Grouping difficulty

Question

CREATE TABLE t97
(customer_number INTEGER,
customer_name VARCHAR2(100),
days INTEGER,
payment_schedule_id INTEGER,
CLASS VARCHAR2(3),
amt INTEGER,
applied_payment_schedule_id INTEGER,
amount_applied INTEGER,
final_outstanding INTEGER)
insert into t97 values (1135,'ABC',775,4431,'PMT',-466,4431,160,-306);
insert into t97 values (1135,'ABC',791,4431,'PMT',-466,4431,306,-160);
insert into t97 values (1135,'ABC',361,4433,'PMT',-150,4433,100,-50);
insert into t97 values (1135,'ABC',50,4444,'PMT',-150,4444,100,-50);
insert into t97 values (1135,'ABC',56,4444,'PMT',-150,4444,25,-125);
insert into t97 values (1135,'ABC',61,4444,'PMT',-150,4444,25,-125);
insert into t97 values (1135,'ABC',91,5555,'PMT',-500,5555,200,-200);
insert into t97 values (1135,'ABC',182,5555,'PMT',-500,5555,200,-200);
cno     cname     DAYS     sch_id     CLASS     AMT     asch_id     APPLIED     outstanding
1135     ABC     182     5555     PMT     -500     5555     200     -200
1135     ABC     91     5555     PMT     -500     5555     200     -200
1135     ABC     61     4444     PMT     -150     4444     25     -125
1135     ABC     56     4444     PMT     -150     4444     25     -125
1135     ABC     50     4444     PMT     -150     4444     100     -50
1135     ABC     361     4433     PMT     -150     4433     100     -50
1135     ABC     791     4431     PMT     -466     4431     306     -160
1135     ABC     775     4431     PMT     -466     4431     160     -306
hi all
above is a test case for those who can help me.
from the above, lets take payment_schedule_id = 4431
here the amount of -500 has been paid in 2 installments -306 & -160. when we sum (-500 + (-306 - 160)) balance is 0.
another example where payment_schedule_id = 5555
here, against the amount of -500, only (-200 & -200) is recorded. hence when we sum (-500 + (-200 - 200)) balance is -100. this amount is what i want to appear in the final_outstanding column.
how to achieve this in sql?
thanks

Answer 1

SVIL>select CUSTOMER_NUMBER cno, DAYS, PAYMENT_SCHEDULE_ID psid, CLASS, amt, amount_applied,
  2  APPLIED_PAYMENT_SCHEDULE_ID apsid, decode (rank() over (partition by CUSTOMER_NUMBER, PAYMENT_SCHEDULE_ID order by rownum),1,
  3  AMT+sum(AMOUNT_APPLIED) over (partition by CUSTOMER_NUMBER, PAYMENT_SCHEDULE_ID),null) bal
  4  from t97;
       CNO       DAYS       PSID CLA        AMT AMOUNT_APPLIED      APSID        BAL
      1135        775       4431 PMT       -466            160       4431          0
      1135        791       4431 PMT       -466            306       4431
      1135        361       4433 PMT       -150            100       4433        -50
      1135         50       4444 PMT       -150            100       4444          0
      1135         56       4444 PMT       -150             25       4444
      1135         61       4444 PMT       -150             25       4444
      1135         91       5555 PMT       -500            200       5555       -100
      1135        182       5555 PMT       -500            200       5555Max