Handling invalid Dates In query for Invalid dates in date column.

Hi,
I have a date column in my table. This column has corrupted data so the when i use any
to_timestamp function or any other date calcualtions my query breaks with the error:
ORA-01843: not a valid month.
I am aware the data is the issue.
But i want to handle this scenario by putting nulls in the output when ever an invalid date is encountered.
I have done some research and found the custom function is_date() on net.
But i am not suppose to create any new function but handle it with in my query.
Help is appreciated to handle this scenario.

Prasath wrote:
Try this!!
With Tab As(Select '12/01/2009' txt From dual)
SELECT Decode(Length(Replace(Translate( txt
, '0123456789/'
, Null
, to_date(txt,'mm/dd/yyyy')
, NULL) As Validation_date
FROM tab;
Ok ...
SQL> With Tab As(Select '12/01/2009' txt From dual)
2      SELECT Decode(Length(Replace(Translate( txt
3                                            , '0123456789/'
4                                            , '#')
5                                  ,'#'))
6                   , Null
7                   , to_date(txt,'mm/dd/yyyy')
8                   , NULL) As Validation_date
9       FROM tab;
VALIDATIO
01-DEC-09Not sure what that proves, especially in relation to the OP's problem.

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user9179751 wrote:
It wasn't working for me initially but I had to format the date to validate.
SELECT * FROM TABLE WHERE OFFICE_START_DATE < TO_CHAR(SYSDATE, 'YYYY-MM-DD HH24:MI:SS')
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select *
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where to_date(office_start_date) < sysdate
and to_date(office_end_date) > sysdate;If you insist on thinking that a chracter string that looks like a date is a date, what do you make of this:
First, create a table with a char column used as a date:
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Table dropped.
SQL> create table mydemo (
2 alfa_date varchar2(11),
3 rite_date date
4 );
Table created.Now insert some data
SQL> --
SQL> insert into mydemo values ('01-JAN-2010', to_date('01-JAN-2010','DD-MON-YYYY'));
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1 row created.
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1 row created.
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1 row created.
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1 row created.
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1 row created.
SQL> insert into mydemo values ('03-APR-2010', to_date('03-APR-2010','DD-MON-YYYY'));
1 row created.
SQL> commit;
Commit complete.Now, select, and order on the alfa-date;
SQL> select * from mydemo order by alfa_date;
ALFA_DATE RITE_DATE
01-APR-2010 01-APR-10
01-FEB-2010 01-FEB-10
01-JAN-2010 01-JAN-10
02-APR-2010 02-APR-10
02-FEB-2010 02-FEB-10
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03-FEB-2010 03-FEB-10
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No they are not.
Why not?
Now select, and order on the properly defined date column.
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01-JAN-2010 01-JAN-10
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03-JAN-2010 03-JAN-10
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Query for data

Hi all, i am trying to write a query for a specific scenario using analytic functions.
i have a table that has data in week basis. here is some sample data
id date value
1 1/4/10 A
1 1/11/10 B
1 1/18/10 C
2 ....
2 ....
each date represent the beginning of the week. i have another table that contains calendar dates that include day of the week excluding weekends and holidays.
example data
id date
1 1/4/10
1 1/5/10
1 1/6/10
1 1/7/10
1 1/8/10
1 1/11/10
1 ...... SO ON
as you can see 1/1/10, 1/2, 1/3 are not present because they are either holidays or weekends.
what i want to do is join this two tables by id and the output should be the following
1 1/4/10 A
1 1/5/10 A
1 1/6/10 A
1 1/7/10 A
1 1/8/10 A
1 1/11/10 B
1 1/12/10 B
1 1/13/10 B
1 1/14/10 B
1 1/15/10 B
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Hi,
What if the week crosses over 2 months.
Fo example March the last week starts on 29 and has 1st apr and 2nd apr in the same week.Would you consider those?
If not here is one way of doing it.
with t1 as (
            select 1 id,DATE '2010-03-01' dt,'A' val from dual union all
            select 1,DATE '2010-03-08','B' from dual union all
            select 1,DATE '2010-03-15','C' from dual UNION ALL
            select 1,DATE '2010-03-22','D' from dual    UNION ALL
            select 1,DATE '2010-03-29','E' from dual
     t2 as (
            select 1 id,DATE '2010-03-01' dt from dual union all
            select 1,DATE '2010-03-02' from dual union all
            select 1,DATE '2010-03-03' from dual union all
            select 1,DATE '2010-03-04' from dual union all
            select 1,DATE '2010-03-05' from dual union all
            select 1,DATE '2010-03-08' from dual union all
            select 1,DATE '2010-03-09' from dual union all
            select 1,DATE '2010-03-10' from dual union all
            select 1,DATE '2010-03-11' from dual union all
            select 1,DATE '2010-03-12' from dual UNION ALL
            select 1,DATE '2010-03-15' from dual UNION ALL
            select 1,DATE '2010-03-16' from dual UNION ALL
            select 1,DATE '2010-03-17' from dual UNION ALL
            select 1,DATE '2010-03-18' from dual UNION ALL
            select 1,DATE '2010-03-19' from dual UNION ALL
            select 1,DATE '2010-03-22' from dual UNION ALL
            select 1,DATE '2010-03-23' from dual UNION ALL
            select 1,DATE '2010-03-24' from dual UNION ALL
            select 1,DATE '2010-03-25' from dual UNION ALL
            select 1,DATE '2010-03-26' from dual UNION ALL
            select 1,DATE '2010-03-29' from dual UNION ALL
            select 1,DATE '2010-03-30' from dual UNION ALL
            select 1,DATE '2010-03-31' from dual UNION ALL
            select 1,DATE '2010-04-01' from dual UNION ALL
            select 1,DATE '2010-04-01' from dual                                )
           SELECT DISTINCT a.ID,b.dt,a.val,to_char(b.dt,'IW') FROM t1 a,t2 b WHERE a.ID=b.ID
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Bhushan

Trouble writing Query for Pivoting data from a table

I am having a little trouble writing a query for converting the below table data into a pivot data. I am trying to write a query for which if I give a single valid report_week date as input it should give me the data for that week and also provide two extra columns, one which gives the data of last week for the same countries and the second column which gives the difference of numbers in both the columns(i.e. COUNT - COUNT_LAST_WEEK).
REPORT_WEEK     DIVISION     COUNT
9/26/2009     country1     81
9/26/2009     country2     97
9/26/2009     country3     12
9/26/2009     country4     26
9/26/2009     country5     101
10/3/2009     country1     85
10/3/2009     country2     98
10/3/2009     country3     10
10/3/2009     country4     24
10/3/2009     country5     101
10/10/2009     country1     84
10/10/2009     country2     98
10/10/2009     country3     10
10/10/2009     country4     25
10/10/2009     country5     102
For example, if I give input as 10/10/2009, the output should be as give below.
REPORT_WEEK     DIVISION     COUNT     COUNT_LAST_WEEK     DIFFERENCE
10/10/2009     country1     84     85     -1
10/10/2009     country2     98     98     0
10/10/2009     country3     10     10     0
10/10/2009     country4     25     24     1
10/10/2009     country5     102     101     1
For example, if I give input as 10/3/2009, the output should be as give below.
REPORT_WEEK     DIVISION     COUNT     COUNT_LAST_WEEK     DIFFERENCE
10/3/2009     country1     85     81     4
10/3/2009     country2     98     97     1
10/3/2009     country3     10     12     -2
10/3/2009     country4     24     26     -2
10/3/2009     country5     101     101     0
Can anyone please shed some light on Query building for the above scenarios.
Thank you
SKP
Edited by: user11343284 on Oct 10, 2009 7:53 AM
Edited by: user11343284 on Oct 10, 2009 8:28 AM

I assume there is no gap in report weeks. If so:
SQL> variable report_week varchar2(10)
SQL> exec :report_week := '10/10/2009'
PL/SQL procedure successfully completed.
with t as (
           select to_date('9/26/2009','mm/dd/yyyy') report_week,'country1' division,81 cnt from dual union all
           select to_date('9/26/2009','mm/dd/yyyy'),'country2',97 from dual union all
           select to_date('9/26/2009','mm/dd/yyyy'),'country3',12 from dual union all
           select to_date('9/26/2009','mm/dd/yyyy'),'country4',26 from dual union all
           select to_date('9/26/2009','mm/dd/yyyy'),'country5',101 from dual union all
           select to_date('10/3/2009','mm/dd/yyyy'),'country1',85 from dual union all
           select to_date('10/3/2009','mm/dd/yyyy'),'country2',98 from dual union all
           select to_date('10/3/2009','mm/dd/yyyy'),'country3',10 from dual union all
           select to_date('10/3/2009','mm/dd/yyyy'),'country4',24 from dual union all
           select to_date('10/3/2009','mm/dd/yyyy'),'country5',101 from dual union all
           select to_date('10/10/2009','mm/dd/yyyy'),'country1',84 from dual union all
           select to_date('10/10/2009','mm/dd/yyyy'),'country2',98 from dual union all
           select to_date('10/10/2009','mm/dd/yyyy'),'country3',10 from dual union all
           select to_date('10/10/2009','mm/dd/yyyy'),'country4',25 from dual union all
           select to_date('10/10/2009','mm/dd/yyyy'),'country5',102 from dual
select max(report_week) report_week,
        division,
        max(cnt) keep(dense_rank last order by report_week) cnt_this_week,
        max(cnt) keep(dense_rank first order by report_week) cnt_last_week,
        max(cnt) keep(dense_rank last order by report_week) - max(cnt) keep(dense_rank first order by report_week) difference
from t
where report_week in (to_date(:report_week,'mm/dd/yyyy'),to_date(:report_week,'mm/dd/yyyy') - 7)
group by division
order by division
REPORT_WE DIVISION CNT_THIS_WEEK CNT_LAST_WEEK DIFFERENCE
10-OCT-09 country1            84            85         -1
10-OCT-09 country2            98            98          0
10-OCT-09 country3            10            10          0
10-OCT-09 country4            25            24          1
10-OCT-09 country5           102           101          1
SQL> exec :report_week := '10/3/2009'
PL/SQL procedure successfully completed.
SQL> /
REPORT_WE DIVISION CNT_THIS_WEEK CNT_LAST_WEEK DIFFERENCE
03-OCT-09 country1            85            81          4
03-OCT-09 country2            98            97          1
03-OCT-09 country3            10            12         -2
03-OCT-09 country4            24            26         -2
03-OCT-09 country5           101           101          0
SQL> SY.

Two or more productid will be accquired by same customerid, by same shipvia, on the same day of the week of shipped date. i want the simple query for this.

consider this situation,
Two or more productid will be accquired by same customerid, by same shipvia, on the same day of the week of shipped date. i want the simple query for this.
my tables are from northwind:
[orders] = OrderID, CustomerID, EmployeeID, OrderDate, RequiredDate, ShippedDate, ShipVia, Freight, ShipName, ShipAddress, ShipCity, ShipRegion, ShipPostalCode, ShipCountry.
[orders details] = OrderID, ProductID, UnitPrice, Quantity, Discount.
i tried some but it is not exact, it gives wrong result.
select pd.CustomerID,pd.ProductID, pd.no_of_time_purchased, sd.ShipVia, sd.same_ship_count, shipped_day from
select ProductID,o.CustomerID,COUNT(productid) as no_of_time_purchased
from orders o join [Order Details] od on o.OrderID=od.OrderID group by ProductID,o.CustomerID
having count(od.ProductID) >1) pd
join
(select OrderID,customerid, shipvia, count(shipvia)as same_ship_count, DATENAME(DW,ShippedDate)as shipped_day from orders
group by customerid, ShipVia, ShippedDate having COUNT(ShipVia) > 1 ) sd
on sd.CustomerID=pd.CustomerID

Hi,
I think I have a solution that will at least give you a clue how to go about it. I have simplified the tables you mentioned and created them as temporary tables on my side, with some fake data to test with. I have incldued the generation of these temporary
tables for your review.
In my example I have included:
1. A customer which has purchased the same product on the same day, using the same ship 3 times,
2. Another example the same as the first but the third purchase was on a different day
3. Another example the same as the first but the third purchase was a different product
4. Another example the same as the first but the third purchase was using a different "ShipVia".
You should be able to see that by grouping on all of the columns that you wich to return, you should not need to perform any subselects.
Please let me know if I have missed any requirements.
Hope this helps:
CREATE TABLE #ORDERS
OrderID INT,
CustomerID INT,
OrderDate DATETIME,
ShipVia VARCHAR(5)
CREATE TABLE #ORDERS_DETAILS
OrderID INT,
ProductID INT,
INSERT INTO #ORDERS
VALUES
(1, 1, GETDATE(), 'ABC'),
(2, 1, GETDATE(), 'ABC'),
(3, 1, GETDATE(), 'ABC'),
(4, 2, GETDATE() - 4, 'DEF'),
(5, 2, GETDATE() - 4, 'DEF'),
(6, 2, GETDATE() - 5, 'DEF'),
(7, 3, GETDATE() - 10, 'GHI'),
(8, 3, GETDATE() - 10, 'GHI'),
(9, 3, GETDATE() - 10, 'GHI'),
(10, 4, GETDATE() - 10, 'JKL'),
(11, 4, GETDATE() - 10, 'JKL'),
(12, 4, GETDATE() - 10, 'MNO')
INSERT INTO #ORDERS_DETAILS
VALUES
(1, 1),
(2, 1),
(3, 1),
(4, 2),
(5, 2),
(6, 2),
(7, 3),
(8, 3),
(9, 4),
(10, 5),
(11, 5),
(12, 5)
SELECT * FROM #ORDERS
SELECT * FROM #ORDERS_DETAILS
SELECT
O.CustomerID,
OD.ProductID,
O.ShipVia,
COUNT(O.ShipVia),
DATENAME(DW, O.OrderDate) AS [Shipped Day]
FROM #ORDERS O
JOIN #ORDERS_DETAILS OD ON O.orderID = OD.OrderID
GROUP BY OD.ProductID, O.CustomerID, O.ShipVia, DATENAME(DW, O.OrderDate) HAVING COUNT(OD.ProductID) > 1
DROP TABLE #ORDERS
DROP TABLE #ORDERS_DETAILS

Crosstab Query for Remaining Revenue (Count, If, Date Between )

Hi all, hope you had a great new year.
I am wanting to create a crosstab query for my Projects which shows ProjectID in the row headers and Time Periods split into months quarter or year as the Column Headers using the [DateAgreed] from the Session table.
I have created crosstabs which show revenue from sessions and count of sessions with different time periods but i am trying to make it so that it counts only completed sessions from before the column date, so that i can then multiply by the [SessionCost].
Any ideas guys?
Here's what i have been working with;
TRANSFORM Sum(([tblSession]![SessionCompleted]*[tblProject]![SessionCost])) AS Revenue
SELECT tblProject.ProjectID, tblCompany.CompanyName
FROM (tblSession INNER JOIN tblCompany ON tblSession.CompanyID = tblCompany.CompanyID) INNER JOIN ((tblProject INNER JOIN tblProjectMetrics ON tblProject.ProjectID = tblProjectMetrics.ProjectID) INNER JOIN qryProjectStatus ON tblProject.ProjectID = qryProjectStatus.ProjectID)
ON (tblProject.ProjectID = tblSession.ProjectID) AND (tblCompany.CompanyID = tblProject.CompanyID)
GROUP BY tblProject.ProjectID, tblCompany.CompanyName, tblProject.Total
PIVOT Format([DateAgreed],"yyyy-mm");
Thanks :)

Hi Gord0oo,
You could concatenates the data as a result and show in a cell.
TRANSFORM Sum([tblProject]![SessionCost])) & ";" & Sum([tblSession]![SessionCompleted]) AS Revenue
Regards
Starain
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Handling invalid Dates In query for Invalid dates in date column.

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