Help,how to check a input type?

Dear all experts,
in the selection-screen,user need to key in the vendor consignment code ( vdrcsg for mslb-lifnr ) some user key in storage location ( mseg-lgort ) in this field. Is there anyway tat i can do verification before procees to the start-of-selection? how to check if the user key in correct data type to the selection screen? thanks

hi Joan,
Check these links :
http://help.sap.com/saphelp_erp2005vp/helpdata/en/79/34a234d9b511d1950e0000e8353423/frameset.htm
http://www.erpgenie.com/abap/selection_screens.htm
http://www.sapdevelopment.co.uk/reporting/selscr/selscr_loopscreen.htm
priyanka.

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hi, i am creating this basic program/game. i need to get two inputs from the user. the problem is when i run the program it gets the first input from the user but then doesn't get the second input.. please help, the code is as follows:
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(i will reply to this post with the code required to make the SavitchIn.readline thing work.

this is the code required for the SavitchIn read- copy the below code and save it as SavitchIn.java:
import java.io.*;
import java.util.*;
*Class for simple console input.
*A class designed primarily for simple keyboard input of the form
*one input value per line. If the user enters an improper input,
*i.e., an input of the wrong type or a blank line, then the user
*is prompted to reenter the input and given a brief explanation
*of what is required. Also includes some additional methods to
*input single numbers, words, and characters, without going to
*the next line.
public class SavitchIn
*Reads a line of text and returns that line as a String value.
*The end of a line must be indicated either by a new-line
*character '\n' or by a carriage return '\r' followed by a
*new-line character '\n'. (Almost all systems do this
*automatically. So, you need not worry about this detail.)
*Neither the '\n', nor the '\r' if present, are part of the
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public static String readLine()
char nextChar;
String result = "";
boolean done = false;
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nextChar = readChar();
if (nextChar == '\n')
done = true;
else if (nextChar == '\r')
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result = result + nextChar;
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*Reads the first string of nonwhite characters on a line and
*returns that string. The rest of the line is discarded. If
*the line contains only white space, then the user is asked
*to reenter the line.
public static String readLineWord()
String inputString = null,
result = null;
boolean done = false;
while(!done)
inputString = readLine();
StringTokenizer wordSource =
new StringTokenizer(inputString);
if (wordSource.hasMoreTokens())
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System.out.println(
"Your input is not correct. Your input must");
System.out.println(
"contain at least one nonwhitespace character.");
System.out.println(
"Please, try again. Enter input:");
return result;
*Precondition: The user has entered a number of type int on
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*and/or after the number.
*Action: Reads and returns the number as a value of type int.
*The rest of the line is discarded. If the input is not
*entered correctly, then in most cases, the user will be
*asked to reenter the input. In particular, this applies to
*incorrect number formats and blank lines.
public static int readLineInt()
String inputString = null;
int number = -9999;//To keep the compiler happy.
//Designed to look like a garbage value.
boolean done = false;
while (! done)
try
inputString = readLine();
inputString = inputString.trim();
number = Integer.parseInt(inputString);
done = true;
catch (NumberFormatException e)
System.out.println(
"Your input number is not correct.");
System.out.println("Your input number must be");
System.out.println("a whole number written as an");
System.out.println("ordinary numeral, such as 42");
System.out.println("Minus signs are OK,"
+ "but do not use a plus sign.");
System.out.println("Please, try again.");
System.out.println("Enter a whole number:");
return number;
*Precondition: The user has entered a number of type long on
*a line by itself, except that there may be white space
*before and/or after the number.
*Action: Reads and returns the number as a value of type
*long. The rest of the line is discarded. If the input is not
*entered correctly, then in most cases, the user will be asked
*to reenter the input. In particular, this applies to
*incorrect number formats and blank lines.
public static long readLineLong()
String inputString = null;
long number = -9999;//To keep the compiler happy.
//Designed to look like a garbage value.
boolean done = false;
while (! done)
try
inputString = readLine();
inputString = inputString.trim();
number = Long.parseLong(inputString);
done = true;
catch (NumberFormatException e)
System.out.println(
"Your input number is not correct.");
System.out.println("Your input number must be");
System.out.println("a whole number written as an");
System.out.println("ordinary numeral, such as 42");
System.out.println("Minus signs are OK,"
+ "but do not use a plus sign.");
System.out.println("Please, try again.");
System.out.println("Enter a whole number:");
return number;
*Precondition: The user has entered a number of type double
*on a line by itself, except that there may be white space
*before and/or after the number.
*Action: Reads and returns the number as a value of type
*double. The rest of the line is discarded. If the input is
*not entered correctly, then in most cases, the user will be
*asked to reenter the input. In particular, this applies to
*incorrect number formats and blank lines.
public static double readLineDouble()
String inputString = null;
double number = -9999;//To keep the compiler happy.
//Designed to look like a garbage value.
boolean done = false;
while (! done)
try
inputString = readLine();
inputString = inputString.trim();
number = Double.parseDouble(inputString);
done = true;
catch (NumberFormatException e)
System.out.println(
"Your input number is not correct.");
System.out.println("Your input number must be");
System.out.println("an ordinary number either with");
System.out.println("or without a decimal point,");
System.out.println("such as 42 or 9.99");
System.out.println("Please, try again.");
System.out.println("Enter the number:");
return number;
*Precondition: The user has entered a number of type float
*on a line by itself, except that there may be white space
*before and/or after the number.
*Action: Reads and returns the number as a value of type
*float. The rest of the line is discarded. If the input is
*not entered correctly, then in most cases, the user will
*be asked to reenter the input. In particular,
*this applies to incorrect number formats and blank lines.
public static float readLineFloat()
String inputString = null;
float number = -9999;//To keep the compiler happy.
//Designed to look like a garbage value.
boolean done = false;
while (! done)
try
inputString = readLine();
inputString = inputString.trim();
number = Float.parseFloat(inputString);
done = true;
catch (NumberFormatException e)
System.out.println(
"Your input number is not correct.");
System.out.println("Your input number must be");
System.out.println("an ordinary number either with");
System.out.println("or without a decimal point,");
System.out.println("such as 42 or 9.99");
System.out.println("Please, try again.");
System.out.println("Enter the number:");
return number;
*Reads the first nonwhite character on a line and returns
*that character. The rest of the line is discarded. If the
*line contains only white space, then the user is asked to
*reenter the line.
public static char readLineNonwhiteChar()
boolean done = false;
String inputString = null;
char nonWhite = ' ';//To keep the compiler happy.
while (! done)
inputString = readLine();
inputString = inputString.trim();
if (inputString.length() == 0)
System.out.println(
"Your input is not correct.");
System.out.println("Your input must contain at");
System.out.println(
"least one nonwhitespace character.");
System.out.println("Please, try again.");
System.out.println("Enter input:");
else
nonWhite = (inputString.charAt(0));
done = true;
return nonWhite;
*Input should consist of a single word on a line, possibly
*surrounded by white space. The line is read and discarded.
*If the input word is "true" or "t", then true is returned.
*If the input word is "false" or "f", then false is returned.
*Uppercase and lowercase letters are considered equal. If the
*user enters anything else (e.g., multiple words or different
*words), then the user is asked to reenter the input.
public static boolean readLineBoolean()
boolean done = false;
String inputString = null;
boolean result = false;//To keep the compiler happy.
while (! done)
inputString = readLine();
inputString = inputString.trim();
if (inputString.equalsIgnoreCase("true")
|| inputString.equalsIgnoreCase("t"))
result = true;
done = true;
else if (inputString.equalsIgnoreCase("false")
|| inputString.equalsIgnoreCase("f"))
result = false;
done = true;
else
System.out.println(
"Your input number is not correct.");
System.out.println("Your input must be");
System.out.println("one of the following:");
System.out.println("the word true,");
System.out.println("the word false,");
System.out.println("the letter T,");
System.out.println("or the letter F.");
System.out.println("You may use either upper-");
System.out.println("or lowercase letters.");
System.out.println("Please, try again.");
System.out.println("Enter input:");
return result;
*Reads the next input character and returns that character. The
*next read takes place on the same line where this one left off.
public static char readChar()
int charAsInt = -1; //To keep the compiler happy
try
charAsInt = System.in.read();
catch(IOException e)
System.out.println(e.getMessage());
System.out.println("Fatal error. Ending Program.");
System.exit(0);
return (char)charAsInt;
*Reads the next nonwhite input character and returns that
*character. The next read takes place immediately after
*the character read.
public static char readNonwhiteChar()
char next;
next = readChar();
while (Character.isWhitespace(next))
next = readChar();
return next;
*The following methods are not used in the text, except for
*a brief reference in Chapter 2. No program code uses them.
*However, some programmers may want to use them.
*Precondition: The next input in the stream consists of an
*int value, possibly preceded by white space, but definitely
*followed by white space.
*Action: Reads the first string of nonwhite characters
*and returns the int value it represents. Discards the first
*whitespace character after the word. The next read takes
*place immediately after the discarded whitespace.
*In particular, if the word is at the end of a line, the
*next reading will take place starting on the next line.
*If the next word does not represent an int value,
*a NumberFormatException is thrown.
public static int readInt() throws NumberFormatException
String inputString = null;
inputString = readWord();
return Integer.parseInt(inputString);
*Precondition: The next input consists of a long value,
*possibly preceded by white space, but definitely
*followed by white space.
*Action: Reads the first string of nonwhite characters and
*returns the long value it represents. Discards the first
*whitespace character after the string read. The next read
*takes place immediately after the discarded whitespace.
*In particular, if the string read is at the end of a line,
*the next reading will take place starting on the next line.
*If the next word does not represent a long value,
*a NumberFormatException is thrown.
public static long readLong()
throws NumberFormatException
String inputString = null;
inputString = readWord();
return Long.parseLong(inputString);
*Precondition: The next input consists of a double value,
*possibly preceded by white space, but definitely
*followed by white space.
*Action: Reads the first string of nonwhitespace characters
*and returns the double value it represents. Discards the
*first whitespace character after the string read. The next
*read takes place immediately after the discarded whitespace.
*In particular, if the string read is at the end of a line,
*the next reading will take place starting on the next line.
*If the next word does not represent a double value,
*a NumberFormatException is thrown.
public static double readDouble()
throws NumberFormatException
String inputString = null;
inputString = readWord();
return Double.parseDouble(inputString);
*Precondition: The next input consists of a float value,
*possibly preceded by white space, but definitely
*followed by white space.
*Action: Reads the first string of nonwhite characters and
*returns the float value it represents. Discards the first
*whitespace character after the string read. The next read
*takes place immediately after the discarded whitespace.
*In particular, if the string read is at the end of a line,
*the next reading will take place starting on the next line.
*If the next word does not represent a float value,
*a NumberFormatException is thrown.
public static float readFloat()
throws NumberFormatException
String inputString = null;
inputString = readWord();
return Float.parseFloat(inputString);
*Reads the first string of nonwhite characters and returns
*that string. Discards the first whitespace character after
*the string read. The next read takes place immediately after
*the discarded whitespace. In particular, if the string
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String result = "";
char next;
next = readChar();
while (Character.isWhitespace(next))
next = readChar();
while (!(Character.isWhitespace(next)))
result = result + next;
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next = readChar();
if (next != '\n')
System.out.println(
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*Precondition: The user has entered a number of type byte on
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String inputString = null;
byte number = -123;//To keep the compiler happy.
//Designed to look like a garbage value.
boolean done = false;
while (! done)
try
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inputString = inputString.trim();
number = Byte.parseByte(inputString);
done = true;
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System.out.println("whole number in the range");
System.out.println("-128 to 127, written as");
System.out.println("an ordinary numeral, such as 42.");
System.out.println("Minus signs are OK,"
+ "but do not use a plus sign.");
System.out.println("Please, try again.");
System.out.println("Enter a whole number:");
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*Precondition: The user has entered a number of type short on
*a line by itself, except that there may be white space before
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*Action: Reads and returns the number as a value of type short.
*The rest of the line is discarded. If the input is not
*entered correctly, then in most cases, the user will be
*asked to reenter the input. In particular, this applies to
*incorrect number formats and blank lines.
public static short readLineShort()
String inputString = null;
short number = -9999;//To keep the compiler happy.
//Designed to look like a garbage value.
boolean done = false;
while (! done)
try
inputString = readLine();
inputString = inputString.trim();
number = Short.parseShort(inputString);
done = true;
catch (NumberFormatException e)
System.out.println(
"Your input number is not correct.");
System.out.println("Your input number must be a");
System.out.println("whole number in the range");
System.out.println("-32768 to 32767, written as");
System.out.println("an ordinary numeral, such as 42.");
System.out.println("Minus signs are OK,"
+ "but do not use a plus sign.");
System.out.println("Please, try again.");
System.out.println("Enter a whole number:");
return number;
public static byte readByte() throws NumberFormatException
String inputString = null;
inputString = readWord();
return Byte.parseByte(inputString);
public static short readShort() throws NumberFormatException
String inputString = null;
inputString = readWord();
return Short.parseShort(inputString);
//The following was intentionally not used in the code for
//other methods so that somebody reading the code could more
//quickly see what was being used.
*Reads the first byte in the input stream and returns that
*byte as an int. The next read takes place where this one
*left off. This read is the same as System.in.read(),
*except that it catches IOExceptions.
public static int read()
int result = -1; //To keep the compiler happy
try
result = System.in.read();
catch(IOException e)
System.out.println(e.getMessage());
System.out.println("Fatal error. Ending Program.");
System.exit(0);
return result;

Help,how to check a input type?

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