Hi I need a report

Question

Hi,
I am having two tables as following I need a difference report as following. I was used to write a minus query to find the differences but I am asked to show a report
as following. So can any one help me in this regard.
Table1
ID Name
1 Nancy
2. Paul
3. David
Table2
ID Name
1 Fancy
4 John
3 David
Required report as follows.
ID Name1 Name2
1 Nancy Fancy
2 Paul -----
4 ----- John

Answer 1

... But if we have a composite key with a Hire date as a key
then how can we get the response. That means I need
a hire Date field also to be added in between EID &
ENAME. Can any one suggest me a solution for this.
test@ora>
test@ora>
test@ora> --
test@ora> with table1 as (
  2    select 1 as id, 'Nancy' as name, to_date('01/01/2007','mm/dd/yyyy') as hire_date from dual union all
  3    select 2, 'Paul',  to_date('01/01/2005','mm/dd/yyyy') from dual union all
  4    select 3, 'David', to_date('01/01/2006','mm/dd/yyyy') from dual),
  5  table2 as (
  6    select 1 as id, 'Fancy' as name, to_date('01/01/2007','mm/dd/yyyy') as hire_date from dual union all
  7    select 4, 'John',  to_date('01/01/2005','mm/dd/yyyy') from dual union all
  8    select 3, 'David', to_date('01/01/2006','mm/dd/yyyy') from dual)
  9  --
10  select
11    coalesce(t1.id,t2.id)     as id,
12    nvl(t1.name,'-----')      as name1,
13    case when t1.hire_date is null then '-----' else to_char(t1.hire_date,'mm/dd/yyyy') end as hire_date1,
14    nvl(t2.name,'-----')      as name2,
15    case when t2.hire_date is null then '-----' else to_char(t2.hire_date,'mm/dd/yyyy') end as hire_date2
16  from table1 t1
17  full outer join table2 t2
18  on (t1.id = t2.id and t1.hire_date = t2.hire_date)
19  where nvl(t1.name,chr(0)) <> nvl(t2.name,chr(0));
        ID NAME1 HIRE_DATE1 NAME2 HIRE_DATE2
         1 Nancy 01/01/2007 Fancy 01/01/2007
         2 Paul  01/01/2005 ----- -----
         4 ----- -----      John  01/01/2005
test@ora>
test@ora>
test@ora>isotope