Group by Having Count(*)
Hi...
I'm back again and I'm ever hopeful that I will get some needed help.
I'm trying to use the groupby and having Count(*) on a table, but I think
I have my group by wrong...I keep getting the wrong output.
Here's my code:
Select Course_ID,Count(*),Department_ID,Class_ID,Class_Room
from Class
Group By Course_ID,Department_ID,Class_ID,Class_Room
Having Count(*) >=1
and this is the output:
COURS COUNT(*) DEPARTMENT_ID CLASS_ID CLASS_ROOM
50 1 MATH 103600 140
101 1 BIO 109100 180
101 1 ENGL 108300 150
115 1 HIST 108400 200
183 1 PSYCH 103400 150
183 1 PSYCH 108600 240
184 1 HIST 104500 200
198 1 PHILO 104200 150
199 1 ENG 110300 255
199 1 ECON 120200 235
Now, what should be happeing is that Count should give me 2*101,2*183,2*199 but I keep
getting 1 of each...
Any ideas about where I'm going Wrong?
Drake,
In short, you are grouping on too many things. You need to group on only course_id when looking for duplicates, and then join the duplicate courses back to the course table to get the rest of the data:
select c.course_id, c.department_id,
c.class_id, c.class_room
from class c,
(select course_id, count(*) howmany
from class
group by course_id
having count(*) > 1) dups
where c.course_id = dups.course_id;
Hi...
I'm back again and I'm ever hopeful that I will get some needed help.
I'm trying to use the groupby and having Count(*) on a table, but I think
I have my group by wrong...I keep getting the wrong output.
Here's my code:
Select Course_ID,Count(*),Department_ID,Class_ID,Class_Room
from Class
Group By Course_ID,Department_ID,Class_ID,Class_Room
Having Count(*) >=1
and this is the output:
COURS COUNT(*) DEPARTMENT_ID CLASS_ID CLASS_ROOM
50 1 MATH 103600 140
101 1 BIO 109100 180
101 1 ENGL 108300 150
115 1 HIST 108400 200
183 1 PSYCH 103400 150
183 1 PSYCH 108600 240
184 1 HIST 104500 200
198 1 PHILO 104200 150
199 1 ENG 110300 255
199 1 ECON 120200 235
Now, what should be happeing is that Count should give me 2*101,2*183,2*199 but I keep
getting 1 of each...
Any ideas about where I'm going Wrong?
Similar Messages
-
I have this code with an error:
SELECT (CASE id_type
WHEN 4 THEN companyid
ELSE nric
END) AS customerid
FROM customer
GROUP BY customerid HAVING COUNT (*customerid*) = 1
The error is at the bold word with the error: Invalid identifier. How should I rewrite my sql statement?SELECT CUSTOMERID FROM
SELECT (CASE id_type
WHEN 4 THEN companyid
ELSE nric
END) AS customerid
FROM customer
GROUP BY customerid HAVING COUNT (customerid) = 1 -
Count(field) group by having changed to an analytic function
Goal: Be able to show columns with data not in the group by clause.
I couldn't find this on the 'net either by looking here or by googling for it (unless I'm looking for the wrong thing). I'm doing a regular:
select fielda, count(fielda)
from some_table
group by fielda1
having count(field1) > 1;
to find out where I have duplicates in a table (fielda). I get fielda and the count of those records back (ie X, 2). However, I want to add several more fields that may or may not be different for each of those records.
For example:
1 record has fielda = X, field2 = Test, field3 = Oracle, field4 = Unix
1 record has fielda = X, field2 = Testa, field3 = Sybase, field4 = Windows.
I want to be able to have the following output:
X, 2 (count of records with fieldA = X), Test, Oracle, Unix
X, 2 (count of records with fieldA = X), Testa, Sybase, Windows
I'm not sure if this is one of those where I have to do a subquery on or not. Any ideas?
Thanks as always!
VicSorry, I misread your statement - it is poorly formatted. Besides incorrect use of aliases you are referencing columns that are not in inline view, therefore you must include it there:
select nsn,
item_type_name,
item_type_id,
date_time_added,
function_name
from (
select it.nsn,
it.item_type_name,
it.item_type_id,
it.date_time_added,
fn.function_name,
count(*) over (partition by it.nsn) cnt,
it.item_type_cat_id,
ic.item_category_id,
ic.function_id ic_function_id,
fn.function_id fn_function_id
from item_types it,
item_categories ic, functions fn
where it.nsn is not null
and it.item_type_cat_id = ic.item_category_id
and ic.function_id = fn.function_id
where cnt > 1
and nsn is not null
and item_type_cat_id = item_category_id
and ic_function_id = fn_function_id
order by nsn;SY. -
Select query having count function is returning null
Hi Everyone,
Please see the query and help me to get this solved.
DB version
Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - 64bi
PL/SQL Release 10.2.0.1.0 - Production
"CORE 10.2.0.1.0 Production"
TNS for Linux: Version 10.2.0.1.0 - Production
NLSRTL Version 10.2.0.1.0 - ProductionQUERY
SELECT COUNT(*) as V_COUNT
FROM LAB_ORDER_TMPLT_TEST
WHERE TEST_ID IN
(SELECT WEST_TEST_ID
FROM TEST_CODE_CONVERSION TCC
WHERE TCC.EAST_TEST_ID = 2769)
GROUP BY LAB_ORDER_TMPLT_ID
HAVING COUNT(*) > 1;
It's returning null. Is there any way I can get the value as zero instead of null? Please help.Regards,
BS2012.Hi,
BS2012 wrote:
Hi Everyone,
Please see the query and help me to get this solved.
DB version
Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - 64bi
PL/SQL Release 10.2.0.1.0 - Production
"CORE 10.2.0.1.0 Production"
TNS for Linux: Version 10.2.0.1.0 - Production
NLSRTL Version 10.2.0.1.0 - ProductionQUERY
SELECT COUNT(*) as V_COUNT
FROM LAB_ORDER_TMPLT_TEST
WHERE TEST_ID IN
(SELECT WEST_TEST_ID
FROM TEST_CODE_CONVERSION TCC
WHERE TCC.EAST_TEST_ID = 2769)
GROUP BY LAB_ORDER_TMPLT_ID
HAVING COUNT(*) > 1;
It's returning null.
Really? COUNT never returns NULL; it always returns 0 or a positive integer.
Do you mean the query results in "no rows selected"?
Is there any way I can get the value as zero instead of null? Please help.Do you want a query that will produce the same output as the query above, but will produce a single row containing 0 when the query above does not produce anything? That sounds like a job for an outer join:
WITH original_query AS
SELECT COUNT(*) AS v_count
FROM lab_order_tmplt_test
WHERE test_id IN
( SELECT west_test_id
FROM test_code_conversion tcc
WHERE tcc.east_test_id = 2769
GROUP BY lab_order_tmplt_id
SELECT NVL (o.v_count, 0) AS v_count
FROM dual
LEFT OUTER JOIN original_query o ON o.v_count > 0
;If you'd care to post CREATE TABLE and INSERT statements for the sample data, then I could test this. -
Group by having clause problem
Hi,
I have a query like this:
select a.id,a.first_nm,a.last_nm,a.subgroup_id
from temp a
where (a.subgroup_id like 'D%' or a.subgroup_id like 'G%')
group by a.id,a.first_nm,a.last_nm,a.subgroup_id having
count(*) >1
union
select b.id,b.first_nm,b.last_nm,b.subgroup_id
from temp b
where b. subgroup_id like 'F%'
group by b.id,b.first_nm,b.last_nm,b.subgroup_id having count(*) > 2;
I want the result like this:
10001 Wendy Lin DAP
10001 Wendy Lin GMP
10002 Jim Davis FAD
10002 Jim Davis FIP
10002 Jim Davis FIAP
My query above didn't give the right result, Can someone help me?
Thank you very much!
WendyYou may like to try this way...
select id,name,sub_id
from a
where id in (select id
from a
group by id
having count(id)>1)
order by id,name, sub_id asc;
results are..
ID NAME CODE
1 wendy DIA
1 wendy LCA
1 wendy PLA
2 jim CPR
2 jim DIA
2 jim PLA
Hope this helps. -
I have two queries below- first of which outputs one record, the Second query doesn't.
Can you explain why First query returns always records, at least one record? In explanation, can you say which process is runned after which (something like where is runned firstly, then group by, then...)?
--First:
select count(count(1)) from dual
where 1=2
group by dummy
having count(dummy) > 0;--1 row, value: 0
--Second:
select count(1) from dual
where 1=2
group by dummy
having count(dummy) > 0;--0 rowsHi,
Aggregate queries with nested aggregate functions (such as "COUNT (COUNT (1))") always return exactly 1 row, even if there are no rows in the table (or, as in your first example, no rows survive the WHERE clause).
The outer layer of nested aggreate functions is evaluated after the GROUP BY and HAVING clauses have been applied.
If you have a GROUP BY clause, but no nested aggregate fucntions, then the output contains one row for every distinct group, subject to the WHERE- and HAVING clauses. In your second example, no rows are left after the WHERE clause, so there will be no rows in the output.
You can think of things as happening in this order
(1) WHERE
(2) GROUP BY
(3) (inner) aggregate fucntions
(4) HAVING
(5) Nested aggregate functions
The optimizer may not actually follow the steps above, but you won't notice that.
Edited by: Frank Kulash on Mar 25, 2010 11:51 AM
The following thread may help you:
Re: group function -
Another group by having problem I think ...
I have a table defined like so ...
create table mytable (
subcode number,
name varchar2(10)
I suspect that I have records in this table that look like so ...
SUBCODE NAME
123 Jim
123 Mary
... this is bad.
I ran a query like this ...
select subcode, name, count(subcode) from mytable group by subcode, name having count(subcode) > 1
... and got back zero results.
Does this mean I DO NOT have duplicates?
ThanksYou do have duplicates but your statement doesn't show that since you are grouping by SUBCODE and NAME. Since your have the same SUBCODE but a different NAME for the duplicate SUBCODE you get only 1 result with your group by statement. Here are two examples:
select subcode, name, count(subcode)
from mytable
group by subcode, name
SUBCODE COUNT(SUBCODE)
123 2
select subcode, name, count(subcode)
from mytable
group by subcode, name
SUBCODE NAME COUNT(SUBCODE)
123 JIM 1
123 MARY 1This statement will give you what you are looking for:
select subcode, name
from mytable
where subcode = (select subcode
from mytable
group by subcode
having count(subcode) > 1); -
Create Table From a Having Count Select
Hello Folks, any ideas here, I need to create a table using the below 'Select' as the criteria.
I have the following table and its has duplicate records, identified by double Unique_seq. I want to create a table of these else where, then delete them from schema.tablename.
Schmea.tablename
field1
field2
field3
field4
Unique_Seq
SELECT Unique_Seq,COUNT(Unique_Seq)
FROM Schema.Tablename
GROUP BY Unique_Seq
HAVING ( COUNT(Unique_Seq) > 1
I want to create the table using all the fields from schema.tablename
ThanksThanks for the table script and insert statement.
here is what you are looking for
select * from tester_c;
AD_ID CD_ID UNIQUE_SEQ Z_MASTER_KEY
OP0021889/10 OP0021889/10 529832 NNCC00491362OP0021889/1025-JAN-10
OP0021889/10 529832 NNCC0049136225-JAN-10
OP0022096/10 539481 NNCC0060037812-JAN-10
OP0022096/10 OP0022096/10 539481 NNCC00600378OP0022096/1012-JAN-10
LI0192 IK735241 53925 PP54TH34120988
KL1923836 65478 BG7892534KL1923836
KL1923836 65478 BG7892534KL1923836
PQ8712346 BN27345236 64877 7234723642
8 rows selected.
Elapsed: 00:00:00.01Pushing duplicate data into a new table tester_c_dup
CREATE Table tester_c_dup as SELECT * FROM tester_c A WHERE a.rowid > ANY (SELECT B.rowid FROM
Tester_c B
WHERE
a.Unique_Seq = B.Unique_Seq)
select * from tester_c_dup;
AD_ID CD_ID UNIQUE_SEQ Z_MASTER_KEY
OP0021889/10 529832 NNCC0049136225-JAN-10
OP0022096/10 OP0022096/10 539481 NNCC00600378OP0022096/1012-JAN-10
KL1923836 65478 BG7892534KL1923836
Elapsed: 00:00:00.01Deleting duplicate data from tester_c table
DELETE FROM tester_c A WHERE a.rowid > ANY (SELECT B.rowid FROM
Tester_c B
WHERE
a.Unique_Seq = B.Unique_Seq)
select * from tester_c;
AD_ID CD_ID UNIQUE_SEQ Z_MASTER_KEY
OP0021889/10 OP0021889/10 529832 NNCC00491362OP0021889/1025-JAN-10
OP0022096/10 539481 NNCC0060037812-JAN-10
LI0192 IK735241 53925 PP54TH34120988
KL1923836 65478 BG7892534KL1923836
PQ8712346 BN27345236 64877 7234723642
Elapsed: 00:00:00.00HTH,
Prazy -
How to display rows in PSA having count(wbs) 1
Hi there BW gurus.
I have a history in the SQL world, where it is quite easy to write a SQL code to get out the rows from a table with duplicates in one spesific field. (Beeing indexed or not)
I have tried to search for this option where we diplays the content in an PSA. but not found it.
Anyone having a good solution for this.
(I am not an ABAP-er)
Best Regards IngridHi Ingrid,
following ABAP returns all languages which more than one user is assigned to.
data: l_langu type usr01-langu.
data: l_Num type i.
SELECT count( * ) langu
into (l_Num, l_langu)
FROM usr01
GROUP BY langu
having count( * ) GT 1.
write: / l_langu, ' - ', l_num.
endselect.
e.g. language E is assigned to 27 users.
Hope this gives you an idea.
Regards,
Jürgen -
Can I write merge SQL statement having count(*)?
Hi this is a followup question of my previous post. I tried to use a merge SQL statement to solve my problem but now I bump into another problem.
Now I have a table where the field I need to update is a partial PK
when using a merge SQL statement, I have to put a where clause that check if count(*) = 1 because of the PK constraint
Where can I put the count(*) = 1 clause?
Here are the details:
I have two tables TA and TB, where TA contains the fields ID, FULLNAME, TYPE and TB contains the fields ID, FIRSTNAME
I want to update the firstnames in TB to be the firstnames from TA where TB.ID = TA.ID and TA.TYPE = 'ABC'
{ID, FIRSTNAME} are PKs but for the same ID, there can be more than 1 firstname.
e.g.
TA
ID | FULLNAME | TYPE
1 Caroline T ABC
2 Mary C DEF
3 Peter J ABC
TB
ID | FIRSTNAME
1 Caroline
1 Carol
1 C,
3 Peter
I need to update TB with the new firstnames from TA where type is 'ABC' but only for those fields that have count(TB.ID) = 1
when I try to run this SQL statement
merge into TB B using TA A
on (A.ID = B.ID and A.TYPE = 'ABC')
when matched then update set B.FIRSTNAME = substr(A.FULLNAME, 1, instr(A.FULLNAME, ',') - 1)
I got this error SQL Error: ORA-00001: unique constraint (TEST.PK_TB) violated
which I believe is because I updated those fields say ID = 1, all with 'Caroline'
that means I will have to add a clause having count(TB.ID) = 1
How would you do it?
Server is Oracle 11g
Thank you!Hi,
One way is to join ta and tb in the USING clause, and eliminate the duplicates there.
MERGE INTO tb dst
USING (
SELECT ta.id
, REGEXP_SUBSTR ( MIN (ta.fullname)
, '^[^,]*'
) AS firstname
FROM ta
JOIN tb ON ta.id = tb.id
WHERE ta.type = 'ABC'
GROUP BY ta.id
HAVING COUNT (*) = 1
) src
ON (scr.id = dst.id)
WHEN MATCHED THEN UPDATE
SET dst.firstname = src.firstname
;If you'd care to post CREATE TABLE and INSERT statements for your sample data, then I could test this.
I used REGEXP_SUBST instead of SUBSTR and INSTR to find the firstname, because I find it a little cleaner, and becuase it returns something even when there is no ',' in fullname, which I'm guessing is what you really want. (None of the fullnames in your sample data have ','s.) You could use SUBSTR and INSTR instead. -
with my_table as
(select '402' id, '75175637' snr from dual union all
select '400' id, '15208367' snr from dual union all
select '400' id, '45208312' snr from dual union all
select '400' id, '55208344' snr from dual union all
select '402' id, '65208317' snr from dual union all
select '402' id, '65208317' snr from dual union all
select '402' id, '75208310' snr from dual union all
select '402' id, '85208310' snr from dual union all
select '421' id, '75208310' snr from dual union all
select '421' id, '99908456' snr from dual union all
select '422' id, '10008222' snr from dual) -- end of data sample
select b.snr
from (select id, snr
from my_table
group by id, snr) b
group by b.snr
having count(*) > 1 ;
SNR
75208310SNR 75208310 is among ID 402 and 421. The output should be the following:
ID SNR
402 75208310
421 75208310Does anybody have an idea?Thank you @all,
Warren,
after I add the statement >>select '402' id, '65208317' snr from dual union all<<
to the data sample I get the following
SQL> with my_table as
2 (select '402' id, '75175637' snr from dual union all
3 select '400' id, '15208367' snr from dual union all
4 select '400' id, '45208312' snr from dual union all
5 select '400' id, '55208344' snr from dual union all
6 select '402' id, '65208317' snr from dual union all
7 select '402' id, '65208317' snr from dual union all -- additional statement
8 select '402' id, '75208310' snr from dual union all
9 select '402' id, '85208310' snr from dual union all
10 select '421' id, '75208310' snr from dual union all
11 select '421' id, '99908456' snr from dual union all
12 select '422' id, '10008222' snr from dual) -- end of data sample
13 select distinct
14 mt1.id,
15 mt1.snr
16 from my_table mt1,
17 (select snr, count(*) cnt
18 from my_table
19 group by snr) mt2
20 where mt1.snr = mt2.snr
21 and mt2.cnt > 1;
ID SNR
402 65208317
402 75208310
421 75208310
SQL> But I do not need 402, 65208317 in my output.
I solved it with
SQL> with my_table as
2 (select '402' id, '75175637' snr from dual union all
3 select '400' id, '15208367' snr from dual union all
4 select '400' id, '45208312' snr from dual union all
5 select '400' id, '55208344' snr from dual union all
6 select '402' id, '65208317' snr from dual union all
7 select '402' id, '65208317' snr from dual union all -- additional statement
8 select '402' id, '75208310' snr from dual union all
9 select '402' id, '85208310' snr from dual union all
10 select '421' id, '75208310' snr from dual union all
11 select '421' id, '99908456' snr from dual union all
12 select '422' id, '10008222' snr from dual) -- end of data sample
13 select id, snr
14 from
15 ( select id, snr, count(*) over (partition by snr) as cnt
16 from my_table
17 group by id, snr
18 )
19 where cnt > 1
20 ;
ID SNR
402 75208310
421 75208310
SQL> -
How can I forward a mail to multiple mail accounts that I have in a group without having to add them one by one?
I don't think that you can. Yahoo's basic email features do not include mail forwarding.
-
I would like to count how many ID have only had 1 Enrolment by year:
I am assuming you would have to use having count = 1 or something like that.
So I have the following example below
ID 1 has 2 enrolments so dont count
ID 2 has only 1 enrolment so count
ID 3 has 2 enrolments so dont count
ID 4 has 1 enrolment so count
ID 5 has 2 enrolments so dont count
ID 6 has 1 so count
ID 7 and 8 have one each so count.
Thanks
CREATE TABLE DAN_PRU
(ID VARCHAR2(8),
UNIT VARCHAR2(8),
YEAR VARCHAR2(8))
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (1,'POP','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (1,'DOP','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (2,'KUIP','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (3,'DIP','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (3,'YUP','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (4,'SII','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (5,'DYY','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (5,'LIW','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (6,'DFG','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (7,'DWQ','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (8,'DFR','2013');GIVES:
ID UNIT YEAR
1 POP 2013
1 DOP 2013
2 KUIP 2013
3 DIP 2013
3 YUP 2013
4 SII 2013
5 DYY 2012
5 LIW 2012
6 DFG 2012
7 DWQ 2011
8 DFR 2011WANT
ENROLMENTS YEAR
2 2013
1 2012
2 2011
using oracle 10Hi,
Interesting problem!
Chloe_19 wrote:
I would like to count how many ID have only had 1 Enrolment by year:
I am assuming you would have to use having count = 1 or something like that.That's an obvious first step. What makes this such an interesting problem is how you get from there to the final answer.
What is the final answer? Do you want just one row, containing just one number (5 in this case, since there are 5 ids (2, 4, 6, 7 and 8) that have only 1 enrollment?
So I have the following example below
ID 1 has 2 enrolments so dont count
ID 2 has only 1 enrolment so count
ID 3 has 2 enrolments so dont count
ID 4 has 1 enrolment so count
ID 5 has 2 enrolments so dont count
ID 6 has 1 so count
ID 7 and 8 have one each so count.
Thanks
CREATE TABLE DAN_PRU
(ID VARCHAR2(8),
UNIT VARCHAR2(8),
YEAR VARCHAR2(8)) Why is year a VARCHAR2? Why is it 8 characters long?
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (1,'POP','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (1,'DOP','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (2,'KUIP','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (3,'DIP','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (3,'YUP','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (4,'SII','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (5,'DYY','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (5,'LIW','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (6,'DFG','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (7,'DWQ','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (8,'DFR','2013');
GIVES:How does the data above give the results below.
For example, it looks like '2013' is the only year in the data. How do you get '2011' and '2012' in the results?
Can the same id have multiple years? What results would you want in that case?
ID UNIT YEAR
1 POP 2013
1 DOP 2013
2 KUIP 2013
3 DIP 2013
3 YUP 2013
4 SII 2013
5 DYY 2012
5 LIW 2012
6 DFG 2012
7 DWQ 2011
8 DFR 2011WANTAre you saying the results below are what you want?
ENROLMENTS YEAR
2 2013
1 2012
2 2011
using oracle 10Can you get a result set that contains one row per id? (Or for each id/year combination; it's unclar what you want.)
Can you restrict that result set to contain only the ids with only 1 enrollment?
If you had a table like the previous result set, how would you solve the problem? Remember, any result set can be treated like a table, using a WITH clause. -
Where, Group By, Having, Order --- Usage sequence?
Hi
Can anyone tell me the sequence in which below clauses can be placed:
Where, Group By, Having, Order by
Moreover can we use Having after where and before Group By?
Thanks!! http://gurunguns.wordpress.comHere is a good blog explaining the sequence
http://pratchev.blogspot.com/2007/05/anatomy-of-query.html
Premature optimization is the root of all evil in programming. (c) by Donald Knuth
Naomi Nosonovsky, Sr. Programmer-Analyst
My blog -
A method of grouping a total count of errors by date
Dear SQL Gurus,
Can anyone guide me (with the script below) as to how I'm can group a total count of error by DISTINCT(CREATION_DATE)?
11g Enterprise Edition Release 11.2.0.2.0
SCRIPT:
select
CREATION_DATE, request_id, rpad (regexp_substr(summary,'[^\.|^:]+'), 60, '_') as "iCash Dep Error Summary",count(*)
from BKS_OM.bks_icash_dep_errors
group by CREATION_DATE, request_id, regexp_substr(summary,'[^\.|^:]+');
RESULTS:
CREATION_DATE REQUEST_ID iCash Dep Error Summary COUNT(*)
02-JUL-12 415967 Validation Failure__________________________________________ 1
02-JUL-12 415967 Validation Failure__________________________________________ 1
02-JUL-12 415967 Validation Failure__________________________________________ 1
02-JUL-12 415967 Validation Failure__________________________________________ 1
02-JUL-12 415967 Validation Failure__________________________________________ 2
06-JUL-12 417699 Validation Failure__________________________________________ 1
06-JUL-12 417699 Validation Failure__________________________________________ 1
06-JUL-12 417773 Validation Failure__________________________________________ 16
02-JUL-12 415967 Validation Failure__________________________________________ 1
06-JUL-12 417773 Validation Failure__________________________________________ 1
Regards,
DIBS812
Edited by: DIBS812 on Aug 3, 2012 10:51 AMThat did the trick John. Thank you for providing me the solution.
Thanks everyone for your response!
select trunc(creation_date), request_id,
rpad(regexp_substr(summary,'[^\.|^:]+'), 60, '_') as "iCash Dep Error Summary",
count(*)
from bks_om.bks_icash_dep_errors
group by trunc(creation_date), request_id, regexp_substr(summary,'[^\.|^:]+');
TRUNC(CREATION_DATE) REQUEST_ID iCash Dep Error Summary COUNT(*)
19-JUL-12 422601 Validation Failure__________________________________________ 326
19-JUL-12 423343 Validation Failure__________________________________________ 383
20-JUL-12 423650 Validation Failure__________________________________________ 439
02-JUL-12 415967 Validation Failure__________________________________________ 53
16-JUL-12 421687 Validation Failure__________________________________________ 277
06-JUL-12 417699 Validation Failure__________________________________________ 21
10-JUL-12 419189 Validation Failure__________________________________________ 124
06-JUL-12 417773 Validation Failure__________________________________________ 124
18-JUL-12 422529 Validation Failure__________________________________________ 269
19-JUL-12 422894 Validation Failure__________________________________________ 326
19-JUL-12 422901 Validation Failure__________________________________________ 326
18-JUL-12 422357 Validation Failure__________________________________________ 277
19-JUL-12 422865 Validation Failure__________________________________________ 326
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