Two or more productid will be accquired by same customerid, by same shipvia, on the same day of the week of shipped date. i want the simple query for this.

Question

consider this situation,
 Two or more productid will be accquired by same customerid, by same shipvia, on the same  day of the week of shipped date. i want the simple query for this.
my tables are  from northwind:
[orders] = OrderID, CustomerID, EmployeeID, OrderDate, RequiredDate, ShippedDate, ShipVia, Freight, ShipName, ShipAddress, ShipCity, ShipRegion, ShipPostalCode, ShipCountry.
[orders details] = OrderID, ProductID, UnitPrice, Quantity, Discount.
i tried some but it is not exact, it gives wrong result.
select pd.CustomerID,pd.ProductID, pd.no_of_time_purchased, sd.ShipVia, sd.same_ship_count, shipped_day from
select ProductID,o.CustomerID,COUNT(productid) as no_of_time_purchased
from orders o join [Order Details] od on o.OrderID=od.OrderID group by ProductID,o.CustomerID
having count(od.ProductID) >1) pd
join
(select OrderID,customerid, shipvia, count(shipvia)as same_ship_count, DATENAME(DW,ShippedDate)as shipped_day from orders
group by customerid, ShipVia, ShippedDate having COUNT(ShipVia) > 1 ) sd
on sd.CustomerID=pd.CustomerID

Answer 1

Hi,
I think I have a solution that will at least give you a clue how to go about it. I have simplified the tables you mentioned and created them as temporary tables on my side, with some fake data to test with. I have incldued the generation of these temporary
tables for your review.
In my example I have included:
1. A customer which has purchased the same product on the same day, using the same ship 3 times,
2. Another example the same as the first but the third purchase was on a different day
3. Another example the same as the first but the third purchase was a different product
4. Another example the same as the first but the third purchase was using a different "ShipVia".
You should be able to see that by grouping on all of the columns that you wich to return, you should not need to perform any subselects.
Please let me know if I have missed any requirements.
Hope this helps:
CREATE TABLE #ORDERS
 OrderID INT,
 CustomerID INT,
 OrderDate DATETIME,
 ShipVia VARCHAR(5)
CREATE TABLE #ORDERS_DETAILS
 OrderID INT,
 ProductID INT,
INSERT INTO #ORDERS
VALUES
(1, 1, GETDATE(), 'ABC'),
(2, 1, GETDATE(), 'ABC'),
(3, 1, GETDATE(), 'ABC'),
(4, 2, GETDATE() - 4, 'DEF'),
(5, 2, GETDATE() - 4, 'DEF'),
(6, 2, GETDATE() - 5, 'DEF'),
(7, 3, GETDATE() - 10, 'GHI'),
(8, 3, GETDATE() - 10, 'GHI'),
(9, 3, GETDATE() - 10, 'GHI'),
(10, 4, GETDATE() - 10, 'JKL'),
(11, 4, GETDATE() - 10, 'JKL'),
(12, 4, GETDATE() - 10, 'MNO')
INSERT INTO #ORDERS_DETAILS
VALUES
(1, 1),
(2, 1),
(3, 1),
(4, 2),
(5, 2),
(6, 2),
(7, 3),
(8, 3),
(9, 4),
(10, 5),
(11, 5),
(12, 5)
SELECT * FROM #ORDERS
SELECT * FROM #ORDERS_DETAILS
SELECT
 O.CustomerID,
 OD.ProductID,
 O.ShipVia,
 COUNT(O.ShipVia),
 DATENAME(DW, O.OrderDate) AS [Shipped Day]
FROM #ORDERS O
JOIN #ORDERS_DETAILS OD ON O.orderID = OD.OrderID
GROUP BY OD.ProductID, O.CustomerID, O.ShipVia, DATENAME(DW, O.OrderDate) HAVING COUNT(OD.ProductID) > 1
DROP TABLE #ORDERS
DROP TABLE #ORDERS_DETAILS