Have I done this correct, but I still need help on #7

Question

1. Provide a SQL statement that displays the FIRSTNAME and LASTNAME of each customer separated by a comma. The FIRSTNAME and LASTNAME should be capitalized and concatenated together with a column alias of “Full Name”. The output should be sorted in ascending order by LASTNAME.
SELECT FIRSTNAME||','||LASTNAME "FULL NAME"
FROM CUSTOMERS;
FULL NAME
BONITA,MORALES
RYAN,THOMPSON
LEILA,SMITH
THOMAS,PIERSON
CINDY,GIRARD
MESHIA,CRUZ
TAMMY,GIANA
KENNETH,JONES
JORGE,PEREZ
JAKE,LUCAS
REESE,MCGOVERN
WILLIAM,MCKENZIE
NICHOLAS,NGUYEN
JASMINE,LEE
FULL NAME
STEVE,SCHELL
MICHELL,DAUM
BECCA,NELSON
GREG,MONTIASA
JENNIFER,SMITH
KENNETH,FALAH
20 rows selected.
2. Provide a SQL statement that displays the current date in the format MM/DD/YY.
SELECT TO_CHAR( '10/25/06')
FROM DUAL
TO_CHAR(
10/25/06
3. Provide a SQL statement that displays the TITLE and publisher NAME of each book in the “COMPUTER” CATEGORY.
SELECT TITLE, CATEGORY
FROM BOOKS, PUBLISHER
WHERE CATEGORY = 'COMPUTER'
TITLE      CATEGORY
DATABASE IMPLEMENTATION      COMPUTER
HOLY GRAIL OF ORACLE      COMPUTER
HANDCRANKED COMPUTERS      COMPUTER
E-BUSINESS THE EASY WAY      COMPUTER
DATABASE IMPLEMENTATION      COMPUTER
HOLY GRAIL OF ORACLE      COMPUTER
HANDCRANKED COMPUTERS      COMPUTER
E-BUSINESS THE EASY WAY      COMPUTER
DATABASE IMPLEMENTATION      COMPUTER
HOLY GRAIL OF ORACLE      COMPUTER
HANDCRANKED COMPUTERS      COMPUTER
E-BUSINESS THE EASY WAY      COMPUTER
DATABASE IMPLEMENTATION      COMPUTER
HOLY GRAIL OF ORACLE      COMPUTER
TITLE      CATEGORY
HANDCRANKED COMPUTERS      COMPUTER
E-BUSINESS THE EASY WAY      COMPUTER
DATABASE IMPLEMENTATION      COMPUTER
HOLY GRAIL OF ORACLE      COMPUTER
HANDCRANKED COMPUTERS      COMPUTER
E-BUSINESS THE EASY WAY      COMPUTER
20 rows selected.
4. Provide a SQL statement that displays the CUSTOMER# and LASTNAME for each customer along with the ORDER# of any order that the customer placed. The statement should include all customers including those that have not placed any orders.
SELECT LASTNAME,ORDER#
FROM CUSTOMERS C, ORDERS O
WHERE C.CUSTOMER#=O.CUSTOMER#
ORDER BY O.ORDER#
LASTNAME      ORDER#
GIRARD      1000
LUCAS      1001
MCGOVERN      1002
MORALES      1003
FALAH      1004
MONTIASA      1005
SMITH      1006
GIANA      1007
PIERSON      1008
GIRARD      1009
SMITH      1010
LUCAS      1011
NELSON      1012
LEE      1013
LASTNAME      ORDER#
GIANA      1014
FALAH      1015
SMITH      1016
SCHELL      1017
MORALES      1018
MONTIASA      1019
JONES      1020
21 rows selected.
5. Provide a SQL statement that displays the total QUANTITY of books ordered.
SELECT CUSTOMER#, FIRSTNAME, LASTNAME
FROM ORDERS NATURAL JOIN ORDERITEMS NATURAL JOIN CUSTOMERS
HAVING SUM(QUANTITY)=ALL
(SELECT MAX(SUM(QUANTITY))
FROM ORDERS NATURAL JOIN ORDERITEMS GROUP BY CUSTOMER#)
GROUP BY CUSTOMER#, FIRSTNAME, LASTNAME;
CUSTOMER#      FIRSTNAME      LASTNAME
1007      TAMMY      GIANA
6. Provide a SQL statement that displays the TITLE of all books that COST more than the average cost of all books.
SELECT TITLE,AVG(COST)
FROM BOOKS
GROUP BY TITLE
TITLE      AVG(COST)
BIG BEAR AND LITTLE DOVE      5.32
BODYBUILD IN 10 MINUTES A DAY      18.75
BUILDING A CAR WITH TOOTHPICKS      37.8
COOKING WITH MUSHROOMS      12.5
DATABASE IMPLEMENTATION      31.4
E-BUSINESS THE EASY WAY      37.9
HANDCRANKED COMPUTERS      21.8
HOLY GRAIL OF ORACLE      47.25
HOW TO GET FASTER PIZZA      17.85
HOW TO MANAGE THE MANAGER      15.4
PAINLESS CHILD-REARING      48
REVENGE OF MICKEY      14.2
SHORTEST POEMS      21.85
THE WOK WAY TO COOK      19
14 rows selected.
7. Provide a SQL statement that displays each SHIPSTATE along with the number of orders shipped to each state. Include only those states that more than 3 orders were shipped to.
8. Provide a SQL statement that displays each book CATEGORY in the database. The category should only appear once in the output.
SELECT TITLE, CATEGORY
FROM BOOKS
TITLE      CATEGORY
BODYBUILD IN 10 MINUTES A DAY      FITNESS
REVENGE OF MICKEY      FAMILY LIFE
BUILDING A CAR WITH TOOTHPICKS      CHILDREN
DATABASE IMPLEMENTATION      COMPUTER
COOKING WITH MUSHROOMS      COOKING
HOLY GRAIL OF ORACLE      COMPUTER
HANDCRANKED COMPUTERS      COMPUTER
E-BUSINESS THE EASY WAY      COMPUTER
PAINLESS CHILD-REARING      FAMILY LIFE
THE WOK WAY TO COOK      COOKING
BIG BEAR AND LITTLE DOVE      CHILDREN
HOW TO GET FASTER PIZZA      SELF HELP
HOW TO MANAGE THE MANAGER      BUSINESS
SHORTEST POEMS      LITERATURE
14 rows selected.

Answer 1

3. Provide a SQL statement that displays the TITLE and publisher NAME of each book in the “COMPUTER” CATEGORY.
TITLE CATEGORY
DATABASE IMPLEMENTATION COMPUTER
HOLY GRAIL OF ORACLE COMPUTER
HANDCRANKED COMPUTERS COMPUTER
E-BUSINESS THE EASY WAY COMPUTER
DATABASE IMPLEMENTATION COMPUTER
HOLY GRAIL OF ORACLE COMPUTER
HANDCRANKED COMPUTERS COMPUTER
E-BUSINESS THE EASY WAY COMPUTER
DATABASE IMPLEMENTATION COMPUTER
HOLY GRAIL OF ORACLE COMPUTER
HANDCRANKED COMPUTERS COMPUTER
E-BUSINESS THE EASY WAY COMPUTER
DATABASE IMPLEMENTATION COMPUTER
HOLY GRAIL OF ORACLE COMPUTER
TITLE CATEGORY
HANDCRANKED COMPUTERS COMPUTER
E-BUSINESS THE EASY WAY COMPUTER
DATABASE IMPLEMENTATION COMPUTER
HOLY GRAIL OF ORACLE COMPUTER
HANDCRANKED COMPUTERS COMPUTER
E-BUSINESS THE EASY WAY COMPUTER
20 rows selected.
Result is wrong - you have a catrtesian product between books and publisher i.e. each book is repeated for each publisher. You need to join books to publisher and you need to select the publisher name
4. Provide a SQL statement that displays the CUSTOMER# and LASTNAME for each customer along with the ORDER# of any order that the customer placed. The statement should include all customers including those that have not placed any orders.
SELECT LASTNAME,ORDER#
FROM CUSTOMERS C, ORDERS O
WHERE C.CUSTOMER#=O.CUSTOMER#
ORDER BY O.ORDER#This is wrong, you need to use an outer join between customers and orders to satisfy the requirement:
The statement should include all customers including those that have not placed any orders.
5. Provide a SQL statement that displays the total QUANTITY of books ordered.
SELECT CUSTOMER#, FIRSTNAME, LASTNAME
FROM ORDERS NATURAL JOIN ORDERITEMS NATURAL JOIN CUSTOMERS
HAVING SUM(QUANTITY)=ALL
(SELECT MAX(SUM(QUANTITY))
FROM ORDERS NATURAL JOIN ORDERITEMS GROUP BY CUSTOMER#)
GROUP BY CUSTOMER#, FIRSTNAME, LASTNAME;
CUSTOMER# FIRSTNAME LASTNAME
1007 TAMMY GIANA
I can't see a quantity here and you should avoid NATURAL JOINs like the plague:
SELECT CUSTOMER#, FIRSTNAME, LASTNAME, SUM(QUANTITY)
I'm not exactly sure what you're attempting with the
HAVING SUM(QUANTITY)=ALL
(SELECT MAX(SUM(QUANTITY))
FROM ORDERS NATURAL JOIN ORDERITEMS GROUP BY CUSTOMER#)
GROUP BY CUSTOMER#, FIRSTNAME, LASTNAME;bit.
6. Provide a SQL statement that displays the TITLE of all books that COST more than the average cost of all books.
SELECT TITLE,AVG(COST)
FROM BOOKS
GROUP BY TITLEThis doesn't do what was asked, it just selects the average cost of each book - which will be exactly the same as the actual cost of each book. You need to use a sub query here.
8. Provide a SQL statement that displays each book CATEGORY in the database. The category should only appear once in the output.
The title does not need to be in the output here and you need to use distinct.
HTH
David