Group by having clause problem

Question

Hi,
I have a query like this:
select a.id,a.first_nm,a.last_nm,a.subgroup_id
from temp a
where (a.subgroup_id like 'D%' or a.subgroup_id like 'G%')
group by a.id,a.first_nm,a.last_nm,a.subgroup_id having
count(*) >1
union
select b.id,b.first_nm,b.last_nm,b.subgroup_id
from temp b
where b. subgroup_id like 'F%'
group by b.id,b.first_nm,b.last_nm,b.subgroup_id having count(*) > 2;
I want the result like this:
10001 Wendy Lin DAP
10001 Wendy Lin GMP
10002 Jim Davis FAD
10002 Jim Davis FIP
10002 Jim Davis FIAP
My query above didn't give the right result, Can someone help me?
Thank you very much!
Wendy

Answer 1

You may like to try this way...
select id,name,sub_id
from a
where id in (select id
from a
group by id
having count(id)>1)
order by id,name, sub_id asc;
results are..
ID NAME CODE
1 wendy DIA
1 wendy LCA
1 wendy PLA
2 jim CPR
2 jim DIA
2 jim PLA
Hope this helps.