Help me join these two scripts please!

hello, I have two statements
      SELECT
   --distinct
         a.address_line3
        ,a.address_line4
        ,a.address_line5
        ,a.post_code
        ,a.tel_no
        ,l.claim_no
        ,lpad(row_number() OVER(ORDER BY l.claim_no), 6, '0') AS snum
        ,l.input_title
        ,l.input_surname
     ,l.INPUT_HOUSE_NO
     ,l.INPUT_BUILDING
     ,l.INPUT_FLAT
        ,l.input_address_line1
        ,l.input_address_line2
        ,l.input_address_line3
        ,l.input_address_line4
        ,l.input_post_code
        ,to_char(sysdate, 'MON YYYY') AS prntdate
     ,l.input_title AS input_title2
     ,l.input_surname AS input_surname2
     ,h.lpa_amt
     ,h.START_DATE
     ,h.elig_rate
     ,h.rate_rebate
     ,h.rr_amt
     ,h.lpa_applic
     ,h.lpa_amt AS lpa_amt2
     ,a.sho_name
        FROM lpa_input l, lpa_address a, lpa_history h, lpa_credhist_ha c
     wHERE a.aun_code = l.input_aun_code
     AND l.claim_no = h.claim_no
     AND h.claim_no = c.claim_no
     and ent_seqno = (select max (ent_seqno) from lpa_history where claim_no = l.claim_no)
SELECT DISTINCT CLAIM_NO FROM LPA_HISTORY
WHERE DATE_created > '01/APR/2009' AND CLAIM_NO NOT IN
(select CLAIM_NO from lpa_notifications)
ORDER BY CLAIM_NOCan i put this select statment at the end of the first script??
Thanks

Hi try this
SELECT
distinct
a.address_line3
,a.address_line4
,a.address_line5
,a.post_code
,a.tel_no
,l.claim_no
,lpad(row_number() OVER(ORDER BY l.claim_no), 6, '0') AS snum
,l.input_title
,l.input_surname
,l.INPUT_HOUSE_NO
,l.INPUT_BUILDING
,l.INPUT_FLAT
,l.input_address_line1
,l.input_address_line2
,l.input_address_line3
,l.input_address_line4
,l.input_post_code
,to_char(sysdate, 'MON YYYY') AS prntdate
,l.input_title AS input_title2
,l.input_surname AS input_surname2
,h.lpa_amt
,h.START_DATE
,h.elig_rate
,h.rate_rebate
,h.rr_amt
,h.lpa_applic
,h.lpa_amt AS lpa_amt2
,h.CLAIM_NO
,a.sho_name
FROM lpa_input l, lpa_address a, lpa_history h, lpa_credhist_ha c
WHERE a.aun_code = l.input_aun_code
AND l.claim_no = h.claim_no
AND h.claim_no = c.claim_no
AND ent_seqno = (select max (ent_seqno) from lpa_history where claim_no = l.claim_no)
AND DATE_created > '01/APR/2009' AND CLAIM_NO NOT IN
(select CLAIM_NO from lpa_notifications)
ORDER BY h.CLAIM_NONOTE: not tested.

Similar Messages

Joining these two queries

I have two queries. The First one is long but very simple. All it has is long list of columns.
First one:
SELECT CL.CLIENT_ID, CA.CASE_ID, to_char(SYSDATE,'RRMMDD'),
CL.MASTER_CLIENT_ID,
CL.NAME1,
nvl(CL.NAME2,' '),
nvl(CL.ADDRESS1,' '),
nvl(CL.ADDRESS2,' '),
CL.POCO_POSTAL_CODE, nvl(CL.CITY,' '),
nvl(CL.AUTO_SURV_CODE,0),
CA.Col_Collector_Id
FROM CLIENT CL, CASES CA
WHERE CA.CL_CLIENT_ID = CL.CLIENT_ID AND
CA.CASE_ID = :current_case_id
Second one:
SQL SELECT nvl(REF_NO,' '), nvl(to_char(DATE_OF_JUDGEMENT,'rrmmdd'),' ')
FROM CASE_INSTANCES
WHERE IN_INSTANCE_TYPE IN (1,8) AND
CA_CASE_ID = :current_case_id AND
PETITION_DATE = (SELECT max(PETITION_DATE)
FROM CASE_INSTANCES
WHERE IN_INSTANCE_TYPE IN (1,8)
AND CA_CASE_ID = :current_case_id
AND ROWNUM < 2 );
The :current_case_id is passed as a parameter. The table in the second query i.e. CASE_INSTANCES is related to the first query with the CA_CASE_ID. Not all records fetched by the first query have a record in the second query. So you might have to use a LEFT JOIN or something. trying to join these two has worn me out. Please help me out someone.

Hi,
Simplified Solution:
SELECT * FROM (
                    SELECT CL.CLIENT_ID, CA.CASE_ID, TO_CHAR(SYSDATE,'RRMMDD'),
                    CL.MASTER_CLIENT_ID,
                    CL.NAME1,
                    NVL(CL.NAME2,' '),
                    NVL(CL.ADDRESS1,' '),
                    NVL(CL.ADDRESS2,' '),
                    CL.POCO_POSTAL_CODE, NVL(CL.CITY,' '),
                    NVL(CL.AUTO_SURV_CODE,0),
                    CA.Col_Collector_Id
                    FROM CLIENT CL, CASES CA
                    WHERE CA.CL_CLIENT_ID = CL.CLIENT_ID ) a,
                    (SELECT NVL(REF_NO,' '), NVL(TO_CHAR(DATE_OF_JUDGEMENT,'rrmmdd'),' '),CA_CASE_ID
                         FROM CASE_INSTANCES
                         WHERE IN_INSTANCE_TYPE IN (1,8) AND
                         CA_CASE_ID = :current_case_id AND
                         PETITION_DATE = (SELECT MAX(PETITION_DATE)
                                                  FROM CASE_INSTANCES
                                                  WHERE IN_INSTANCE_TYPE IN (1,8)
                                                  AND CA_CASE_ID = :current_case_id
                                                  AND ROWNUM < 2
                    ) b
WHERE a.case_id = b.ca_case_id(+)
Regards
K.Rajkumar

Need help on combining these two program

Hi all,
I needed some help on combining these two program. But i not very sure how to do it.
My program in working with TimeIn/TimeOut attendance taking. The snippet vi "insert data" is the where i start to TimeIn and insert into the microsoft access. And i wanted to insert it together with a camera catching the user's face. But i have no clues on how to combine them.
Can u guys give me some ideas to help me ?
Thanks in advance.
Attachments:
IMAQdx.png ‏55 KB
insert data.png ‏68 KB

Hi Himanshu,
But if i put everything inside the IMAQdx loop ,it make my whole program more complicated.
This is how my program looks like below.
I only want to display the image only when i "insert" all data into the database ( which i given at the perivous post).
Is there other way?? And how do u make the IMAQdx loop stop without putting a stop button?? Because everytime i run the program,it will run continuously at the IMAQdx loop..
Thank in Advance.
Attachments:
FYP.png ‏205 KB

How to join these two queries

Hi experts,
I need to join two queries but not sure how:
select id from test_table1;
select *
from table(f_function(null
                       ,null
                       ,1 -- the id
                       ,sysdate);One query has IDs needed to run the second query. Is there a way to join those two?
The result should be all columns from test_table1 + all columns from f_function.
Best regards,
Igor
Edited by: Igor S. on Mar 8, 2013 5:18 AM

Hi,
Igor S. wrote:
select *
from test_table1,
table(
f_function(
null,
null,
id,
sysdate
select *
from test_table1,
table(
f_function(
null,
null,
id,
sysdate
) xyz
where test_table1.id = xyz.id
/So these two queries are the same?Try it and see.
You'll find that the 2nd one produces an error. But if you change it to
select *
from test_table1,
        table(
              f_function(
                         null,
                         null,
                         id,
                         sysdate
                        )      -- No alias here
             ) xyz             -- Alias here, instead
where test_table1.id = xyz.id
/Then, assuming f_function produces a column called id, it will work.
Whether it produces the same results or not depends on what the function returns, and whether either id is NULL.
If the id column that the function returns is the same as the id value that you pass to it, and is never NULL, then the 2 queries will produce the same results.
Either way, each row of test_table1 will be joined to each row that the function produces with the argument(s) from that row. The column names produced by the function and the values in those columns are determined by the function; they do not need to have anything in common with any table. In practice, a function like f_function will usually not return an column that is always identical to any of its inputs, since that value is already available from the input.

MODS: PLEASE MERGE THESE TWO THREADS PLEASE

My thread came first (POST 4.3 issues) but in any event these two similar threads should be merge please, and thank you.
http://discussions.info.apple.com/thread.jspa?threadID=2779105&tstart=0
http://discussions.info.apple.com/thread.jspa?threadID=2777224&start=0&tstart=0

Hi,
Your Profile will give you the number that is you - 1,406,710 in the URL bar and that was 2 and half years ago
This Poster registered today (2th March 2011) and the number is already up to 2,558,089 (1,151,379 new people in that time)
I used someone I came across today that has very little info to look at in their Profile.
Obviously very low numbers in a profile relate to people who registered very early in the life of Apple Discussions (With some tweaks when the Jive Software was Implemented - for some reason I ended up with 208)
Also just as obvious is the fact that not everyone who has ever registered still posts. But many that are posting take several posts to get to a satisfactory conclusion.
You get the idea.
10:01 PM Sunday; March 20, 2011
Message was edited by: Ralph Johns (UK)

Help in joining of two tables

Hi, I want to join table #1 and #2 and want to get results from #1 but want to include all timelines of #1 and #2 in results. Please help on this query. Thanks.
create table #1 (code_p char(4), code_h char(2), code_date datetime, Area char(2), agent char(5))
insert into #1 values ('DEHG','2','1901-01-01','AF','ST')
insert into #1 values ('DEHC','3','1901-01-01','AG','ST')
insert into #1 values ('DEHL','1','1901-01-01','AS','GT')
create table #2 (code_p char(4), code_h char(2), code_date datetime)
insert into #2 values ('DEHG','2','1901-01-01')
insert into #2 values ('DEHG','2','2010-01-01')
insert into #2 values ('DEHC','3','1901-01-01')
insert into #2 values ('DEHC','3','2010-01-01')
insert into #2 values ('DEHC','3','2011-01-01')
insert into #2 values ('DEHL','1','1901-01-01')
Select * from #1 a
join #2 b on a.code_p = b.code_p and a.code_h = b.code_h and
a.code_date = b.code_date
--Expected output
code_p code_h code_date Area agent
DEHG 2 1901-01-01    AF ST
DEHG 2 2010-01-01     AF ST
DEHC 3 1901-01-01    AF ST
DEHC 3 2010-01-01     AF ST
DEHC 3 2011-01-01     AF ST
DEHL 1 1901-01-01    AF ST

--Your Query
Select a.code_p, a.code_h, b.code_date, a.Area, a.agent from #1 a
join #2 b on a.code_p = b.code_p and a.code_h = b.code_h and
a.code_date = b.code_date
--YOUR Query OUTPUT
DEHG 2
1901-01-01 00:00:00.000
AF ST
DEHC 3
1901-01-01 00:00:00.000
AG ST
DEHL 1
1901-01-01 00:00:00.000
AS GT
Can you try this
select A.code_p,A.code_h,B.code_date,A.Area,A.agent from #1 A
join #2 B on A.code_h = b.code_h
where A.code_h in (3,2,1)
DEHG 2
1901-01-01 00:00:00.000
AF ST
DEHG 2
2010-01-01 00:00:00.000
AF ST
DEHC 3
1901-01-01 00:00:00.000
AG ST
DEHC 3
2010-01-01 00:00:00.000
AG ST
DEHC 3
2011-01-01 00:00:00.000
AG ST
DEHL 1
1901-01-01 00:00:00.000
AS GT
Please Mark This As Answer if it helps to solve the issue

Could I have some help with making these two files merge?

Copyright - Trademarking - Prohibiting further use of these files (Unless you are helping me) - Etc..
Hello, I'm back with another problem and if you read the last post you would have realized that I shortened the code. My goal is to replace my spacer and header with a single header that I based my design around. I just can not get this too work with the rest of the document I have had too many attempts. I will post my header files in 'RED' to begin with and the files I need to combine in 'BLUE'
Preview of Header:
Link to the Header HTML Coding:
Expertpcguides.com
Link to CSS Coding of the Header:
http://www.expertpcguides.com/css/header-styling.css
Example of one of the Html pages that I need to merge:
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Thanks for the help in advance.

You're not getting any help because your HTML & CSS code is pretty messy. It's like asking an interior designer to make over a very untidy bedroom. It's not going to happen until you clean things up.
I would start with just the basic HTML code like this. Avoid those redundant style10, style19, style108 tags.    You really don't need them. HTML selectors provide you with all the hooks you need for most things. Also, you should run a spell check. I saw errors but I didn't fix them.
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<style>
/**CSS RESET**/
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img { vertical-align: bottom }
ol, ul { list-style: none; }
/**LAYOUT STYLES**/
body {margin:0;}
header {margin:0; }
header h1 {}
header h2 {}
/**top nav**/
nav { margin: 4% }
nav li { display: inline }
nav li a {
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nav li a:visited { }
nav li a:hover, nav li a:active, nav li a:focus { }
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section.top li {
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section.top li:after {content: '| ';}
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Help in join of two tables

Hi,
I have following 2 tables
CREATE TABLE a
sr_no INT
CREATE TABLE b
sr_no INT,
startdate DATE,
remark VARCHAR2(30)
One to many mapping relationship exists between the two tables.
for each sr_no in table a ther exists multiple/no record in table b.
If there are multiple entries in table b for a single entry in table a,
then i want remark data which is corresponding to minimum of the startdate in table b
Example data of table b
1     10/15/2009     one
1     10/29/2009     one1
2     10/28/2009     two
3     10/27/2009     three
4     10/26/2009     four
minimum date of the first 2 records is 10/15/2009.so i want remark as "one" when i join the 2 tables.
How do we achieve that ?

Something like this?
SELECT SUB.SR_NO
,       SUB.STARTDATE
,       B.REMARK
FROM
        SELECT SR_NO
        ,       MIN(STARTDATE) AS STARTDATE
        FROM   B
        GROUP BY SR_NO
)       SUB
JOIN    B       ON B.SR_NO = SUB.SR_NO AND B.STARTDATE = SUB.STARTDATEThat is one possibility. There are many, many ways to achieve this kind of result.

Can anyone join these two into one?

<?if:1=1?>Page 1<?end if?><?if:1!=1?>Other Page<?end if?>
<?fo:page-number?>
I want to replace the first 1 with the page number function...
Please help me, I'n running out of time.

Hi Tim,
I don't think it is important which functionallity I want to achieve. My real question is: can I use a function (like <?fo:page-number?> in a function (like <?if:?>).
Kind regards,
Corné

Help with search and replace script please

Hi all
I've written a javascript which uses various GREP and text find/changes to copy some text from the first two paragraphs of a document and use them elsewhere (in the running head and footers) and now I want to delete the first two paragraphs. Not sure how I would do that. If I was doing a manual find/change (with nothing selected) it would automatically select the first para in the first text box but when I run teh following;
app.findGrepPreferences.findWhat = "^.+$";
app.changeGrepPreferences.changeTo="";
app.activeDocument.changeGrep();
it finds all paragraphs and deletes them. I was going to include the code twice; once to delete the first paragraph and then again to delete the other (new first) paragraph. My JS skills are shaky but I'm quite comfortable with GREP. Can anyone point me in the right direction for how I acheive what I want? If I did a for loop surely I'd just be doing the same thing but more than once!
Much to my surprise the rest of the script is working although it made my brain hurt!
thanks for any suggestions,
Iain

Oooh. After
myStory=app.activeDocument.stories.everyItem();
the variable "myStory" won't point to just a single story, but ... to "every story". So that's why the next line removes more than you intended!
What the "everyItem" thingy internally does is still unclear to me, but that doesn't keep me from using it -- but only when you absolutely, positively want to perform an action on every item
Now the usual examples say something like
myStory = app.activeDocument.stories.item(0); // access first story
but that's No Good. Even if your first story is the one you are targeting today, tomorrow, in a different document, it'll be story #1, or #5, or #255. There is no general rule that states the first story is always the largest one, or something like that.
If this is going to be used with a document template, the best way to identify the target story is by giving the first text frame a unique label. Otherwise, you'll have to think of something else ... A couple of other strategies:
1. You are already using GREP to find stuff. If one of those searches is guaranteed to return just text in the one story you are interested in, you can use this.
2. You mention headers and footers. If your main text is the only one that runs through multiple text frames, you can loop over all stories and check which one runs through than a single text frame.
3. ... (I'm pretty sure there are some more strategies ...)

Doubt on creating join between two tables

Hi friends,
I have two tables , ekes and eine
my requirement is if Ekes-ebtyp = 'X1'.
then Ekes-ebtyp = EKES-EINDT + Eine-j_3alitra.
the doubt is there is no primary key common between this table . actually in my whole program for purchase order i used EBELN for extracting details when two tables are involved . in this two tables no two primary keys are common to extract data ...is there any ways please suggest..
the code i wrote is
loop at li_ekes assigning <fl_ekes>.
read table li_eine assigning <fl_eine> with table key (here i need to give some unique fields to join these two fields please guide me which field i can use.).
<fl_ekes>-ebtyp = <fl_ekes>-EINDT + <fl_eine>-j_3alitra.

Hi,
Both tables have field EBELN in common.
You can use it to extract data from both.
Hope this helps.
reward if helpful.
Regards,
Sipra

Please help me to correct the script

I try to write a script by my slef, but not work
app.findGrepPreferencest = firstLineIndent:8, leftIndent:8;
app.changeGrepPreferences = firstLineIndent:8, leftIndent:16;
app.changeGrep();
app.findGrepPreferences = app.changeGrepPreferences = null;
Can someone please help me to correct the script, please.

both two script are working
but waht if I change the script into this format?
function(){
app.findGrepPreferences.firstLineIndent = "8 mm";
app.findGrepPreferences.leftIndent = "8 mm";
app.changeGrepPreferences.firstLineIndent = "8 mm";
app.changeGrepPreferences.leftIndent = "16 mm";
app.selection[0].changeGrep();
app.findGrepPreferences.firstLineIndent = "8 mm";
app.findGrepPreferences.leftIndent = "16 mm";
app.changeGrepPreferences.firstLineIndent = "8 mm";
app.changeGrepPreferences.leftIndent = "24 mm";
app.selection[0].changeGrep();
and then so on,
Can it works?

Need help in join

hi,
Following are my columns data in same table,
Value1 Value2
1 1
2 2
3 4
1 3
My output sould be as like follows
value
1
2
3
4
so please help me on this logc by proving sample query

Hey or in other way i will explain my requirment,
i have two reslutset,
result set A and result set b. i want to join both the result set and bring the output as follows.
resultA
1
2
3
1
resultB
1
2
3
4
ned to join these two results and bring the out put as follows
result:
1
2
3
4
i given my requirement in last post bit wrongly, the above requirement is correct. can u pls help me now

Help with Join

All,
How to join inv.mtl_category_sets_tl and ibe.msites_b. I am having trouble to find which tables i need to join these two tables
I am not getting right mini site id for the caterogy set name
Your help is highly appreciated
Regards
Edited by: 792011 on Sep 12, 2011 12:49 PM

792011 wrote:
Hi Bravid,
11110 is the site_id for ABC Catalog and same thing for 11111 DEF Catalog. These two are different websites
RegardsOkay so why do you have an entry for 11110 DEF and an entry for 11111 ABC in your source data? Where in your source data is there anything that identifies 11110 as site ABC - i.e. is there another attribute here or are you just planning to hard code it?
David

Join on two tables using "LIKE"

Hi all,
I need make join on two tables (QMEL and STXL) using keys for connection:
- field for join of first table is (QMEL-QMNUM - Notif. number - Char 12)
- field for join of second table is (STXL-TDNAME - Char 70)
If it is connection based on EQ, I think, it's no problem but I need to connect it on base of 'LIKE'.
Example:
QMEL-QMNUM = '100100698075'
I would like get all rows from STXL which contain or even better start with notif. number.
Examples I would like connect with QMEL-QMNUM:
STXL-TDNAME = '100100698075'
STXL-TDNAME = '1001006980750001'
STXL-TDNAME = '10010069807500010001'
STXL-TDNAME = '10010069807500010002'
etc..
Am I able to manage that with select which join these two tables this way?
Thanks for any solution
Vaclav Hosek.

Hi,
Write 2 separate selects for this.
select * from QMEL
where......
if sy-subrc = 0.
loop at i_qmel into wa.
r_tdname-option = 'CP'.
r_tdname-sign = 'I'
concatenate wa-qnum '*' into r_tdname-low.
append r_tdname.
endloop.
select *
from STL
where tdname in r_tdname.
endif.

Help me join these two scripts please!

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