Help with the sql
Table 2 is a subset of table 1. All the accounts in table2 are in table 1. Now i want all the accounts in table 1 which are not in table 2. I wrote a sql something like below but ended up getting all the accounts, i know it's because of the left outer join. I need some idea someone please help. Thank you.
select a.account from table 1 a
left outer join
( select account from table 2) turr on turr.account <> a.ccount
There are many ways to achieve that. Here are some ideas:
SELECT account FROM TABLE_1
MINUS
SELECT account FROM TABLE_2
SELECT account
FROM table_1
WHERE NOT EXISTS
( SELECT null
FROM table_2
WHERE table_2.account = table_1.account
SELECT account
FROM table_1
WHERE account NOT IN (SELECT account FROM table_2)
SELECT table_1.account
FROM table_1
LEFT JOIN table_2 ON table_1.account = table_2.account
WHERE table_2.account IS NULL
;
Similar Messages
-
Please help with the sql logic
The below is going to be a record set from for a view from the FROM CLAUSE
1. Find component DOCUMENT where the document type = Square Metres (DOC.UOM_STD_ID = 'METR_MTR) If any components are found, retrieve the Document records for these components ONLY.
2. Otherwise, if no components exist with a Document type = Square Metres, look for components with a Document type of Acres (DOC.UOM_STD_ID = 'ACRE'). If found, retrieve the Space Lease records for these components ONLY.
3. Otherwise, if the Document does not have components with a type = Square Metres or Acres, look for components with the type of (DOC.UOM_STD_ID = 'PARK'). Then retrieve the departments associated with these parking components.
For Space Lease records above, retrieve the associated Org ID (SPACE.SPORG).
Return all departments where
the associated Org Type (ORG.ORGCLASS) = 'NON'
or the associated Org Type (ORG.ORGCLASS) = 'GD'
Thank youmaybe something like:
SQL> select emp.empno, emp.ename, emp.deptno
2 from emp,
3 (select case when (select 1 from emp where deptno = 10 and rownum = 1) = 1 then 1
4 when (select 2 from emp where deptno = 60 and rownum = 1) = 2 then 2
5 else 3
6 end case_col
7 from dual) d1
8 where deptno = decode(d1.case_col,1,10,
9 2,60,
10 3,70);
EMPNO ENAME DEPTNO
7839 KING 10
7782 CLARK 10
7934 MILLER 10
SQL> in you code it will be something like:
select ...
from document t1,
(select case when (select 1 from document doc where DOC.UOM_STD_ID = 'METR_MTR' and rownum = 1) = 1 then 1
when (select 1 from document doc where DOC.UOM_STD_ID = 'ACRE' and rownum = 1) = 2 then 2
else 3
end case_col
from dual) d1
where t1.uom_std_id = decode(d1.case_col,1,'METR_MTR',
2,'ACRE',
3,'PARK',
null);note: untested -
Please Help with the sql below for hierarchies
Hi all.
I have a table named stg_org_hier whose data looks like this
i would like to build the hierarchy from BU,AREA,REGION,DISTRICT,TERR
There are data cyles in the data below
stg_org has this data
QTR_CD HIER_LVL_CD CURR_RDT_ID DISTRICT_RDT_ID
2007Q4 AREA E0F7B00000000 E0F7B00000000
2007Q4 BU E0F7B00000000 E0F7B00000000
2007Q4 AREA E0F7B40000088 E0F7B40000000
2007Q4 REGION N0F7B40400000 E0F7B40000000
2007Q4 REGION E0F7B40700000 E0F7B40000000
2007Q4 AREA E0F7B00000088 E0F7B00000000
2007Q4 AREA E0F7B40000000 E0F7B00000000
2007Q4 DISTRICT N0F6B40405C99 N0F7B40400000
2007Q4 REGION N0F7B40400088 N0F7B40400000
2007Q4 DISTRICT N0F7B40405M99 N0F7B40400000
2007Q4 TERR N0F1B40405201 N0F7B40405M99
they would like to see the output in the below in the below form
QTR_CD HIER_LVL_CD CURR_RDT_ID DISTRICT_RDT_ID
2007Q4 BU E0F7B00000000 E0F7B00000000
2007Q4 AREA E0F7B00000000 E0F7B00000000
2007Q4 AREA E0F7B00000088 E0F7B00000000
2007Q4 AREA E0F7B40000000 E0F7B00000000
2007Q4 AREA E0F7B40000088 E0F7B40000000
2007Q4 REGION E0F7B40700000 E0F7B40000000
2007Q4 REGION N0F7B40400000 E0F7B40000000
2007Q4 DISTRICT N0F6B40405C99 N0F7B40400000
2007Q4 REGION N0F7B40400088 N0F7B40400000
2007Q4 DISTRICT N0F7B40405M99 N0F7B40400000
2007Q4 TERR N0F1B40405201 N0F7B40405M99
Here is the sql i have written :
select curr_terr_rdt_id,district_rdt_id,hier_lvl_cd,level from STG_ORG_QTR_SF_HCHY
connect by prior
curr_terr_rdt_id=district_rdt_idqtr_cd,hier_lvl_cd,curr_rdt_id, district_rdt_id
2007Q4,BU, E0F7B00000000,E0F7B00000000
2007Q4,AREA, E0F7B00000000,E0F7B00000000
2007Q4,AREA, E0F7B00000088,E0F7B00000000
2007Q4,AREA, E0F7B40000000,E0F7B00000000
2007Q4,AREA, E0F7B40000088,E0F7B40000000
2007Q4,REGION, E0F7B40700000,E0F7B40000000
2007Q4,REGION, N0F7B40400000,E0F7B40000000
2007Q4,DISTRICT, N0F6B40405C99,N0F7B40400000
2007Q4,REGION, N0F7B40400088,N0F7B40400000
2007Q4,DISTRICT, N0F7B40405M99,N0F7B40400000
2007Q4,TERR, N0F1B40405201,N0F7B40405M99Not having a database at hand right now is helpful this time ;)
Indenting the data clearly shows that the hierarchy rules are being violated (cycles you are mentioning do not matter in this case):
Each node must have a unique predecessor except the root having none (in your case data on lines 3 and 4 both point to lines 1 and 2)
2007Q4,BU, E0F7B00000000,E0F7B00000000
2007Q4,AREA, E0F7B00000000,E0F7B00000000
2007Q4,AREA, E0F7B00000088,E0F7B00000000
2007Q4,AREA, E0F7B40000000,E0F7B00000000
2007Q4,AREA, E0F7B40000088,E0F7B40000000
2007Q4,REGION, E0F7B40700000,E0F7B40000000
2007Q4,REGION, N0F7B40400000,E0F7B40000000
2007Q4,DISTRICT, N0F6B40405C99,N0F7B40400000
2007Q4,REGION, N0F7B40400088,N0F7B40400000
2007Q4,DISTRICT, N0F7B40405M99,N0F7B40400000
2007Q4,TERR, N0F1B40405201,N0F7B40405M99Removing the first data line or changing it's curr_rdt_id will make hierarhical queries work (lines 1 and 2 would better not point to themself)
Regards
Etbin
Message was edited by: Etbin
user596003 -
Hi ALL,
Test_dpnt is a table.from this i want to find the total no.of applications
(ssc,ssa,ssb,ssd,map,maq,oet,oet)---total 8.
parent - 2(since oet is indepentdent)
children---4
independent-2
source_app is the parent applications
dpnt_app---child application of parent
source_app dpnt_app
ssc ssa
ssc ssb
ssc ssd
mad map
mad maq
oet oet
I want the output likethis
total parent child independent
8 2 4 2
How to write the sql for thisstill unclear to me on how you will be able to get the output as
total parent child independent
8 2 4 2based on the sample data you have posted below:
app_srce app_dpnt app_dpnt-typ-c
43 190 R
43 191 R
150 200 R
150 201 R
300 300 Rdo you mean by the output should look something like this:
srce count dpnt count
2 1
1
2 1
1
1 1or that it needs to count all the rows for each of the 3 columns -
Help with the SQL Query: How to use case.
Q:- I have written a query which will written the following output.
C1 C2 C3
a ---- b.1 ---- 1
a ---- b.1 ---- 1
a ---- b.1 ---- 2
a ---- b.1 ---- 3
a ---- b.1 ---- 3
a ---- b.2 ---- 1
a ---- b.2 ---- 2
a ---- b.2 ---- 2
a ---- b.3 ---- 1
ac---- b.1 ---- 1
ac---- b.1 ---- 2
ac---- b.2 ---- 1
ac---- b.2 ---- 2
ac---- b.2 ---- 3
ac---- b.2 ---- 3
ac---- b ---- 1
But i want the output to print in the following way. Please suggest.
C1 C2 C3
a ---- b.1 ---- 1
------------------2
------------------3
a ---- b.2 ---- 1
------------------2
a ---- b.3 ---- 1
ac---- b.1 ---- 1
------------------2
ac---- b.2 ---- 1
------------------2
ac---- b.2 ---- 3
ac---- b ---- 1
Edited by: user555994 on Jan 18, 2011 1:42 AM
Edited by: user555994 on Jan 18, 2011 1:43 AMOr may be
SQL> ed
Wrote file afiedt.buf
1 WITH sample_data AS
2 (SELECT 'a' C1,'b.1' C2, 1 C3 FROM dual UNION ALL
3 SELECT 'a' C1,'b.1' C2, 1 C3 FROM dual UNION ALL
4 SELECT 'a' C1,'b.1' C2, 2 C3 FROM dual UNION ALL
5 SELECT 'a' C1,'b.1' C2, 3 C3 FROM dual UNION ALL
6 SELECT 'a' C1,'b.1' C2, 3 C3 FROM dual UNION ALL
7 SELECT 'a' C1,'b.2' C2, 1 C3 FROM dual UNION ALL
8 SELECT 'a' C1,'b.2' C2, 2 C3 FROM dual UNION ALL
9 SELECT 'a' C1,'b.2' C2, 2 C3 FROM dual UNION ALL
10 SELECT 'a' C1,'b.3' C2, 1 C3 FROM dual UNION ALL
11 SELECT 'ac' C1,'b.1' C2, 1 C3 FROM dual UNION ALL
12 SELECT 'ac' C1,'b.1' C2, 2 C3 FROM dual UNION ALL
13 SELECT 'ac' C1,'b.2' C2, 1 C3 FROM dual UNION ALL
14 SELECT 'ac' C1,'b.2' C2, 2 C3 FROM dual UNION ALL
15 SELECT 'ac' C1,'b.2' C2, 3 C3 FROM dual UNION ALL
16 SELECT 'ac' C1,'b.2' C2, 3 C3 FROM dual UNION ALL
17 SELECT 'ac' C1,'b' C2, 1 C3 FROM dual
18 )
19 SELECT
20 NVL2(LAG(C1) OVER (PARTITION BY C1,C2 ORDER BY C1,C2,C3),NULL,C1) C1
21 ,NVL2(LAG(C2) OVER (PARTITION BY C1,C2 ORDER BY C1,C2,C3),NULL,C2) C2
22 ,C3
23* FROM (SELECT DISTINCT c1,c2,c3 FROM sample_data)
SQL> /
C1 C2 C3
a b.1 1
2
3
a b.2 1
2
a b.3 1
ac b 1
ac b.1 1
2
ac b.2 1
2
C1 C2 C3
3
12 rows selected.
SQL> -
Help with an SQL Query on the Logger
We are running UCCE 8.5(3) and need help with an SQL query. When I run the below I would also like to see skill group information(name preferably)? Any help would be greatly appreciated!
select * from dbo.t_Termination_Call_Detail where DateTime between '10-11-2012 00:00:00:00' and
'10-11-2012 23:59:59:59'David, thanks for replying. Unfortunitly I don't know enough about SQL to put that into a query and have it return data. Would you be able to give an example on what the query would look like?
-
Help with: java.sql.SQLIntegrityConstraintViolationException
Hi, guys
I need help with the following exception: java.sql.SQLIntegrityConstraintViolationException: The statement was aborted because it would have caused a duplicate key value in a unique or primary key constraint or unique index identified by 'SQL090403155751200' defined on 'BOOK_ORDER'.
the things is my primary key is unique, so i checked the indexes and i found that i have two 'SQL090403155751200' indexes.
I would like to know:
1. can i delete the index without causing further database problems
2. what causes this problem and how can i avoid it.
By the way im using netbeans 6.5 and derby databaserizza_99 wrote:
I would like to know:
1. can i delete the index without causing further database problems
2. what causes this problem and how can i avoid it.
By understanding what the application/system is supposed to be doing and the correctly creating indexes on the database that reflect the business needs.
Once you do that then the nature of the indexes that are needed are obvious.
You certainly don't delete indexes without that understanding however. -
I need help with the discoverer lineage.sql that allows hyper drill from V5 OWB Eul into OWB portal.
I am still on OWB 9.0.3 and seem to have a small version problem. the portal is up, and i can jump to portal reports from within the browser ok. I have created the eul definitions in disco using the bridge. the lineage work book is working but the url being generated is the wrong format for the portal.
Does anyone know how I can sort out the lineage url construction to parse the correct format?
thanks.
Richard.WOW! Nobody knows huh?
Well I'll let you know how I fixed it. Basically change the Disco Eul complex folder definition. After working out why the Url being contructed was wrong I changed the complex formula imbeded within the EUL object to parse the correct formula. And it now works. (I also added the hyperdrill for Impact analysis)
However the 9.03 repository is essentally a single table cmpallclasses and our table is huge. After getting the url parsing sorted, the actual underlying views were not returning data in a timely manner. Looking at the base table it has a single index, a quick bit 'o' tuning and having added three indexes my impact views return in under 2 mins which I am happy with. But my portal times out and spits out the no response from server which I think is an apache setting http.conf a generic time out. I am not sure why it may be a portal issue. I have set the owbportal to 1200 as a timeout, but something else is kicking in and killing the connex does anyone have a clue?
This is a big repository, I have around 1500 mappings now. Does anyone else have a production OWB repository of any real size?
Having sorted this out on 9.03, I am going to see how much I can apply to the 9.2 variant.
Thanks.
Richard. -
Help with Oracle SQL to strip unwanted characters
Hello,
I have 2 columns (Weight and Height) where I need to strip the alpha characters and convert them to numbers (I am required to derive additional columns where I need to present
these values in inches, cm, KG, LB, etc. (and thus the need to convert them to numbers). I am too much a novice to understand the best way to convert these columns into numbers (same precision as you see here).
See the image below for a sample of what these columns currently contain. I simply need help with the Oracle SQL code to parse/convert these vales into number. Thanks in advance for your assistance!
DaveHi,
In addition to
Erland Sommarskog's comment which is of course correct and this i not the forum to ask question about Oracle, I dont want to leave you without a lead :-)
The solution both in SQL Server and Oracle should based on Regular Expressions. I highly recommended NOT to use T-SQL solutions in this case, as mentioned above, unless this is a very small table and the need is very simple and include finding one point
in the string as in
SaravanaC solution (when he assume thge string format is based on 2 parts (1) Number + (2) unit type).
In Oracle there is a build in Regular Expressions option as mentioned here: http://docs.oracle.com/cd/B12037_01/appdev.101/b10795/adfns_re.htm
In SQL Server the PATINDEX is used for simple cases and there is no built in Regular Expressions, but you can add it using CLR as shown in this link http://msdn.microsoft.com/en-us/magazine/cc163473.aspx
[Personal Site] [Blog] [Facebook] -
What will I do with the SQL Server (2012/2014) (Standard/Enterprise) Licenses?
Are these the same as software product keys, or just some pieces of paper the company needs to have on hand?
In which case, when we install SQL Server 2014, (and when looked for videos) - there is only 1 product key value to be put in, is there some other screen in the setup to input the License bought ( in our case will be Core licenses).
So in addition to the Core Licenses do will a Product key be needed? Would product key from an msdn work, as it is the licenses that we will buy to indicate that we bought to run the software on server X?
Thanks for any indications.1. What will I do with the SQL Server (2012/2014) (Standard/Enterprise) Licenses?
Are these the same as software product keys, or just some pieces of paper the company needs to have on hand?
2. In which case, when we install SQL Server 2014, (and when looked for videos) - there is only 1 product key value to be put in, is there some other screen in the setup to input the License bought ( in our case will be Core licenses).
3. So in addition to the Core Licenses do will a Product key be needed? Would product key from an msdn work, as it is the licenses that we will buy to indicate that we bought to run the software on server X?
Thanks for any indications.
I will answer your question point wise
1. Keeping license key is good idea it helps you during audit and you have proof that you are using a valid Microsoft License. Plus in scenario of disaster where whole box gets damanged you might need to install SQL Server again in that case during
reinstallation on setup page where you need to enter key you might need need it. If you are missing your paper then you are in trouble.
2. Only on product key page license key is required and it is not required anywhere else during installation. Unless you enter valid product key installation will not proceed further.
3 License makes you a valid owner of Microsoft product with restrictions on how much hardware resource you can use how much max connections you can make etc. Key lets you install it on Windows machine making sure that you are using valid Microsoft product.
This was just a general idea please speak to your licensing specialist for more details. This is technical forum and we generally ask user to speak to licensing expert for such queries.
Please mark this reply as answer if it solved your issue or vote as helpful if it helped so that other forum members can benefit from it.
My TechNet Wiki Articles -
I have done extensive programming with the SQL Toolkit with LabVIEW versions through 6.1. My customer now wants to upgrade to Windows 7, so I am trying to upgrade to LabVIEW 2009 (my latest purchased version) using the Database Connectivity Toolkit, and the SQL Toolkit Compatibility vis. Everything seemed to be going okay with the higher level SQL operations, but I ran into trouble with the Get Column Name.vi.
The pictures below show the problem. The original SQL Toolkit connected the Prepare SQL.vi with the Get Column Name.vi with a cluster of two references, one for connection, and one for sql. The new compatibility vis have a class conflict in the wire because the Prepare SQL.vi contains a cluster with connection, and command references, but the Get Column Name.vi expects a cluster with connection and recordset references.
How do I resolve this conflict?
Thank You.
DanI've never worked with the old version of the toolkit, so I don't know how it did things, but looking inside the SQL prep VI, it only generates a command, and the the column name VI wants a recordset. I'm not super familiar with all the internals of ADO, but my understanding is that is standard - you only have the columns after you execute the command and get the recordset back. What you can apparently do here is insert the Execute Prepared SQL VI in the middle and that will return what you need.
I'm not sure why it worked before. Maybe the execute was hidden inside the prep VI or maybe you can get the column names out of the command object before execution. In general, I would recommend considering switching to the newer VIs.
Try to take over the world! -
Hi can you help with the following panic attack report,
hi can you help with the following panic attack report, macbook pro OS 10.7.3
Interval Since Last Panic Report: 157997 sec
Panics Since Last Report: 1
Anonymous UUID: 7ADCF50C-CC18-405E-9D5C-03325D3A83FA
Thu Mar 29 05:37:28 2012
panic(cpu 0 caller 0xffffff80002c266d): Kernel trap at 0xffffff800021d905, type 14=page fault, registers:
CR0: 0x000000008001003b, CR2: 0xffffef801a845328, CR3: 0x0000000019452019, CR4: 0x00000000000606e0
RAX: 0xffffff801a8450d8, RBX: 0xffffff800e79f340, RCX: 0xffffff801a8450d8, RDX: 0xffffef801a8450d8
RSP: 0xffffff80a4623e90, RBP: 0xffffff80a4623eb0, RSI: 0x0000000020c85580, RDI: 0x0000000000000001
R8: 0xffffff80008bd890, R9: 0xffffff80058aeac8, R10: 0xfffffe80539a9928, R11: 0x0008000000053d89
R12: 0xffffff800e79f370, R13: 0xffffff8000846288, R14: 0xffffff801a8450c0, R15: 0x0000000000000001
RFL: 0x0000000000010206, RIP: 0xffffff800021d905, CS: 0x0000000000000008, SS: 0x0000000000000010
CR2: 0xffffef801a845328, Error code: 0x0000000000000002, Faulting CPU: 0x0
Backtrace (CPU 0), Frame : Return Address
0xffffff80a4623b50 : 0xffffff8000220702
0xffffff80a4623bd0 : 0xffffff80002c266d
0xffffff80a4623d70 : 0xffffff80002d7a1d
0xffffff80a4623d90 : 0xffffff800021d905
0xffffff80a4623eb0 : 0xffffff800021daad
0xffffff80a4623ee0 : 0xffffff800023caa9
0xffffff80a4623f10 : 0xffffff800023cb36
0xffffff80a4623f30 : 0xffffff80005a3258
0xffffff80a4623f60 : 0xffffff80005ca448
0xffffff80a4623fb0 : 0xffffff80002d7f39
BSD process name corresponding to current thread: SophosAntiVirus
Mac OS version:
11D50b
Kernel version:
Darwin Kernel Version 11.3.0: Thu Jan 12 18:47:41 PST 2012; root:xnu-1699.24.23~1/RELEASE_X86_64
Kernel UUID: 7B6546C7-70E8-3ED8-A6C3-C927E4D3D0D6
System model name: MacBookPro8,3 (Mac-942459F5819B171B)
System uptime in nanoseconds: 5720232329361
last loaded kext at 5694112402758: com.apple.iokit.IOSCSIBlockCommandsDevice 3.0.3 (addr 0xffffff7f807a3000, size 86016)
last unloaded kext at 248390619372: com.apple.driver.AppleUSBUHCI 4.4.5 (addr 0xffffff7f80a4e000, size 65536)
loaded kexts:
com.sophos.kext.sav 7.3.0
com.apple.driver.AppleUSBCDC 4.1.15
com.apple.driver.AppleHWSensor 1.9.4d0
com.apple.filesystems.autofs 3.0
com.apple.driver.AppleMikeyHIDDriver 122
com.apple.driver.AudioAUUC 1.59
com.apple.driver.AppleUpstreamUserClient 3.5.9
com.apple.driver.AppleMCCSControl 1.0.26
com.apple.driver.AppleHDA 2.1.7f9
com.apple.driver.AppleMikeyDriver 2.1.7f9
com.apple.driver.AppleIntelHD3000Graphics 7.1.8
com.apple.driver.AGPM 100.12.42
com.apple.kext.ATIFramebuffer 7.1.8
com.apple.driver.SMCMotionSensor 3.0.1d2
com.apple.iokit.IOUserEthernet 1.0.0d1
com.apple.driver.AppleSMCLMU 2.0.1d2
com.apple.Dont_Steal_Mac_OS_X 7.0.0
com.apple.driver.AudioIPCDriver 1.2.2
com.apple.driver.ACPI_SMC_PlatformPlugin 4.7.5d4
com.apple.driver.AppleMuxControl 3.0.16
com.apple.driver.AppleLPC 1.5.3
com.apple.ATIRadeonX3000 7.1.8
com.apple.driver.AppleUSBTCButtons 225.2
com.apple.driver.AppleUSBTCKeyboard 225.2
com.apple.driver.AppleIRController 312
com.apple.AppleFSCompression.AppleFSCompressionTypeDataless 1.0.0d1
com.apple.AppleFSCompression.AppleFSCompressionTypeZlib 1.0.0d1
com.apple.BootCache 33
com.apple.iokit.SCSITaskUserClient 3.0.3
com.apple.iokit.IOAHCIBlockStorage 2.0.1
com.apple.driver.AppleUSBHub 4.5.0
com.apple.driver.AppleFWOHCI 4.8.9
com.apple.driver.AirPort.Brcm4331 513.20.19
com.apple.iokit.AppleBCM5701Ethernet 3.0.8b2
com.apple.driver.AppleEFINVRAM 1.5.0
com.apple.driver.AppleAHCIPort 2.2.0
com.apple.driver.AppleSmartBatteryManager 161.0.0
com.apple.driver.AppleUSBEHCI 4.5.8
com.apple.driver.AppleACPIButtons 1.4
com.apple.driver.AppleRTC 1.4
com.apple.driver.AppleHPET 1.6
com.apple.driver.AppleSMBIOS 1.7
com.apple.driver.AppleACPIEC 1.4
com.apple.driver.AppleAPIC 1.5
com.apple.driver.AppleIntelCPUPowerManagementClient 167.3.0
com.apple.nke.applicationfirewall 3.2.30
com.apple.security.quarantine 1.1
com.apple.driver.AppleIntelCPUPowerManagement 167.3.0
com.apple.iokit.IOSCSIBlockCommandsDevice 3.0.3
com.apple.iokit.IOUSBMassStorageClass 3.0.1
com.apple.kext.triggers 1.0
com.apple.driver.AppleAVBAudio 1.0.0d11
com.apple.driver.DspFuncLib 2.1.7f9
com.apple.driver.AppleSMBusController 1.0.10d0
com.apple.iokit.IOSurface 80.0
com.apple.iokit.IOFireWireIP 2.2.4
com.apple.iokit.IOBluetoothSerialManager 4.0.3f12
com.apple.iokit.IOSerialFamily 10.0.5
com.apple.iokit.IOAVBFamily 1.0.0d22
com.apple.driver.AppleHDAController 2.1.7f9
com.apple.iokit.IOHDAFamily 2.1.7f9
com.apple.iokit.IOAudioFamily 1.8.6fc6
com.apple.kext.OSvKernDSPLib 1.3
com.apple.driver.ApplePolicyControl 3.0.16
com.apple.driver.AppleSMC 3.1.1d8
com.apple.driver.IOPlatformPluginFamily 4.7.5d4
com.apple.driver.AppleSMBusPCI 1.0.10d0
com.apple.driver.AppleGraphicsControl 3.0.16
com.apple.driver.AppleBacklightExpert 1.0.3
com.apple.iokit.IONDRVSupport 2.3.2
com.apple.kext.ATI6000Controller 7.1.8
com.apple.kext.ATISupport 7.1.8
com.apple.driver.AppleIntelSNBGraphicsFB 7.1.8
com.apple.iokit.IOGraphicsFamily 2.3.2
com.apple.driver.BroadcomUSBBluetoothHCIController 4.0.3f12
com.apple.driver.AppleUSBBluetoothHCIController 4.0.3f12
com.apple.iokit.IOBluetoothFamily 4.0.3f12
com.apple.driver.AppleThunderboltDPInAdapter 1.5.9
com.apple.driver.AppleThunderboltDPAdapterFamily 1.5.9
com.apple.driver.AppleThunderboltPCIDownAdapter 1.2.1
com.apple.driver.AppleUSBMultitouch 227.1
com.apple.iokit.IOUSBHIDDriver 4.4.5
com.apple.driver.AppleUSBMergeNub 4.5.3
com.apple.driver.AppleUSBComposite 4.5.8
com.apple.iokit.IOSCSIMultimediaCommandsDevice 3.0.3
com.apple.iokit.IOBDStorageFamily 1.6
com.apple.iokit.IODVDStorageFamily 1.7
com.apple.iokit.IOCDStorageFamily 1.7
com.apple.driver.XsanFilter 403
com.apple.iokit.IOAHCISerialATAPI 2.0.1
com.apple.iokit.IOSCSIArchitectureModelFamily 3.0.3
com.apple.driver.AppleThunderboltNHI 1.3.2
com.apple.iokit.IOThunderboltFamily 1.7.4
com.apple.iokit.IOUSBUserClient 4.5.8
com.apple.iokit.IOFireWireFamily 4.4.5
com.apple.iokit.IO80211Family 412.2
com.apple.iokit.IOEthernetAVBController 1.0.0d5
com.apple.iokit.IONetworkingFamily 2.0
com.apple.iokit.IOAHCIFamily 2.0.7
com.apple.iokit.IOUSBFamily 4.5.8
com.apple.driver.AppleEFIRuntime 1.5.0
com.apple.iokit.IOHIDFamily 1.7.1
com.apple.iokit.IOSMBusFamily 1.1
com.apple.security.sandbox 177.3
com.apple.kext.AppleMatch 1.0.0d1
com.apple.security.TMSafetyNet 7
com.apple.driver.DiskImages 331.3
com.apple.iokit.IOStorageFamily 1.7
com.apple.driver.AppleKeyStore 28.18
com.apple.driver.AppleACPIPlatform 1.4
com.apple.iokit.IOPCIFamily 2.6.8
com.apple.iokit.IOACPIFamily 1.4
Model: MacBookPro8,3, BootROM MBP81.0047.B27, 4 processors, Intel Core i7, 2.2 GHz, 4 GB, SMC 1.70f5
Graphics: AMD Radeon HD 6750M, AMD Radeon HD 6750M, PCIe, 1024 MB
Graphics: Intel HD Graphics 3000, Intel HD Graphics 3000, Built-In, 384 MB
Memory Module: BANK 0/DIMM0, 2 GB, DDR3, 1333 MHz, 0x80AD, 0x484D54333235533642465238432D48392020
Memory Module: BANK 1/DIMM0, 2 GB, DDR3, 1333 MHz, 0x80AD, 0x484D54333235533642465238432D48392020
AirPort: spairport_wireless_card_type_airport_extreme (0x14E4, 0xD6), Broadcom BCM43xx 1.0 (5.100.98.75.19)
Bluetooth: Version 4.0.3f12, 2 service, 18 devices, 2 incoming serial ports
Network Service: AirPort, AirPort, en1
Serial ATA Device: TOSHIBA MK7559GSXF, 750.16 GB
Serial ATA Device: MATSHITADVD-R UJ-898
USB Device: FaceTime HD Camera (Built-in), apple_vendor_id, 0x8509, 0xfa200000 / 3
USB Device: hub_device, 0x0424 (SMSC), 0x2514, 0xfa100000 / 2
USB Device: BRCM2070 Hub, 0x0a5c (Broadcom Corp.), 0x4500, 0xfa110000 / 5
USB Device: Bluetooth USB Host Controller, apple_vendor_id, 0x821a, 0xfa113000 / 8
USB Device: Apple Internal Keyboard / Trackpad, apple_vendor_id, 0x0245, 0xfa120000 / 4
USB Device: hub_device, 0x0424 (SMSC), 0x2514, 0xfd100000 / 2
USB Device: IR Receiver, apple_vendor_id, 0x8242, 0xfd110000 / 3Get rid of Sophos Anti-Virus software you have installed. Use the uninstaller or:
Uninstalling Software: The Basics
Most OS X applications are completely self-contained "packages" that can be uninstalled by simply dragging the application to the Trash. Applications may create preference files that are stored in the /Home/Library/Preferences/ folder. Although they do nothing once you delete the associated application, they do take up some disk space. If you want you can look for them in the above location and delete them, too.
Some applications may install an uninstaller program that can be used to remove the application. In some cases the uninstaller may be part of the application's installer, and is invoked by clicking on a Customize button that will appear during the install process.
Some applications may install components in the /Home/Library/Applications Support/ folder. You can also check there to see if the application has created a folder. You can also delete the folder that's in the Applications Support folder. Again, they don't do anything but take up disk space once the application is trashed.
Some applications may install a startupitem or a Log In item. Startupitems are usually installed in the /Library/StartupItems/ folder and less often in the /Home/Library/StartupItems/ folder. Log In Items are set in the Accounts preferences. Open System Preferences, click on the Accounts icon, then click on the LogIn Items tab. Locate the item in the list for the application you want to remove and click on the "-" button to delete it from the list.
Some software use startup daemons or agents that are a new feature of the OS. Look for them in /Library/LaunchAgents/ and /Library/LaunchDaemons/ or in /Home/Library/LaunchAgents/.
If an application installs any other files the best way to track them down is to do a Finder search using the application name or the developer name as the search term. Unfortunately Spotlight will not look in certain folders by default. You can modify Spotlight's behavior or use a third-party search utility, Easy Find, instead. Download Easy Find at VersionTracker or MacUpdate.
Some applications install a receipt in the /Library/Receipts/ folder. Usually with the same name as the program or the developer. The item generally has a ".pkg" extension. Be sure you also delete this item as some programs use it to determine if it's already installed.
There are many utilities that can uninstall applications. Here is a selection:
AppZapper
Automaton
Hazel
CleanApp
Yank
SuperPop
Uninstaller
Spring Cleaning
Look for them at VersionTracker or MacUpdate.
For more information visit The XLab FAQs and read the FAQ on removing software. -
hello applecare can you help with the macbook pro i did the update the last one and safari doesn't open anything .. what should i do ?
Hello John...
You may have a Safari third party add on installed that was compatible with the previous version of Safari but not 5.1. Try troubleshooting > Safari: Unsupported third-party add-ons may cause Safari to unexpectedly quit or have performance issues
FYI... this is a user to user forum. If you can't resolve the issue, information for contacting AppleCare here. -
Need some help with the colour profile please. Urgent! Thanks
Dear all, I need help with the colour profile of my photoshop CS6.
I've taken a photo with my Canon DSLR. When I opened the raw with ACDSee, the colour looks perfectly ok.
So I go ahead and open in photoshop. I did nothing to the photo. It still looks ok
Then I'm prompt the Embedded Profile Mismatch error. I go ahead and choose Discard the embedded profile option
And the colour started to get messed up.
And the output is a total diasater
Put the above photo side by side with the raw, the red has became crimson!!
So I tried the other option, Use the embedded profile
The whole picture turns yellowish in Photoshop's interface
And the output is just the same as the third option.
Could someone please guide me how to fix this? Thank you.I'm prompt the Embedded Profile Mismatch error. I go ahead and choose Discard the embedded profile option
always use the embedded profile when opening tagged images in Photoshop - at that point Photoshop will convert the source colors over to your monitor space correctly
if your colors are wrong at that point either your monitor profile is off, or your source colors are not what you think they are - if other apps are displaying correctly you most likely have either a defective monitor profile or source profile issues
windows calibrate link:
http://windows.microsoft.com/en-US/windows7/Calibrate-your-display
for Photoshop to work properly, i recall you want to have "use my settings for this device" checked in Color Management> Device tab
you may want to download the PDI reference image to check your monitor and print workflows
and complete five easy steps to profile enlightenment in Photoshop
with your settings, monitor profile and source profiles sorted out it should be pretty easy to pinpoint the problem... -
Hi, please help with the installation of Lightroom 4, I bought a new Mac (Apple) and I want to install a software that I have on the album cd. My new computer does not have the drives. Can I download software from Adobe? Is my license number just to be able to download the srtony adobe.
Adobe - Lightroom : For Macintosh
Hal
Maybe you are looking for
-
Error while Installment Plan creation
Dear friends , When i am saving the installment plan i am getting this error can anyone please let me know how to rectify this error Internal error: Incorrect use of a function module Function module FKK_TAX_EXEMPT_KEY_DETERMINE was called with incom
-
Did DreamWeaver CS5 fix the missing "Volumes" in local file paths for "Browse in-"?
I can't "Browse in Chrome", no matter what I do. I tried: Re-Installing Chrome. (It's a drag-drop operation. nothing to install ) Searched in Preferences for a value like the Opendiff to compare documents. If you select "browse in Firefox" it works.
-
Passer de snow leopard a lion 10.7
Bonjour, Je suis sur snow léopard je souhaite passer a lion 10.7 , je ne trouve plus sur apple store de lien pour acheter lion 10.7. de plus l'orsque j'éssai de telecharger mountain lion 10.8 apple store m'indique que ma machine n'est pas compatble .
-
Updation of MCHB-CLABS value on Post Goods Issue through VL01n
When POsting Goods Issue I need to change MCHB-CLABS value. My requirement: When quantity left in the stock is less than (MCHB-CLABS) .005 I am adding the remaining quantity left to delivered quantity, but the stock (MCHB-CLABS) is not getting upd
-
Summing up the networking grief
I'm apparently having similar issues as many others with internet/network performance following update of my MacBook to 10.5/10.5.1. Possible solutions are spread out over many threads here, so I'd like to try to pull them together and note that they