Help in the below scenario

Hi,
I have a table with a column called "DESC".
My requirement is ,if the input is "abc",then the output should be [a][c] .
The datatype of the column is varchar(10).
Please help me in this.
Thanks
Thanks,
Pandeeswaran
Edited by: Pandeesh on Jan 2, 2012 10:16 AM

Use REGEXP_REPLACE:
with tbl as (select 'abc' descr from dual)
select descr,
regexp_replace(descr,'(.)','[\1]') new_descr
from tbl
DES NEW_DESCR
abc [a][c]
SQL>
SY.

Similar Messages

How to deal with BRS for the below scenario?

Hi,
I would like to know the solution for the below scenario for BRS:
I have a customer who was maintaining their accounts with Tally software for their previous Financial Year. This year they have shifted to SAP B1 2005B. They have issued few cheques for their vendors in the month of march 2008 which has been realised in the month of April 2008. As per Tally, the closing balance of their bank is 8 Lakh but as per the bank statement, their closing balance is 23 Lakhs. In SAP, the opening Balance for the bank is considered as 23 Lakhs. Now there are 15 Lakh worth cheques which were not realised for the month of March 2008.
Example:
abc a/c - 3Lakh
def a/c - 5lakh
xyz a/c - 7 lakh
How do i reconcile for this scenario and what procedures do i follow in SAP?
Thanks and Regards,
Kaushal

Hi Kamlesh,
Thanks for your response.
Actually, In the "Process External Bank Statement" window, i see that there are few entries which is for the previous year and which has not been reconciled. I have never worked practically on BRS and hence, i am scared to make any changes in the clients database without being confident on what i am doing. I need to reconcile for one of their Bank a/c for the month of April '08. I have the copy of the statements for the month ending 31st Mar 08 and 30th Apr 08. The closing balances are as below:
31/03/08 - 2300000.00
30/04/08 - 3100000.00
Now my OB for Bank a/c for April '08 in SAP is 2300000.00 Dr.
When i go to External Bank Reconciliation - Selection Criteria Screen (Manual Reconciliation), here are the detail that i enter:
Last Balance: INR -7,000,000.00000 (Grayed out by the system)
Ending Balance: INR -3,100,000.00000 (Entered by me)
End Date: 30/04/08 (Entered by me)
"Reconciliation Bank Statement" Screen opens up and shows the below balances in the screen:
Cleared Book Balance: INR -7,000,000.00000
Statement Ending Balance: INR -3,100,000.00000
Difference: INR 3,800,000.00000
As per the Bank statement, i have found all the transactions listed out here for the month of Apr '08 but, i also found that the open transactions for the previous month from April '08 have been lying in "Process External Bank Statement" window.
Could you please help me solve my issue as to what needs to be done or could you also get me some links from where i can get few documents for processing External Bank Reconciliations?
That will be of a great help for me. I need steps as to what needs to be done first and then the next so that i can arrive at the correct closing balance for the month April '08.
Thanks in Advance....
Regards,
Kaushal

How will the system handle delta in the below scenario

How will the system handle delta in the below scenario
Day 1
DS--->DSO
PSA
Document Number| Customer | sales value
1001| RAMLAL | 10000
Your change log for DSO will read
Req1| 1001|RAMLAL|10000|N
DSO(overwrite)
1001|RAMLAL|10000|
Day 1
DSO--->Cube
Req1| 1001|RAMLAL|10000|
Day2
DS--->DSO
PSA
Document Number| Customer | sales value
1001| RAMLAL | 30000
Your change log for DSO will read
Req2 | 1001 | RAMLAL | -10000 | X
Req2 | 1001 | RAMLAL | 30000
DSO(Overwrite)
1001 | RAMLAL | 30000
Day 2
DSO--->Cube
Req1|1001|RAMLAL|10000|
Req2|1001|RAMLAL|20000|
Please explain with example
Scenario 1: Req1 & Req2 are deleted ONLY from change log on Day 3
On Day 4:
DS--->DSO
Document Number| Customer | sales value|STOR_NO(ROCANCEL)
1001| RAMLAL | 10000|C
What will happen to the Sales Value in the cube?
What will happen to the Req1&Req2 in the cube?
Thanks
Tanya

Tanya,
Please explain with example
Scenario 1: Req1 & Req2 are deleted ONLY from change log on Day 3
On Day 4:
DS--->DSO
Document Number| Customer | sales value|STOR_NO(ROCANCEL)
1001| RAMLAL | 10000|C
What will happen to the Sales Value in the cube?
What will happen to the Req1&Req2 in the cube?
Document Number| Customer | sales value|STOR_NO(ROCANCEL)
1001| RAMLAL | 10000 |C
--> Here 1000 is not correct value, as 1000 is change to 3000. It should be 3000. record should be as below.
Document Number| Customer | sales value|STOR_NO(ROCANCEL)
1001| RAMLAL | 30000 |C
--> As this data related to sales, and i hope you are using standard ABR extractors(Business Content).
ABR datasources delivers before and after images.
Before image:
Document Number| Customer | sales value|STOR_NO(ROCANCEL)
1001| RAMLAL | -3000 |C
Before image:
Document Number| Customer | sales value|STOR_NO(ROCANCEL)
1001| RAMLAL | 0 |C --> value changed from 3000 to Zero.
If you are loading in additive or Overwrite into an ODS total sales for 1001 at end of day 4 will be Zero.
Hope it helps
Srini

Need help on the below query or Pl-SQL

Hello Every one,
Please let me know if some one can help me out with the below scenario either in pl-sql or sql.
Source Data:
0000253800     0.25          0845A     0900A
0000253800     1          0900A     1000A
0000253800     1          1300P     1400P
0000253800     1          1500P     1600P
0000253800     1          1600P     1700P
Output needed:
0000253800     1.25          0845A     1000A
0000253800     1          1300P     1400P
0000253800     2          1500P     1700P
Thanks in Advance....
Edited by: user12564103 on Dec 11, 2011 5:54 PM

Hi,
Welcome to the forum!
Depending on your data and your requirements:
WITH     got_times     AS
     SELECT     column_1, column_2, column_3, column_4
     ,     TO_DATE ( substr (column_3, 1, 4)
               , 'HH24MI'
               )     AS time_3
     ,     TO_DATE ( SUBSTR (column_4, 1, 4)
               , 'HH24MI'
               )     AS time_4
     FROM     table_x
,     got_grp_id     AS
     SELECT     column_1, column_2, column_3, column_4
     ,     time_3, time_4
     ,     time_4 - SUM (time_4 - time_3) OVER ( PARTITION BY column_1
                                    ORDER BY         time_3
                                  )     AS grp_id
     FROM     got_times
SELECT       column_1
,       SUM (column_2)     AS sum_2
,       MIN (column_3) KEEP (DENSE_RANK FIRST ORDER BY time_3)
                    AS min_3
,       MAX (column_4) KEEP (DENSE_RANK LAST ORDER BY time_4)
                    AS max_4
FROM       got_grp_id
GROUP BY column_1
,       grp_id
ORDER BY column_1
,       grp_id
;Whenever you have a problem, please post CREATE TABLE and INSERT statements for your sample data, as well as the results you want from that data. Explain, with specific examples, how you get the results you want from that data.
Always say which version of Oracle you're using. The query above will work in Oracle 9.1 (and higher).
Since this is your first thread, I'll do this for you:
CREATE TABLE     table_x
(     column_1     NUMBER
,     column_2     NUMBER
,     column_3     VARCHAR2 (5)
,     column_4     VARCHAR2 (5)
INSERT INTO table_x (column_1, column_2, column_3, column_4) VALUES (253800, .25, '0845A', '0900A');
INSERT INTO table_x (column_1, column_2, column_3, column_4) VALUES (253800, 1,   '0900A', '1000A');
INSERT INTO table_x (column_1, column_2, column_3, column_4) VALUES (253800, 1,   '1300P', '1400P');
INSERT INTO table_x (column_1, column_2, column_3, column_4) VALUES (253800, 1,   '1500P', '1600P');
INSERT INTO table_x (column_1, column_2, column_3, column_4) VALUES (253800, 1,   '1600P', '1700P');Column_1 identifes a day.
Column_2 is an amount that I need to total.
Column_3 and column_4 are starting and ending times. We can assume that they are all valid times (in 'HH24MI' format, plus a redundant 'A' or 'P') on the same day, column_3 is always less than column_4, and that the range of two rows for the same value of column_1 never overlap. Column_4 of one row may be equal to column_3 of another rows with the same column_1, but it will never be greater.
Each row of the output represent a contiguous group of rows (each ending exactly when the next one begins) with the same column_1, with the common column_1, the total of column_2, and the range of the group.
For example, the first two rows for a single group, because they have the same value for column_1, and one ends exactly when the other begins (at 9:00 AM). This group represents day 253800, from 8:45 AM to 10:00 AM. The totla of column_2 fro this group is .25 + 1 = 1.25.
The next row (from 1:00 PM to 2:00 PM) is a group all by itself, because there is a gap one either side of it separating it from its nearest neighbor on the same day."
Of course, I'm guessing at lots of things.
Edited by: Frank Kulash on Dec 11, 2011 9:44 PM
Changed TO_DATE calls.
Edited by: Frank Kulash on Dec 11, 2011 9:52 PM
Added sample question.

Need help in the below command excution

Hi Champs,
Can any one help with the below command, It is not working.
Get-CsUser | Where-Object {$_.dialplan -eq "USDAL"} | Grant-CsLocationPolicy -PolicyName "Dallas Location Policy"
Regards
Vijendhar

You could try something like:
$userlist = Get-CsUser -ResultSize Unlimited
foreach ($user in $userlist)
if ($user.dialplan -eq $Null)
$pool = (Get-csdialplan | Where-Object {$_.Identity -like ("*" + $user.RegistrarPool)})
if ($pool.length -ge "1") {write-host ("Pool simple name: " + $pool.simplename + ", Identity: " + $pool.identity)}
if (($pool.simplename -eq "USDal") -or ($pool.identity -eq "USDal"))
Write-host "Please Grant location policy to: $user.Displayname"
# Get-csuser $user.identity | Grant-CsLocationPolicy -PolicyName "Dallas Location Policy"
$pool = $Null
Use at your own risk as I haven't had a chance to test, I have commented out the grant so you can test prior to changes.
Please mark posts as answers/helpful if it answers your question.
Blog
Lync Validator - Used to assist in the validation and documentation of Lync Server 2013.

Need help on the below query.

Hi All,
I've a query given below..
SELECT W.WONUM,
     W.STATUS,
     WS.CHANGEDATE,
     EH.OLD_RATE
     FROM
     WORKORDER W,
     WOSTATUS WS,
     ESTIMATE_HEADER@GQMFOF EH
WHERE WS.CHANGEDATE BETWEEN '01-Oct-2009' AND '1-Nov-2009'
AND W.WONUM = WS.WONUM
AND EH.OLD_RATE = 'N'
AND WS.WOSTATUS = 'CLOSE';
I would like to get All the data which status =closed in the month of Oct for Old rate,
So for this i am writing the query above. But not getting the o/p.
It is giving me that " Table/View doesn't exist.
There 2 schemas MAXIMO,GQMMGR..
DBlinks are GQMFOF,MAXFOFNC..
Can anyone help me while writing the above query...
Regards,
gr.

A question was asked in your other thread. But the problem was you dint care to give an answer.
Dont open duplicate post.
I need help on the below problem..

I need help on the below problem..

Hi All,
I need help on the below problem..
I've 2 Schemas called
1. MAXIMO and DBLink is GQMFOF
2. GQMMGR adn DBLink is MAXFOFNC
Now i would likw to retrive the data from both the schemas,
i.e some columns from WORKORDER table of maximo schema and some columns from ESTIMATE_HEADER table
of GQMMGR schema..
I'm trying to get the data using DB links, but it is giving TABLE/VIEW doesn't exist.
Please help me on this.
Regards,
gr.

Does your user has the SELECT privelage granted for accessing those tables?

Help in the below code

I want to run the below code for zone_id 1 to 12. How will I do that ?
Kindly help me on this.
DECLARE
CURSOR c1 IS SELECT item FROM [email protected];
CURSOR c2(tmp_item VARCHAR2) IS
    SELECT location FROM rpm_zone_location WHERE zone_id = 1
    MINUS
    SELECT DISTINCT location from rpm_clearance WHERE item = tmp_item AND reset_ind = 1 and location in
      (select location from rpm_zone_location where zone_id=1);
BEGIN
FOR i IN c1
LOOP
    FOR j IN c2 (i.item)
    LOOP
      INSERT INTO RMS12.RPM_CLEARANCE
(CLEARANCE_ID,
CLEARANCE_DISPLAY_ID,
STATE,
REASON_CODE,
LOC_EXCEPTION_PARENT_ID,
PARENT_EXCEPTION_PARENT_ID,
CLEARANCE_RESET_ID,
RESET_IND,
ITEM,
DIFF_ID,
ZONE_ID,
LOCATION,
ZONE_NODE_TYPE,
EFFECTIVE_DATE,
OUT_OF_STOCK_DATE,
RESET_DATE,
CHANGE_TYPE,
CHANGE_AMOUNT,
CHANGE_CURRENCY,
CHANGE_PERCENT,
CHANGE_SELLING_UOM,
PRICE_GUIDE_ID,
VENDOR_FUNDED_IND,
FUNDING_TYPE,
FUNDING_AMOUNT,
FUNDING_AMOUNT_CURRENCY,
FUNDING_PERCENT,
SUPPLIER,
DEAL_ID,
DEAL_DETAIL_ID,
PARTNER_TYPE,
PARTNER_ID,
CREATE_DATE,
CREATE_ID,
APPROVAL_DATE,
APPROVAL_ID,
LOCK_VERSION)
SELECT
RPM_CLEARANCE_SEQ.Nextval,
'reset:'||CLEARANCE_DISPLAY_ID,
'pricechange.state.approved',
REASON_CODE,
LOC_EXCEPTION_PARENT_ID,
PARENT_EXCEPTION_PARENT_ID,
CLEARANCE_RESET_ID,
1,
ITEM,
DIFF_ID,
null,
c2.location,
0,
null,
OUT_OF_STOCK_DATE,
null,
CHANGE_TYPE,
CHANGE_AMOUNT,
CHANGE_CURRENCY,
CHANGE_PERCENT,
CHANGE_SELLING_UOM,
PRICE_GUIDE_ID,
VENDOR_FUNDED_IND,
FUNDING_TYPE,
FUNDING_AMOUNT,
FUNDING_AMOUNT_CURRENCY,
FUNDING_PERCENT,
SUPPLIER,
DEAL_ID,
DEAL_DETAIL_ID,
PARTNER_TYPE,
PARTNER_ID,
CREATE_DATE,
'RMS12',
APPROVAL_DATE,
'RMS12',
LOCK_VERSION
from rpm_clearance where zone_id=1 and item = j.item;
    END LOOP;
    COMMIT;
END LOOP;
END;

It might be a good idea to post this again using the "code" button so that it's properly formatted. Take your time so that it's as accurate as possible. And don't forget to say at what point as the program executes this eligibility is being considered.

Help on the below problem..

Hi all,
I've a SQL query which is written to retrive the data from 3 tables & 2 views.Again the 2 views are based on 3 tables each. When i execute the query in explain plan it is giving cost = 8870. i've rebuild all the indexes which are using in where clause of all the tables.Finally i've reduced the cost to 3347.But still it is taking much time to execute.
So any one give the complete details of "What are the steps to be taken(follow) while tuning this type of queries. What i've to do in this scenario to reduce the time taking.Indexes are there in all the tables.But 2 tables are scaning full though indexes are there.
Using Oracle 10g ver.
Executing in TOAD 8.1.6 ver.
Please help me on this. And if possible send me some documents.
Regards,
grace

gracy wrote:
I've a SQL query which is written to retrive the data from 3 tables & 2 views.Again the 2 views are based on 3 tables each. When i execute the query in explain plan it is giving cost = 8870. i've rebuild all the indexes which are using in where clause of all the tables.Finally i've reduced the cost to 3347.But still it is taking much time to execute.What is the unit of cost? We know it is not US dollars.. so what is it then? And just what does a cost of 8870 mean? And how much better is that than a cost of 3347?
Do you think that cost can be plotted on a linear scale? If so, then the cost of 3347 should be 3.7 times faster/better than the cost of 8870.
But it is not. Why? Because of the assumption what cost mean... and not knowing what it actually means and whether or not it can be used as an effective means to determine how much better performance is, why use it?
Surely, you need to know WHAT a number means before using that number to determine the better/faster option?
Bottom line - do not use cost unless you are intimately familiar with exactly what you are dealing with. Rather deal with what you can see and measure effectively and understand easily. And this is I/O. How much I/O is needed using SQL A versus how much I/O is needed using SQL B.
I/O is the most expensive operation in a database. The less I/O you do, the faster the SQL is. Which is we have features like indexes, partitions, clusters and so on - all these are methods to reduce I/O. To provide better/smaller I/O paths for the database to find the rows that we are interested in.
And surely dealing with I/O gives you a far better understanding of the impact of a query than a cost that you do not even know the unit type of?

Link between EKBE and EKET for the below scenario

Hi all
We have a requirement to display schedule line number(eket-etenr) for purchase order and for each history of quantities in table EKBE (ekbe-ebeln ,ekbe-ebelp). Please suggest how we can link these two tables,
As i need to display the eket-etenr upto the quantity confirmed on latest date..
The example is below for quantity 81.
If Purshase history is
EKET-menge EKET- etenr
81 --- 0001
5 -
0002
10 --- 0003
date move-typ EKBE-menge ***-sum ETENR
01/26/2004 101 10 10 0001
01/26/2004 101 10 20 0001
01/27/2004 101 20 40 0001
01/27/2004 101 20 60 0001
01/30/2005 101 10 70 0001
03/31/2005 101 1 71 0001
03/31/2005 101 10 81 0001
04/01/2005 101 9 90 0001
11/20/2006 102 -9 81 0001
06/04/2006 101 3 84 0002
06/05/2006 101 1 85 0002
06/06/2006 102 -1 -1 84 0002
06/07/2006 101 3 87 0003
06/08/2006 101 9 96 0003
We need to display EKET-ETENr for each ekbe entry whenever the quantity is delivered til that line.
Pleae suggest possible ways.
Regards,
Latha.

Hi,
Pls chk this relations-
EKBE-> EKKO->based on EBELN
EKKO -> EKPO based on EBELN
EKPO->EKET based on EBELN, EBELP
First try to get the Purchase order numbers into EKKO from EKBE based on this get their itmes from EKPO from this we can get the EKET values based on both documnet number and theier items.
To get the history of the PO(EBELN) check this select statement -
SELECT
     ebeln      "Purchasing Document Number
     ebelp      "Item Number of Purchasing Document
     gjahr      "Financial year
     vgabe      "Transaction/event type, purchase order
     belnr      "Number of material document
     bwart      "Movement type
     budat      "Posting date in the document
     menge      "Quantity
     wrbtr      "Amount in document currency
     waers      "Currency Key
     matnr      "Material number
     werks      "plant
     charg      "Batch
     FROM ekbe
     INTO TABLE i_ekbe
     WHERE gjahr IN s_gjahr AND
           budat IN s_budat AND
           werks = p_plant.
SORT i_ekbe BY ebeln gjahr matnr vgabe bwart.
if i_ekbe[] is not initial.
SELECT
           ebeln    "PO
           lifnr       "VENDOR
      FROM ekko
      INTO TABLE i_ekko
      FOR ALL ENTRIES IN i_ekbe
      WHERE ebeln = i_ekbe-ebeln.
endif.
SORT i_ekko BY ebeln.
if i_ekko[] is not intitial.
SELECT
            ebeln    "Purchasing Document Number
            ebelp    "Purchasing Document ITEM
            matnr    "Materail No.
            menge    "qty
            meins    "unit
              umrez    "Conversion factor                 "MOD-005
              umren    "conversion factor                 "MOD-005
        FROM ekpo
        INTO TABLE i_ekpo
             FOR ALL ENTRIES IN i_ekko
        WHERE ebeln = i_ekko-ebeln.
endif.
if i_ekpo[] is not initial.
    SELECT   *
           FROM eket
           INTO TABLE i_eket
           FOR ALL ENTRIES IN i_ekpo
           WHERE ebeln = i_ekpo-ebeln
           AND   ebelp = i_ekpo-ebelp.
endif.
Hope this solves your issue. Chanegethe WHERE conditions wherever necessarry as per your requiremnets.
Regards
Lekha

Need help with the following scenario

Hi guys,
I have to implement a solution which requires me to duplicated all the rows from a table to another in reverse order. For eg. I have table1 containing the following rows:
200, 350, 700, 90
All these numbers are sorted according to their ROW_ID_BLOCK_NUMBER. When these rows are replicated over to another table, say table2, it should be inserted in the following order:
90, 700, 350, 200
I do not have another column column that stores the running identity number for each row and I don't intend to implement that right now. I was wondering if that can be implemented using the DBMS_ROWID package and if so, how? Any help is greatly appreciated here. Thanks in advance.

In 10g, assuming you've built a table with row dependencies enabled
SCOTT @ jcave102 Local> create table a (
2 col1 number
3 )
4 rowdependencies;
Table created.
Elapsed: 00:00:00.04the ORA_ROWSCN pseudocolumn will tell you the SCN (system change number) of the transaction that inserted the rows
SCOTT @ jcave102 Local> insert into a values( 1 );
1 row created.
Elapsed: 00:00:00.07
SCOTT @ jcave102 Local> insert into a values( 2 );
1 row created.
Elapsed: 00:00:00.01
SCOTT @ jcave102 Local> commit;
Commit complete.
Elapsed: 00:00:00.00
SCOTT @ jcave102 Local> insert into a values( 3 );
1 row created.
Elapsed: 00:00:00.04
SCOTT @ jcave102 Local> commit;
Commit complete.
Elapsed: 00:00:00.01
SCOTT @ jcave102 Local> select ora_rowscn, col1 from a;
ORA_ROWSCN       COL1
   6270940          1
   6270940          2
   6270944          3
Elapsed: 00:00:00.09Sorting on that, assuming you insert the rows in the right logical order, should work (the documentation only guarantees that the SCN of the row is greater than or equal to the SCN when a row was modified, so it's not guaranteed, but I don't know of a mechanism that would cause the ORA_ROWSCN to change without DML affecting the row in this example so it's relatively safe, at least with your current Oracle version). If ROWDEPENDENCIES is not set, the default is that the SCN is tracked at the block rather than the row level.
Justin

Help in the below query

Hi ,
I have the following string
select '1, ,3, , , abc, ,dce,234, , , abc 1 ,1 ,4 ' from dual
and i have translations for
abc,dce and abc 1 respecitvely as
X ,Y and Z
which i strore in a table as
1 abc X
2 dce Y
3 abc 1 Z
now i want to replace these tranlations in my original string such that my spaces etc are intact ( note that i cannot use the replace function directly)
MY final string should look like
1, ,3, , , X, ,Y,234, , , Z ,1 ,4
any pointers how i can achieve it.
Thanks

Prazy wrote:
Aketi Jyuuzou wrote:
I like recursive with clause B-)Yes but recursive with clause is being supported only from 11gR2 but OP is using *10gR2* B-)Hehe I was to start create SQL seeing OP's first Post only :-)
And I prefer recursive with clause than model clause B-)
And my prev SQL is wrong.
with t as(
select '1, ,3, , , abc, ,dce,234, , , abc 1 ,1 ,4 '
as str from dual),
repstr(ID,befo,aft) as(
select 1,'abc','X' from dual union
select 2,'dce','Y' from dual union
select 3,'abc 1','Z' from dual),
rec(str,LV) as(
select RegExp_Replace(a.str,
       '(,|^)( *)' || b.befo || '( *)(,|$)',
       '\1\2' || b.aft || '\3\4'),1
from t a,repstr b
where b.ID=1
union all
select RegExp_Replace(a.str,
       '(,|^)( *)' || b.befo || '( *)(,|$)',
       '\1\2' || b.aft || '\3\4'),a.LV+1
from rec a,repstr b
where a.LV+1 = b.ID)
select max(str) Keep(Dense_Rank Last order by LV) as str
from rec;
STR
1, ,3, , , X, ,Y,234, , , Z ,1 ,4

Can someone help decipher the below panic error?

Interval Since Last Panic Report: 5 sec
Panics Since Last Report:          1
Anonymous UUID:                    56112AF8-6418-4920-9611-83ECB5E29C19
Sun Mar 10 09:42:04 2013
panic(cpu 0 caller 0x2a8ac2): Kernel trap at 0x00292af7, type 14=page fault, registers:
CR0: 0x80010033, CR2: 0x00000010, CR3: 0x37721000, CR4: 0x000006e8
EAX: 0x0eef62b0, EBX: 0x80000000, ECX: 0x0eef62b0, EDX: 0x00000000
CR2: 0x00000010, EBP: 0x7ddabcf8, ESI: 0x00000000, EDI: 0x00000000
EFL: 0x00010202, EIP: 0x00292af7, CS: 0x00000008, DS: 0x00000010
Error code: 0x00000000
Backtrace (CPU 0), Frame : Return Address (4 potential args on stack)
0x7ddab9f8 : 0x21b449 (0x5ce420 0x7ddaba2c 0x2238a5 0x0)
0x7ddaba48 : 0x2a8ac2 (0x590478 0x292af7 0xe 0x590642)
0x7ddabb28 : 0x29e9a8 (0x7ddabb40 0x76 0x7ddabcf8 0x292af7)
0x7ddabb38 : 0x292af7 (0xe 0x48 0x10 0x10)
0x7ddabcf8 : 0x2936d6 (0xeef62b8 0x10000000 0x1 0x1042000)
0x7ddabd68 : 0x260897 (0xeef62b8 0xff8d000 0x1 0x1098d000)
0x7ddabe98 : 0x260e32 (0x1098d000 0x1 0x0 0x0)
0x7ddabed8 : 0x281fb3 (0xffdc854 0xff8d000 0x1 0x1098d000)
0x7ddabf38 : 0x479c06 (0xffdc854 0xff8d000 0x1 0xa00000)
0x7ddabf78 : 0x4ecbb9 (0xfff57e0 0xeeff048 0xf53b684 0x1)
0x7ddabfc8 : 0x29f43d (0xeeff044 0x0 0x10 0x0)
BSD process name corresponding to current thread: mds
Mac OS version:
10D575
Kernel version:
Darwin Kernel Version 10.3.0: Fri Feb 26 11:58:09 PST 2010; root:xnu-1504.3.12~1/RELEASE_I386
System model name: MacPro4,1 (Mac-F221BEC8)
System uptime in nanoseconds: 895007347562
unloaded kexts:
com.apple.filesystems.msdosfs          1.6.1 (addr 0x7d5d1000, size 0x53248) - last unloaded 373865381269
loaded kexts:
com.highpoint-tech.kext.HighPointRR          1.0.0
com.apple.driver.AppleHWSensor          1.9.3d0
com.apple.driver.AppleTyMCEDriver          1.0.1d8
com.apple.driver.AGPM          100.10.21
com.apple.driver.AudioAUUC          1.4
com.apple.driver.AppleMikeyHIDDriver          1.2.0
com.apple.driver.AppleUpstreamUserClient          3.3.2
com.apple.Dont_Steal_Mac_OS_X          7.0.0
com.apple.driver.AppleMikeyDriver          1.8.4fc3
com.apple.GeForce          6.1.0
com.apple.driver.Intel82574L          1.0.4b1
com.apple.driver.AppleIntelNehalemProfile          11
com.apple.driver.AudioIPCDriver          1.1.2
com.apple.driver.AppleHDA          1.8.4fc3
com.apple.driver.AppleUSBDisplays          251
com.apple.driver.AirPortBrcm43xx          422.91.27
com.apple.driver.ACPI_SMC_PlatformPlugin          4.1.1d0
com.apple.driver.AppleLPC          1.4.11
com.apple.filesystems.autofs          2.1.0
com.apple.iokit.IOAHCIBlockStorage          1.6.1
com.apple.iokit.SCSITaskUserClient          2.6.2
com.apple.BootCache          31
com.apple.AppleFSCompression.AppleFSCompressionTypeZlib          1.0.0d1
com.apple.driver.AppleUSBHub          3.9.6
com.apple.driver.AppleFWOHCI          4.5.7
com.apple.driver.AppleUSBEHCI          3.9.6
com.apple.driver.AppleAHCIPort          2.1.1
com.apple.driver.AppleUSBUHCI          3.9.6
com.apple.driver.AppleEFINVRAM          1.3.0
com.apple.driver.AppleRTC          1.3.1
com.apple.driver.AppleHPET          1.5
com.apple.driver.AppleACPIButtons          1.3.2
com.apple.driver.AppleSMBIOS          1.5
com.apple.driver.AppleACPIEC          1.3.2
com.apple.driver.AppleAPIC          1.4
com.apple.security.sandbox          0
com.apple.security.quarantine          0
com.apple.nke.applicationfirewall          2.1.11
com.apple.driver.AppleIntelCPUPowerManagementClient          104.3.0
com.apple.driver.AppleIntelCPUPowerManagement          104.3.0
com.apple.iokit.IOSCSIBlockCommandsDevice          2.6.2 - last loaded 890932740795
com.apple.driver.AppleProfileReadCounterAction          17
com.apple.driver.AppleProfileTimestampAction          10
com.apple.driver.AppleProfileThreadInfoAction          14
com.apple.driver.AppleProfileRegisterStateAction          10
com.apple.driver.AppleProfileKEventAction          10
com.apple.driver.AppleProfileCallstackAction          20
com.apple.iokit.IOSurface          74.0
com.apple.iokit.IOBluetoothSerialManager          2.3.1f4
com.apple.iokit.IOSerialFamily          10.0.3
com.apple.driver.DspFuncLib          1.8.4fc3
com.apple.iokit.IOAudioFamily          1.7.6fc2
com.apple.kext.OSvKernDSPLib          1.3
com.apple.driver.AppleSMBusController          1.0.8d0
com.apple.nvidia.nv50hal          6.1.0
com.apple.NVDAResman          6.1.0
com.apple.iokit.IONDRVSupport          2.1
com.apple.iokit.IOFireWireIP          2.0.3
com.apple.iokit.IO80211Family          310.6
com.apple.iokit.IONetworkingFamily          1.9
com.apple.iokit.AppleProfileFamily          41
com.apple.driver.AppleHDAController          1.8.4fc3
com.apple.iokit.IOGraphicsFamily          2.1
com.apple.iokit.IOHDAFamily          1.8.4fc3
com.apple.driver.AppleSMC          3.0.1d2
com.apple.driver.IOPlatformPluginFamily          4.1.1d0
com.apple.driver.AppleSMBusPCI          1.0.8d0
com.apple.driver.XsanFilter          402.1
com.apple.driver.AppleUSBHIDKeyboard          1.2.0a3
com.apple.driver.AppleHIDKeyboard          1.2.0a3
com.apple.driver.BroadcomUSBBluetoothHCIController          2.3.1f4
com.apple.driver.AppleUSBBluetoothHCIController          2.3.1f4
com.apple.iokit.IOBluetoothFamily          2.3.1f4
com.apple.driver.AppleUSBMergeNub          3.9.6
com.apple.iokit.IOUSBHIDDriver          3.9.6
com.apple.driver.AppleUSBComposite          3.9.0
com.apple.iokit.IOSCSIMultimediaCommandsDevice          2.6.2
com.apple.iokit.IOBDStorageFamily          1.6
com.apple.iokit.IODVDStorageFamily          1.6
com.apple.iokit.IOCDStorageFamily          1.6
com.apple.iokit.IOSCSIParallelFamily          2.0.0
com.apple.iokit.IOFireWireFamily          4.2.6
com.apple.iokit.IOUSBUserClient          3.9.6
com.apple.iokit.IOAHCISerialATAPI          1.2.3
com.apple.iokit.IOSCSIArchitectureModelFamily          2.6.2
com.apple.iokit.IOAHCIFamily          2.0.3
com.apple.iokit.IOUSBFamily          3.9.6
com.apple.driver.AppleEFIRuntime          1.3.0
com.apple.iokit.IOHIDFamily          1.6.2
com.apple.iokit.IOSMBusFamily          1.1
com.apple.security.TMSafetyNet          6
com.apple.kext.AppleMatch          1.0.0d1
com.apple.driver.DiskImages          283
com.apple.iokit.IOStorageFamily          1.6
com.apple.driver.AppleACPIPlatform          1.3.2
com.apple.iokit.IOPCIFamily          2.6
com.apple.iokit.IOACPIFamily          1.3.0
Model: MacPro4,1, BootROM MP41.0081.B07, 8 processors, Quad-Core Intel Xeon, 2.26 GHz, 10 GB, SMC 1.39f5
Graphics: NVIDIA GeForce GT 120, NVIDIA GeForce GT 120, PCIe, 512 MB
Memory Module: global_name
AirPort: spairport_wireless_card_type_airport_extreme (0x14E4, 0x88), Broadcom BCM43xx 1.0 (5.10.91.27)
Bluetooth: Version 2.3.1f4, 2 service, 19 devices, 1 incoming serial ports
Network Service: AirPort, AirPort, en2
PCI Card: scsi, sppci_scsi_bus, Slot-3
PCI Card: pci-bridge, sppci_pci2pcibridge, Slot-4
PCI Card: pci-bridge, sppci_pci2pcibridge, Slot-4
PCI Card: pcibdbd,a10c, sppci_video, Slot-4@5,1,0
PCI Card: NVIDIA GeForce GT 120, Display, Slot-1
Serial ATA Device: HL-DT-ST DVD-RW GH41N
Serial ATA Device: PIONEER BD-RW   BDR-206
Serial ATA Device: WDC WD6400AAKS-41H2B0, 596.17 GB
SCSI Device: SCSI Target Device @ 16
USB Device: Hub, 0x05ac (Apple Inc.), 0x9122, 0xfd300000
USB Device: Keyboard Hub, 0x05ac (Apple Inc.), 0x1006, 0xfd310000
USB Device: Kensington Expert Mouse, 0x047d (Kensington), 0x1020, 0xfd313000
USB Device: Apple Keyboard, 0x05ac (Apple Inc.), 0x0220, 0xfd312000
USB Device: Apple Cinema HD Display, 0x05ac (Apple Inc.), 0x921e, 0xfd320000
USB Device: BRCM2046 Hub, 0x0a5c (Broadcom Corp.), 0x4500, 0x5a100000
USB Device: Bluetooth USB Host Controller, 0x05ac (Apple Inc.), 0x8215, 0x5a110000
FireWire Device: built-in_hub, Up to 800 Mb/sec
FireWire Device: unknown_device, Unknown

Boot into Safe Mode. If there are no more panics then uninstall your HighPoint RAID software. See if the panics cease. If they do contact HighPoint for a newer driver.
You can also try removing the Kensington mouse and using the mouse that came with the computer.
The affected thread was Spotlight indexing.

Pls. is the below scenario is possible in SAP?

Hello,
We are from bulk sale industry, our customers are individual store operators. We want to provide a Adobe Interactive Form in our portal to these customers so that they will enter material data submits the form to the workflow/system.
Pls. note users does NOT have SAP access
Just they hv our company's Portal access
1) Customers are individual store operators
2) We want to place a Adobe Interactive Form for our customers in our portal
3) So that customers will open the portal and then opens the AIF and enters the input data
4) Finally, they will submit the form for workflow
Then, it should save into SAP system after proper workflow process is done
Pls. let us know the feasibility, concerns, approach, thoughts, pro & cons
Thank you

Hi,
until such time SAP delivers Adobe Document Services in Hana Cloud, in case you don't have it available somwehere in your landscape yet, you'd need to install ADS on SAP Netweaver usage type AS Java. The use of Interactive Forms can unter certain circumstances be subject to additional Adobe licence costs.
cheers,
Janis

Need Help with the below query

Hi All,
I'm working on Oracle HRMS tables which have date tracking facility.
I'm working on Oracle 10G.
I have a table per_all_assignments_f(seeded) which contains the employee related information.
It has normal hours and the assignment_id(primary key) in the table
The data is something like
assignment_id
123                   30                   01-Jan-2000               31-dec-2009
123                    32                 01-Jan-2010               31-dec-2012
123
assignment_id
Normal_hours
Effective_start_Date
Effective_end_Date
123
30
01-Jan-2000
31-dec-2009
123
32
01-Jan-2010
31-dec-2012
123
40
01-Jan-20103
40                  01-jan-2013               31-dec-4712
Now I'd like to pass the latest date(sysdate) to a function which should give me the
last changed normal hours as on today. In this case 32.
select normal_hours from per_all_assignments_f where
assignment_id=123
and trunc(latest_date) between effective_start_date and effective_end_date
This will give me the latest normal hours of 40 but I want the last changed hours irrespective of how many ever be the changes.
hope I'm clear in specifying my requirement.
Appreciate your time
Thanks,
AJ

877722 wrote:
It has normal hours and the assignment_id(primary key) in the table
How PK value is repeating in your sample data!
877722 wrote:
This will give me the latest normal hours of 40 but I want the last changed hours irrespective of how many ever be the changes.
hope I'm clear in specifying my requirement.
Nope. What is "changed hours"? Not able to break your source code! a tough one, I say.
By the way, follow the link shared by Karthick and will be easy to answer for anyone.
Thanks!

Help in the below scenario

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