Having the '\' character in a string

I get errors when I try to construct a string, say like this:
String blahblah = new String("IBM\ROOT\IMAGE");
Basically it seems like I can't store that '\' character in a string at all. Is this true?
Thanks in advance.

the '\' character is used to indicate an escape sequence, used for things like '\n' (new line). To do what you want you can do this:
String blahblah = new String("IBM\\ROOT\\IMAGE"); //notice the double slash '\\' you would also have to do this for double and single quotes, e.g. ( new String("Bill said, \" Anne told me to \'go home now\'\"") : for... Bill said, "Anne told me to 'go home now'")

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Replacing the \ character in a string

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thx

The escape is for the compiler, I think, and then you need to escape the backslash.
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� {�

How to escape the character in a string?

I have the following code that is causing an error. I'm
attempting to use < (less than) character in a string that is
part of a dynamic query:
<cfif url.age eq 1>
<cfset askAge = " < 15">
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The error occurs as a result of the line <cfset askAge = "
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Dave,
What if you passed off the output of the lt/gt symbols to the
query itself?
Something like,
<cfif url.age eq 1>
<cfset compareOperator = "less"/>
<cfset askAge = "15">
<cfelseif url.age eq 10>
<cfset compareOperator = "between"/>
<cfset askAge = " 56 and 60">
<cfelseif url.age eq 11>
<cfset compareOperator = "greater"/>
<cfset askAge = "60">
</cfif>
Then in the query:
<cfquery name="qTest" datasource="dsn">
SELECT * FROM myTable
WHERE age
<cfswitch expression="#compareOperator#">
<cfcase value="less">
<
</cfcase>
<cfcase value="greater">
>
</cfcase>
<cfcase value="between">
BETWEEN
</cfcase>
<cfdefaultcase>
=
</cfdefaultcase>
</cfswitch>
#askAge#
</cfquery>
Probably a better way, at least a more efficient way, but
just a thought...cfswitch processed pretty quickly and this would
remove any issues with trying to use <> symbols.
Cheers,
Craig

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A beautiful query posted by a guru in this forum long time ago.
SQL> set line 1000
SQL> l
1     SELECT ename
2          , Letter_repetition
3          , COUNT(*)repetition_count
4     FROM ( SELECT ename
5                   , Letter_repetition
6                FROM emp
7               MODEL
8                     RETURN UPDATED ROWS
9                     PARTITION BY (ename)
10                     DIMENSION BY (0 i)
11                     MEASURES (ename Letter_repetition)
12                     ( Letter_repetition[FOR i FROM 1 TO
13                                         length(Letter_repetition[0])
14                                         INCREMENT 1] = SUBSTR(Letter_repetition[0],CV(i),1)
15                     )
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17      GROUP BY ename
18          , Letter_repetition
19*    HAVING COUNT(*) > 1
SQL> /
ENAME                               LETTER_REPETITION                   REPETITION_COUNT
SCOTT                               T                                                  2
TURNER                              R                                                  2
ALLEN                               L                                                  2
MILLER                              L                                                  2
ADAMS                               A                                                  2
SQL>

Find the count of the character in a string

Hi,
i have a scenario like i have one string in that character is repeated for more than one time.
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regexp_count() function.
Better answers available on the SQL-PLSQL forum. PL/SQL
Edited by: SK1 on May 24, 2012 11:30 AM

Replacing a character in a string to another character

hi,
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I want to Replace all the Existence of the word - "Test" in a string with "Test1" whereever a space exits before the word Test and someother alphabet after "Test" i.e. Test will be replaced with Test1 if a word starts with Test and contains more alphabets also. For example - TestName should be replaced with Test1Name while MyTest should not be updated to MyTest1.
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My new wirelss keyboard is repeating the "\" character endlessly; also inserting them into the string of characters I'm typing. It does is in word and in both safari and firefox. How do I get this to stop?

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Try changing the batteries on the keyboard or see if the keyboard has some sort of reset available.

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Hello Experts,
I have a scenario where in I have to check the occurrence of a character in a string and based on that I have to pass a data into target field.
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Thanks in advance.
Regards
Advit Ramesh

Hi Advit,
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Standard Functions (SAP Library - SAP Exchange Infrastructure)
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Eng Swee

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I need to return the first character of a string, convert it to an integer, and compare it with another integer to see if they're the same. Sounds simple, even for me, but it won't work!!!
// First question >
Object userValue1 = JOptionPane.showInputDialog("Blah Blah Blah", JOptionPane.PLAIN_MESSAGE, null, options1, options1[0]);
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C:\Documents and Settings\imholt\My Documents\OOPAttempt\21_Questions\Engine.java:170: cannot resolve symbol
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location: class java.lang.Object
Variables.placeholder = (int) userValue1.charAt(0);
^
1 error
I have a sneaky suspicion that once I find out what the problem was, I will ask myself why I didn't see it before...

Try this
Object userValue1 = JOptionPane.showInputDialog("Blah Blah Blah", JOptionPane.PLAIN_MESSAGE, null, options1, options1[0]);
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Inserting the "enter" character in a String

Hi,
I would like to insert a "enter" character in a String to create a new line.
something like this
String test = "teste" + char(10) + "teste";
Thanks in advanced
Ricardo

Are you trying to do this in an email? You didn't mention that. If your email encoding doesn't support new lines (the most simple encoding doesn't) you can't send them. I don't know why you'd get those results though, unless you actually put "\\n\\r" in the Java program.
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How to replace only the first specified character in a string and leave other occurrence of the character alone.

Hello my Friends:
I have a string that looks like this in a column:
Hello, World, Hello, Planet
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Working on some bad data source.
I need to replace the character regardless of it's location as long as it is the first.
I tried something like this, but I soon discovered that if the comma or character is missing the the string may get truncated or altered. If there are no characters in the string, then I want to simply leave it alone.
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Thanks my friends.

I have a string that looks like this in a column:
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Oh, sorry about that. Anyway:
SELECT MyString = CASE WHEN CHARINDEX(',', @MyValue, 0) >= 1
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Erland Sommarskog, SQL Server MVP, [email protected]
Erland, love you sense of humor!! :)
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How we can find the last character in a string(Urgent Plz!)

Gurus!
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Use the substr() and length() functions -
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What is the function to count the occurance of a character in a string.
like 'test test1 test2 test3' with in this string there are 3 white spaces.
instr will give the first one, replace will change the all... and what's for the occurance (number of white spaces, which is 3 in this case) count
Message was edited by:
gladnn

SQL> var a varchar2(25)
SQL> exec :a := 'gghhhh999jjjj'
&nbsp
PL/SQL procedure successfully completed.
&nbsp
SQL> select length(:a) - nvl(length(replace(:a,'h','')),0) from dual;
&nbsp
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4Rgds.

Count the occurence of a character in a string

Post Author: halfpat
CA Forum: Formula
Hello to everyone,
I use CR 8,0. Is anyone can tell me if this is possible:
I have a string "12345-C-1 23456-C-2 34567-C-4", how can I count the occurence of the "C" character in this string ?Is the InStr function can help me to do this ?
I appreciate any suggestion,
Thanks.

Post Author: bettername
CA Forum: Formula
How about measuring the length of the string, and subtracting the length of the same string where C is replaced with <nothing>?
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Which method to count the number of character in a string?

Hi all,
I want to know which class and method to count the number of character in a string?
Gary

http://java.sun.com/j2se/1.4.2/docs/api/java/lang/String.html

Having the '\' character in a string

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