v_count > 0
;If you'd care to post CREATE TABLE and INSERT statements for the sample data, then I could test this. -
Group by having clause problem
Hi,
I have a query like this:
select a.id,a.first_nm,a.last_nm,a.subgroup_id
from temp a
where (a.subgroup_id like 'D%' or a.subgroup_id like 'G%')
group by a.id,a.first_nm,a.last_nm,a.subgroup_id having
count(*) >1
union
select b.id,b.first_nm,b.last_nm,b.subgroup_id
from temp b
where b. subgroup_id like 'F%'
group by b.id,b.first_nm,b.last_nm,b.subgroup_id having count(*) > 2;
I want the result like this:
10001 Wendy Lin DAP
10001 Wendy Lin GMP
10002 Jim Davis FAD
10002 Jim Davis FIP
10002 Jim Davis FIAP
My query above didn't give the right result, Can someone help me?
Thank you very much!
WendyYou may like to try this way...
select id,name,sub_id
from a
where id in (select id
from a
group by id
having count(id)>1)
order by id,name, sub_id asc;
results are..
ID NAME CODE
1 wendy DIA
1 wendy LCA
1 wendy PLA
2 jim CPR
2 jim DIA
2 jim PLA
Hope this helps. -
I have two queries below- first of which outputs one record, the Second query doesn't.
Can you explain why First query returns always records, at least one record? In explanation, can you say which process is runned after which (something like where is runned firstly, then group by, then...)?
--First:
select count(count(1)) from dual
where 1=2
group by dummy
having count(dummy) > 0;--1 row, value: 0
--Second:
select count(1) from dual
where 1=2
group by dummy
having count(dummy) > 0;--0 rowsHi,
Aggregate queries with nested aggregate functions (such as "COUNT (COUNT (1))") always return exactly 1 row, even if there are no rows in the table (or, as in your first example, no rows survive the WHERE clause).
The outer layer of nested aggreate functions is evaluated after the GROUP BY and HAVING clauses have been applied.
If you have a GROUP BY clause, but no nested aggregate fucntions, then the output contains one row for every distinct group, subject to the WHERE- and HAVING clauses. In your second example, no rows are left after the WHERE clause, so there will be no rows in the output.
You can think of things as happening in this order
(1) WHERE
(2) GROUP BY
(3) (inner) aggregate fucntions
(4) HAVING
(5) Nested aggregate functions
The optimizer may not actually follow the steps above, but you won't notice that.
Edited by: Frank Kulash on Mar 25, 2010 11:51 AM
The following thread may help you:
Re: group function -
Another group by having problem I think ...
I have a table defined like so ...
create table mytable (
subcode number,
name varchar2(10)
I suspect that I have records in this table that look like so ...
SUBCODE NAME
123 Jim
123 Mary
... this is bad.
I ran a query like this ...
select subcode, name, count(subcode) from mytable group by subcode, name having count(subcode) > 1
... and got back zero results.
Does this mean I DO NOT have duplicates?
ThanksYou do have duplicates but your statement doesn't show that since you are grouping by SUBCODE and NAME. Since your have the same SUBCODE but a different NAME for the duplicate SUBCODE you get only 1 result with your group by statement. Here are two examples:
select subcode, name, count(subcode)
from mytable
group by subcode, name
SUBCODE COUNT(SUBCODE)
123 2
select subcode, name, count(subcode)
from mytable
group by subcode, name
SUBCODE NAME COUNT(SUBCODE)
123 JIM 1
123 MARY 1This statement will give you what you are looking for:
select subcode, name
from mytable
where subcode = (select subcode
from mytable
group by subcode
having count(subcode) > 1); -
Create Table From a Having Count Select
Hello Folks, any ideas here, I need to create a table using the below 'Select' as the criteria.
I have the following table and its has duplicate records, identified by double Unique_seq. I want to create a table of these else where, then delete them from schema.tablename.
Schmea.tablename
field1
field2
field3
field4
Unique_Seq
SELECT Unique_Seq,COUNT(Unique_Seq)
FROM Schema.Tablename
GROUP BY Unique_Seq
HAVING ( COUNT(Unique_Seq) > 1
I want to create the table using all the fields from schema.tablename
ThanksThanks for the table script and insert statement.
here is what you are looking for
select * from tester_c;
AD_ID CD_ID UNIQUE_SEQ Z_MASTER_KEY
OP0021889/10 OP0021889/10 529832 NNCC00491362OP0021889/1025-JAN-10
OP0021889/10 529832 NNCC0049136225-JAN-10
OP0022096/10 539481 NNCC0060037812-JAN-10
OP0022096/10 OP0022096/10 539481 NNCC00600378OP0022096/1012-JAN-10
LI0192 IK735241 53925 PP54TH34120988
KL1923836 65478 BG7892534KL1923836
KL1923836 65478 BG7892534KL1923836
PQ8712346 BN27345236 64877 7234723642
8 rows selected.
Elapsed: 00:00:00.01Pushing duplicate data into a new table tester_c_dup
CREATE Table tester_c_dup as SELECT * FROM tester_c A WHERE a.rowid > ANY (SELECT B.rowid FROM
Tester_c B
WHERE
a.Unique_Seq = B.Unique_Seq)
select * from tester_c_dup;
AD_ID CD_ID UNIQUE_SEQ Z_MASTER_KEY
OP0021889/10 529832 NNCC0049136225-JAN-10
OP0022096/10 OP0022096/10 539481 NNCC00600378OP0022096/1012-JAN-10
KL1923836 65478 BG7892534KL1923836
Elapsed: 00:00:00.01Deleting duplicate data from tester_c table
DELETE FROM tester_c A WHERE a.rowid > ANY (SELECT B.rowid FROM
Tester_c B
WHERE
a.Unique_Seq = B.Unique_Seq)
select * from tester_c;
AD_ID CD_ID UNIQUE_SEQ Z_MASTER_KEY
OP0021889/10 OP0021889/10 529832 NNCC00491362OP0021889/1025-JAN-10
OP0022096/10 539481 NNCC0060037812-JAN-10
LI0192 IK735241 53925 PP54TH34120988
KL1923836 65478 BG7892534KL1923836
PQ8712346 BN27345236 64877 7234723642
Elapsed: 00:00:00.00HTH,
Prazy -
Error loading Cache group but Cache group created with out error
Hi
I have created a cache group but when I load that cache group I get following error:
Command> load cache group SecondCache commit every 1 rows;
5056: The cache operation fails: error_type=<Oracle Error>, error_code=<972>, error_message:ORA-00972: identifier is too long
5037: An error occurred while load TESTUSER.SECONDCACHE:Load failed (ORA-00972: identifier too long)
The command failed.
Please help.
Looking forward for your reply.
/AhmadHi Chris!
Thanks for urgent response. I solved my problem to some extent but want to share.
Acctualy I was having a column named # which is a primary key also. When I change that column name from # to some other name like some characters then the cahe group is loaded successfuly.
Is there anyway in TimesTen to load columns names # .
I read in the documentation of TimesTen that it allows columns names as # , so it is the reason it is creating the cache group but fails to load do not know the reason.
The code for creating cache group is as follows:
create cache group MEASCache from testuser."MEAS"("UPDATED" number not
null,"UNOCCUPIEDRECORD" number not null,"VALUECURRENT" number not null,"EQSFREF
" number not null,"IMPLEMENTED" number not null,"FORMAT" number not null,"#" number not null,primary key("#"))
When I change the # column to like eg Identity it works fine.
/Ahmad -
Hi I've tried the following code but getting the error subscript beyond count error
create or replace procedure test(
p_srrce in DIM_AD.DE%type,
p_date in varchar2,
p_asset_id in DISET.PE_ID%type,
p_nt_id in FAT_T.DT_ID%type,
chek_status out varchar2,
logs_dat out varchar2
IS
TYPE da_list IS TABLE OF FAT_T.DT_ID%TYPE;
TYPE pd_list IS TABLE OF FAT_T.pd%TYPE;
TYPE v_txt_list IS TABLE OF FAT_T.v_txt%TYPE;
TYPE ttime_list IS TABLE OF FAT_T.ttime%TYPE;
type t_rowid IS TABLE OF rowid INDEX BY binary_INTEGER;
v_d_srce varchar2(222);
v_prdat date ;
no_d_eep exception;
v_da_list da_list ;
v_pd_list pd_list ;
v_v_txt_list v_txt_list ;
v_ttime_list ttime_list ;
v_rowid t_rowid ;
BEGIN
v_d_srce := trim(p_srrce);
v_prdat := to_date(trim(p_date),'mm/dd/yyyy');
DBMS_OUTPUT.PUT_LINE ( 'value v_prdat '||v_prdat );
------ After executing this procedure the output statemnt has come till here after the got the error subscript beyond count
SELECT
DT_ID,
pd,
v_txt,
ttime
fdp.ROWID
bulk collect into v_da_list , v_pd_list ,v_v_txt_list , v_ttime_list,v_rowid
FROM
FAT_T
WHERE
pd = NVL(p_asset_id ,pd)
AND DT_ID = NVL(p_nt_id ,DT_ID)
AND pedt=v_prdat ;
FOR i in v_da_list.first .. v_da_list.last LOOP
DBMS_OUTPUT.PUT_LINE ( 'Values are '||v_da_list(i) );
END LOOP ;
EXCEPTION
END;
Please help in thisHi,
it's hard to reproduce without having your data at hand.
Is it possible for you to reproduce the error with a table having few rows?
Can you post CREATE TABLE and INSERT statement for FAT_T table?
How many rows do you have in FAT_T table?
The error 6533 literally has this explanation:
The SUBSCRIPT_BEYOND_COUNT Exception (ORA-06533) occurs when a program references a nested table or varray element using an index number larger than the number of elements in the collection.
So I can only think that it occurs if you are trying to use an index larger than your table.
That's why I said your original code could have had a problem in the LOOP part in case the query was not returning any row.
But actually in case the array was empty you would get another error in the loop (ORA-06502: PL/SQL: numeric or value error)
I saw that your array type are all nested tables except t_rowid which is an associative array using BINARY_INTEGER as index.
This index can be up to 2^32. So unless you have a very high number of rows (more than 2.15 billions) you should not get this error.
I can suggest to check 2 things:
How many rows does your SELECT statement returns?
Comment the exception block to see exactly which line is throwing that error.
Post some sample data to reproduce your problem
Actually if I try to do something similar in my environment using EMP table I don't get any error (if my select returns rows):
SQL*Plus: Release 11.2.0.1.0 Production on Thu Nov 7 12:22:28 2013
Copyright (c) 1982, 2010, Oracle. All rights reserved.
Connected to:
Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - Production
With the Partitioning, OLAP, Data Mining and Real Application Testing options
SQL>
SQL> DECLARE
2 TYPE t_empno IS TABLE OF emp.empno%TYPE;
3 TYPE t_ename IS TABLE OF emp.ename%TYPE;
4 TYPE t_hiredate IS TABLE OF emp.hiredate%TYPE;
5 TYPE t_sal IS TABLE OF emp.sal%TYPE;
6 TYPE t_rowid IS TABLE OF ROWID
7 INDEX BY BINARY_INTEGER;
8
9 v_empno t_empno;
10 v_ename t_ename;
11 v_hiredate t_hiredate;
12 v_sal t_sal;
13 v_rowid t_rowid;
14
15 BEGIN
16 SELECT empno, ename, hiredate, sal
17 , ROWID
18 BULK COLLECT INTO v_empno, v_ename, v_hiredate, v_sal
19 , v_rowid
20 FROM emp;
21
22 FOR i IN v_empno.FIRST .. v_empno.LAST
23 LOOP
24 DBMS_OUTPUT.put_line ('Values are ' || v_empno (i));
25 END LOOP;
26 END;
27 /
Values are 7369
Values are 7499
Values are 7521
Values are 7566
Values are 7654
Values are 7698
Values are 7782
Values are 7788
Values are 7839
Values are 7844
Values are 7876
Values are 7900
Values are 7902
Values are 7934
PL/SQL procedure successfully completed.
SQL>
Regards.
Alberto -
How to display rows in PSA having count(wbs) 1
Hi there BW gurus.
I have a history in the SQL world, where it is quite easy to write a SQL code to get out the rows from a table with duplicates in one spesific field. (Beeing indexed or not)
I have tried to search for this option where we diplays the content in an PSA. but not found it.
Anyone having a good solution for this.
(I am not an ABAP-er)
Best Regards IngridHi Ingrid,
following ABAP returns all languages which more than one user is assigned to.
data: l_langu type usr01-langu.
data: l_Num type i.
SELECT count( * ) langu
into (l_Num, l_langu)
FROM usr01
GROUP BY langu
having count( * ) GT 1.
write: / l_langu, ' - ', l_num.
endselect.
e.g. language E is assigned to 27 users.
Hope this gives you an idea.
Regards,
Jürgen
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