Having count of 1
I would like to count how many ID have only had 1 Enrolment by year:
I am assuming you would have to use having count = 1 or something like that.
So I have the following example below
ID 1 has 2 enrolments so dont count
ID 2 has only 1 enrolment so count
ID 3 has 2 enrolments so dont count
ID 4 has 1 enrolment so count
ID 5 has 2 enrolments so dont count
ID 6 has 1 so count
ID 7 and 8 have one each so count.
Thanks
CREATE TABLE DAN_PRU
(ID VARCHAR2(8),
UNIT VARCHAR2(8),
YEAR VARCHAR2(8))
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (1,'POP','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (1,'DOP','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (2,'KUIP','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (3,'DIP','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (3,'YUP','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (4,'SII','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (5,'DYY','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (5,'LIW','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (6,'DFG','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (7,'DWQ','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (8,'DFR','2013');GIVES:
ID UNIT YEAR
1 POP 2013
1 DOP 2013
2 KUIP 2013
3 DIP 2013
3 YUP 2013
4 SII 2013
5 DYY 2012
5 LIW 2012
6 DFG 2012
7 DWQ 2011
8 DFR 2011WANT
ENROLMENTS YEAR
2 2013
1 2012
2 2011
using oracle 10
Hi,
Interesting problem!
Chloe_19 wrote:
I would like to count how many ID have only had 1 Enrolment by year:
I am assuming you would have to use having count = 1 or something like that.That's an obvious first step. What makes this such an interesting problem is how you get from there to the final answer.
What is the final answer? Do you want just one row, containing just one number (5 in this case, since there are 5 ids (2, 4, 6, 7 and 8) that have only 1 enrollment?
So I have the following example below
ID 1 has 2 enrolments so dont count
ID 2 has only 1 enrolment so count
ID 3 has 2 enrolments so dont count
ID 4 has 1 enrolment so count
ID 5 has 2 enrolments so dont count
ID 6 has 1 so count
ID 7 and 8 have one each so count.
Thanks
CREATE TABLE DAN_PRU
(ID VARCHAR2(8),
UNIT VARCHAR2(8),
YEAR VARCHAR2(8)) Why is year a VARCHAR2? Why is it 8 characters long?
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (1,'POP','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (1,'DOP','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (2,'KUIP','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (3,'DIP','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (3,'YUP','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (4,'SII','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (5,'DYY','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (5,'LIW','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (6,'DFG','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (7,'DWQ','2013');
INSERT INTO DAN_PRU (ID, UNIT, YEAR) VALUES (8,'DFR','2013');
GIVES:How does the data above give the results below.
For example, it looks like '2013' is the only year in the data. How do you get '2011' and '2012' in the results?
Can the same id have multiple years? What results would you want in that case?
ID UNIT YEAR
1 POP 2013
1 DOP 2013
2 KUIP 2013
3 DIP 2013
3 YUP 2013
4 SII 2013
5 DYY 2012
5 LIW 2012
6 DFG 2012
7 DWQ 2011
8 DFR 2011WANTAre you saying the results below are what you want?
ENROLMENTS YEAR
2 2013
1 2012
2 2011
using oracle 10Can you get a result set that contains one row per id? (Or for each id/year combination; it's unclar what you want.)
Can you restrict that result set to contain only the ids with only 1 enrollment?
If you had a table like the previous result set, how would you solve the problem? Remember, any result set can be treated like a table, using a WITH clause.
Similar Messages
-
Select query having count function is returning null
Hi Everyone,
Please see the query and help me to get this solved.
DB version
Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - 64bi
PL/SQL Release 10.2.0.1.0 - Production
"CORE 10.2.0.1.0 Production"
TNS for Linux: Version 10.2.0.1.0 - Production
NLSRTL Version 10.2.0.1.0 - ProductionQUERY
SELECT COUNT(*) as V_COUNT
FROM LAB_ORDER_TMPLT_TEST
WHERE TEST_ID IN
(SELECT WEST_TEST_ID
FROM TEST_CODE_CONVERSION TCC
WHERE TCC.EAST_TEST_ID = 2769)
GROUP BY LAB_ORDER_TMPLT_ID
HAVING COUNT(*) > 1;
It's returning null. Is there any way I can get the value as zero instead of null? Please help.Regards,
BS2012.Hi,
BS2012 wrote:
Hi Everyone,
Please see the query and help me to get this solved.
DB version
Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - 64bi
PL/SQL Release 10.2.0.1.0 - Production
"CORE 10.2.0.1.0 Production"
TNS for Linux: Version 10.2.0.1.0 - Production
NLSRTL Version 10.2.0.1.0 - ProductionQUERY
SELECT COUNT(*) as V_COUNT
FROM LAB_ORDER_TMPLT_TEST
WHERE TEST_ID IN
(SELECT WEST_TEST_ID
FROM TEST_CODE_CONVERSION TCC
WHERE TCC.EAST_TEST_ID = 2769)
GROUP BY LAB_ORDER_TMPLT_ID
HAVING COUNT(*) > 1;
It's returning null.
Really? COUNT never returns NULL; it always returns 0 or a positive integer.
Do you mean the query results in "no rows selected"?
Is there any way I can get the value as zero instead of null? Please help.Do you want a query that will produce the same output as the query above, but will produce a single row containing 0 when the query above does not produce anything? That sounds like a job for an outer join:
WITH original_query AS
SELECT COUNT(*) AS v_count
FROM lab_order_tmplt_test
WHERE test_id IN
( SELECT west_test_id
FROM test_code_conversion tcc
WHERE tcc.east_test_id = 2769
GROUP BY lab_order_tmplt_id
SELECT NVL (o.v_count, 0) AS v_count
FROM dual
LEFT OUTER JOIN original_query o ON o.v_count > 0
;If you'd care to post CREATE TABLE and INSERT statements for the sample data, then I could test this. -
Group by Having Count(*)
Hi...
I'm back again and I'm ever hopeful that I will get some needed help.
I'm trying to use the groupby and having Count(*) on a table, but I think
I have my group by wrong...I keep getting the wrong output.
Here's my code:
Select Course_ID,Count(*),Department_ID,Class_ID,Class_Room
from Class
Group By Course_ID,Department_ID,Class_ID,Class_Room
Having Count(*) >=1
and this is the output:
COURS COUNT(*) DEPARTMENT_ID CLASS_ID CLASS_ROOM
50 1 MATH 103600 140
101 1 BIO 109100 180
101 1 ENGL 108300 150
115 1 HIST 108400 200
183 1 PSYCH 103400 150
183 1 PSYCH 108600 240
184 1 HIST 104500 200
198 1 PHILO 104200 150
199 1 ENG 110300 255
199 1 ECON 120200 235
Now, what should be happeing is that Count should give me 2*101,2*183,2*199 but I keep
getting 1 of each...
Any ideas about where I'm going Wrong?Drake,
In short, you are grouping on too many things. You need to group on only course_id when looking for duplicates, and then join the duplicate courses back to the course table to get the rest of the data:
select c.course_id, c.department_id,
c.class_id, c.class_room
from class c,
(select course_id, count(*) howmany
from class
group by course_id
having count(*) > 1) dups
where c.course_id = dups.course_id;
Hi...
I'm back again and I'm ever hopeful that I will get some needed help.
I'm trying to use the groupby and having Count(*) on a table, but I think
I have my group by wrong...I keep getting the wrong output.
Here's my code:
Select Course_ID,Count(*),Department_ID,Class_ID,Class_Room
from Class
Group By Course_ID,Department_ID,Class_ID,Class_Room
Having Count(*) >=1
and this is the output:
COURS COUNT(*) DEPARTMENT_ID CLASS_ID CLASS_ROOM
50 1 MATH 103600 140
101 1 BIO 109100 180
101 1 ENGL 108300 150
115 1 HIST 108400 200
183 1 PSYCH 103400 150
183 1 PSYCH 108600 240
184 1 HIST 104500 200
198 1 PHILO 104200 150
199 1 ENG 110300 255
199 1 ECON 120200 235
Now, what should be happeing is that Count should give me 2*101,2*183,2*199 but I keep
getting 1 of each...
Any ideas about where I'm going Wrong? -
I have this code with an error:
SELECT (CASE id_type
WHEN 4 THEN companyid
ELSE nric
END) AS customerid
FROM customer
GROUP BY customerid HAVING COUNT (*customerid*) = 1
The error is at the bold word with the error: Invalid identifier. How should I rewrite my sql statement?SELECT CUSTOMERID FROM
SELECT (CASE id_type
WHEN 4 THEN companyid
ELSE nric
END) AS customerid
FROM customer
GROUP BY customerid HAVING COUNT (customerid) = 1 -
Having count- count(count(1))
I have two queries below- first of which outputs one record, the Second query doesn't.
Can you explain why First query returns always records, at least one record? In explanation, can you say which process is runned after which (something like where is runned firstly, then group by, then...)?
--First:
select count(count(1)) from dual
where 1=2
group by dummy
having count(dummy) > 0;--1 row, value: 0
--Second:
select count(1) from dual
where 1=2
group by dummy
having count(dummy) > 0;--0 rowsHi,
Aggregate queries with nested aggregate functions (such as "COUNT (COUNT (1))") always return exactly 1 row, even if there are no rows in the table (or, as in your first example, no rows survive the WHERE clause).
The outer layer of nested aggreate functions is evaluated after the GROUP BY and HAVING clauses have been applied.
If you have a GROUP BY clause, but no nested aggregate fucntions, then the output contains one row for every distinct group, subject to the WHERE- and HAVING clauses. In your second example, no rows are left after the WHERE clause, so there will be no rows in the output.
You can think of things as happening in this order
(1) WHERE
(2) GROUP BY
(3) (inner) aggregate fucntions
(4) HAVING
(5) Nested aggregate functions
The optimizer may not actually follow the steps above, but you won't notice that.
Edited by: Frank Kulash on Mar 25, 2010 11:51 AM
The following thread may help you:
Re: group function -
Create Table From a Having Count Select
Hello Folks, any ideas here, I need to create a table using the below 'Select' as the criteria.
I have the following table and its has duplicate records, identified by double Unique_seq. I want to create a table of these else where, then delete them from schema.tablename.
Schmea.tablename
field1
field2
field3
field4
Unique_Seq
SELECT Unique_Seq,COUNT(Unique_Seq)
FROM Schema.Tablename
GROUP BY Unique_Seq
HAVING ( COUNT(Unique_Seq) > 1
I want to create the table using all the fields from schema.tablename
ThanksThanks for the table script and insert statement.
here is what you are looking for
select * from tester_c;
AD_ID CD_ID UNIQUE_SEQ Z_MASTER_KEY
OP0021889/10 OP0021889/10 529832 NNCC00491362OP0021889/1025-JAN-10
OP0021889/10 529832 NNCC0049136225-JAN-10
OP0022096/10 539481 NNCC0060037812-JAN-10
OP0022096/10 OP0022096/10 539481 NNCC00600378OP0022096/1012-JAN-10
LI0192 IK735241 53925 PP54TH34120988
KL1923836 65478 BG7892534KL1923836
KL1923836 65478 BG7892534KL1923836
PQ8712346 BN27345236 64877 7234723642
8 rows selected.
Elapsed: 00:00:00.01Pushing duplicate data into a new table tester_c_dup
CREATE Table tester_c_dup as SELECT * FROM tester_c A WHERE a.rowid > ANY (SELECT B.rowid FROM
Tester_c B
WHERE
a.Unique_Seq = B.Unique_Seq)
select * from tester_c_dup;
AD_ID CD_ID UNIQUE_SEQ Z_MASTER_KEY
OP0021889/10 529832 NNCC0049136225-JAN-10
OP0022096/10 OP0022096/10 539481 NNCC00600378OP0022096/1012-JAN-10
KL1923836 65478 BG7892534KL1923836
Elapsed: 00:00:00.01Deleting duplicate data from tester_c table
DELETE FROM tester_c A WHERE a.rowid > ANY (SELECT B.rowid FROM
Tester_c B
WHERE
a.Unique_Seq = B.Unique_Seq)
select * from tester_c;
AD_ID CD_ID UNIQUE_SEQ Z_MASTER_KEY
OP0021889/10 OP0021889/10 529832 NNCC00491362OP0021889/1025-JAN-10
OP0022096/10 539481 NNCC0060037812-JAN-10
LI0192 IK735241 53925 PP54TH34120988
KL1923836 65478 BG7892534KL1923836
PQ8712346 BN27345236 64877 7234723642
Elapsed: 00:00:00.00HTH,
Prazy -
How to display rows in PSA having count(wbs) 1
Hi there BW gurus.
I have a history in the SQL world, where it is quite easy to write a SQL code to get out the rows from a table with duplicates in one spesific field. (Beeing indexed or not)
I have tried to search for this option where we diplays the content in an PSA. but not found it.
Anyone having a good solution for this.
(I am not an ABAP-er)
Best Regards IngridHi Ingrid,
following ABAP returns all languages which more than one user is assigned to.
data: l_langu type usr01-langu.
data: l_Num type i.
SELECT count( * ) langu
into (l_Num, l_langu)
FROM usr01
GROUP BY langu
having count( * ) GT 1.
write: / l_langu, ' - ', l_num.
endselect.
e.g. language E is assigned to 27 users.
Hope this gives you an idea.
Regards,
Jürgen -
Can I write merge SQL statement having count(*)?
Hi this is a followup question of my previous post. I tried to use a merge SQL statement to solve my problem but now I bump into another problem.
Now I have a table where the field I need to update is a partial PK
when using a merge SQL statement, I have to put a where clause that check if count(*) = 1 because of the PK constraint
Where can I put the count(*) = 1 clause?
Here are the details:
I have two tables TA and TB, where TA contains the fields ID, FULLNAME, TYPE and TB contains the fields ID, FIRSTNAME
I want to update the firstnames in TB to be the firstnames from TA where TB.ID = TA.ID and TA.TYPE = 'ABC'
{ID, FIRSTNAME} are PKs but for the same ID, there can be more than 1 firstname.
e.g.
TA
ID | FULLNAME | TYPE
1 Caroline T ABC
2 Mary C DEF
3 Peter J ABC
TB
ID | FIRSTNAME
1 Caroline
1 Carol
1 C,
3 Peter
I need to update TB with the new firstnames from TA where type is 'ABC' but only for those fields that have count(TB.ID) = 1
when I try to run this SQL statement
merge into TB B using TA A
on (A.ID = B.ID and A.TYPE = 'ABC')
when matched then update set B.FIRSTNAME = substr(A.FULLNAME, 1, instr(A.FULLNAME, ',') - 1)
I got this error SQL Error: ORA-00001: unique constraint (TEST.PK_TB) violated
which I believe is because I updated those fields say ID = 1, all with 'Caroline'
that means I will have to add a clause having count(TB.ID) = 1
How would you do it?
Server is Oracle 11g
Thank you!Hi,
One way is to join ta and tb in the USING clause, and eliminate the duplicates there.
MERGE INTO tb dst
USING (
SELECT ta.id
, REGEXP_SUBSTR ( MIN (ta.fullname)
, '^[^,]*'
) AS firstname
FROM ta
JOIN tb ON ta.id = tb.id
WHERE ta.type = 'ABC'
GROUP BY ta.id
HAVING COUNT (*) = 1
) src
ON (scr.id = dst.id)
WHEN MATCHED THEN UPDATE
SET dst.firstname = src.firstname
;If you'd care to post CREATE TABLE and INSERT statements for your sample data, then I could test this.
I used REGEXP_SUBST instead of SUBSTR and INSTR to find the firstname, because I find it a little cleaner, and becuase it returns something even when there is no ',' in fullname, which I'm guessing is what you really want. (None of the fullnames in your sample data have ','s.) You could use SUBSTR and INSTR instead. -
Having count(*) 1
with my_table as
(select '402' id, '75175637' snr from dual union all
select '400' id, '15208367' snr from dual union all
select '400' id, '45208312' snr from dual union all
select '400' id, '55208344' snr from dual union all
select '402' id, '65208317' snr from dual union all
select '402' id, '65208317' snr from dual union all
select '402' id, '75208310' snr from dual union all
select '402' id, '85208310' snr from dual union all
select '421' id, '75208310' snr from dual union all
select '421' id, '99908456' snr from dual union all
select '422' id, '10008222' snr from dual) -- end of data sample
select b.snr
from (select id, snr
from my_table
group by id, snr) b
group by b.snr
having count(*) > 1 ;
SNR
75208310SNR 75208310 is among ID 402 and 421. The output should be the following:
ID SNR
402 75208310
421 75208310Does anybody have an idea?Thank you @all,
Warren,
after I add the statement >>select '402' id, '65208317' snr from dual union all<<
to the data sample I get the following
SQL> with my_table as
2 (select '402' id, '75175637' snr from dual union all
3 select '400' id, '15208367' snr from dual union all
4 select '400' id, '45208312' snr from dual union all
5 select '400' id, '55208344' snr from dual union all
6 select '402' id, '65208317' snr from dual union all
7 select '402' id, '65208317' snr from dual union all -- additional statement
8 select '402' id, '75208310' snr from dual union all
9 select '402' id, '85208310' snr from dual union all
10 select '421' id, '75208310' snr from dual union all
11 select '421' id, '99908456' snr from dual union all
12 select '422' id, '10008222' snr from dual) -- end of data sample
13 select distinct
14 mt1.id,
15 mt1.snr
16 from my_table mt1,
17 (select snr, count(*) cnt
18 from my_table
19 group by snr) mt2
20 where mt1.snr = mt2.snr
21 and mt2.cnt > 1;
ID SNR
402 65208317
402 75208310
421 75208310
SQL> But I do not need 402, 65208317 in my output.
I solved it with
SQL> with my_table as
2 (select '402' id, '75175637' snr from dual union all
3 select '400' id, '15208367' snr from dual union all
4 select '400' id, '45208312' snr from dual union all
5 select '400' id, '55208344' snr from dual union all
6 select '402' id, '65208317' snr from dual union all
7 select '402' id, '65208317' snr from dual union all -- additional statement
8 select '402' id, '75208310' snr from dual union all
9 select '402' id, '85208310' snr from dual union all
10 select '421' id, '75208310' snr from dual union all
11 select '421' id, '99908456' snr from dual union all
12 select '422' id, '10008222' snr from dual) -- end of data sample
13 select id, snr
14 from
15 ( select id, snr, count(*) over (partition by snr) as cnt
16 from my_table
17 group by id, snr
18 )
19 where cnt > 1
20 ;
ID SNR
402 75208310
421 75208310
SQL> -
PL/SQL update rate using having count
Hi am newbie at pl/sql
I need to update rate_per_hour for all projects having less than 5 employee to 500
here is the code what i wrote, but it updates all employee
set serveroutput on
declare
cursor rate_cur is
select * from project
for update of rate_per_hour;
begin
for rate_rec IN rate_cur
loop
update project
set rate_per_hour=500
where current of rate_cur;
end loop;
end;Here is my tables:
CREATE TABLE employee(
empid number(5),
empname varchar(20),
address varchar(20),
no_of_dependents number(5),
deptno number(5),
CONSTRAINT EMPLOYEE_PKEY PRIMARY KEY(empid),
CONSTRAINT EMPLOYEE_FKEY FOREIGN KEY(deptno) REFERENCES department(deptno));
CREATE TABLE project(
projectno number(5),
location varchar(20),
incharge number(5),
rate_per_hour number(5),
CONSTRAINT PROJECT_PKEY PRIMARY KEY(projectno),
CONSTRAINT PROJECT_FKEY FOREIGN KEY(incharge) REFERENCES employee(empid));
CREATE TABLE assignment(
empid number(5),
projectid number(5),
hours number(5),
CONSTRAINT ASSIGNMENT_FKEY FOREIGN KEY(empid) REFERENCES employee(empid),
CONSTRAINT ASSIGNEMNT_FKEY2 FOREIGN KEY(projectid) REFERENCES project(projectno));please suggest a solution
Edited by: user12970368 on Dec 15, 2011 6:55 AMhere is test data
/*department table */
insert into department values(201,'ADMINISTRATION',10000,101);
insert into department values(202,'FINANCE',10000,102);
insert into department values(203,'ACCOUTING',10000,103);
insert into department values(204,'HR',10000,104);
insert into department values(205,'TESTING',10000,105);
/*employee table
insert into employee values(101,'Marlen', 'DXB1',5,201);
insert into employee values(102,'Oleg', 'DXB2',2,201);
insert into employee values(103,'Adil', 'SHJ1',1,202);
insert into employee values(104,'Sultan', 'AD1',0,202);
insert into employee values(105,'John', 'AD2',1,203);
insert into project values(001,'Dubai Marina',101,50);
insert into project values(002,'Bur Dubai',101,40);
insert into project values(003,'Palm Jumeirah',103,60);
insert into project values(004,'Media city',101,100);
insert into project values(005,'TECOM',101,30);
/*assignment table */
insert into assignment values(101,001,55);
insert into assignment values(101,004,128);
insert into assignment values(101,005,77);
insert into assignment values(102,002,27);
insert into assignment values(103,003,250);Edited by: user12970368 on Dec 15, 2011 6:54 AM -
Count(field) group by having changed to an analytic function
Goal: Be able to show columns with data not in the group by clause.
I couldn't find this on the 'net either by looking here or by googling for it (unless I'm looking for the wrong thing). I'm doing a regular:
select fielda, count(fielda)
from some_table
group by fielda1
having count(field1) > 1;
to find out where I have duplicates in a table (fielda). I get fielda and the count of those records back (ie X, 2). However, I want to add several more fields that may or may not be different for each of those records.
For example:
1 record has fielda = X, field2 = Test, field3 = Oracle, field4 = Unix
1 record has fielda = X, field2 = Testa, field3 = Sybase, field4 = Windows.
I want to be able to have the following output:
X, 2 (count of records with fieldA = X), Test, Oracle, Unix
X, 2 (count of records with fieldA = X), Testa, Sybase, Windows
I'm not sure if this is one of those where I have to do a subquery on or not. Any ideas?
Thanks as always!
VicSorry, I misread your statement - it is poorly formatted. Besides incorrect use of aliases you are referencing columns that are not in inline view, therefore you must include it there:
select nsn,
item_type_name,
item_type_id,
date_time_added,
function_name
from (
select it.nsn,
it.item_type_name,
it.item_type_id,
it.date_time_added,
fn.function_name,
count(*) over (partition by it.nsn) cnt,
it.item_type_cat_id,
ic.item_category_id,
ic.function_id ic_function_id,
fn.function_id fn_function_id
from item_types it,
item_categories ic, functions fn
where it.nsn is not null
and it.item_type_cat_id = ic.item_category_id
and ic.function_id = fn.function_id
where cnt > 1
and nsn is not null
and item_type_cat_id = item_category_id
and ic_function_id = fn_function_id
order by nsn;SY. -
How do I use count for this query?
How do I display all the addresses in a table that have more than one (or >1) account number? I wasn't sure how or if I should use count along with group by and having to get the expected results.
select address from tablename
group by address having count(1) > 1; -
Creation of object in universe to show the count in report
Hi,
I am trying to create an object in universe.
I had a table called projects in which there are projectid and managers and now i want to show in report as below.
15 PMu2019s assigned to 1-3 Projects
10 PMu2019s assigned to 4 Projects
20 PMu2019s assigned to > 5 Projects
The count of managers assigned to the number of projects. Could any one pls explain in detail how i can do this in universe.
Thanks,
EswarHi,
Here is the syntax:
SELECT CAST(SUM(a.nb_Mgr) AS VARCHAR) + ' Managers: 1-2 projects' as Nb_Mgr FROM
(SELECT Count(distinct Manager) as nb_Mgr from ISL.dbo.Projects group by Manager having count(Project) <= 2) a
UNION
SELECT CAST(SUM(a.nb_Mgr) AS VARCHAR) + ' Managers: 3-5 projects' FROM
(SELECT Count(distinct Manager) as nb_Mgr from ISL.dbo.Projects group by Manager having count(Project) > 2 and count(Project) <= 5) a
UNION
SELECT CAST(SUM(a.nb_Mgr) AS VARCHAR) + ' Managers: > 5 projects' FROM
(SELECT Count(distinct Manager) as nb_Mgr from ISL.dbo.Projects group by Manager having count(Project) > 5) a
By the way you can create a more sophisticated derived table that let users choosing tha values for the number of projects:
SELECT CAST(SUM(a.nb_Mgr) AS VARCHAR) + ' Managers < ' + @Prompt('Min threshold','A',,mono,free) + ' projects' as Nb_Mgr FROM
(SELECT Count(distinct Manager) as nb_Mgr from ISL.dbo.Projects group by Manager having count(Project) < @Prompt('Min threshold','N',,mono,free)) a
UNION
SELECT CAST(SUM(a.nb_Mgr) AS VARCHAR) + ' Managers between ' + @Prompt('Min threshold','A',,mono,free) + ' and ' + @Prompt('Max threshold','A',,mono,free) + ' projects' FROM
(SELECT Count(distinct Manager) as nb_Mgr from ISL.dbo.Projects group by Manager having count(Project) >= @Prompt('Min threshold','N',,mono,free) and count(Project) <= @Prompt('Max threshold','N',,mono,free)) a
UNION
SELECT CAST(SUM(a.nb_Mgr) AS VARCHAR) + ' Managers > ' + @Prompt('Max threshold','A',,mono,free) + ' projects' FROM
(SELECT Count(distinct Manager) as nb_Mgr from ISL.dbo.Projects group by Manager having count(Project) > @Prompt('Max threshold','N',,mono,free)) a
Regards
Didier -
Hi Everyone,
I have a table Table1
Table1: ID, Name, Sales, Time
Sample data:
1, Loo, Y, 20-JUL-09 01.20.17.000000000 PM
2, Rey, Y, 20-JUL-09 01.20.17.000000000 PM
1, Loo, Y, 20-JUL-09 01.20.17.000000000 PM
1, Loo, Y, 20-JUL-09 01.20.17.000000000 PM
3, Bon, Y, 20-JUL-09 01.20.17.000000000 PM
1, Loo, Y, 19-JUL-09 01.20.17.000000000 PM
I want the result as:
1, 3
2, 1
3, 1
i.e employee with id 1 and count of his apperaince in the table where data is 20-JULY-09
Any suggestions and inputs are appreciated.
Thanks
KasiHi,
user10651875 wrote:
Thanks that worked.
If i want to change the query to get the ID which is having a count > 20 keeping all the other clauses, what should i modify?Do you mean you only want to diplay rows where count>20 (if any)?
Add a HAVING clause, immediately after the GROUP BY clause:
SELECT id
, COUNT (*) AS cnt
FROM table1
WHERE TRUNC (time) = DATE '2009-07-20'
GROUP BY id
HAVING COUNT (*) > 20;HAVING is similar to WHERE, but WHERE is evaluated before aggregate functions (like COUNT in this example) are compute. HAVING is evaluated after the aggregate functions are computed, therefore, you can use them in the HAVING clause. (In fact, you should never have a HAVING clause that doesn't use aggregate functions.) -
Having with more than one clause
Hi
Is posssible to have a query with more than one clause in having condition
Example In my query I have Count , Sum and AVG , I need to use 3 conditions in having, Is It possible ?
Thank you in advanceHi,
yes, in Having you can also use AND and OR.
with x as (select 1 nr from dual)
select nr
from x
group by nr
having count(*) = 1
and sum(nr) = 1Herald ten Dam
http://htendam.wordpress.com
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