Help with if/else in displaying data - (possibly foreach)

Question

Hello all,
I've been trying to set something up, and I'm having difficulty getting it to work.
Lines 84-111 have become my biggest difficulty.  I've got an if/else statement set up so that if one record has an image located on the localhost that image is pulled up.  The way I have it now, this works great.
If I swap lines 93-96 with 102-105, and just tweek line 90, I can get it to work if the image is located on an alias and not the localhost.
The problem is that if I have it like it is now, I can't get both to work at the same time.  So, I'm trying to get the if/else statement to apply to each record that is being pulled up.  It seems like what it is doing now is choosing which part of the if/else statement it needs to use for the first record, and then applies that for all records.
Is there a way to have it coded like it is now for the if/else statement (because I want to be able to add multiple alias' and just check to see if the image is on the localhost or not); but have the image be displayed no matter if the image is located on the localhost or an alias?
The following is what I've got so far:
<?php
$search = $_GET['series'];
$query_begin=" SELECT * FROM movies WHERE movie_name_series = '$search' ";
$search_begin = mysql_query($query_begin) or die(mysql_error());
$row_begin = mysql_fetch_assoc($search_begin);
if($row_begin == 0){
?>
<script type="text/javascript"><!--
setTimeout('Redirect()',0000);
function Redirect()
  location.href = 'index.php?content=noresult';
// --></script>
<?php
else
                $query_display = "SELECT * from series WHERE series_id = '$search'";
       $result_display = mysql_query($query_display);
       $row_display = mysql_fetch_array($result_display, MYSQL_ASSOC);
          $series_id = $row_diaplay['series_id'];
          $series_name = $row_display['series_name'];
    ?>
<h2>All Movies in our Library categorized in the series <?php echo $series_name ?></h2>
<br />
<div style="float: left; width: auto">
    Click on the name of the movie to edit the movie.
</div>
     <br />
        <hr size="1" noshade="noshade" />
  <br />
<?php
$query="SELECT * FROM movies
  INNER JOIN family_rating ON movies.movie_star_rating=family_rating.star_id
  INNER JOIN alias ON movies.alias=alias.alias_id
  INNER JOIN parent_alert ON movies.parent_alert=parent_alert.alert_id
  INNER JOIN rating ON movies.movie_rating=rating.rating_id
  WHERE movies.movie_name_series='$search'
  ORDER BY movies.movie_name ASC";
$result= mysql_query($query)or die (mysql_error());
while($row=mysql_fetch_array($result)){
// Display the data
?>
    <table width="200" style="margin: 20px">
    <tr align="center">
  <td valign="top">
   <h1 style="font-size: 12px"><?php echo $row['movie_name']; ?></h1>
        </td>
    </tr>
    <tr align="center">
  <td valign="top" style="width: 100%; border-bottom: ridge #FFF; border-left: ridge #FFF; background: url(assets/images/transback.png) repeat; padding: 10px">
   <a class="ToolText" onMouseOver="javascript:this.className='ToolTextHover'" onMouseOut="javascript:this.className='ToolText'">
   <style media="screen" type="text/css">
          #coverart {
            display: block;
            width: 110px;
            height: 150px;
          #coverart:hover {
            background: url("assets/icons/play_movie.png") no-repeat 0 0;
          background-size: 110px;
         </style>
        <p>
         <form action="index.php?content=play_movie" method="post">
            <input type="hidden" value="<?php echo $row['movie_id']; ?>" name="movie" />
         <input type="hidden" value="<?php echo $row['warning'] ?>" name="warning" />
                                    <?php
          if ($row['alias_name']='localhost') {
         ?>
                                    <input onmouseover='this.src="assets/icons/play_movie.png"'
                                     onmouseout='this.src="movies/coverart/<?php echo $row['art']; ?>"'
                                    type="image" src="movies/coverart/<?php echo $row['art']; ?>"
                                    style="border: none" height="150" width="110" />
                                    <?php
          }else{
           ?>
                                    <input onmouseover='this.src="assets/icons/play_movie.png"'
                                     onmouseout='this.src="http://<?php echo $row['ip_address']; ?>/<?php echo $row['alias_name']; ?>/coverart/<?php echo $row['art']; ?>"'
         type="image" src="http://<?php echo $row['ip_address']; ?>/<?php echo $row['alias_name']; ?>/coverart/<?php echo $row['art']; ?>"
                                    style="border: none" height="150" width="110" />
                                    <?php
          ?>
            </form>
                                    </p>
                                <span><h2 align="center"><?php echo $row['movie_name']; ?></h2>
        <?php echo $row['rating_name']; ?>
                                <h4><?php echo $row['description']; ?></h4>
        <?php
         if($row['parent_alert']='1') {
          ?>
        <p align"center"><img src="assets/icons/<?php echo $row['alert_file_name']; ?>"></p></span>
                                <?php
         } else {
         ?>
            </a>
            <img src="assets/icons/s_<?php echo $row['star_file_name']; ?>" />
        </td>
</tr>
    </table>
<?
?>
I've looked through a number of tutorials and it's been indicated to use a for each loop.  However, I can't seem to get this to work.  Is there anything I can do to get this to work the way I am trying to?  Is it a problem with my if/else or do I need a for each?  If I need a for each, how do I do that?
Thanks.

Answer 1

Thank you for your reply.  I apologize for not being as clear as I needed to be, so I'll try and explain better.
I've got a page that pulls up some records from a database, where I've got an if / else statement as part of the section where it displays the data.
                                    <?php
          if ($row['alias_name']='localhost') {
         ?>
                                    <input onmouseover='this.src="assets/icons/play_movie.png"'
                                     onmouseout='this.src="movies/coverart/<?php echo $row['art']; ?>"'
                                    type="image" src="movies/coverart/<?php echo $row['art']; ?>"
                                    style="border: none" height="150" width="110" />
                                    <?php
          }else{
           ?>
                                    <input onmouseover='this.src="assets/icons/play_movie.png"'
                                     onmouseout='this.src="http://<?php echo $row['ip_address']; ?>/<?php echo $row['alias_name']; ?>/coverart/<?php echo $row['art']; ?>"'
         type="image" src="http://<?php echo $row['ip_address']; ?>/<?php echo $row['alias_name']; ?>/coverart/<?php echo $row['art']; ?>"
                                    style="border: none" height="150" width="110" />
                                    <?php
          ?>
When the records are pulled, it seems like only the first part of the if / else statement is being applied to every record that is being pulled. The problem is if I've got records like the following:
Record one - (file on the host computer)
needs to be displayed from the condition
src="movies/coverart/<?php echo $row['art']; ?>"
Record two - (file on networked external hard drive)
needs to be displayed from the condition
src="http://<?php echo $row['ip_address']; ?>/<?php echo $row['alias_name']; ?>/coverart/<?php echo $row['art']; ?>
The way it's coded now, only record one will display the image (record two will not display the image).  If I swap the order of the conditions, only record two will display the image (record one will not display the image).
How do I get both record one and record two to display the image when both appear on the same page from a single search query?
If I still did not explain it well enough, please let me know and I will try and do better.  Again, thank you for your help.