Help: Last Month Last Day till 12:00:00 PM

Hello Folks,
I am trying to get the last months last day in the query for developing a report. I have tried the code as below
TRUNC (SYSDATE, 'MONTH') - 1 but it returns
11/30/2009 12:00:00 AMbut i need to get the data up until 12:00:00 PM. Can anybody please throw some light on this.Thanks

Hi,
fsitja wrote:
You shouldn't use a mixed syntax. Either you go ANSI on the whole FROM or you can use the Oracle join syntax for every table.Very well put! You CAN mix syntaxes, but it's confusing, and I've never seen an example where plain ANSI syntax doesn't get the right results more clearly.
OP:
If you say
FROM "CUBS SNAPSHOT",client, CancelDesc
INNER JOIN(...)then the parentheses must contain a sub-query, starting with SELECT (or maybe WITH).
See [your previous message|http://forums.oracle.com/forums/message.jspa?messageID=3993062#3993062] for what you need to do if you want help.
As mentioned in that thread, there is no need to group the INNER JOINS. The results will always be the same, regardless of what order the tables are joined.
You can write the arithmetic expression:
5 + x + y + 1lots of different ways, including
5 + (x + (y + 1))
((5 + x) + y) + 1
(5 + x) + (y + 1)
(5 + x + y) + 1
5 + (x + y) + 1and it may be a good idea, if it makes your code clearer, so human beings can understand it more easily. But the results will always be the same, no matter how you group the addition operations.
In the same way, no matter how multiple INNER JOINs are grouped, the results will be the same. I can't think of any situation where clarity would be enhanced by spelling out a join order.

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Hi ,
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from dual
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hi ,
the query sent by you is correct and could it be in corporated for this query :
SELECT TRUNC(inst_due_date) + (LEVEL-1 ) * (ilpa_term_type),iloan_code,LOAN_AMT,FEE_AMT,
LOAN_DATE,LOAN_STATUS_ID
FROM (
SELECT inst_due_date,sm.iloan_code,LOAN_AMT,
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When we drag and drop date column and unit cost in the report like below we will have
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Sep29     $10
sep30     $12
Oct1       $12
Oct2       $14
..........ans so on
The source sustem program runs on last day of the month around 8pm for setting up cost to reflect on 1st of every month
But the nighly OBI load ( Runs at 2am every day) when incrementally updating Sep30 data picks up $12 from the erp and populates in OBI.
But actually speaking, on Sep30 the cost was $10.
There is no way of running the ERP program to run afer OBI load. Hence we need an expression in the RPD (not answers) saying
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Date        Cost
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sep30     $10
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Nov1      $13.5

You can achieve the above requirement for current month alone with below steps:
The solution requires to have a union report
First part of the report will have Date and Cost fields with a report level date filter, Date NOT IN (TIMESTAMPADD( SQL_TSI_DAY , -(1), TIMESTAMPADD( SQL_TSI_MONTH , 1, TIMESTAMPADD( SQL_TSI_DAY , DAYOFMONTH( CURRENT_DATE) * -(1) + 1, CURRENT_DATE))))
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Change the column formula for Date to display only Current_Date
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Pls mark if correct/helpful.

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Pavan Kumar Prakhya

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How to get the last day of the next month?

Hi all.
I need to get the last day of the next month. E.g. if the date is 20.03.2008 I need to get 30.04.2008.
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TIA, Nikolai.

hi Nikolai,
pls. have a look athe following piece of code:
PARAMETERS : p_date TYPE sy-datum.
DATA : gv_res TYPE sy-datum.
CALL FUNCTION 'CALCULATE_DATE'
EXPORTING
*   DAYS              = '0'
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   start_date        = p_date
IMPORTING
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==> Now you have (gv_res) 2 months later as today
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ec

How to get the last day of the previous month

Hello Team,
If my input date is today , then i need to find out the last day of the previous month for the same.
Can someone help me to find out .. how can this be done.
Regards,
Ravi

Hi,
Try the below code.
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The formula I am have currently is:
DateSerial(Year({Name.JOIN_DATE}), Month({Name.JOIN_DATE}) + 1, 0)+1
this will give me 3/1/2009, but I need 3/31/2009.
Any help appreciated.
Thanks!

Hi Joe,
You can use the following logic which also takes into account the extra day in a leap year. You will need 5 formulas for this:
First create a formula that calculates current month, call it @Current Month MM
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Next create another formula called @Current Month Start Date which will give you the beginning of the month.
totext(Date (year(currentdate),tonumber({@Current Month MM}) ,1 ))
Next create another formula called @Current Year yyyy
Year(Name.JOIN_DATE)
Next, create a formula called @DaysofMonth with the following logic:
if tonumber({@Current Year yyyy}) mod 4 = 0 then
choose(month(date({@Current Month Start Date})),31,29,31,30,31,30,31,31,30,31,30,31) else
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Lastly create a formula called @Ending Date of Month
totext(Date (year(currentdate),tonumber({@Current Month MM}) ,{@DaysOfMonth} ))
I hope this information proves useful.
Regards,
Zack H.
Edited by: Zack H on Feb 3, 2009 5:34 PM
Edited by: Zack H on Feb 3, 2009 5:38 PM

Last day of previous month, first day of current month

Hi,
Whats the best way to calculate the last date of the previous month, and the first day of the current month.
Thank you for your help.
Sumit.

Here are FMs
SG_PS_GET_LAST_DAY_OF_MONTH    FM calculating the last day of a month
FVOZ
RE_LAST_DAY_OF_MONTH
HRHCP00_TIME_HANDLING
HR_HCP_GET_LAST_DAY_OF_MONTH
HRVE_REPORTING
HRVE_LAST_DAY_OF_MONTH
RPDD                           HR-D: Payroll Germany
RP_LAST_DAY_OF_MONTHS          HR-D: Determine last day of month
SLS0                           PAW - Miscelaneous (MISC)
SLS_MISC_GET_LAST_DAY_OF_MONTH FM calculating the last day of a month
VVSRCH
LAST_DAY_OF_MONTHS
BWSO_DATE_GET_FIRST_WEEKDAY
CKSO
CK_F_GET_FIRST_DAY_OF_DATE
HRBEN00SPENDA
HR_BEN_SPENDA_FIRST_LAST_DAY
HRPB
HRPP_CCODE_GET_FIRSTDAY_PERIOD
HRVE_PAYROLL
HRVE_GET_FIRST_LAST_MONDAY
JBT6
ISB_GET_FIRST_DAY
KED2
RKE_GET_FIRST_DAY_IN_PERIOD
MCP2
MC_PERIOTAB_BT_FIRST_LASTDAY
MC_PERIO_GET_FIRST_AND_LASTDAY
Thanks
SK

To get first day and last day of month.

Please help, I need a sql function that will return the first day of a month when I enter a date that is on or before the 15th and then returns the last day of the month when I enter a date of the 16th or later.
This is my query but I get ORA-00932: inconsistent datatypes: expected DATE got CHAR error.
select CASE
WHEN to_char(:p_date, 'DD') < 15 THEN
add_months((LAST_DAY(:p_date)+1), -1)
WHEN to_char(:p_date, 'DD') > 15 THEN
TO_CHAR(LAST_DAY(:p_date))
end
from dual;
Thanks

Hi,
please use the good habit to mark your questions as answered when you are satisfied with the answers.
Additionally when you put some code or output please enclose it between two lines starting with {noformat}{noformat}
i.e.:
{noformat}{noformat}
SELECT ...
{noformat}{noformat}
Regards.
Al

Day must be between 1 and last day of month

Hi
I have a master detail form for overtime entries.
Master Block contain emp_no,name,month etc.
Detail block contain a date field ,,from time, to time etc
when i enter the date in detail block it defaults the month from Server date and i am getting the error "Day must be between 1 and last day of ...."
The form is going to reside on server so i cant go for changing system date for that.
THe work around i am trying is i have created a dummy item in detail block for Date(dd) entry and populating my original date field on the basis of it.
so that i can get rid of last day validation of month.The datatype of dummy item is char
my code is
c_day varchar(2);
c_month varchar(2);
c_year varchar(4);
d_date varchar(8);
begin
c_day := :DETAIL.dummy;
c_month := to_char(:MASTER.month, 'mm');
c_year := to_char(:master.month, 'yyyy');
d_date := c_day||c_month||c_year;
:DETAIL.ot_date := to_date(d_date,'ddmmyyyy');
end;
I am using post change trigger on my dummy item but i am getting ORA-01840 for that.I have tried several ways but it is giving different type of date errors for that.
Any help is highly appreciated

Dear try this
SELECT RUN_NUM, CV AS MONTH_DATE
FROM
SELECT ROWNUM AS RUN_NUM,TO_DATE('01-' || 'SEP' || '-' || 2007 ,'DD/MM/YYYY')+ (ROWNUM-1) CV
FROM
(SELECT 1 FROM DUAL GROUP BY CUBE (1,1,1,1,1)) A
WHERE TO_CHAR(CV,'MON-YYYY') = 'SEP-2007'

Get first and last day given month name with combobox

hi guys ;
I loaded to month name in combobox and I want to get first and last day by the name of month from selected Combobox
So if I select to february than results get 01.02.2015 and 28.02.2015
if select March than 01.03.2015 and 31.03.2015
Thanks .

Thank you for useful post , How to change Culturinfo as a Turkish Month name ?
your's code is work if I use English month name But it was get error when use the turkish month name
If you are running your application on a Turkish Windows you could use the System.Globalization.CultureInfo.CurrentCulture:
int month = DateTime.ParseExact(monthName, "MMMM", System.Globalization.CultureInfo.CurrentCulture).Month;
Or you could use create an explicit culture object like this:
System.Globalization.CultureInfo ci = new System.Globalization.CultureInfo("tr-TR");
int month = DateTime.ParseExact(monthName, "MMMM", ci).Month;
Please remember to mark all helpful posts as answer to close your threads.

ORA-01847: day of month must be between 1 and last day of month error

Hi All
When i run the following code i'm getting the error:ORA-01847: day of month must be between 1 and last day of month error
SELECT t2.owner_cat,
t1.owner_id,
stock_id,
Sum(received_amount) received_amount,
Sum(curr_amount) curr_amount,
Sum(used_amount) used_amount,
To_char(Add_months(date_work,6),'YYYY') date_work
FROM (SELECT owner_id_to owner_id,
stock_id_to stock_id,
Sum(full_amount) received_amount,
0 curr_amount,
0 used_amount,
To_char(0) date_work
FROM dw_wms_mat_transfer
WHERE master_code_id IN ('8664','8665')
GROUP BY owner_id_to,
stock_id_to
UNION ALL
SELECT owner_id,
stock_id,
0 received_amount,
Sum(curr_amount) curr_amount,
0 used_amount,
To_char(0) date_work
FROM dw_wms_mat_inv
WHERE master_code_id IN ('8664','8665')
GROUP BY owner_id,
stock_id
UNION ALL
SELECT t2.owner_id,
t1.stock_id,
0 received_amt,
0 curr_amt,
Sum(amount) used_amt,
To_char(Add_months(date_work,6),'YYYY') date_work
FROM dw_wms_wo_mat_dc t1,
(SELECT owner_id,
stock_id
FROM dw_wms_mat_inv
WHERE master_code_id IN ('8664','8665')
GROUP BY owner_id,
stock_id) t2
WHERE t1.stock_id = t2.stock_id
GROUP BY t2.owner_id,
t1.stock_id,
To_char(Add_months(date_work,6),'YYYY')) t1,
dw_wms_setup_owner t2
WHERE t1.owner_id = t2.owner_id
GROUP BY t2.owner_cat,
t1.owner_id,
stock_id,
To_char(Add_months(date_work,6),'YYYY')
But when i just run the inner query:
(SELECT owner_id_to owner_id,
stock_id_to stock_id,
Sum(full_amount) received_amount,
0 curr_amount,
0 used_amount,
To_char(0) date_work
FROM dw_wms_mat_transfer
WHERE master_code_id IN ('8664','8665')
GROUP BY owner_id_to,
stock_id_to
UNION ALL
SELECT owner_id,
stock_id,
0 received_amount,
Sum(curr_amount) curr_amount,
0 used_amount,
To_char(0) date_work
FROM dw_wms_mat_inv
WHERE master_code_id IN ('8664','8665')
GROUP BY owner_id,
stock_id
UNION ALL
SELECT t2.owner_id,
t1.stock_id,
0 received_amt,
0 curr_amt,
Sum(amount) used_amt,
To_char(Add_months(date_work,6),'YYYY') date_work
FROM dw_wms_wo_mat_dc t1,
(SELECT owner_id,
stock_id
FROM dw_wms_mat_inv
WHERE master_code_id IN ('8664','8665')
GROUP BY owner_id,
stock_id) t2
WHERE t1.stock_id = t2.stock_id
GROUP BY t2.owner_id,
t1.stock_id,
To_char(Add_months(date_work,6),'YYYY'))
I'm not getting that error, any help please?

Hi,
Like Anuraq already explained, you need to keep in mind that when you apply a to_char, you've turned your DATE datatype into a STRING and by doing that you've lost the ability to use the add_months function again in your outer query.
Using a simplified example, extracted from your example:
MHO%xe> select to_char(add_months(date_work, 6), 'yyyy') date_work
2 from ( select to_char(0) date_work
3         from dual
4         union all
5         select to_char(0) date_work
6         from dual
7         union all
8         select to_char(add_months(sysdate, 6), 'yyyy') date_work
9         from dual
10       );
select to_char(add_months(date_work, 6), 'yyyy') date_work
FOUT in regel 1:
.ORA-01847: day of month must be between 1 and last day of monthHowever, you should either do something like:
MHO%xe> select nvl(to_char(add_months(date_work, 12), 'yyyy'), '0') date_work
2 from ( select to_date(null) date_work
3         from dual
4         union all
5         select to_date(null) date_work
6         from dual
7         union all
8         select sysdate date_work
9         from dual
10       );
DATE
0
0
2010or (less clear, more confusing):
MHO%xe> select nvl(to_char(add_months(date_work, 6), 'yyyy'), '0') date_work
2 from ( select to_date(null) date_work
3         from dual
4         union all
5         select to_date(null) date_work
6         from dual
7         union all
8         select add_months(sysdate, 6) date_work
9         from dual
10       );
DATE
0
0
2010It's not clear to me why you're using add_months twice (inner + outer query) in your original example.
As you can see you can get the same results using it only once in your outer query.

Need to find the last day of the previous month

hi folks,
the code goes like this...
data: xt247 type t247,
      monthn(30) type c,
      monthnumber type i,
      bforwardmonth type i.
call function 'RP_LAST_DAY_OF_MONTHS'
EXPORTING
    day_in            = s_date
IMPORTING
    last_day_of_month = e_date.
write: 'The last day of the month', e_date.
select single * from t247 into xt247
        where spras = sy-langu
          and mnr = e_date+4(2).
monthnumber = xt247-mnr.
write:' The month number', monthnumber.
determine the previous month.
bforwardmonth = monthnumber - 1.
From here I need to determine the last day of the previous month How can I do?
Thanks for your help.
Santhosh

Hi all,
here's the shortest solution:
REPORT z123.
PARAMETERS p_datum LIKE sy-datum DEFAULT sy-datum.
DATA ultimo LIKE sy-datum.
<b>ultimo = p_datum - p_datum+6(2).</b>
WRITE: / p_datum, 20 ultimo COLOR 2.
it's not my solution :
it's from <a href="http://www.abapforum.com/forum/viewtopic.php?t=1434&highlight=ultimo">Andrew_</a>
regards Andreas

Help: Last Month Last Day till 12:00:00 PM

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