Group by with date

Question

Hi !
I need help (sorry for my english) :
my sql :
SELECT ligne,TO_CHAR(TO_DATE(DATE_VAL),'DD/MM/YYYY') DATE_VAL,COUNT(*)
FROM VALID, MIS, SERV
WHERE     id_mis=id_mis_val AND id_serv=id_serv_vmis
AND DATE_VAL >= '04/06/2007' AND DATE_VAL < '06/06/2007'
AND LIGNE_VSERV = 923
GROUP BY date_val
the result :
900 04/06/2007 1
900 04/06/2007 2
900 04/06/2007 1
900 04/06/2007 1
900 04/06/2007 1
900 05/06/2007 1
WHY ?
I want the result like that :
900 04/06/2007 6
900 05/06/2007 1
How to make that ? please help!
Thanks a lot

Answer 1

Why not...?
SQL>  create table t(c1 date,cnt number);
Table created.
SQL> insert into t
  2  values(sysdate,10);
1 row created.
SQL> insert into t
  2  values(sysdate,15);
1 row created.
SQL> insert into t
  2  values(sysdate-12,15);
1 row created.
SQL> insert into t
  2  values(sysdate-12,15);
1 row created.
SQL> select to_char(c1,'ddmmyyyy') c1,sum(cnt) sm
  2  from t
  3  group by to_char(c1,'ddmmyyyy');
C1               SM                                                            
02062007         30                                                            
14062007         25
Message was edited by:
        jeneesh
Forgot to refresh...